We want to find a base $b$ such that $285_{10}$ is a four-digit number in base $b$ with an odd final digit.
In base $b$, a four-digit number ranges from $b^3$ to $b^4-1$.
We want the final digit of $285_{10}$ to be odd, so the final digit in base $b$ must be 1, 3, 5, 7, or 9.
Since $b^3 \leq 285_{10} \leq b^4-1$, we can test different values of $b$ to find the desired base.
Let's start with $b=6$. In base 6, $285_{10}$ is equivalent to $625_{6}$, which is a four-digit number with an odd final digit.
Therefore, the base that satisfies the condition is $\boxed{6}$.The answer is: 6
Below is a math problem. Provide a detailed, step-by-step solution.

### Problem:
What base would result in the representation of $285_{10}$ being a four-digit number with an odd final digit?

### Answer:
