The total number of marbles is $2+3+10=15$.
The probability of drawing a red marble on the first draw is $\frac{2}{15}$.
After drawing a red marble, there is one red marble left out of a total of $15-1=14$ marbles.
So the probability of drawing a second red marble is $\frac{1}{14}$.
Therefore, the probability of drawing two red marbles is $\frac{2}{15} \times \frac{1}{14} = \boxed{\frac{1}{105}}$.
The answer is: \frac{1}{105}
Below is a math problem. Provide a detailed, step-by-step solution.

### Problem:
In a jar with two red marbles, three green marbles, and ten white marbles (and no other marbles), two marbles are drawn randomly without replacement. What is the probability that both of the marbles drawn will be red? Express your answer as a common fraction.

### Answer:
