There are a total of $\binom{7}{2}=21$ ways to choose 2 apples from the 7 apples.
Out of the 7 apples, there are $\binom{3}{2}=3$ ways to choose 2 green apples.
Therefore, the probability that both apples he chooses are green is $\frac{3}{21}=\boxed{\frac{1}{7}}$.
The answer is: \frac{1}{7}
Below is a math problem. Provide a detailed, step-by-step solution.

### Problem:
James has 7 apples. 4 of them are red, and 3 of them are green. If he chooses 2 apples at random, what is the probability that both the apples he chooses are green?

### Answer:
