To rewrite $3x^2 - 6x - 2$ in the form $a(x - h)^2 + k$, we need to complete the square.
First, we factor out the leading coefficient of $3$ from the quadratic: $3(x^2 - 2x) - 2$.
Next, we add and subtract $(2/2)^2 = 1$ inside the parentheses: $3(x^2 - 2x + 1 - 1) - 2$.
This allows us to rewrite the expression as $3((x - 1)^2 - 1) - 2$.
Expanding, we have $3(x - 1)^2 - 3 - 2$, which simplifies to $3(x - 1)^2 - 5$.
Comparing this expression to $a(x - h)^2 + k$, we can see that $a = 3$, $h = 1$, and $k = -5$.
Therefore, the sum of $a$, $h$, and $k$ is $3 + 1 - 5 = \boxed{-1}$.
The answer is: -1
Below is a math problem. Provide a detailed, step-by-step solution.

### Problem:
If we rewrite $3x^2 - 6x - 2$ in the form $a(x - h)^2 + k$, what is the sum of $a$, $h$, and $k$?

### Answer:
