$i^2 = -1$, so $i^4 = (-1)^2 = 1$.
Since $i^4 = 1$, we can divide 22 by 4 and find that $i^{22} = i^{4 \cdot 5 + 2} = (i^4)^5 \cdot i^2 = 1^5 \cdot -1 = -1$.
Similarly, we can divide 222 by 4 and find that $i^{222} = i^{4 \cdot 55 + 2} = (i^4)^{55} \cdot i^2 = 1^{55} \cdot -1 = -1$.
Therefore, $i^{22} + i^{222} = -1 + (-1) = \boxed{-2}$.
The answer is: -2
Below is a math problem. Provide a detailed, step-by-step solution.

### Problem:
Evaluate $i^{22} + i^{222}$.

### Answer:
