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- [x] I have searched the [issues](https://github.com/apache/dubbo/issues) of this repository and believe that this is not a duplicate.

### Environment

* Dubbo version: 3.0.7
* Operating System version: all
* Java version: all

### Steps to reproduce this issue

1. 使用阿里巴巴的包实现了扩展com.alibaba.dubbo.registry.RegistryFactory,并重写了方法
org.alibaba.dubbo.registry.Registry getRegistry(com.alibaba.dubbo.common.URL url)
 
目前系统数量比较多,升级dubbo3.0.7后编译失败,查看了Dubbo3中的com.alibaba.dubbo.registry.RegistryFactory,类型发现
这个类型的getRegistry的返回值变了,返回了apache的org.apache.dubbo.registry.Registry
org.apache.dubbo.registry.Registry getRegistry(com.alibaba.dubbo.common.URL url);

如果这样搞的话,我这个依赖库中的扩展就无法同时支持新老版本的getRegistry方法了使用了高版本的包重写了getRegistry这个方法低版本的包就无法用我的扩展类型

Pls. provide [GitHub address] to reproduce this issue.

### Expected Behavior

<!-- What do you expect from the above steps？-->
麻烦兼容下低版本,其他类型做的都挺好的返回值alibaba的包下面就是alibaba的类型 

### Actual Behavior

<!-- What actually happens? -->

目前alibaba的包中出现 apache的类型 自定义扩展到 同学们的开发的工具包可能是无法兼容dubbo新版本的,导致升级困难

/*
 * Licensed to the Apache Software Foundation (ASF) under one or more
 * contributor license agreements.  See the NOTICE file distributed with
 * this work for additional information regarding copyright ownership.
 * The ASF licenses this file to You under the Apache License, Version 2.0
 * (the "License"); you may not use this file except in compliance with
 * the License.  You may obtain a copy of the License at
 *
 *     http://www.apache.org/licenses/LICENSE-2.0
 *
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 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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package com.alibaba.dubbo.registry;
import org.apache.dubbo.common.URL;
import org.apache.dubbo.registry.Registry;
@Deprecated
public interface RegistryFactory extends org.apache.dubbo.registry.RegistryFactory {
    Registry getRegistry(com.alibaba.dubbo.common.URL url);
    @Override
    default Registry getRegistry(URL url) {
        return this.getRegistry(new com.alibaba.dubbo.common.URL(url));
    }
}