The common difference of the arithmetic sequence is $\frac{59-2}{20-1}= \frac{57}{19}$. 
To find the 5th term, we can use the formula for the nth term of an arithmetic sequence: 
$a_n = a_1 + (n-1)d$, where $a_n$ is the nth term, $a_1$ is the first term, and $d$ is the common difference. 
Plugging in the values, we have $a_5 = 2 + (5-1)\left(\frac{57}{19}\right) = 2 + 4\left(\frac{57}{19}\right) = 2 + \frac{4(57)}{19} = 2 + \frac{228}{19} = 2 + 12 = \boxed{14}$. 
The answer is: 14
Below is a math problem. Provide a detailed, step-by-step solution.

### Problem:
What is the 5th term of an arithmetic sequence of 20 terms with first and last terms of 2 and 59, respectively?

### Answer:
