We can rewrite $2400$ as $7^x$ to find the value of $x$.
Taking the logarithm base $7$ of both sides, we have $\log_{7}{2400} = x$.
Now, we need to find the value of $x$.
Since $7^3 = 343$ and $7^4 = 2401$, we know that $x$ is between $3$ and $4$.
Since $2400$ is closer to $2401$ than to $343$, we can round $x$ to the nearest integer as $\boxed{4}$.
The answer is: 4
Below is a math problem. Provide a detailed, step-by-step solution.

### Problem:
What is $\log_{7}{2400}$ rounded to the nearest integer?

### Answer:
