Let the number be $x$.
We are given that $1 + \frac{1}{x} = \frac{7}{3}$.
Subtracting 1 from both sides gives $\frac{1}{x} = \frac{7}{3} - 1 = \frac{4}{3}$.
Taking the reciprocal of both sides gives $x = \frac{3}{4}$.
So the original number is $\boxed{\frac{3}{4}}$.
The answer is: \frac{3}{4}
Below is a math problem. Provide a detailed, step-by-step solution.

### Problem:
If one more than the reciprocal of a certain number is equal to 7/3, what is the original number expressed as a common fraction?

### Answer:
