If a set of marbles can be divided equally among $2$, $3$, $4$, $5$, and $6$ children, then the number of marbles must be a multiple of the least common multiple (LCM) of $2$, $3$, $4$, $5$, and $6$.
The prime factorization of these numbers is $2$, $3$, $2^2$, $5$, and $2\cdot 3$.
The LCM is $2^2\cdot 3\cdot 5=60$.
Therefore, the least number of marbles the set could have is $\boxed{60}$.
The answer is: 60
Below is a math problem. Provide a detailed, step-by-step solution.

### Problem:
A set of marbles can be divided in equal shares among $2$, $3$, $4$, $5$, or $6$ children with no marbles left over. What is the least number of marbles that the set could have?

### Answer:
