First, we can list the prime factorizations of the three numbers:
\[12 = 2^2 \cdot 3^1,\]
\[18 = 2^1 \cdot 3^2,\]
\[30 = 2^1 \cdot 3^1 \cdot 5^1.\]
To find the least common multiple, we take the highest power of each prime that appears in the factorizations.
So, the least common multiple is $2^2 \cdot 3^2 \cdot 5^1 = \boxed{180}$.The answer is: 180
Below is a math problem. Provide a detailed, step-by-step solution.

### Problem:
What is the least common multiple of 12, 18 and 30?

### Answer:
