We are given that a box with a volume of $X$ $\text{cm}^3$ can hold 50 paperclips.
To find out how many paperclips a box with a volume of 48 $\text{cm}^3$ can hold, we can set up a proportion using the given information:
$X$ $\text{cm}^3$ / 50 paperclips = 48 $\text{cm}^3$ / $Y$ paperclips
We can cross-multiply and solve for $Y$:
$X \cdot Y = 48 \cdot 50$
$Y = \frac{48 \cdot 50}{X}$
Given that the value of $Y$ is 150, we can substitute it into the equation:
150 = $\frac{48 \cdot 50}{X}$
Multiplying both sides of the equation by $X$ to eliminate the fraction, we get:
$150X = 48 \cdot 50$
Dividing both sides of the equation by 150, we find:
$X = \frac{48 \cdot 50}{150}$
$X = \frac{48}{3}$
$X = 16$
The value of $X$ is 16.
The answer is: 16
Below is a math problem. Provide a detailed, step-by-step solution.

### Problem:
A box with a volume of X $\text{cm}^3$ can hold 50 paperclips. How many paperclips could a box with a volume of 48 $\text{cm}^3$ hold?
If we know the answer to the above question is 150, what is the value of unknown variable X?

### Answer:
