The factors of 6 are 1, 2, 3, and 6.
The reciprocals of these numbers are $1/1$, $1/2$, $1/3$, and $1/6$.
The sum of these reciprocals is $1/1 + 1/2 + 1/3 + 1/6 = \frac{6}{6} + \frac{3}{6} + \frac{2}{6} + \frac{1}{6} = \frac{12}{6} = \boxed{2}$.
The answer is: 2
Below is a math problem. Provide a detailed, step-by-step solution.

### Problem:
What is the sum of the reciprocals of the natural-number factors of 6?

### Answer:
