To convert $53_6$ to base 10, we have $53_6 = 5 \cdot 6^1 + 3 \cdot 6^0 = 33$.
Similarly, to convert $113_b$ to base 10, we have $113_b = 1 \cdot b^2 + 1 \cdot b^1 + 3 \cdot b^0$.
Since $113_b = 33$, we have $b^2 + b + 3 = 33$.
Rearranging, we get $b^2 + b - 30 = 0$.
Factoring, we have $(b+6)(b-5) = 0$.
Since $b$ must be positive, the positive value of $b$ is $\boxed{5}$.
The answer is: 5
Below is a math problem. Provide a detailed, step-by-step solution.

### Problem:
The base six number $53_{6}$ is equal to the base $b$ number $113_{b}$. What is the positive value of $b$?

### Answer:
