### Godot version

v4.0.beta11.official [91713ced8]

### System information

macOS 13.1

### Issue description

When using a function with a return type of `void` as the return value of another function with a return type of `void`, the following error occurs: 
> Cannot get return value of call to "foo()" because it returns "void"

This wasn't a problem in Godot 3.x and Godot 4.x until now. Seems it's related to https://github.com/godotengine/godot/pull/70702. 

I understand why this is happening, but I'd expect to be able to use functions like this that return `void` because they both use the matching return type. It seems overly strict.

In a real world example I use this to return early when switching states in a FSM:

```gdscript
func _process(_delta: float) -> void:
  if player.is_grounded():
    return state_machine.transition_to("ground") # returns void

  if player.is_on_wall():
    return state_machine.transition_to("wall") # returns void
```

### Steps to reproduce

```gdscript
extends Node

func foo() -> void:
	print("hello")

func _ready() -> void:
	return foo()
```

### Minimal reproduction project

[godot_4_return_value_regression.zip](https://github.com/godotengine/godot/files/10385377/godot_4_return_value_regression.zip)

bool is_shared = Variant::is_type_shared(assigned.type.builtin_type);
					if (!known_type || !is_shared) {
						if (!known_type) {
							
							gen->write_jump_if_shared(assigned);
						}
						if (!info.is_named) {
							gen->write_set(info.base, info.key, assigned);
						} else {
							gen->write_set_named(info.base, info.name, assigned);
						}
						if (!known_type) {
							gen->write_end_jump_if_shared();
						}
					}
					if (!info.is_named && info.key.mode == GDScriptCodeGenerator::Address::TEMPORARY) {
						gen->pop_temporary();
					}
					if (assigned.mode == GDScriptCodeGenerator::Address::TEMPORARY) {
						gen->pop_temporary();
					}
					assigned = info.base;
				}
				bool known_type = assigned.type.has_type;
				bool is_shared = Variant::is_type_shared(assigned.type.builtin_type);
				if (!known_type || !is_shared) {
					
					
					if (assign_class_member_property != StringName()) {
						if (!known_type) {