In 2005, half the number of kids came compared to 2004, so there were 60/2 = 30 kids.
In 2006, 2/3 as many kids came compared to 2005, so there were 30 * (2/3) = 20 kids.
Therefore, 20 kids came to the cookout in 2006.
#### 20
The answer is: 20
Below is a math problem. Provide a detailed, step-by-step solution.

### Problem:
If there were initially 60 kids at a cookout in 2004, and in 2005, half the number of kids came compared to 2004, and in 2006, 2/3 as many kids came compared to 2005, how many kids came to the cookout in 2006?

### Answer:
