### Godot version

v4.0.beta11.official [91713ced8]

### System information

macOS 13.1

### Issue description

When using a function with a return type of `void` as the return value of another function with a return type of `void`, the following error occurs: 
> Cannot get return value of call to "foo()" because it returns "void"

This wasn't a problem in Godot 3.x and Godot 4.x until now. Seems it's related to https://github.com/godotengine/godot/pull/70702. 

I understand why this is happening, but I'd expect to be able to use functions like this that return `void` because they both use the matching return type. It seems overly strict.

In a real world example I use this to return early when switching states in a FSM:

```gdscript
func _process(_delta: float) -> void:
  if player.is_grounded():
    return state_machine.transition_to("ground") # returns void

  if player.is_on_wall():
    return state_machine.transition_to("wall") # returns void
```

### Steps to reproduce

```gdscript
extends Node

func foo() -> void:
	print("hello")

func _ready() -> void:
	return foo()
```

### Minimal reproduction project

[godot_4_return_value_regression.zip](https://github.com/godotengine/godot/files/10385377/godot_4_return_value_regression.zip)

for (const KeyValue<StringName, int64_t> &E : p_type.enum_values) {
		if (E.value == p_value) {
			return true;
		}
	}
	return false;
}
#endif
void GDScriptAnalyzer::update_const_expression_builtin_type(GDScriptParser::ExpressionNode *p_expression, const GDScriptParser::DataType &p_type, const char *p_usage, bool p_is_cast) {
	if (p_expression->get_datatype() == p_type) {
		return;
	}
	if (p_type.kind != GDScriptParser::DataType::BUILTIN && p_type.kind != GDScriptParser::DataType::ENUM) {
		return;
	}
	GDScriptParser::DataType expression_type = p_expression->get_datatype();
	bool is_enum_cast = p_is_cast && p_type.kind == GDScriptParser::DataType::ENUM && p_type.is_meta_type == false && expression_type.builtin_type == Variant::INT;
	if (!is_enum_cast && !is_type_compatible(p_type, expression_type, true, p_expression)) {
		push_error(vformat(R"(Cannot %s a value of type "%s" as "%s".)", p_usage, expression_type.to_string(), p_type.to_string()), p_expression);
		return;
	}
	GDScriptParser::DataType value_type = type_from_variant(p_expression->reduced_value, p_expression);