Print table of users with UID >=1000 with header and formatted output, using colon as separator (`%-20s` mean: 20 left-align string characters, `%6s` means: 6 right-align string characters)
awk 'BEGIN {FS=":";printf "%-20s %6s %25s\n", "Name", "UID", "Shell"} $4 >= 1000 {printf "%-20s %6d %25s\n", $1, $4, $7}' /etc/passwd