The prime factorization of 91 is $7 \times 13$.
To find the sum of all the positive divisors of 91, we can use the formula for the sum of divisors of a number.
For a prime factorization of $p_1^{a_1} \cdot p_2^{a_2} \cdot \ldots \cdot p_n^{a_n}$,
the sum of the divisors is equal to $(1 + p_1 + p_1^2 + \ldots + p_1^{a_1})(1 + p_2 + p_2^2 + \ldots + p_2^{a_2}) \ldots (1 + p_n + p_n^2 + \ldots + p_n^{a_n})$.
For 91, we have $(1 + 7)(1 + 13) = 8 \times 14 = \boxed{112}$.
The answer is: 112
Below is a math problem. Provide a detailed, step-by-step solution.

### Problem:
What is the sum of all the positive divisors of 91?

### Answer:
