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# Type of request: This is a ...

[ ] bug report
[X ] feature request

# Detailed description

I'm using localstack to create a dynamoDb table locally with a dynamodb stream and a flink application consuming data from the stream
The shardId created in localstack follows this format

shardId-000000000000-798cedd84a2953c5af70a131f8701f35

Flink expects this format
shardId-00000001592367572726-07776efd

The difference is just after the prefix shardId.
Normally the real shardId created by amazon use is composed by shardId prefix, 20-digit timestamp and 0-36 or more characters separated by '-'

The current shardId format is not valid for flink applications and it's not following the real pattern used by amazon

## Expected behavior

ShardId must follow the pattern
shardId prefix, 20-digit timestamp and 0-36 or more characters separated by '-'

## Actual behavior

The shardId follows the pattern
shardId prefix, 12 0s and 33 characters separated by '-'

# Steps to reproduce

Create a dynamodb table

## Command used to start LocalStack

I'm using docker and docker compose to run localstack


## Client code (AWS SDK code snippet, or sequence of "awslocal" commands)

aws --endpoint-url=http://localhost:4566 dynamodb create-table \
    --table-name temp4 \
    --attribute-definitions AttributeName=partition_key,AttributeType=S AttributeName=sort_key,AttributeType=S \
    --key-schema AttributeName=partition_key,KeyType=HASH AttributeName=sort_key,KeyType=RANGE \
    --provisioned-throughput ReadCapacityUnits=100,WriteCapacityUnits=100 \
    --stream-specification StreamEnabled=true,StreamViewType=NEW_AND_OLD_IMAGES


try:
        socket.inet_aton(addr)
        return True
    except socket.error:
        return False
def is_zip_file(content):
    stream = BytesIO(content)
    return zipfile.is_zipfile(stream)
def unzip(path, target_dir, overwrite=True):
    if is_alpine():
        
        flags = '-o' if overwrite else ''
        return run('cd %s; unzip %s %s' % (target_dir, flags, path))
    try:
        zip_ref = zipfile.ZipFile(path, 'r')
    except Exception as e:
        LOG.warning('Unable to open zip file: %s: %s' % (path, e))
        raise e
    
    
    try:
        for file_entry in zip_ref.infolist():
            _unzip_file_entry(zip_ref, file_entry, target_dir)
    finally:
        zip_ref.close()
def _unzip_file_entry(zip_ref, file_entry, target_dir):