In an arithmetic sequence, the difference between consecutive terms is constant.
Let's call this common difference $d$.
The thirteenth term is the first term plus twelve times the common difference, so we have the equation $5+12d=29$.
Solving for $d$, we find $d=2$.
The fiftieth term is the first term plus forty-nine times the common difference, so the value of the fiftieth term is $5+49(2)=\boxed{103}$.
The answer is: 103
Below is a math problem. Provide a detailed, step-by-step solution.

### Problem:
In an arithmetic sequence, the first term is 5 and the thirteenth term is 29. What is the value of the fiftieth term?

### Answer:
