The minimum number of marbles that can be divided equally among 2, 3, 4, 5, or 6 children is the least common multiple (LCM) of these numbers.
To find the LCM, we prime factorize each number: \[
\begin{aligned} 2 &= 2 \\ 3 &= 3 \\ 4 &= 2^2 \\ 5 &= 5 \\ 6 &= 2 \cdot 3 . \end{aligned}
\] The LCM is then the product of the highest powers of all the prime factors: \[
\text{lcm}(2,3,4,5,6) = 2^2 \cdot 3 \cdot 5 = 60 .
\] So, the minimum number of marbles is $\boxed{60}$.
The answer is: 60
Below is a math problem. Provide a detailed, step-by-step solution.

### Problem:
What is the minimum number of marbles in a set that can be divided equally among 2, 3, 4, 5, or 6 children with no marbles left over?

### Answer:
