To solve $x^2 - 2x > 35$, we start by moving all the terms to one side to get $x^2 - 2x - 35 > 0$.
Next, we can factor the quadratic to get $(x-7)(x+5) > 0$.
Now, we can use the zero product property and set each factor greater than zero to find the intervals where the inequality is true.
For $(x-7) > 0$, we have $x > 7$.
For $(x+5) > 0$, we have $x > -5$.
Since we are looking for the intersection of these two intervals, the solution is $x \in \boxed{(-\infty, -5) \cup (7, \infty)}$.
The answer is: (-\infty,-5)\cup(7,\infty)
Below is a math problem. Provide a detailed, step-by-step solution.

### Problem:
For what values of $x$ is $x^2-2x>35$? Express your answer in interval notation.

### Answer:
