Recall that $\log_{a}{b}-\log_{a}{c}=\log_{a}{\frac{b}{c}}$.
Applying this rule, we have $\log_{3}{81}-\log_{3}{\frac{1}{9}}=\log_{3}{\frac{81}{\frac{1}{9}}}=\log_{3}{729}$.
Since $3^6=729$, we have $\log_{3}{729}=\boxed{6}$.
The answer is: 6
Below is a math problem. Provide a detailed, step-by-step solution.

### Problem:
Evaluate $\log_{3}{81}-\log_{3}{\frac{1}{9}}$.

### Answer:
