We are given that $5a + 2b = 0$ and $a$ is two less than $b$.
Substituting $b = a + 2$ into the first equation, we get $5a + 2(a + 2) = 0$.
Simplifying, we have $7a + 4 = 0$.
Solving for $a$, we find $a = -\frac{4}{7}$.
Substituting this value back into the equation $b = a + 2$, we get $b = -\frac{4}{7} + 2 = \frac{10}{7}$.
Therefore, $7b = 7 \cdot \frac{10}{7} = \boxed{10}$.
The answer is: 10
Below is a math problem. Provide a detailed, step-by-step solution.

### Problem:
Given that $5a + 2b = 0$ and $a$ is two less than $b$, what is the value of $7b$?

### Answer:
