For the first lawsuit, there is a 30% chance of winning $5,000,000 and a 70% chance of winning $0.
For the second lawsuit, there is a 50% chance of winning $2,000,000 and a 50% chance of winning $1,000,000.
To calculate the probability of losing both lawsuits, we multiply the probabilities of losing each lawsuit together: 70% * 50% = 35%.
To calculate the probability of winning both lawsuits, we multiply the probabilities of winning each lawsuit together: 30% * 50% = 15%.
To determine how much more likely it is to lose both lawsuits compared to winning both, we subtract the probability of winning both from the probability of losing both: 35% - 15% = 20%.
Therefore, it is 20% more likely that Andy loses both lawsuits compared to winning both of them.
#### 20
The answer is: 20
Below is a math problem. Provide a detailed, step-by-step solution.

### Problem:
Andy is a lawyer who's working on two lawsuits. The first lawsuit has a 30% chance of paying out $5,000,000 upon a win and $0 if he loses it. The second lawsuit has a 50% chance of paying out $1,000,000 if Andy loses and a 50% chance of paying out $2,000,000 if he wins.  Expressed as a percentage, how much more likely is it that Andy loses both lawsuits compared to winning both of them?

### Answer:
