We want to find the value of $x$ such that $8^x = 2$.
Since $8 = 2^3$, we have $(2^3)^x = 2$, which simplifies to $2^{3x} = 2^1$.
Therefore, we must have $3x = 1$, which means $x = \frac{1}{3}$.
Thus, $\log_82 = \boxed{\frac{1}{3}}$.
The answer is: \frac{1}{3}
Below is a math problem. Provide a detailed, step-by-step solution.

### Problem:
Evaluate $\log_82$.

### Answer:
