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- [x] I have searched the [issues](https://github.com/apache/dubbo/issues) of this repository and believe that this is not a duplicate.

### Environment

* Dubbo version: 3.1.11
* Operating System version: MAC
* Java version: 1.8

### Steps to reproduce this issue

1. 使用3.1.11的版本定义一个接口提供服务，接口中包含相同名字不同参数的X个方法，那么在provider的url上methods参数就会有多个重复的方法名
2. 在2.6.x的consumer端引用该服务时，methodInvokerMap会根据相同方法名存放X个重复invoker地址，如果默认使用random负载均衡，相当于该provider有着X倍的权重一样，压力会是X倍
3. 在刚升dubbo3的时候，如果一台机器收到的流量是其他机器的X倍，可能压力较大会有风险

![duplicate](https://github.com/apache/dubbo/assets/3276231/fa4c2aab-e13c-4bd8-8b8a-3bfada07175c)
![addMap](https://github.com/apache/dubbo/assets/3276231/79b59170-020a-482e-82e2-0ebd6e162d67)


Pls. provide [GitHub address] to reproduce this issue.

### Expected Behavior

在生成provider url的methods参数时，去掉重复的方法名

### Actual Behavior

同名不同参数的方法名，会在url上生成多次

红圈中是灰度发布一台的重复现象
![methods](https://github.com/apache/dubbo/assets/3276231/6c27459e-dc1b-4ad8-b1bf-57c51115c4d8)


AsyncMethodInfo asyncMethodInfo = methodConfig.convertMethodConfig2AsyncInfo();
                if (asyncMethodInfo != null) {
                    attributes.put(methodConfig.getName(), asyncMethodInfo);
                }
            }
        }
        return attributes;
    }
    /**
     * Append all configuration required for service reference.
     *
     * @return reference parameters
     */
    private Map<String, String> appendConfig() {
        Map<String, String> map = new HashMap<>(16);
        map.put(INTERFACE_KEY, interfaceName);
        map.put(SIDE_KEY, CONSUMER_SIDE);
        ReferenceConfigBase.appendRuntimeParameters(map);
        if (!ProtocolUtils.isGeneric(generic)) {
            String revision = Version.getVersion(interfaceClass, version);
            if (StringUtils.isNotEmpty(revision)) {
                map.put(REVISION_KEY, revision);
            }
            String[] methods = methods(interfaceClass);
            if (methods.length == 0) {
                logger.warn(CONFIG_NO_METHOD_FOUND, "", "", "No method found in service interface: " + interfaceClass.getName());
                map.put(METHODS_KEY, ANY_VALUE);
            } else {
                List<String> copyOfMethods = new ArrayList<>(Arrays.asList(methods));
                copyOfMethods.sort(Comparator.naturalOrder());