We are given that two congruent cones are enclosed within a cylinder.
The radius of each cone is X cm and the height is 12 cm.
The base of each cone is a base of the cylinder, and the height of the cylinder is 24 cm.
To find the volume of the cylinder not occupied by the cones, we need to find the volume of the cylinder and subtract the volume of the cones.
The formula for the volume of a cylinder is:
Volume of cylinder = $\pi r^2 h$
where $r$ is the radius and $h$ is the height.
The formula for the volume of a cone is:
Volume of cone = $\frac{1}{3} \pi r^2 h$
where $r$ is the radius and $h$ is the height.
Given that the volume of the cylinder not occupied by the cones is $2304\pi$, we can set up the equation:
Volume of cylinder - 2 * Volume of cone = 2304\pi
$\pi r^2 (24) - 2 * \frac{1}{3} \pi r^2 (12) = 2304\pi$
Simplifying the equation, we have:
$24r^2 - 8r^2 = 2304$
$16r^2 = 2304$
Dividing both sides of the equation by 16, we find:
$r^2 = 144$
Taking the square root of both sides of the equation, we get:
$r = 12$
The value of $X$ is 12.
The answer is: 12
Below is a math problem. Provide a detailed, step-by-step solution.

### Problem:
Two congruent cones with radius X cm and height 12 cm are enclosed within a cylinder. The base of each cone is a base of the cylinder, and the height of the cylinder is 24 cm. What is the number of cubic centimeters in the volume of the cylinder not occupied by the cones? Express your answer in terms of $\pi$.
If we know the answer to the above question is 2304\pi, what is the value of unknown variable X?

### Answer:
