The expression $\frac{3x}{2x^2 - 6x + 4}$ is undefined when the denominator is equal to zero.
So, we set $2x^2 - 6x + 4 = 0$ and solve for $x$.
Factoring, we get $(2x - 2)(x - 2) = 0$.
This gives us $x = 1$ and $x = 2$ as the values where the expression is undefined.
Therefore, the domain of the equation is all real numbers except $x = 1$ and $x = 2$.
Hence, $A + B = 1 + 2 = \boxed{3}$.
The answer is: 3
Below is a math problem. Provide a detailed, step-by-step solution.

### Problem:
The domain of the equation $y = \frac{3x}{2x^2 - 6x + 4}$ is the set of all real numbers with the exception of the values $x = A$ and $x = B$. What is $A + B$?

### Answer:
