### Godot version

v4.0.beta11.official [91713ced8]

### System information

macOS 13.1

### Issue description

When using a function with a return type of `void` as the return value of another function with a return type of `void`, the following error occurs: 
> Cannot get return value of call to "foo()" because it returns "void"

This wasn't a problem in Godot 3.x and Godot 4.x until now. Seems it's related to https://github.com/godotengine/godot/pull/70702. 

I understand why this is happening, but I'd expect to be able to use functions like this that return `void` because they both use the matching return type. It seems overly strict.

In a real world example I use this to return early when switching states in a FSM:

```gdscript
func _process(_delta: float) -> void:
  if player.is_grounded():
    return state_machine.transition_to("ground") # returns void

  if player.is_on_wall():
    return state_machine.transition_to("wall") # returns void
```

### Steps to reproduce

```gdscript
extends Node

func foo() -> void:
	print("hello")

func _ready() -> void:
	return foo()
```

### Minimal reproduction project

[godot_4_return_value_regression.zip](https://github.com/godotengine/godot/files/10385377/godot_4_return_value_regression.zip)

reduce_expression(p_match->test);
	for (int i = 0; i < p_match->branches.size(); i++) {
		resolve_match_branch(p_match->branches[i], p_match->test);
		decide_suite_type(p_match, p_match->branches[i]);
	}
}
void GDScriptAnalyzer::resolve_match_branch(GDScriptParser::MatchBranchNode *p_match_branch, GDScriptParser::ExpressionNode *p_match_test) {
	for (int i = 0; i < p_match_branch->patterns.size(); i++) {
		resolve_match_pattern(p_match_branch->patterns[i], p_match_test);
	}
	resolve_suite(p_match_branch->block);
	decide_suite_type(p_match_branch, p_match_branch->block);
}
void GDScriptAnalyzer::resolve_match_pattern(GDScriptParser::PatternNode *p_match_pattern, GDScriptParser::ExpressionNode *p_match_test) {