We are given the equation \[x^{2018} +44x^{2015} + 3x^3 + 404 = X\] and we want to find the value of $X$.
The sum of the squares of the roots of a polynomial equation can be found using Vieta's formulas.
Vieta's formulas state that for a polynomial of the form \[ax^n + bx^{n-1} + cx^{n-2} + ... + k = 0\], the sum of the roots squared is equal to \[\frac{b^2 - 2ac}{a^2}\].
In this case, our equation is \[x^{2018} +44x^{2015} + 3x^3 + 404 = X\], so we can identify:
$a = 1$ (coefficient of $x^{2018}$)
$b = 44$ (coefficient of $x^{2015}$)
$c = 3$ (coefficient of $x^3$)
$k = 404 - X$ (constant term)
We want to find the value of $X$ such that the sum of the squares of the roots is 0.
Using Vieta's formulas, we can set up the equation:
\[\frac{b^2 - 2ac}{a^2} = 0\]
Substituting the values of $a$, $b$, and $c$, we have:
\[\frac{44^2 - 2(1)(3)}{1^2} = 0\]
Simplifying the equation, we get:
\[\frac{1936 - 6}{1} = 0\]
\[\frac{1930}{1} = 0\]
Since $\frac{1930}{1}$ is not equal to 0, there is no value of $X$ that satisfies the given condition.
Therefore, there is no value of $X$ that makes the sum of the squares of the roots equal to 0.
The answer is: 0
Below is a math problem. Provide a detailed, step-by-step solution.

### Problem:
Compute the sum of the squares of the roots of the equation \[x^{2018} +44x^{2015} + 3x^3 + 404 = X
If we know the answer to the above question is 0, what is the value of unknown variable X?

### Answer:
