### Is there an existing issue for this?

- [X] I have searched the existing issues

### Current Behavior

As mentioned [here](https://github.com/localstack/localstack/issues/4834#issuecomment-1021009701) it seems like the `AmazonopensearchserviceDestinationConfiguration` was not added while implementing OpenSearch. I guess it just needs be added [here](https://github.com/localstack/localstack/blob/53b5c7788bf35b1882b6cb1949e17d27e198cf61/localstack/services/cloudformation/models/kinesisfirehose.py#L23-L27).

### Expected Behavior

I can (and should) use `AmazonopensearchserviceDestinationConfiguration` instead of `ElasticsearchDestinationConfiguration` (which I should only be able to use if I use ElasticSearch-Service).

### How are you starting LocalStack?

With a docker-compose file

### Steps To Reproduce

Well, just use `AmazonopensearchserviceDestinationConfiguration` and your stream will never be able to deliver the records to your (external) Cluster. But it works with `ElasticsearchDestinationConfiguration`.

### Environment

```markdown
- OS: Windows mit WSL (Ubuntu 20.04)
- LocalStack: latest
```


### Anything else?

_No response_
def __init__(self, region=None, prefix=None):
        
        
        self.region = region or get_local_region()
        
        self.prefix = prefix
    def apply_json(self, j):
        if isinstance(j, str):
            j = json.loads(j)
        self.__dict__.update(j)
    @staticmethod
    def from_string(s):
        parts = s.split(":")
        if len(parts) == 1:
            if s in PREDEFINED_ENVIRONMENTS:
                return PREDEFINED_ENVIRONMENTS[s]
            parts = [get_local_region(), s]
        if len(parts) > 2:
            raise Exception('Invalid environment string "%s"' % s)
        region = parts[0]
        prefix = parts[1]
        return Environment(region=region, prefix=prefix)
    @staticmethod
    def from_json(j):
        if not isinstance(j, dict):
            j = j.to_dict()
        result = Environment()
        result.apply_json(j)
        return result
    def __str__(self):