An obtuse angle is greater than a right angle (90 degrees).
If one angle in the triangle is 50% larger than a right angle, then it measures $90 + 0.5(90) = 90 + 45 = 135$ degrees.
Since the triangle is isosceles, the other two angles are equal.
Let's call the measure of one of these angles $x$ degrees.
Then the sum of the angles in the triangle is $x + x + 135 = 2x + 135$ degrees.
We know that the sum of the angles in a triangle is 180 degrees, so we can write the equation $2x + 135 = 180$.
Solving for $x$, we find $x = \frac{180 - 135}{2} = \frac{45}{2} = 22.5$ degrees.
Therefore, one of the smaller angles in the triangle measures approximately $\boxed{22.5}$ degrees.
The answer is: 22.5
Below is a math problem. Provide a detailed, step-by-step solution.

### Problem:
In an obtuse, isosceles triangle, one angle is 50% larger than a right angle. What is the measure, in degrees, of one of the two smaller angles in the triangle? Give your answer as a decimal rounded to the nearest tenth.

### Answer:
