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Tag Archives: Mike Pompeo
Pompeo Effectively Admits To Assange Allegations, by Caitlin Johnstone
Mike Pompeo is whatever comes below the scum of the earth. From Caitlin Johnstone at caitlinjohnstone.com:
In the process of issuing another not-really-a-denial about a Yahoo News report that the CIA plotted to kidnap, extradite and assassinate WikiLeaks founder Julian Assange in 2017, former CIA director Mike Pompeo said that the 30 former government officials the report was based on "should all be prosecuted for speaking about classified activity inside the Central Intelligence Agency."
Here are some quotes from the exchange on Pompeo's recent Megyn Kelly Show appearance courtesy of Mediaite:
Kelly asked Pompeo about the claims.
"Makes for pretty good fiction, Megyn," said Pompeo. "They should write such a novel."
He added, "Whoever those 30 people who allegedly spoke with one of these reporters, they should all be prosecuted for speaking about classified activity inside the Central Intelligence Agency."
Pompeo called Wikileaks a "non-state hostile intelligence service" that is "actively seeking to steal American classified information."
"You deny the report?" asked Kelly.
"There's pieces of it that are true," said Pompeo. "We tried to protect American information from Julian Assange and Wikileaks, absolutely, yes. Did our justice department believe they had a valid claim which would've resulted in the extradition of Julian Assange to the United States to stand trial? Yes. I supported that effort for sure. Did we ever engage in activity that was inconsistent with U.S. law?… We're not permitted by U.S. law to conduct assassinations. We never acted in a way that was inconsistent with that."
Posted in Civil Liberties, Collapse, Governments, Horseshit, Intelligence, Morality, Politics, Propaganda, Tyranny
Tagged Julian Assange persecution, Mike Pompeo
Pathetic Presser, Texas Triumph, and President Pompeo: The Week in Review, by PF Whalen
Texas doesn't crash and burn; Biden does, and Pompeo shines. From PF Whalen at thebluestateconservative.com:
Headline #1: Biden Holds First Presidential Press Conference
On Thursday, President Joe Biden held his first press conference more than two months into his presidency; the longest such period without a press conference by a U.S. President since press conferences have existed.
Thoughts and Observations:
In Fifth Grade, I ran for class president. There were two key issues during that election: 1) the fairness of our school's classroom monitors, and 2) permissible activities during recess. On the day of that election, we had a Q&A session which was monitored by one of our teachers. Along with the other 11-year olds running for president, the questions we faced that day, including follow-up questions, were more difficult than any questions Biden faced on Thursday.
Biden's performance during the hour-long presser was disturbingly feeble. He lost his train of thought multiple times, he had to be reminded of the questions he'd been asked, he blatantly lied, and he came across as unprepared and bewildered. For those of us who've felt Biden is nothing more than a figurehead, his first press conference not only solidified that opinion, it crystallized it.
Posted in Governments, Media, Politics
Tagged Biden press conference, Mike Pompeo, Texas
FYI Trump's Latest Yemen Move Is Far Worse Than The Capitol Riot, by Caitlin Johnstone
The Washington protest doesn't hold a candle to killing a bunch of kids and other innocent Yemeni civilians. From Caitlin Johnstone at caitlinjohnstone.com:
While the Capitol riot is being hysterically compared to Pearl Harbor and Kristallnacht by the political/media class, the Trump administration has done something far, far worse that is receiving far, far less attention.
The US State Department has officially announced its intention to designate Yemen's Houthis as a terrorist group, as many had previously warned. Humanitarian organizations have been condemning the move as it will make it more difficult to provide aid to a population that is already being brutalized by the worst mass atrocity in the entire world, a Saudi-led atrocity which could not occur without the help of the western power alliance.
We are already seeing some effects of this designation.
We are ceasing all operations in the United States for the time being, as well as putting a temporary halt to our intended plans for humanitarian fundraising.
Let it be known that the Trump Administration just criminalized foreign humanitarian aid to #Yemen. pic.twitter.com/uUDEgEu9hP
— Yemen Solidarity Council (@YSCouncil) January 11, 2021
ntiwar's Dave DeCamp reports the following:
The terror designation will hamper the efforts of international charities that deliver food to Houthi-controlled areas, where 70 percent of Yemen's population lives and malnutrition is the most widespread.
Aid agencies fear their work in north Yemen will now be criminalized since the Houthis are the authority they have to deal with and make transactions with. US terror designations open up sanctions on any individuals or entities that do business with those Washington brands as terrorists.
Pompeo said exemptions would be made for humanitarian goods. But any additional roadblocks for aid agencies will cause more suffering in Yemen since the situation is so dire. "Even with exemptions, the operation will be compromised," said Janti Soeripto, the president of Save the Children, according to AP News.
Posted in Foreign Policy, Geopolitics, Governments, Morality
Tagged Mike Pompeo, Saudi Arabia, Yemen
Two Paradigms Clash: Offers for U.S.-China-Russia Partnership That Won WWII or Hellish Plunge Into WWIII, by Matthew Ehret
We can live together or die together, those are the choices. From Matthew Ehret at strategic-culture.org:
The Pentagon's new military report on China released on September 1st has demonstrated that the outdated and deadly Cold War mentality which has wrought such destruction upon the world since the end of WWII has not only become more deeply embedded into the psyche of dominant foreign policy officials in the Pentagon, it demonstrated that the current American establishment is totally unfit to survive in today's nuclear age. In our nuclear age, Hobbesian laws of the jungle will only result in mass extermination. If we are to survive beyond the coming decade, it is high time that a higher moral paradigm befitting of human dignity becomes hegemonic.
If one wishes to play the role of Alice and join the tea party which these Pentagon Mad Hatters are hosting, one would be expected to believe that the belligerent aggressor in the Pacific theater is not the America which has spread its military tentacles around China's backyard since Obama's Asia Pivot that was announced in 2012, but rather China itself. The authors of the Pentagon report assert that it is China who is interested in expansionism, overthrowing the "rule of law", conquering the weak of the Pacific and overtaking the US as a globally hegemonic power, both militarily and with their Belt and Road Initiative, which the Washington Consensus has labelled a debt trap.
More recently, Pompeo has sent Undersecretary of State Keith Krach to Taiwan to belligerently organize bilateral free trade deals and several military deals worth $7 billion which the current basket-case leadership of Taiwan is all too happy to oblige.
Posted in Foreign Policy, Geopolitics, Governments, Military, War
Tagged China, Mike Pompeo, President Trump, Russia, Vladimir Putin, Xi Jinping
When it comes to Iran, how many failures is enough for Pompeo? by Muhammad Sahimi
Mike Pompeo has done nothing but embarrass himself. From Muhammad Sahimi at responsiblestatecraft.org:
For many years Secretary of State Mike Pompeo has worked to bring Iran to heel, if not to destroy the Islamic Republic altogether. He would presumably prefer to accomplish those ends through economic and political warfare, but it is unlikely he would object to military attacks if that is what it takes. As a Congressman from Kansas as early as 2014, he was urging Washington to attack Tehran's nuclear facilities, noting it would take "under 2,000 sorties," or bombings, to do the job. "This is not an insurmountable task for the coalition forces," he said.
Pompeo is an ideologue rather than a diplomat. His urge to confront Iran appears to be motivated by his Christian Zionism and support for Israel, as well as, as some believe, his own presidential ambitions. Adding to these factors are no doubt his views about American exceptionalism that require such countries as Iran, Venezuela, Syria, and Iraq to bow to U.S. demands for their own good, all of which creates a mixture dangerous to world peace, and to the Middle East, in particular.
As CIA Director Pompeo released the agency's documents taken from Osama bin Laden's hideout in Pakistan, but gave advanced copies to the Foundation for Defense of Democracies, a well-funded, stridently pro-Israel lobby and think tank that opposed the JCPOA and has long promoted waging economic warfare against Iran. Pompeo had presumably hoped that FDD would uncover evidence linking Iran directly to al-Qaeda — much as the George W. Bush's administration struggled to link Saddam Hussein to Al Qaeda nearly 20 years ago — so that the 2002 Authorization for use of Military Force in the so-called war on terror could be invoked against Iran. The FDD obliged and published a report. But the evidence for such a link that it adduced from the documents was so weak that it was almost entirely ignored by lawmakers and major media alike.
Posted in Geopolitics, Governments, History, Politics, Propaganda
Tagged Iran, Mike Pompeo
Maintaining Pretence Over Reality: 'Simply Put, the Iranians Outfoxed the U.S. Defence Systems', by Alastair Crooke
The neocons inside and outside the Trump Administration can talk all they want about waging war against Iran, but supported by the Chinese and Russians, Iran would be a tough, perhaps impossible, nut to crack. From Alastair Crooke at strategic-culture.org:
So it never was then a 'peace agreement' between Israel and the UAE. It was 'normalisation' for the purposes of mounting a military alliance against Iran. Pompeo suggested so, this weekend. He said that the UAE and Israel have agreed to form a security and military alliance against Iran to 'protect' U.S. interests and the Middle East. This agreement and any that might follow means that there will be an Israeli military and security military presence in the Gulf, and a joint Israeli-UAE intelligence base on Socotra Island in the Red Sea basin overlooking the Bab al-Mandab Strait. According to Pompeo, this agreement will transform the conflict in the Middle East from being Arab-Israeli, to Arab-Iranian, and perhaps Arab-Turkish later on.
The language used by Pompeo is significant in another way. Trump is proud of having taken Jerusalem 'off the table' (in the context of negotiations with the Palestinians). He says he has taken the Golan and the Jordan valley 'off the table, too'. Pompeo's formulation of the conflict transformation he believes he has just engineered says something else too: It is that the Palestinian issue is 'off the table' as well. It is now all about Iran (in Trump's optic). The Palestinians are to stew in their own juices.
Well, Pompeo perhaps was speaking loosely when he designates it now an Arab-Iranian conflict. It is (at least for now), the UAE alone that has put itself on the Front Line. The Qatari-owned Al Quds al-Arabi scathingly noted that "in this alleged alliance against Iran … were the unwanted were to happen, and [a larger] war break out against Iran, the Emirates will be on the receiving end of the blows – and will be the biggest loser."
Posted in Foreign Policy, Geopolitics, Governments, Military
Tagged Iran, Israel, Mike Pompeo, President Trump, Russia, UAE
Let's Talk U.S. Foreign Policy: It Is the Root Cause of Many Evils, by Philip Giraldi
For those who love bipartisanship, US foreign policy has been a bipartisan disaster. From Philip Giraldi at strategic-culture.org:
As the United States sinks deeper into a multi-faceted global crisis that no politician seems able or even willing to address, one hears more and more often demands for radical change in who runs the country and to what end. Of course, Donald J. Trump offered such a dramatic shift in priorities four years ago, but he has been unable to deliver due to his own inability to execute and the ill-conceived machinations of those whom he has chosen as advisers. The Democrats for their part are offering little beyond a repeat of their 2016 pander to grievance groups in an effort to cobble together an unassailable majority based on buying off the party's various constituencies.
But there is one area where change could come dramatically if either party were actually motivated to do something that would truly benefit the American people, and that is in the area of foreign and national security policy where the president has considerable power to set priorities and redirect both the State and Defense Departments. Unfortunately, foreign and national security policy is almost never discussed during the presidential campaigns and this time would already appear to be no exception. That means that the one thing that is a constant amidst all the smoke and mirrors is the continued bellicosity of both parties on the world stage.
The Republicans are apparently eager to "democratize" Latin America while the Democrats in particular are wedded to the "foreign interference" angle to explain their loss in 2016, with Hillary Clinton predictably advising in her Democratic National Convention speech that the public should "Vote to make sure we — not a foreign adversary — choose our president." Indeed, the tendency to create and then demonize "foreign conspiracies" is generally supported by the establishment and its parasitical media, since it enables the billionaire oligarchs who really run the country to grow fatter while also avoiding any blame for the declining fortunes of most of the American people.
Posted in Foreign Policy, Geopolitics, Governments, History, Military, Politics, Propaganda, War
Tagged Europe, Iran, Iran nuclear deal, Mike Pompeo, President Trump
Pompeo's Iran Failures Make War More Likely, by Ron Paul
Trump and Pompeo said we'd get a better nuclear deal with Iran if we backed out of Obama, and five other nations', deal. They backed out, but to date have no better deal with Iran. From Ron Paul at ronpaulinstitute.org:
The US foreign policy establishment has for decades been dominated by neoconservative interventionists and falsely-named "humanitarian" interventionists. These people believe that because the United States is the one "exceptional nation," no conflict anywhere in the world could possibly be solved without our butting our noses into it.
One of President Obama's few foreign policy successes was to work with European countries on a deal that would see a reduction of sanctions on Iran in exchange for a series of Iranian moves demonstrating its abandonment of a nuclear weapon.
The American neocons as well as the hardliners in Saudi Arabia and Israel were furious at the compromise, but for a couple of years it showed real promise. Trade between Europe and Iran was increasing and there was no evidence that Iran was reneging on its obligations. Even American companies were looking to Iran for business opportunities. Whenever goods flow between nations, war becomes less likely.
President Trump has had problems with policy consistency throughout his first term in office. But, unfortunately, his few policy consistencies have been the most ill-advised ones. On the campaign trail Trump relentlessly attacked Obama's Iran policy and promised to pull the US out of the JCPOA Iran agreement.
Posted in Foreign Policy, Geopolitics, Governments, History
Tagged Iran nuclear deal, Mike Pompeo, President Trump
Washington's Campaign Against China Could Lead to War, by Brian Cloughley
Posted on August 6, 2020 | Leave a comment
Mike Pompeo certainly talks like a man looking for a fight. From Brian Cloughley at strategic-culture.org:
When prominent U.S. personalities such as Secretary of State Pompeo speak critically and scornfully about leaders and other prominent figures of countries with whose policies they disagree, they ignore or even welcome the fact that such attacks are heard not only by the persons at whom they are aimed. The citizens of the country concerned are unlikely to disregard such criticism, and even if they may agree with some of it — perhaps all of it — on a purely practical or individual basis, they do not accept the premise that their countries are in the wrong because some foreign representative sounds off against their leaders.
There is a campaign of denigration being waged by Washington against Beijing, and Secretary Pompeo is brandishing the sharpest sword. His speech of July 23 at the Richard Nixon Library and Museum was a definitive indication of how the United States stands in regard to the People's Republic of China, and its very title made it clear that Washington has no intention of engaging in reasoned dialogue that could lead to rapprochement with the Chinese government. Pompeo's discourse on 'Communist China and the Free World's Future' was a venomous diatribe aimed at persuading the world community to combine against the PRC.
Pompeo is nostalgic for the good old days of the Cold War, and warned that "If we bend the knee now, our children's children may be at the mercy of the Chinese Communist Party, whose actions are the primary challenge today in the free world. General Secretary Xi is not destined to tyrannise inside and outside of China forever, unless we allow it. Now, this isn't about containment. Don't buy that. It's about a complex new challenge that we've never faced before."
Posted in Eurasian Axis, Foreign Policy, Geopolitics, Governments, History, Military, Politics, Propaganda, War
Tagged China, Mike Pompeo
A United State of Delusion, by Patrick Lawrence
The US is not the world's indispensable nation or global policeman, it's an empire in decline. From Patrick Lawrence at consortiumnews.com:
Americans are caught in a kind of national psychosis, wherein little of what is said about foreign conduct — from Germany to the South China Sea — can be taken at face value.
Applause for Secretary of State Mike Pompeo's speech on "Communist China and the Free World's Future," at Richard Nixon Presidential Library, Yorba Linda, California, July 23, 2020. (U.S. State Department, Ron Przysucha)
Let's face it: The Trump regime has from the first had a tenuous relationship with reality. A thousand jobs at a Midwestern air-conditioner plant don't go to Mexico and the revival of American manufacturing is coming to a theater near you. The U.S. supports jihadist savages in Syria in the name of "freedom" and human rights. The administration is about to ban TikTok, a harmless but highly popular video application, and it's not about suppressing a superior competitor: It's about protecting Americans in the name of "national security."
Sure thing.
President Donald Trump can hardly be blamed for inventing this nation's dangerous detachment from what we quaintly call the real world. By my reckoning, the last president to speak honestly of things as they are and to say what he meant was Franklin D. Roosevelt. But the national malady, our shared delusions, has worsened markedly under the Trump regime, it is true.
Look westward across the Pacific, eastward across the Atlantic and southward to Latin America: The U.S. leadership and the clerks in the press who serve it have swooned deeply into delusions of this sort over the past couple of weeks. Here's the thing to note: Fewer and fewer people, other than a regrettable proportion of Americans, seem any longer to take seriously what America says it is doing and why. The effect, we must not miss, is increasing isolation.
Posted in Foreign Policy, Geopolitics, Government, Imperialism, Propaganda
Tagged American empire, China, Mike Pompeo, President Trump


How to Install the Fire TV Guru Build The Fire TV Guru Build is a great resource for Kodi users running the app on Fire devices. Installation is pretty simple, though you do have to go through the extra step of installing a wizard before you can install the build.
After the installation process gets over, just go back to the home screen of kodi and navigate to the Video tab on the screen. You could see two integrated options such as Files and Add-ons. Just navigate to the Add-ons option and click that thing.
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Contents. 0.0.1 Good Evening Guys and Girls , Hope you are all well. This blog will show you how to Install Elysium Kodi Addon Kodi Addon , this is Movie and Tv Show addon.


Data is from the July 2018 Vibes "2018 US Mobile Consumer Report" conducted by Cite Research. 1,000 US smartphone owners ages 18+ were surveyed online during March 2018. 66% of respondents were male and 33% were female. 27% of respondents were ages 18-34, 21% ages 35-44, 16% ages 45-54 and 18% ages 55+. Vibes is a mobile solutions provider.


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Geoff Mann on Thomas Piketty's 'Capital in the Twenty-First Century'
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Redeye Collective
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Capital in the Twenty-First Century surveys 200 years of economic history and wealth distribution. It's sold more than 100,000 copies and is one of the most talked-about economics book in decades. Geoff Mann is associate professor of geography at SFU. He was one of the speakers at a recent public forum in Vancouver organized by the Canadian Centre for Policy Alternatives, SFU's Centre for Humanities and Ricochet Media.
Check out our website for more information about Redeye.
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wealth distribution
Capital in the Twenty-First Century
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redpajama_set_name: RedPajamaCommonCrawl


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INTERVIEW: ARC on Evolution
June Jun 14, 2007
Behind the scenes of most online or travel agency bookings, ARC (also known as the Airline Reporting Corporation) tracks, audits and reports on various elements of nearly $80 billion worth of transactions a year. But some dramatic changes are underway as ARC transforms from simply a bank settlement plan to a provider of business intelligence and data analytics. ARC president and CEO David Collins, along with vice president of marketing, sales and customer care Mike Premo, spoke at length last month with The Beat's Mary Ann McNulty about ARC's role in the industry today and tomorrow. An excerpt follows:
McNulty: A couple months ago, ARC introduced a new itinerary detail product for airlines and said it would help improve corporate contracts and assess agency incentive programs. Can you give us an update?
Collins: I don't have the number of airlines with me, but I think it's been a successful program. One of the things we set out to do with these things, particularly when you bring it up in that context, is to be the trusted, neutral source so everyone is talking off the same page. Both sides can look at the same data and have a discussion.
McNulty: Is this product--analyzing and dissecting data that you settle--representative of what ARC views as its future in data analytics, rather than just transaction processing and settlement, which you've really been known for over these past 20 years, and the 20 before that for your predecessor (the Air Traffic Conference of America's Area Settlement Plan)?
Collins: Yes. We've really evolved into three business lines now. The first is our traditional reporting and settlement function, which is alive and healthy and doing well. We continue to bring that up to date. We took the industry out of the paper age there and have made it an electronic and highly efficient system. Our second business line is data and analytics. By going electronic, it really positioned us to do that because we sit on 39 months of data. Data in this day and age is what helps drive businesses. Slicing and dicing data is what helps you be successful these days. Our third business line is what we call industry products and services. An example of that is our recently introduced ARC Marketplace, which is enabling our travel agents to sell destination products and earn commissions, and they are products that they may not have sold before because getting the commissions in the past was hard. Because of ARC's efficient money-moving system, we can take care of that for them.
McNulty: Are you planning any such enhanced reporting tools for corporations or agencies?
Premo: When ARC launched into the data business, we took a very conservative viewpoint of who would be able to get what parts of this data. We're a little more comfortable now that those policies are solid, and we are expanding the community that will have access to more information to include employers, card companies and others that have business on the transaction. We typically have really limited that to agencies--and agencies on a very limited data set. Those data sharing policies are under review and we've got some proposals in front of our governance committees right now to make more of that data available to the different communities that we serve.
Collins: Underlying that is the principal of "right to see." If you're an employer, you can't go in and see another employers' travel. If you're a credit card company, you can't go in and see another credit card companies' data. You can go in and see your own because you want to know what's going on.
Premo: We have customers who want to see more data about a transaction than they have on their own internal system. So we can supplement their data in a way that adds some value for them, or for their customers. Visa is never going to see American Express' transaction data from ARC. We take protective measures so no personally identifying information is accessible, and ensure that apart from your own data, you can only see aggregate market data. We're a fairly conservative organization in terms of those types of policies and we should note that we're one of the few industry companies that is [Payment Card Industry]-compliant, so we do adhere to PCI security standards around card numbers, names, etc. That's a significant undertaking, one that we're quite proud of, but also a certification that you can lose with some ease. So we treat data security very seriously.
McNulty: When will these policies be reviewed and when will the products be released?
Collins: They will be reviewed at the end of June and [the products will be] out right after that.
McNulty: Historically, ARC has formed working groups or pilot programs to learn how best to introduce controversial changes, like ETDNs (Electronic Ticket Delivery Networks) and Corporate Travel Department designations. As you began developing the new line of business of analyzing data, what type of discussions or debates were held, and with whom?
Collins: That's in a sense a very timely question because one of the things that ARC has set out to do in recent years is become much more customer-focused, to be in the market learning what our customers want, and don't want, from us. We now have a sales and marketing organization that Mike Premo heads up. We've had that in place now for about two years, but it's new for ARC to get out there more and talk to all our customers, whether it be airlines, large agents, small agents, large corporations or small corporations to learn what they're doing with our products today and where we can help them moving forward. I wouldn't call it a dramatic shift. It's all part of our evolution as a company as we grow and look at new opportunities to serve our customers better.
McNulty: Did you have any discussions with your customer advisory boards or conduct pilots?
Collins: This has been more one-on-one, getting their feedback and testing ideas.
Premo: We're more externally focused as an organization. We use a very typical product management methodology to develop our products and decide whether we should take them to market or not. ... Yes, it's a little less traditional in ARC's working committees and industry groups, but it reflects our maturing as an organization and shift to a more entrepreneurial focus.
McNulty: Your evolution is raising some concerns, especially from those who are concerned about data ownership issues and privacy, and are questioning whether ARC has a right to analyze the data and then sell those reports to others. Yes, you have the data, but what gives you the right to repurpose?
Collins: We have a different approach to data. Our approach is around rights to use rather than ownership. Who actually owns a piece of data [is something] we can talk about all week long. We base what we do at ARC on rights to use. We consider the people with the greatest rights to any piece of data the passenger and the airline. We derive our rights to use from the airlines. We believe we have complete authority to use that data. That said, we respect privacy laws. We are Safe Harbor-compliant, as far as the European Community is concerned, and obviously individual data--credit card data--isn't included on any of the products we sell. We respect privacy and we have certain corporate policies that we adhere to, to respect those things.
McNulty: What do you see as ARC's future role in this industry? Where do you expect most of your revenues to come from in the future?
Collins: One of the interesting things about ARC is that one of our core attributes is still very vital in the marketplace today. We've always made business efficient to conduct and I don't think that's going away. For most of those 20 years, and even prior in the other 20, people have speculated that ARC is a dinosaur. We've shown that we're far from it. We've shown amazing adaptability as a company. We were a leader in going electronic and taking paper out of the industry. Our core is strong, healthy and will lead this company for the foreseeable future. Data will become a bigger product for us--a revenue generator for us--in the future as we learn how to deliver products that customers want and as customers learn how to use data better. Data analytics in this day and age is critical to run a successful business. If you're not highly analytical about what you're doing in the marketplace, you're not going to be successful. Thirdly, we'll come up with other products that will benefit people when you look at what our efficiencies are built around, and that's moving money, storing data and moving data. In a nutshell, that's what we do, and we do it very efficiently.
McNulty: At the end of 2006, your customers included about 152 airlines and railroads, 21,000 agencies and 200 corporate travel departments. Where would you like to see those numbers and how can you get there?
Collins: On airlines, we'd like to see that grow. There are a lot of airlines--maybe smaller ones in this country, but mostly in other countries--that could take advantage of ARC and our efficiencies to market. Our number of airlines has gone up consistently over the past four years, so we continue to look at developing the number of airlines we have participating.
As far as travel agencies, you're well aware that the number is going down (in terms of locations, it's now half what it once was). What we might see in the future is that the number of traditional ARC-accredited agents might continue to go down as consolidation continues. But you might see us serving more of the non-traditional agent. There are more agencies out there specializing in cruises and tours, or home-based agents. We would probably look to those agents, probably not to be accrediting for airline tickets, but to provide other services that we do, such as Marketplace or the travel agency service fee [an ARC tool that facilitates such collections], which has been very successful.
As far as corporations are concerned, I don't know that we have a goal to increase or decrease. We have a goal to provide what the market wants. So what we've done out there is provide choice. Corporations will vary in what they want to do. If you build widgets, you probably may want to focus all your skills on building widgets, and leave a travel management company who is expert at travel to run your travel. You may have different attitudes as a corporation and want to control all your travel spend and have far greater insight. What we think we do is provide two alternatives to the customer corporation and they can go down either route. We don't mind them going down either route.
McNulty: What do they want from the CTD designation? What will cause them to choose that route more often?
Premo: We actually have about 150 active CTDs today. Over 200 might have applied, but I'm not sure they all got to live status. Some have been bought by other companies and some have reverted back to regular TMC [configurations]. Our view is that we think it's a good thing for a corporation to have the ability for an ARC appointment. Not everyone is going to choose that, but in this era, there are more challenges in travel programs and infrastructure in programs than there has probably ever been. With GDS content fees, the economics changed by a couple dollars last summer. The shortage of travel professionals--because of the cloud around agency business and 9/11 and other factors--can create staffing challenges. Some companies are more security-conscious. They don't want outsiders to look at their travel activity. When you look at those kinds of dynamics, probably over time there will be more companies to say, "A CTD makes sense for me." Do we think there's going to be a land rush and there will be 50,000 CTDs anytime soon? No, I don't think so. But we like the relationship. It's a very strong and vibrant community. They're all very passionate about CTD status and we will go out of our way to support them and the community.
McNulty: And create more products?
Premo: Yes, we have a couple things to talk about. At [the National Business Travel Association conference in Boston next month], we'll have some things to talk about.
McNulty: At the CTD conference in December in Sonoma, Calif., Mike mentioned that you were trying to convince the airlines to process their own Web sales through ARC due to the cost-efficiencies you've attained. Any success?
Premo: We've actually had a U.S. regional carrier start to have some interesting conversations with us around that. It's early days. That's a fairly radical concept in the mind of the industry. But when you look at issues like becoming PCI-compliant... We basically run three major locations and have 400 employees. For us to put in place the standards, systems and protocols to meet PCI was a big challenge. And we have $80 billion of scale to spread that investment across. If you're an airline and have 20,000 or 40,000 employees, hundreds of locations, and people accessing your systems all over the world, can you really be cost-effective, or as cost-effective as someone like ARC? Over time, I think our argument is going to be successful.
McNulty: Another thing you've been working on is helping airlines reduce credit card fees. Any new products there?
Premo: Come to NBTA.
McNulty: With the growth of Web sales and portals, use of G2 SwitchWorks, ITA Software and others, what percent of all airline sales does ARC process today versus three years ago?
Premo: We hear from major carriers that 30 to 40 percent of their sales are through direct channels. Our share is in the 55 to 60 percent range.
Collins: We've been a flexible system. We have something called the ARC direct connections so we can process through [channels] other than the GDS. G2 is a system provider, and other types of transactions go through that, such as Orbitz. We've gone from having four system providers to 18.
INTERVIEW: CWT CEO Kurt Ekert
INTERVIEW: Travelport CEO Greg Webb
INTERVIEW: Internova Travel Group CEO J.D. O'Hara


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12/03/· The work of the Paths for Reconstruction in the 21st Century project is divided into nine overlapping components of the human endeavor where profound change occurred in the 20th Century and continues to occur in the 21st Century. This change continues to create new frameworks and meanings, new problems, and some new possibilities for humankind.
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30/01/· The Zinn Education Project is producing a national report on the teaching of the Reconstruction era. The report will examine state standards, course requirements, frameworks, and support for teachers in each state. It will also include stories about creative efforts by districts and/or individual teachers in each state to teach outside the textbook about Reconstruction.
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In Collaboration with FEM (Female Engineers Monash), WISE is happy to announance that Aurecon's annual Office Visit is coming up these holidays! This is a great chance to learn more about Aurecon and all their fields, meet some current employees and inspiring leaders, find out more about their graduate program and get recruitment advice. It'll be an amazing opportunity to widen your network and see what life after uni could be like. Morning tea will be provided! Not only this, you get to network with a bunch of great FEM & WISE members!
This event is primarily for women studying engineering in the civil, envrionmental, engineering management and energy systems.
Go on and register if you're interested in coming along, but we do have limited places so please let us know if you register and cannot attend.


Bee Gees singer Robin Gibb is still in intensive care after waking from a coma over the weekend, and doctors revealed his diagnosis for the first time late yesterday. He is also suffering from cancer.
The 62-year-old music icon has advanced colorectal cancer, the doctor said in a statement.
His pneumonia was a complication caused by chemotherapy and two operations, which weakened his system and exposed him to infection, said Dr. Andrew Thillainayagam, the attending physician.
Gibb became comatose as a result of the pneumonia last week, and Thillainayagam warned Gibb's family that he might not wake up. Family members kept a vigil at his bedside, and his wife, Dwina Gibb, even sang to him.
His ability to speak and recognize people bodes well for his condition, although it's unknown whether he has been able to fight off the lung infection.
Gibb is "exhausted, extremely weak and malnourished," Thillainayagam said. He is breathing with an oxygen mask and is receiving food and antibiotics intravenously.
"It is testament to Robin's extraordinary courage, iron will and deep reserves of physical strength that he has overcome quite incredible odds to get where he is now," Thillainayagam said in a statement.
Robin underwent cancer treatment and the disease was thought to be in remission. But the pneumonia may be related to yet another tumor, according to reports.
The youngest Gibb brother, Andy, died from heart failure in 1988. He was 30 at the time, and had a successful solo career.
Gibb last performed in February at a charity concert in London.
Donald Trump Dumps Cheryl Tiegs: What the Hell Happened?


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Mega Cash Returns
Bob Veres
Lifestyle, Lifestyle, Money
There wasn't a lot of fanfare when Apple Computer announced that it would commit $100 billion of the excess cash it had laying around to buying back its own shares. This may be because, as you can see from the chart, the company has made a quarterly habit of committing enormous sums to buying shares of what appears to be its favorite stock: Apple Computer. The company purchased $22.8 billion of its own stock in the first quarter under the previous buyback authorization—which, as it turns out, was a new quarterly record for a U.S. company, besting Apple's previous high, and giving the company the 10 biggest quarterly share buybacks in U.S. stock market history.
To get a sense of the scale of these cash commitments, consider that Apple's buyback in 2018's first quarter was enough to buy every single one of the shares of any one of 275 companies in the S&P 500 index. If you add up the $210 billion that Apple has put into its buyback program since 2012, the sum is more than the total market value of all but 20 companies in the U.S. Add to that, Apple's planned annual dividend bill—dollars returned directly to shareholders—will come to an additional $13.2 billion, making this, purely from a total cash standpoint, the highest dividend payment in the world. That single dividend sum alone is greater than the market capitalization of 141 S&P 500 companies.
To the untrained ear, this looks like profligacy—careless shoveling of cash out of the company's vaults, rather than reinvesting in new and better phone technology or a more efficient computer operating system. But if you look purely at the dividend (see chart) as a percentage of share price, Apple is actually paying out less than the average S&P 500 company. And despite the share buybacks and raised dividend, Apple has actually been spending more than $41 billion on research and development since 2013. (see chart)
The bottom line is that Apple could be purchasing companies like Qualcomm and Twitter—or controlling interest in ExxonMobil. But for now company management has decided that the excess money belongs in the hands of its shareholders.
https://www.ft.com/content/b7358f36-4d8e-11e8-97e4-13afc22d86d4
Post by Bob Veres
Bob Veres, a Financial Planning columnist in San Diego, is publisher of Inside Information, an information service for financial advisors.


The beautiful village of Moynalty (Maigh nEalta, meaning "the plain of the flocks) is about 10 minutes from Kells town on the banks of the Owenroe River.
The village was built during the 19th century by the grandson of James Farrell, and it is believed to have been based on a Swiss design. However, the village was only constructed on one side of the river, and it wasn't until the following century when the village spread across to the other side.
A small lace-making industry in Moynalty supplied lace to the wife of King George at Buckingham Palace in London.
The village has become a familiar face in the national Tidy Towns competition. Moynalty was awarded with the title of Best Kept Town in All of Ireland in 2011.
The village also hosts the Moynalty Steam Threshing Festival, held every August since 1975 and well worth a visit as it harks back to yesteryear.
Matthew Gilsenan - Member of the Irish-based classical music group The Celtic Tenors was born in Moynalty in the early 1970s.


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Landweber iterative regularization method for identifying the unknown source of the modified Helmholtz equation
Fan Yang1,
Xiao Liu1 &
Xiao-Xiao Li1
Boundary Value Problems volume 2017, Article number: 91 (2017) Cite this article
In this paper, we consider the inverse problem of identifying the unknown source for the modified Helmholtz equation. We propose the Landweber iterative regularization method to solve this problem and obtain the regularization solution. Under the a priori and a posteriori regularization parameters choice rules, we all obtain the Hölder type error estimates between the exact solution and the regularization solutions. Several numerical examples are also provided to show that the Landweber iterative method works well for solving this problem.
The modified Helmholtz equation or the Yukawa equation which is pointed out in [1] appears in implicit matching schemes for the heat equation, in Debye-Huckel theory, and in the linearization of the Poisson-Boltzmann equation. The underlying free-space Green's function is usually referred to as the Yukawa potential in nuclear physics. In physics, chemistry, and biology, when Coulomb forces are damped by screening effects, this Green's function is also known as the screened Coulomb potential. Especially in microstretch elastic materials [2] and in the thermoelastodynamics of microstretch bodies [3, 4], the modified Helmholtz equation has been applied widely. In recent years, there are much research results on the inverse problem of the modified Helmholtz equation. The Cauchy problems associated with the modified Helmholtz equation have been studied by using different numerical methods, such as the Landweber method with boundary element method and the conjugate gradient method [5], the method of fundamental solutions (MFS) [6], the iteration regularization method [7], Tikhonov type regularization [8], Quasi-reversibility and truncation methods [9–11], Quasi-boundary regularization [12, 13], and so on. Inverse source problems arise in many branches of science and engineering, for example, heat conduction, crack identification, electromagnetic theory, geophysical prospecting, and pollutant detection. For the heat source identification, there have been a large number of research results for different forms of heat sources [14–22], and so on. But to the best of the authors' knowledge, there were few papers for identifying the unknown source on the modified Helmholtz equation. In [23, 24], the authors used the quasi-reversibility method to identify the unknown source of the modified Helmholtz equation on half strip region and half infinite region. In [25], the authors used the simplified Tikhonov regularization method to identify the unknown source for the modified Helmholtz equation. In [26, 27], the authors used the Tikhonov regularization method to identify the unknown source for the modified Helmholtz equation. But in [23–27], the regularization parameters are selected by the a priori rule. There is a defect for any a priori method, i.e., the a priori choice of the regularization parameter depends on the a priori bound E of the unknown solution. However, the a priori bound E cannot be known exactly in practice, and using a wrong constant E may lead to a badly regularized solution.
In this paper, we use the Landweber iterative method to identify the unknown source of the modified Helmholtz equation. The Landweber iterative method is a very popular algorithm and regularization method in inverse problem research. In [28], the authors used the method of iterative method to solve linear inverse problems. Under the posterior regularization parameter choice rule, the convergence order of the regularization solution is obtained. In [29], the authors used the iterative method to solve a nonlinear problems. We not only give the a priori choice of the regularization parameter, but also give the a posteriori choice of the regularization parameter which depends only on the measurable data. Moreover, we compare the effectiveness between the a posteriori choice rule and the a priori choice rule. To the best of the authors' knowledge, there are few papers choosing the regularization parameter by the a posteriori rule for this problem. We consider the modified Helmholtz equation as follows:
$$ \textstyle\begin{cases} \triangle u(x,y)-k^{2}u(x,y)=f(x), & 0< x\leq \pi, 0< y< +\infty, \\ u(0,y)=u(\pi,y)=0, & 0\leq y< +\infty, \\ u(x,0)=0,\qquad u(x,y)\vert _{y\rightarrow \infty }\quad \mbox{is bounded}, & 0\leq x\leq \pi, \\ u(x,1)=g(x), & 0\leq x\leq \pi, \end{cases} $$
where \(g(x)\) is given function in \(L^{2}(0, \pi)\), and \(f(x)\) is an unknown source. The constant k is the wave number. We use the additional condition \(u(x,1)=g(x)\) to determine the unknown source \(f(x)\). Physically, \(g(x)\) can be measured, there will be measurement errors, and we assume the function \(g^{\delta }(x)\in L^{2}(0, \pi)\) as the measurable data which satisfies
$$ \bigl\Vert g-g^{\delta }\bigr\Vert _{L^{2}(0, \pi)}\le \delta, $$
where the constant \(\delta >0\) represents a bound on the measurement error, \(\Vert \cdot \Vert \) is \(L^{2}(0,\pi)\) norm and δ is a noise level.
The remainder of the paper is organized as follows. In Section 2, we formulate some preliminary results. In Section 3, we present the Landweber iterative regularization method. The convergence estimates under an a priori and an a posteriori choice rules will be given in Section 4. Numerical examples are given to show the effectiveness of our method in Section 5. We give a brief conclusion in Section 6.
Some auxiliary results
In this section, we give some auxiliary results, which are very useful for our main conclusion.
For \(0\leq h\leq 1\) and \(n\geq 1\), the following inequalities hold:
$$\begin{aligned}& \begin{aligned}&(1-h)^{n}h\leq \frac{1}{n+1}, \\ &\frac{1-(1-h)^{n}}{h}\leq n. \end{aligned} \end{aligned}$$
Denote \(\rho (h)=(1-h)^{n}h\) and \(\beta (h)=1-(1-h)^{n}-nh\), then
$$\begin{aligned}& \rho '(h)=-n(1-h)^{n-1}h+(1-h)^{n}, \\& \rho '(h)=-n(1-h)^{n-1}h+(1-h)^{n}, \\& \beta '(h)=n(1-h)^{n-1}-n. \end{aligned}$$
Setting \(\rho '(h)=0\), we have
$$h=\frac{1}{n+1}. $$
Note that \(\rho (0)=\rho (1)=0\), \(\rho (h)\) has a unique maximal value at \(h=\frac{1}{n+1}\). Therefore,
$$\rho (h)=(1-h)^{n}h\leq \frac{1}{n+1}. $$
Because \(\beta '(h)\leq 0\) and \(\beta (0)=0\), we can easily obtain \(\beta (h)\leq 0\).
This ends the proof of the Lemma 2.1. □
For \(0< h\leq 1\), \(0<\alpha \leq 1\) and \(n\geq 1\), Lemma 2.1 can be strengthened as the following inequalities:
$$\begin{aligned}& (1-h)^{n}h^{\alpha }\leq {(n+1)}^{-\alpha }, \\& \frac{1-(1-h)^{n}}{h^{\alpha }}\leq n^{\alpha }. \end{aligned}$$
In fact, using the established results (2.1), we can get
$$\begin{aligned}& (1-h)^{n}h^{\alpha }\leq \bigl[(1-h)^{n}h \bigr]^{\alpha }\leq {(n+1)}^{-\alpha }, \\& \frac{1-(1-h)^{n}}{h^{\alpha }}\leq \biggl[\frac{1-(1-h)^{n}}{h}\biggr]^{\alpha } \leq n^{\alpha }. \end{aligned}$$
For \(t\geq 1\), we have
$$ \frac{1}{1-e^{-\sqrt{t}}}\leq 2. $$
$$ \frac{1}{2t}\leq \frac{1-e^{-\sqrt{t}}}{t}\leq \frac{1}{t}. $$
Landweber iterative regularization method
By the method of separation of variables, the solution of problem (1.1) is given by
$$u(x,y)=-\sum_{n=1}^{\infty } \frac{1-e^{-\sqrt{n^{2}+k^{2}}y}}{n^{2}+k ^{2}}f_{n}X_{n}, $$
where \(f_{n}=(f,X_{n})\) and \(X_{n}=\sqrt{\frac{2}{\pi }}\sin(nx)\) (\(n=1,2, \ldots\)) is a set of standard orthogonal bases on the space interval \(L^{2}(0,\pi)\).
Using \(u(x,1)=g(x)\), we obtain
$$ g(x)=-\sum_{n=1}^{\infty }\frac{1-e^{-\sqrt{n^{2}+k^{2}}}}{n^{2}+k ^{2}}f_{n}X_{n}= \sum_{n=1}^{\infty }g_{n}X_{n}, $$
where \(g_{n}=(g,X_{n})\).
Define operator \(K: f\rightarrow g\), then
$$ g(x)=Kf(x)=-\sum_{n=1}^{\infty } \frac{1-e^{-\sqrt{n^{2}+k^{2}}}}{n ^{2}+k^{2}}f_{n}X_{n}. $$
The operator K is a linear self adjoint compact operator, and its singular value is
$$ \mu_{n}=-\frac{1-e^{-\sqrt{n^{2}+k^{2}}}}{n^{2}+k^{2}}; $$
$$ g_{n}=-f_{n}\frac{1-e^{-\sqrt{n^{2}+k^{2}}}}{n^{2}+k^{2}}. $$
Hence we obtain
$$ f_{n}=-g_{n}\frac{n^{2}+k^{2}}{1-e^{-\sqrt{n^{2}+k^{2}}}} $$
$$ f(x)=\sum_{n=1}^{\infty }f_{n}X_{n}=- \sum_{n=1}^{\infty }\frac{n^{2}+k ^{2}}{1-e^{-\sqrt{n^{2}+k^{2}}}}g_{n}X_{n}= \sum_{n=1}^{\infty }\mu _{n}^{-1}g_{n}X_{n}. $$
When \(n\rightarrow \infty \), \(\mu_{n}^{-1}=o(n^{2})\), the exact data function \(g(x)\) must be at least two times lower, but the \(g^{\delta }(x)\), which belongs to \(L^{2}(0, \pi)\), does not necessarily have the same negative power drop of 2. So problem (1.1) is ill-posed. Assume for the unknown source \(f(x)\) there exists an a priori bound as follows:
$$ \bigl\Vert f(\cdot)\bigr\Vert _{p}\leq E,\quad p>0, $$
where \(E>0\) is a constant and \(\Vert f(\cdot)\Vert _{p}\) is defined as follows:
$$ \bigl\Vert f(\cdot)\bigr\Vert _{p}=\Biggl(\sum _{n=1}^{\infty }\bigl(n^{2}+k^{2} \bigr)^{p}\bigl\vert (f,X_{n})\bigr\vert ^{2} \Biggr)^{ \frac{1}{2}}. $$
If \(\Vert f(\cdot)\Vert _{p}\leq E\), \(p>0\), then
$$ \bigl\Vert f(\cdot)\bigr\Vert \leq C_{1}E^{\frac{2}{p+2}}\Vert g\Vert ^{\frac{p}{p+2}}, $$
where \(C_{1}:=2^{\frac{p}{p+2}}\).
From (3.5), (3.8), Lemma 2.3 and the Hölder inequality, we get
$$\begin{aligned} \bigl\Vert f(\cdot)\bigr\Vert ^{2} =& \Biggl\Vert \sum _{n=1}^{\infty }f_{n}\Biggr\Vert ^{2} \\ =& \sum_{n=1}^{\infty }g_{n}^{2} \biggl(\frac{n^{2}+k^{2}}{1-e^{-\sqrt{n ^{2}+k^{2}}}}\biggr)^{2} \\ =& \sum_{n=1}^{\infty }g_{n}^{\frac{4}{p+2}} \biggl(\frac{n^{2}+k^{2}}{1-e ^{-\sqrt{n^{2}+k^{2}}}}\biggr)^{2}g_{n}^{\frac{2p}{p+2}}. \\ \leq &\Biggl(\sum_{n=1}^{\infty }g_{n}^{2} \biggl(\frac{n^{2}+k^{2}}{1-e^{-\sqrt{n ^{2}+k^{2}}}}\biggr)^{p+2}\Biggr)^{\frac{2}{p+2}}\Biggl(\sum _{n=1}^{\infty }g_{n} \Biggr)^{ \frac{2p}{p+2}} \\ \leq & \Biggl(\sum_{n=1}^{\infty }f_{n}^{2} \bigl(n^{2}+k^{2}\bigr)^{p}\biggl( \frac{1}{1-e ^{-\sqrt{n^{2}+k^{2}}}}\biggr)^{p}\Biggr)^{\frac{2}{p+2}}\Biggl(\sum _{n=1}^{\infty }g _{n}\Biggr)^{\frac{2p}{p+2}} \\ \leq & C^{2}_{1}E^{\frac{2}{p+2}}\Vert g\Vert ^{\frac{2p}{p+2}}, \end{aligned}$$
We complete the proof of Theorem 3.1. □
Now, we use the Landweber iterative method to obtain the regularization solution for (1.1) and rewrite the equation \(Kf=g\) in the form \(f=(I-aK^{*}K)f+aK^{*}g\) for some \(a>0\). Iterate this equation, i.e.,
$$ f^{0}(x):=0, \qquad f^{m}(x)=\bigl(I-aK^{*}K \bigr)f^{m-1}(x)+aK^{*}g(x),\quad m=1,2,3,\ldots, $$
where m is iterative step number, and is selected regularization parameter. a is called relaxation factor, and satisfies \(0< a<\frac{1}{ \Vert K\Vert ^{2}}\). For K being a self adjoint operator, we obtain
$$ f^{m,\delta }(x)=a\sum_{k=0}^{m-1} \bigl(I-aK^{2}\bigr)^{k}Kg^{\delta }(x). $$
Using (3.3), we get
$$ f^{m,\delta }(x)=R_{m}g^{\delta }(x)=\sum _{n=1}^{\infty }\frac{1-(1-a \mu_{n}^{2})^{m}}{\mu_{n}}g_{n}^{\delta }X_{n}(x), $$
where \(g_{n}^{\delta }=(g^{\delta },X_{n}(x))\).
Error estimate under two parameters choice rules
In this section, we will give two convergence estimates under an a priori regularization parameter choice rule and an a posteriori regularization parameter choice rule, respectively.
An a priori regularization parameter choice rule
Let \(f(x)\) given by (3.6) be the exact solution of problem (1.1). Let \(f^{m,\delta }(x)\) given by (3.12) be the regularization Landweber iterative approximation solution. Choosing the regularization parameter \(m=[z]\), where
$$ z=\biggl(\frac{E}{\delta }\biggr)^{\frac{4}{p+2}}, $$
then we obtain the following error estimate:
$$ \bigl\Vert f^{m,\delta }(\cdot)-f(\cdot)\bigr\Vert \leq C_{2}E^{\frac{2}{p+2}} \delta^{\frac{p}{p+2}}, $$
where \([z]\) denotes the largest integer less than or equal to z, and \(C_{2}=\sqrt{a}+(\frac{4p}{a})^{\frac{p}{4}}\) is a constant dependent on a, p.
Due to the triangle inequality, we know
$$\begin{aligned}& \bigl\Vert f^{m,\delta }(\cdot)-f(\cdot)\bigr\Vert \\& \quad =\Biggl\Vert \sum_{n=1}^{\infty }\frac{1-(1-a\mu_{n}^{2})^{m}}{\mu_{n}}g_{n}^{\delta }X_{n}(x)- \sum_{n=1}^{\infty}\mu_{n}^{-1}g_{n}X_{n}(x) \Biggr\Vert \\& \quad \leq \Biggl\Vert \sum_{n=1}^{\infty } \frac{1-(1-a\mu_{n}^{2})^{m}}{\mu_{n}}g_{n}^{\delta }X_{n}(x)-\sum _{n=1}^{\infty }\frac{1-(1-a\mu_{n}^{2})^{m}}{\mu_{n}}g_{n}X_{n}(x) \Biggr\Vert \\& \qquad {}+\Biggl\Vert \sum_{n=1}^{\infty } \frac{1-(1-a\mu_{n}^{2})^{m}}{\mu_{n}}g_{n}X_{n}(x)-\sum _{n=1}^{\infty }\mu_{n}^{-1}g_{n}X_{n}(x) \Biggr\Vert \\& \quad =\bigl\Vert f^{m,\delta }(\cdot)-f^{m}(\cdot)\bigr\Vert + \bigl\Vert f^{m}(\cdot)-f(\cdot)\bigr\Vert . \end{aligned}$$
From condition (1.2) and (3.12), we have
$$\begin{aligned}& \bigl\Vert f^{m,\delta }(\cdot)-f^{m}(\cdot)\bigr\Vert ^{2} \\& \quad =\Biggl\Vert \sum_{n=1}^{\infty } \frac{1-(1-a\mu_{n}^{2})^{m}}{\mu_{n}}g_{n}^{\delta }X_{n}(x)-\sum _{n=1}^{\infty}\frac{1-(1-a\mu_{n}^{2})^{m}}{\mu_{n}}g_{n}X_{n}(x) \Biggr\Vert ^{2} \\& \quad =\Biggl\Vert \sum_{n=1}^{\infty } \frac{1-(1-a\mu_{n}^{2})^{m}}{\mu_{n}}\bigl(g_{n}^{\delta }-g_{n} \bigr)X_{n}(x)\Biggr\Vert ^{2} \\& \quad \leq \sup_{n\geq 1}H(n)^{2}\delta^{2}, \end{aligned}$$
where \(H(n):=\frac{1-(1-a\mu_{n}^{2})^{m}}{\mu_{n}}\).
By Lemma 2.1, we get
$$ \frac{1-(1-a\mu_{n}^{2})^{m}}{\mu_{n}}\leq \sqrt{am}, $$
i.e.,
$$ H(n)\leq \sqrt{am}. $$
$$ \bigl\Vert f^{m,\delta }(\cdot)-f^{m}(\cdot)\bigr\Vert \leq \sqrt{am}\delta. $$
On the other hand, using (3.7), we have
$$\begin{aligned} \bigl\Vert f^{m}(\cdot)-f(\cdot)\bigr\Vert ^{2} =& \Biggl\Vert \sum_{n=1}^{\infty } \frac{1-(1-a\mu_{n}^{2})^{m}}{\mu_{n}}g_{n}X_{n}(x)-\sum _{n=1}^{\infty }\mu_{n}^{-1}g_{n}X_{n}(x) \Biggr\Vert ^{2} \\ =&\Biggl\Vert \sum_{n=1}^{\infty } \frac{(1-a\mu_{n}^{2})^{m}}{\mu_{n}}g_{n}X_{n}(x)\Biggr\Vert ^{2} \\ =&\Biggl\Vert \sum_{n=1}^{\infty }\bigl(1-a \mu_{n}^{2}\bigr)^{m}\bigl(n^{2}+k^{2} \bigr)^{-p/2}\bigl(n^{2}+k^{2}\bigr)^{p/2}f_{n}X_{n}(x) \Biggr\Vert ^{2} \\ \leq &\sup_{n\geq 1}Q(n)^{2}E^{2}, \end{aligned}$$
where \(Q(n):=(1-a(-\frac{1-e^{-\sqrt{n^{2}+k^{2}}}}{n^{2}+k^{2}})^{2})^{m}(n ^{2}+k^{2})^{-\frac{p}{2}}\).
Using Lemma 2.2 and Lemma 2.4, we have
$$ Q(n)\leq \biggl(1-\frac{a}{4(n^{2}+k^{2})^{2}}\biggr)^{m}\bigl(n^{2}+k^{2} \bigr)^{- \frac{p}{2}}. $$
Let \(t:=n^{2}+k^{2}\),
$$ F(t):=\biggl(1-\frac{a}{(2t)^{2}}\biggr)^{m}t^{-\frac{p}{2}}. $$
Let \(t_{0}\) satisfy \(F'(t_{0})=0\), and we easily get
$$ t_{0}=\biggl(\frac{a(4m+p)}{4p}\biggr)^{\frac{1}{2}}. $$
$$\begin{aligned} F( t_{0}) =&\biggl(1-\frac{p}{4m+p}\biggr)^{m}\biggl( \frac{a(4m+p)}{4p}\biggr)^{-\frac{p}{4}} \\ \leq & \biggl(\frac{4p}{a(m+1)}\biggr)^{\frac{p}{4}}, \end{aligned}$$
$$ F(t)\leq \biggl(\frac{4p}{a}\biggr)^{\frac{p}{4}}(m+1)^{-\frac{p}{4}}. $$
Thus we obtain
$$ Q(n)\leq \biggl(\frac{4p}{a}\biggr)^{\frac{p}{4}}(m+1)^{-\frac{p}{4}}. $$
$$ \bigl\Vert f^{m}(\cdot)-f(\cdot)\bigr\Vert \leq \biggl( \frac{4p}{a}\biggr)^{\frac{p}{4}}(m+1)^{- \frac{p}{4}}E. $$
Combining (4.5) and (3.12), we choose \(m=[z]\), and get
where \(C_{2}:=\sqrt{a}+(\frac{4p}{a})^{\frac{p}{4}}\).
An a posteriori regularization parameter choice rule
We consider the a posteriori regularization parameter choice in the Morozov discrepancy, and construct regularization solution sequences \(f^{m,\delta }(x)\) by Landweber iterative method. Assume \(\tau >1\) is a given fixed constant. Stop the algorithm at the first occurrence of \(m=m(\delta)\in \mathbb{N}_{0}\) with
$$ \bigl\Vert Kf^{m,\delta }(\cdot)-g^{\delta }(\cdot)\bigr\Vert \leq \tau \delta, $$
where \(\Vert g^{\delta }\Vert \geq \tau \delta\).
Let \(\gamma (m)=\Vert Kf^{m,\delta }(\cdot)-g^{\delta }(\cdot)\Vert \), then we have the following conclusions:
\(\gamma (m)\) is a continuous function;
\(\lim_{m\rightarrow 0}\gamma (m)=\Vert g^{\delta }\Vert \);
\(\lim_{m\rightarrow +\infty }\gamma (m)=0\);
\(\gamma (m)\) is a strictly decreasing function, for any \(m\in (0,+\infty)\).
For fixed \(\tau >1\), and Landweber's iteration method with stopping rule (4.14), we can see that the regularization parameter \(m=m(\delta,g^{\delta })\in \mathbb{N}_{0}\) satisfies
$$ m\leq \biggl(\frac{2(p+2)}{a}\biggr) \biggl(\frac{E}{(\tau -1)\delta } \biggr)^{\frac{4}{p+2}}. $$
From (3.12), we have the representation
$$ R_{m}g=\sum_{n=1}^{\infty } \frac{1-(1-a\mu_{n}^{2})^{m}}{\mu_{n}}g _{n}X_{n}(x) $$
for every \(g\in H^{2}(\Omega)\) and thus
$$\begin{aligned} \Vert KR_{m}g-g\Vert ^{2} =&\Biggl\Vert \sum _{n=1}^{\infty }\bigl(1-\bigl(1-a \mu_{n}^{2}\bigr)^{m}\bigr)g_{n}X_{n}(x)- \sum_{n=1}^{\infty }g_{n}X_{n}(x) \Biggr\Vert ^{2} \\ =&\Biggl\Vert \sum_{n=1}^{\infty }-\bigl(1-a \mu_{n}^{2}\bigr)^{m}g_{n}X_{n}(x) \Biggr\Vert ^{2} \\ =&\sum_{n=1}^{\infty }\bigl(1-a \mu_{n}^{2}\bigr)^{2m}g_{n}^{2}. \end{aligned}$$
From \(\vert 1-a\mu_{n}^{2}\vert <1\), we conclude that \(\Vert KR_{m-1}-I\Vert \leq 1\).
We know that m is the minimum value that satisfies \(\Vert KR_{m}g^{\delta }-g^{\delta }\Vert =\Vert Kf^{m,\delta }-g^{\delta }\Vert \leq \tau \delta \). Hence
$$\begin{aligned} \Vert KR_{m-1}g-g\Vert \geq &\bigl\Vert KR_{m-1}g^{\delta }-g^{\delta } \bigr\Vert -\bigl\Vert (KR_{m-1}-I) \bigl(g-g^{\delta }\bigr) \bigr\Vert \\ \geq &\tau \delta -\Vert KR_{m-1}-I\Vert \delta \\ \geq &(\tau -1)\delta. \end{aligned}$$
On the other hand, using (3.7), we obtain
$$\begin{aligned} \Vert KR_{m-1}g-g\Vert =&\Biggl\Vert \sum _{n=1}^{\infty }\bigl(1-\bigl(1-a\mu_{n}^{2} \bigr)^{m-1}\bigr)g_{n}X_{n}(x)-\sum _{n=1}^{\infty }g_{n}X_{n}(x)\Biggr\Vert \\ =&\Biggl\Vert \sum_{n=1}^{\infty }-\bigl(1-a \mu_{n}^{2}\bigr)^{m-1}(g,X_{n})\Biggr\Vert \\ =&\Biggl\Vert \sum_{n=1}^{\infty }\bigl(1-a \mu_{n}^{2}\bigr)^{m-1}\mu_{n} \bigl(n^{2}+k^{2}\bigr)^{-\frac{p}{2}}f_{n} \bigl(n^{2}+k^{2}\bigr)^{\frac{p}{2}}X_{n}(x)\Biggr\Vert \\ \leq &\sup_{n\geq 1}\bigl\vert \bigl(1-a\mu_{n}^{2} \bigr)^{m-1}\mu_{n}\bigl(n^{2}+k^{2} \bigr)^{-\frac{p}{2}}\bigr\vert E. \end{aligned}$$
$$ S(n):=\bigl(1-a\mu_{n}^{2}\bigr)^{m-1} \mu_{n}\bigl(n^{2}+k^{2}\bigr)^{-\frac{p}{2}}, $$
$$ (\tau -1)\delta \leq S(n)E. $$
Using Lemma 2.4, we have
$$ S(n)\leq \biggl(1-a\biggl(\frac{1}{2t}\biggr)^{2} \biggr)^{m-1}t^{-\frac{p}{2}-1}. $$
$$ G(t)=\biggl(1-a\biggl(\frac{1}{2t}\biggr)^{2} \biggr)^{m-1}t^{-\frac{p}{2}-1}, $$
suppose \(t_{\ast }\) satisfy \(G'(t_{\ast })=0\), we easily get
$$ t_{\ast }=\biggl(\frac{a(4m+p-2)}{4(p+2)}\biggr)^{\frac{1}{2}}, $$
$$\begin{aligned} G(t_{\ast }) =&\biggl(1-\frac{4(p+2)}{4m+p-2}\biggr)^{m-1}\biggl( \frac{a(4m+p-2)}{4(p+2)}\biggr)^{-\frac{p+2}{4}} \\ \leq &\biggl(\frac{2(p+2)}{ma}\biggr)^{\frac{p+2}{4}}. \end{aligned}$$
Combining (4.18) with (4.21), we obtain (4.15). □
Let \(f(x)\) given by (3.6) be the exact solution of problem (1.1). Let \(f^{m,\delta }(x)\) given by (3.12) be the Landweber iterative regularization approximation solution. The regularization parameter is given by (4.14), then we have the following error estimate:
$$ \bigl\Vert f^{m,\delta }(\cdot)-f(\cdot)\bigr\Vert \leq \bigl(C_{1}(\tau +1)^{ \frac{2}{p+2}}+C_{3} \bigr)E^{\frac{2}{p+2}}\delta^{\frac{p}{p+2}}, $$
where \(C_{3}=(2(p+2))(\frac{1}{\tau -1})^{\frac{2}{p+2}}\) is a constant.
Using triangle inequality, we obtain
$$ \bigl\Vert f^{m,\delta }(\cdot)-f^{m}(\cdot)\bigr\Vert \leq \bigl\Vert f^{m,\delta }(\cdot)-f^{m}(\cdot)\bigr\Vert +\bigl\Vert f^{m}(\cdot)-f(\cdot)\bigr\Vert . $$
By (4.5) and Lemma 4.3, we get
$$\begin{aligned} \bigl\Vert f^{m,\delta }(\cdot)-f^{m}(\cdot)\bigr\Vert \leq& \sqrt{am}\delta \\ \leq& C _{4}E^{\frac{2}{p+2}}\delta^{\frac{p}{p+2}}, \end{aligned}$$
where \(C_{3}=(2(p+2))^{\frac{1}{2}}(\frac{1}{\tau -1})^{\frac{2}{p+2}}\).
For the second part of the right side of (4.24), we have
$$\begin{aligned}& K\bigl(f^{m}(\cdot)-f(\cdot)\bigr) \\& \quad =\sum _{n=1}^{\infty }-\bigl(1-a\mu_{n}^{2} \bigr)^{m}g _{n}X_{n}(x) \\& \quad =\sum_{n=1}^{\infty }-\bigl(1-a \mu_{n}^{2}\bigr)^{m}\bigl(g_{n}-g_{n}^{\delta } \bigr)X _{n}(x)+\sum_{n=1}^{\infty }- \bigl(1-a\mu_{n}^{2}\bigr)^{m}g_{n}^{\delta }X_{n}(x). \end{aligned}$$
Using (1.2) and (4.15), we have
$$ \bigl\Vert K\bigl(f^{m}(\cdot)-f(\cdot)\bigr)\bigr\Vert \leq ( \tau +1)\delta. $$
$$\begin{aligned} \bigl\Vert f^{m}(\cdot)-f(\cdot)\bigr\Vert _{H^{p}} =& \Biggl(\sum_{n=1}^{\infty }-\bigl(1-a\mu _{n}^{2}\bigr)^{2m}f_{n}^{2} \bigl(n^{2}+k^{2}\bigr)^{p}\Biggr)^{\frac{1}{2}} \\ \leq &\Biggl(\sum_{n=1}^{\infty }f_{n}^{2} \bigl(n^{2}+k^{2}\bigr)^{p}\Biggr)^{\frac{1}{2}} \\ \leq & E, \end{aligned}$$
and using Theorem 3.1, we have
$$ \bigl\Vert f^{m}(\cdot)-f(\cdot)\bigr\Vert \leq C_{1}(\tau +1)^{\frac{p}{p+2}}E^{ \frac{2}{p+2}}\delta^{\frac{p}{p+2}}. $$
$$ \bigl\Vert f^{m,\delta }(\cdot)-f(\cdot)\bigr\Vert \leq \bigl(C_{1}(\tau +1)^{ \frac{p}{p+2}}+C_{3} \bigr)E^{\frac{2}{p+2}}\delta^{\frac{p}{p+2}}. $$
This completes the proof of Theorem 4.4. □
Numerical implementation and numerical examples
In this section, we present numerical results for examples cases to show the effectiveness of our proposed method.
$$\begin{aligned} K\bigl(f(x)\bigr) =&-\sum_{n=1}^{\infty } \frac{1-e^{-\sqrt{n^{2}+k^{2}}}}{n ^{2}+k^{2}}(f,X_{n})X_{n} \\ =&-\sum_{n=1}^{\infty } \frac{1-e^{-\sqrt{n^{2}+k^{2}}}}{n^{2}+k ^{2}} \int_{0}^{\pi }f(s)\sqrt{\frac{2}{\pi }}\sin(ns)\,ds \sqrt{\frac{2}{ \pi }}\sin(nx) \\ =&- \int_{0}^{\pi }\frac{2}{\pi }\sum _{n=1}^{\infty }\frac{1-e^{-\sqrt{n ^{2}+k^{2}}}}{n^{2}+k^{2}}f(s)\sin(ns)\sin(nx)\,ds \\ =&g(x). \end{aligned}$$
We use the former N sum to approximate the infinite sum as follows:
$$ -\sum_{n=1}^{\infty }\frac{1-e^{-\sqrt{n^{2}+k^{2}}}}{n^{2}+k^{2}}f(s)\sin(ns)\sin(nx) \approx -\sum_{n=1}^{N} \frac{1-e^{-\sqrt{n^{2}+k^{2}}}}{n^{2}+k^{2}}f(s)\sin(ns)\sin(nx). $$
Let \(x_{i}=\frac{(i-1)\pi }{M}\), \(i=1,2,\ldots, M+1\). The integral is discretized by the Simpson formula, then (5.1) can be divided into
$$ Kf(x_{j})=-\frac{2}{\pi }\sum_{i=1}^{M+1} \sum_{n=1}^{N}\frac{1-e^{-\sqrt{n ^{2}+k^{2}}}}{n^{2}+k^{2}}f(x_{i})\sin(nx_{i})\sin(nx_{j}) \omega_{i} \pi. $$
$$ -2\sum_{i=1}^{M+1}\sum _{n=1}^{N}\frac{1-e^{-\sqrt{n^{2}+k^{2}}}}{n ^{2}+k^{2}}f(x_{i})\sin(nx_{i})\sin(nx_{j}) \omega_{i}=g(x_{j}), $$
$$ w_{i}= \textstyle\begin{cases} \frac{1}{3M}, & i=1,M+1, \\ \frac{4}{3M}, &i=2,4,\ldots, M, \\ \frac{2}{3M}, &i=3,5,\ldots, M-1. \end{cases} $$
The matrix form of (5.4) is as follows:
$$ Bf=g, $$
$$\begin{aligned}& B_{ij}=-2\sum_{n=1}^{N} \frac{1-e^{-\sqrt{n^{2}+k^{2}}}}{n^{2}+k^{2}}\sin(nx_{i})\sin(nx_{j}) \omega_{i}, \\& f_{j}=\bigl[f(x_{1}),f(x_{2}),\ldots,f(x_{i}),\ldots,f(x_{M+1})\bigr]^{T}, \\& g_{j}=\bigl[g(x_{1}),g(x_{2}),\ldots,g(x_{i}),\ldots,g(x_{M+1})\bigr]^{T}. \end{aligned}$$
Because K is the adjoint operator, \(B^{\ast }=B\). The corresponding Landweber iterative equation is
$$ f^{m,\delta }(x)=a\sum_{k=1}^{m} \bigl(I-aB^{2}\bigr)^{k-1}Bg^{\delta }(x). $$
In the computational procedure, we take \(p=1\). In discrete format, we take \(M=100\), \(N=6\) to compute the direct problem for the forward problem and choose \(M=200\), \(N=6\) to solve the inverse problem.
Through calculating, we know that the function \(u(x,y)=(1-e^{-\sqrt{2}ky})\sin(kx)\) and the function \(f(x)=-2k^{2}\sin(kx)\) are satisfied with the problem (1.1) with exact data \(g(x)=(1-e^{-\sqrt{2}k})\sin(kx)\), and the a priori bound is
$$ E=\bigl\Vert f(\cdot)\bigr\Vert _{p}=\Biggl(\sum _{n=1}^{N}\bigl(n^{2}+k^{2} \bigr)^{p}\bigl\vert (f,X_{n})\bigr\vert ^{2} \Biggr)^{ \frac{1}{2}}. $$
Noise data is generated by adding a random perturbation, that is,
$$g^{\delta }=g+\varepsilon \bigl(\operatorname{rand}\bigl(\operatorname{size}(g)\bigr)\bigr), $$
where ε is relative error level. The total error level g is given by the following:
$$\delta =\bigl\Vert g^{\delta }-g\bigr\Vert =\sqrt{ \frac{1}{M+1}\sum_{i=1}^{M+1} \bigl(g^{ \delta }(x_{i})-g(x_{i})\bigr)^{2}}. $$
Figure 1 shows the numerical results of \(k=2\), \(\varepsilon =0.001\), \(\varepsilon =0.01\), respectively. In Figure 2, when \(\varepsilon =0.001\), we take \(k=4,5\) to solve this problem.
The comparison of numerical effects between the exact solution and its regularization solution for Example 1 , \(\pmb{k=2}\) : (a) \(\pmb{\varepsilon =0.001}\) , (b) \(\pmb{\varepsilon =0.01}\) .
The comparison of numerical effects between the exact solution and its regularization solution for Example 1 , \(\pmb{\varepsilon =0.001}\) : (a) \(\pmb{k=4}\) , (b) \(\pmb{k=5}\) .
It can be seen from Figures 1-2 that the Landweber iterative regularization method is very effective for solving the inverse problem of the unknown source identification of the modified Helmholtz equation. On the one hand, when the random disturbance increases, the result becomes worse. On the other hand, with the increase of k, the results are slightly worse, which is also consistent with our error estimates.
Consider the following discontinuous function:
$$ f(x)= \textstyle\begin{cases} 0, & 0\leq x\leq \frac{\pi }{4}, \\ \frac{4}{\pi }x-1, &\frac{\pi }{4}< x\leq \frac{\pi }{2}, \\ -\frac{4}{\pi }x+3, &\frac{\pi }{2}< x\leq \frac{3}{4}\pi, \\ 0, &\frac{3}{4}\pi < x\leq \pi. \end{cases} $$
Figure 3 shows the numerical results of \(k=1\), \(\varepsilon =0.001\), \(\varepsilon =0.005\), respectively. In Figure 4, when the error is \(\varepsilon =0.01\), we take \(k=2,4\) to solve this problem. Figures 3-4 show the comparisons of the numerical effects between the exact solution and the regularization solution for the a priori and a posteriori regularization parameter choice rule with Example 2.
The comparison of numerical effects between the exact solution and its regularization solution for Example 2 , \(\pmb{k=1}\) : (a) \(\pmb{\varepsilon =0.001}\) , (b) \(\pmb{\varepsilon =0.005}\) .
The comparison of numerical effects between the exact solution and its regularization solution for Example 2 , \(\pmb{\varepsilon =0.01}\) : (a) \(\pmb{k=2}\) , (b) \(\pmb{k=4}\) .
$$ f(x)= \textstyle\begin{cases} 0, & 0\leq x\leq \frac{\pi }{3}, \\ 1, &\frac{\pi }{3}< x\leq \frac{2}{3}\pi, \\ 0, &\frac{2}{3}\pi < x\leq \pi. \end{cases} $$
Figure 5 shows the numerical results of \(k=1\), \(\varepsilon =0.01\), \(\varepsilon =0.05\), respectively. In Figure 6, when the error is \(\varepsilon =0.001\), we take \(k=2,4\) to solve this problem. Figures 5-6 show the comparisons of the numerical effects between the exact solution and the regularization solution for the a priori and a posteriori regularization parameter choice rule with Example 3.
The comparison of numerical effects between the exact solution and its regularization solution for Example 3 , \(\pmb{k=1}\) : (a) \(\pmb{\varepsilon =0.01}\) , (b) \(\pmb{\varepsilon =0.05}\) .
From Figures 3-6, we can find that the smaller ε, the better the computed approximation is. Moreover, we can also easily find that the a posteriori parameter choice rule works better than the a priori parameter choice rule. This is consistent with our theoretical analysis.
In this paper, we investigated the inverse source problem for the modified Helmholtz equation. The conditional stability was given. The Landweber iterative method is proposed to obtain a regularization solution. The error estimates were obtained under an a priori regularization parameter choice rule and an a posteriori regularization parameter choice rule, respectively. Meanwhile, numerical examples verifies that the Landweber iterative method has efficiency and accuracy.
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The authors would like to thanks the editor and the referees for their valuable comments and suggestions that improve the quality of our paper. The work is supported by the National Natural Science Foundation of China (11561045, 11501272) and the Doctor Fund of Lan Zhou University of Technology.
School of Science, Lanzhou University of Technology, Lanzhou, Gansu, 730050, P.R. China
Fan Yang, Xiao Liu & Xiao-Xiao Li
Fan Yang
Xiao-Xiao Li
Correspondence to Fan Yang.
The main idea of this paper was proposed by Fan Yang and Xiao Liu prepared the manuscript initially and performed all the steps of the proofs in this research. All authors read and approved the final manuscript.
Yang, F., Liu, X. & Li, XX. Landweber iterative regularization method for identifying the unknown source of the modified Helmholtz equation. Bound Value Probl 2017, 91 (2017). https://doi.org/10.1186/s13661-017-0823-8
35R25
modified Helmholtz equation
ill-posed problem
Landweber iterative method


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Barnimie  is a village in the administrative district of Gmina Drawno, within Choszczno County, West Pomeranian Voivodeship, in north-western Poland. It lies approximately  south-east of Drawno,  east of Choszczno, and  east of the regional capital Szczecin.

A historic Sacred Heart church, dating back to the 15th century, is located in Barnimie.

References

Barnimie

redpajama_set_name: RedPajamaWikipedia


For me, long summer weekends evoke memories of the lazy days of summers past. When I was a teen growing up in Southern California, we'd hang out at the beach from morning until night when the last bonfire embers dimmed and we scrambled to find a ride home. The scent of suntan lotion clinging to our skin, sand coating our toes, and promises of "see you tomorrow" floating in the cool air...Now, any summer weekend when I get the chance, I pile my kids, their friends, and our lab Lucy into the family SUV and head to Tahoe. We always have ambitious plans to pack adventure and relaxation into a weekend that magically feels like a long vacation. Summer weekends are about slowing down, making memories, and enjoying the perfect escape...To that end, I have selected eight of my favorite getaways in this glorious Golden State. These choice spots are destinations within easy reach from San Francisco or Los Angeles by car or plane.
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Enjoy the stunning 90-mile stretch of rugged coastline offering plenty of hiking trails to take in its breathtaking beauty. Start at Pfeiffer Big Sur State Park where a 80-foot waterfall dropping from the cliffs to the ocean is the focal point. You can get a view of by paying $10 to park and walk under the highway on a maintained trail. Visit the Historic park and lightstation Saturdays and Wednesdays; 10:00 a.m. & 2:00 p.m. and Sundays at 10:00 a.m.
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Escape from your cubicle and enjoy a meal at Downtown Santa Monica's Third Street Promenade with the return of everyone's favorite Summer lunch series, Picnic on the Promenade, July through August. Ease into the weekend every Friday in July and August with classic board games, Ping-Pong tables, giant Jenga and Connect 4. A DJ will be spinning smooth grooves to help you digest the stresses of the work week or enhance the enjoyment for all of you out-of-towners. Bring your lunch or grab-and-go from one of Downtown's celebrated eateries and soak in the sun!
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A Well Traveled Life features my personal perspective, photos and stories of far-flung destinations. I hope you will be inspired to get out there and GO!


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You are here: United Church Homes > News and Events > Corporate News > The Campaign for Abundant Life Announces Revised Goal of $45 Million
The Campaign for Abundant Life Announces Revised Goal of $45 Million
2020 marked the largest single donation in the history of United Church Homes by long-time friends who made an unparalleled lifetime estate gift of $17.5 million. This sacrificial gift inspired the creation of a new Fund for Growth to provide innovative programs and services at United Church Homes.
"This generous gift nearly doubled our $20 million goal for The Campaign for Abundant Life with two years left in the fundraising cycle," said Gloria Hurwitz, CFRE, Vice President of Advancement. "As a result, the Campaign Steering Committee decided to establish a revised goal to 2023 of $45 million."
Jim Henry, chair of The Campaign for Abundant Life said, "The 17.5 million gift was transformational and will help UCH reimagine life for older adults; however, there remains important work to be done in many of the campaign focus areas including Pastoral Care, Affordable Housing and The Ruth Frost Parker Center for Abundant Aging. This imperative work also needs donor support."
"The revised goal will allow our advancement team and volunteers to continue their vital work of inviting friends into the campaign with their gifts," said Rev. Kenneth Daniel, President and Chief Executive Officer. "We are grateful to continue to celebrate the generosity of many friends of United Church Homes who partner with us in our vision, Where the Spirit Creates Abundant Life in Community."
Corporate News, spirit, Spirit Magazine » Spring 2021, Our Abundant Impact senior living, retirement, ohio, independent living, assisted living, nonprofit, palliative care, campaign for abundant life


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Q: Typescript type for querySelectorAll Due to programming and magic my editor (vscode) knows which type querySelectorAll returns if I let Typescript do the typing for me.
But describing below variable compiled's type manually, is too complex for me to comprehend.
How can I explicitly describe its type?

In jasmine/angular I can (abbreviated):
const fixture = TestBed.createComponent(Proxy);
const component = fixture.componentInstance;
fixture.detectChanges();
const compiled = fixture.debugElement.nativeElement; // Magic does its work and type is known.

const titleElement = compiled.querySelectorAll('h3'); // Hovering pointer over method returns the type.
expect(titleElement.innerText).toBe('a title');

But due to reasons (how jasmine/angular sets up tests with forEach) I must declare compiled beforehand. Presently I declare it let compiled: any; which makes Typescript lose all type knowledge.
let compiled: any; // <- this is the variable I want to type.

const fixture = TestBed.createComponent(Proxy);
const component = fixture.componentInstance;
fixture.detectChanges();
compiled = fixture.debugElement.nativeElement;

const titleElement = compiled.querySelectorAll('h3')[0]; // Hovering does not yield type.
expect(titleElement.innerText).toBe('a title');

redpajama_set_name: RedPajamaStackExchange


Legal problems remake maps of old games.
Hello, everybody. I open this post to ask those of you who already have more experience in this world than I do. I have the idea to remake a map of a video game from 2003. For making a map that already exists in another video game, can I have some kind of legal problem when publishing it in the CSGO workshop? As this is an unofficial map for CSGO I don't know if I may or may not have problems. Thank you for your help, sorry for my English.
Can you use Source SDK as the most current engines?
Thanks for answering and giving your opinions! Another of my doubts: Many Web sites talk about the limitations of Source. Some say that at most on a level there may be 4096 objects between props and brushes. Others say that there is really no limit of props but that a limit of 8192 gives brushes. Can anyone remove doubts about this? Thank you!
Are the custom assets can cause errors with VAC?
Thanks, I understand that better not to abuse such large textures, but if they can be used.
Good job! The models are very nice. I also use Blender to create all models, either for soure or other engines. The theme of the textures, is there any news? Do you know if there are problems in creating maps with bigger textures 1024px what? Sorry for my English.
Thank you for this first information received!
I would like to know what are the technical limitations of the source engine. For example, maximum sizes of textures that can withstand, maximum number of porps map, maximum number of brushes map, maximum number of points of light, maximum number of polygons ... It also would be interesting to make a comparison of constraints between Source, Unity 5 UE4, this would help many developers to choose either engine. In the official documentation only I encounter any of these limitations, but it would be interesting to have it all in a single table. Thank you for your attention and sorry for my English.
Now that the game takes a while with you, do you think that will be as popular as it is now Counter Strike? Do you know if in the future you will have workshop with map editor? I was previously a staunch fan of Rainbow Six 3 Raven Shield, but now is unlike anything I loved.
Low poly fountain for Counter Strike GO map. Textures 512x512. I intend to reuse this model in future projects in Unity 5. In process a version with 1024x1024 textures.


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Star Wars: A New Hope: Vintage Collection Action Figure: Jawa
From: Star Wars
Universe: Star Wars
Manufacturer: Hasbro
Jawas comb the deserts of Tatooine in search of discarded scrap, selling hastily refurbished junk – including droids – to moisture farmers.
Celebrate the legacy of Star Wars, the action-and-adventure-packed space saga from a galaxy far, far away, with premium 3.75-inch scale figures and vehicles from Star Wars The Vintage Collection.
Figures feature premium detail and design across product and packaging inspired by the original line, as well as the movie-inspired collector grade deco that fans have come to know and love. (Additional products each sold separately. Subject to availability.)
Featuring premium detail and design across multiple points of articulation inspired by Star Wars: A New Hope, this collectible Star Wars The Vintage Collection 3.75-inch-scale figure makes a great gift for Star Wars fans and collectors.
Includes: figure and 2 accessories.
With immense vehicles known as Sandcrawlers, Jawas comb the deserts of Tatooine in search of discarded scrap
Star Wars The Vintage Collection 3.75-inch scale classic Star Wars figures and vehicles feature original Kenner branding (Each sold separately. Subject to availability.)
This Jawa action figure is inspired by the character in Star Wars: A New Hope, and makes a great gift for Star Wars collectors and fans ages 4 and up.
Highly poseable with realistic detail, the Star Wars Jawa figure can be displayed in action figure and vehicle collections.
Look for other Star Wars 3.75-inch scale The Vintage Collection figures and vehicles to collect, swap with friends, or give as gifts (Each sold separately. Subject to availability.)
Window Boxed


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