
$3! = 3 \cdot 2 \cdot 1 = 6$.

Therefore, $\sqrt{3! \cdot 3!} = \sqrt{6 \cdot 6} = \sqrt{36} = \boxed{6}$.

The answer is: 6
Below is a math problem. Provide a detailed, step-by-step solution.

### Problem:
What is the value of $\sqrt{3! \cdot 3!}$ expressed as a positive integer?

### Answer:
