### Godot version

v4.0.beta11.official [91713ced8]

### System information

macOS 13.1

### Issue description

When using a function with a return type of `void` as the return value of another function with a return type of `void`, the following error occurs: 
> Cannot get return value of call to "foo()" because it returns "void"

This wasn't a problem in Godot 3.x and Godot 4.x until now. Seems it's related to https://github.com/godotengine/godot/pull/70702. 

I understand why this is happening, but I'd expect to be able to use functions like this that return `void` because they both use the matching return type. It seems overly strict.

In a real world example I use this to return early when switching states in a FSM:

```gdscript
func _process(_delta: float) -> void:
  if player.is_grounded():
    return state_machine.transition_to("ground") # returns void

  if player.is_on_wall():
    return state_machine.transition_to("wall") # returns void
```

### Steps to reproduce

```gdscript
extends Node

func foo() -> void:
	print("hello")

func _ready() -> void:
	return foo()
```

### Minimal reproduction project

[godot_4_return_value_regression.zip](https://github.com/godotengine/godot/files/10385377/godot_4_return_value_regression.zip)

int i = 0;
			for (const GDScriptParser::DataType &par_type : parameters_types) {
				valid = valid && par_type == p_function->parameters[i++]->get_datatype();
			}
			if (!valid) {
				
				String parent_signature = String(function_name) + "(";
				int j = 0;
				for (const GDScriptParser::DataType &par_type : parameters_types) {
					if (j > 0) {
						parent_signature += ", ";
					}
					String parameter = par_type.to_string();
					if (parameter == "null") {
						parameter = "Variant";
					}
					parent_signature += parameter;
					if (j == parameters_types.size() - default_par_count) {
						parent_signature += " = default";
					}
					j++;
				}
				parent_signature += ") -> ";
				const String return_type = parent_return_type.is_hard_type() ? parent_return_type.to_string() : "Variant";
				if (return_type == "null") {
					parent_signature += "void";
				} else {
					parent_signature += return_type;
				}
				push_error(vformat(R"(The function signature doesn't match the parent. Parent signature is "%s".)", parent_signature), p_function);