Find all directories (type d) in the current directory (.), with a minimum depth of 1 (mindepth 1), execute the stat command on each of them (exec stat {} \;), and print the integer of the second and third fields of the output of stat divided by 10 (awk -F. '{print int(($2*1000+$3)/10)}') and sort them numerically (sort -n). Then, print an error if the previous field is greater than the current field (awk -F: '{ if(prev>$1) print "ERROR"; prev=$1 }').
find . -mindepth 1 -type d -exec stat {} \; | awk -F. '{print int(($2*1000+$3)/10)}' | sort -n | awk -F: '{ if(prev>$1) print "ERROR"; prev=$1 }'