Substituting $x=-2$ into the expression, we have $\frac{3+(-2)(3+(-2))-3^2}{(-2)-3+(-2)^2}$.
Simplifying the numerator and denominator, we get $\frac{3-2(1)-9}{-2-3+4}$.
Further simplifying, we have $\frac{3-2-9}{-2-3+4}$.
Continuing to simplify, we get $\frac{-8}{-1}$.
Finally, we have $\frac{-8}{-1}=\boxed{8}$.
The answer is: 8
Below is a math problem. Provide a detailed, step-by-step solution.

### Problem:
Calculate the value of $\frac{3+x(3+x)-3^2}{x-3+x^2}$ when $x$ is equal to $-2$.

### Answer:
