### Is there an existing issue for this?

- [X] I have searched the existing issues

### Feature description

The use case I have in mind is to run Node 16.x Lambdas - the default container registry is `lambci/lambda` which is effectively abandoned. [Not even Node 14.x has been published](https://github.com/lambci/docker-lambda/pull/330). However, switching the registry over to [`amazon/aws-lambda-nodejs`](https://hub.docker.com/r/amazon/aws-lambda-nodejs) still fails to pull the container, since localstack is looking for the tag `nodejs16.x`. I'd like to be able to specify that if the runtime is `nodejs16.x` it just looks for tag `16`.

### 🧑‍💻 Implementation

_No response_

### Anything else?

_No response_
lambda_client.delete_function(FunctionName=func_name)
        assert "ResourceNotFoundException" in str(exc)
    @pytest.mark.skip_snapshot_verify
    def test_add_lambda_permission_aws(
        self, lambda_client, iam_client, create_lambda_function, account_id, snapshot
    ):
        """Testing the add_permission call on lambda, by adding a new resource-based policy to a lambda function"""
        snapshot.add_transformer(snapshot.transform.lambda_api())
        function_name = f"lambda_func-{short_uid()}"
        lambda_create_response = create_lambda_function(
            handler_file=TEST_LAMBDA_PYTHON_ECHO,
            func_name=function_name,
            runtime=LAMBDA_RUNTIME_PYTHON36,
        )
        lambda_arn = lambda_create_response["CreateFunctionResponse"]["FunctionArn"]
        snapshot.match("create_lambda", lambda_create_response)
        
        action = "lambda:InvokeFunction"
        sid = "s3"
        principal = "s3.amazonaws.com"
        resp = lambda_client.add_permission(
            FunctionName=function_name,
            Action=action,
            StatementId=sid,
            Principal=principal,
            SourceArn=aws_stack.s3_bucket_arn("test-bucket"),
        )
        snapshot.match("add_permission", resp)
        
        get_policy_result = lambda_client.get_policy(FunctionName=function_name)