### Godot version

v4.0.beta11.official [91713ced8]

### System information

macOS 13.1

### Issue description

When using a function with a return type of `void` as the return value of another function with a return type of `void`, the following error occurs: 
> Cannot get return value of call to "foo()" because it returns "void"

This wasn't a problem in Godot 3.x and Godot 4.x until now. Seems it's related to https://github.com/godotengine/godot/pull/70702. 

I understand why this is happening, but I'd expect to be able to use functions like this that return `void` because they both use the matching return type. It seems overly strict.

In a real world example I use this to return early when switching states in a FSM:

```gdscript
func _process(_delta: float) -> void:
  if player.is_grounded():
    return state_machine.transition_to("ground") # returns void

  if player.is_on_wall():
    return state_machine.transition_to("wall") # returns void
```

### Steps to reproduce

```gdscript
extends Node

func foo() -> void:
	print("hello")

func _ready() -> void:
	return foo()
```

### Minimal reproduction project

[godot_4_return_value_regression.zip](https://github.com/godotengine/godot/files/10385377/godot_4_return_value_regression.zip)

bool is_base_value_reduced = false;
	Variant base_value = make_expression_reduced_value(p_subscript->base, is_base_value_reduced);
	if (!is_base_value_reduced) {
		return Variant();
	}
	if (p_subscript->is_attribute) {
		bool is_valid = false;
		Variant value = base_value.get_named(p_subscript->attribute->name, is_valid);
		if (is_valid) {
			is_reduced = true;
			return value;
		} else {
			return Variant();
		}
	} else {
		bool is_index_value_reduced = false;