We can rewrite the inequality as $x^2-2x-35>0$.
To solve this quadratic inequality, we can factor it as $(x-7)(x+5)>0$.
The inequality is satisfied when either both factors are positive or both factors are negative.
When $x< -5$, both factors are negative, so the inequality holds.
When $-5<x<7$, the factor $x+5$ is positive and the factor $x-7$ is negative, so the inequality does not hold.
When $x>7$, both factors are positive, so the inequality holds.
Therefore, the solution to the inequality is $x \in \boxed{(-\infty,-5) \cup (7,\infty)}$.
The answer is: (-\infty,-5)\cup(7,\infty)
Below is a math problem. Provide a detailed, step-by-step solution.

### Problem:
For what values of $x$ is $x^2-2x>35$? Express your answer in interval notation.

### Answer:
