Home > The Forums > So much gear, so little time What would YOU do with 2 SM7Bs??
I have an SM7B. I've always looked upon it and used it for certain rock vocals and VO work.
Today I was handed (literally) another oner one (for FREE!). I've never considered other uses for the mic, musically or otherwise.
Aside from the obvious benefit of now having a spare, in case one should fail, are any of you using a pair of SM7Bs for anything? Or if you aren't, would there be a reason you'd buy another one?
I can see using one on a guitar or bass cab...maybe. But 2?
I guess I'm just looking for fun and interesting opinions and applications.
Vox and snare if you're recording a band live.
Interesting concept! Never have done a stereo shaker. But, the SM7B is an awesome idea for shaker. I struggled with shakers until I started using my RE20...but I will now use the SM7B because I have 2 and I can record them in STEREO!! WooHoo. My next song is going to 20 shaker tracks, layered and panned 10 L and 10 R!!
I wonder if we could get Chris to agree to sing to an 'all shaker' version of 'Burden in My Hand'?
vocals, snare, gtr cabs, kick, HI HAT !!!!
Seriously, I AM extremely appreciative and fortunate. A friend of mine bough it (and a few other very nice mics...that I will also end up with) a few yars ago . He was working on a project for a public television broadcast. His intention was to do some of it himself. As soon as he started digging into what it ACTUALLY takes to put together a decent recording...he went out and hired a (somewhat) proper setup with an experienced 'recordist' (your's truly).
I knew there were good uses for it, I just had not considered them too much. Honestly, my mic locker is in decent shape for a small operation with mid-range gear. Especially in terms of 'utility' mics. I think I have 35 or 40 items to choose from in the locker.
I always try to cover most of the functional areas (drums, acoustic gtr. cabs, horns, strings, pianos, etc. with specific mics (within a reasonable price range) that are well suited to their individual tasks. I realize that many mics are great on multiple sources. i also love haveing flexibility and options for any given application.
I do not own any mic over US $2000 (yet!), in fact, most of my mics are under US $1000...half are probably under $500, for that matter. I know there are expensive mics that do great jobs on different tasks, but mics that do great jobs aren't always, necessarily expensive!
I have NO IDEA whi I'm rambling! Maybe I feel guilty for getting this stuff for free and I'm trying to be gracious!
me too! I have a feeling I'll be falling even deeper in love in the coming months.
Will try...I keep seeing hi hat...looks like that will have to be the 1st thing I test. I usually mic all of my drums through my 8 Valley People Transamp Pres...very muscular. I think this mic will do QUITE well on that pre!
I'd try them on overheads ...only because I haven't ever tried a stereo pair on OHs thru a fat tube pre ....could be darkly beautiful or crap.
I'm inspired to pick up a 3rd and a 4th now and replace the oh-so-lack-luster SM57s that I am using on my rack toms. I alternate between an Audix D6, Beta52, RE20 and a DRK218 on the flr tom....maybe the SM7 will do the trick! The 4th one will sit over my hi hat.
For those of you that use them on drums, do you fiddle with the curve switches on the back?
Great on cleaner guitars. Try it on a bass cab. Got a feeling it's probably nice as a single kick mic too.


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Q: Trying to implement dash mechanics into my game. Everything works, except the speed increase I'm an illustrator and pixel artist and I do not know programming at all. I've been studying it specifically to learn how to use Unity and I have no idea of what I'm doing most of the time. All I did so far was by watching YouTube videos and tweaking the code.
So anyways, I managed to make my character jump, double-jump, walk and all the animations seem to be working properly, but the dashing mechanics seems to ignore the speed multiplier. It even plays the dash animation and the trail renderer I told it to play, but the speed remains like the same as if it was just walking. Since I pretty much just copied things I saw other people do and don't quite know what I'm doing, I think my code might be a Frankenstein aberration. But if I'm not wrong it looks like it gets to the point where it triggers the Coroutine, since it plays the dash animation and and the trail renderer. Unity didn't point any errors. So here's the Coroutine I'm using:
    private IEnumerator Dash()
    {
        canDash = false;
        isDashing = true;
        float originalGravity = rb2d.gravityScale;
        rb2d.gravityScale = 0f;
        rb2d.velocity = new Vector2(rb2d.velocity.x * dashingPower, 0f);
        tr.emitting = true;
        yield return new WaitForSeconds (dashingTime);
        tr.emitting = false;
        rb2d.gravityScale = originalGravity;
        isDashing = false;
        yield return new WaitForSeconds(dashingCooldown);
        canDash = true;
    }

Here's the full code for analysis
Thank you all very much in advance!

A: So my knowledge on Unity is limited to a few classes I have taken and its funky to say the least. at the beginning of your code, in the full code link, you set the value for rb2d.velocity which sets your normal move speed.  When you set your code for dashing above, your assigning a new value to rb2d.velocity, which is fine, the problem I would assume, comes in when you realize that setting a new value for rb2d.velocity in the dash portion overwrites your reference to speed in the original declaration.
I could be wrong but I would try changing
rb2d.velocity = new Vector2(rb2d.velocity.x * dashingPower, 0f);

to this
rb2d.velocity = new Vector2((moveInput * (speed * dashingPower), rb2d.velocity.y);

This would be my guess.
Edit: If this doesn't work I still believe your problem lies with your velocity declaration.

A: The reason for this problem is the constant changes of velocity in other parts of the code, which eliminates the effect of the dash. Note that at the same time as running the dash, you set the velocity back to the Move input in the fixed Update code where each frame runs, so this code can not see even a single frame running the dash.
//Moves player on x axis
private void FixedUpdate()
{
    moveInput = Input.GetAxisRaw("Horizontal");
    // Here we have a constant change that inhibits the dash effect..
    rb2d.velocity = new Vector2(moveInput * speed, rb2d.velocity.y);
}

 How to Fix Problem?
Although the best code architecture should always be such that different parts do not interfere with each other and operate independently, creating a Boolean that freeze normal input motion is not always the right way. In the code below, I tried to save the velocity value when pressing the dash key, as well as the mathematical direction of movement with the Mathf.Sign function. It is now sufficient to apply force to the stored velocity for the entire duration of the dash, regardless of whether it is unavoidable:
private IEnumerator Dash()
{
    canDash = false;
    isDashing = true;
    float originalGravity = rb2d.gravityScale;
    rb2d.gravityScale = 0f;

    // Dash Setup..
    var baseVelocity = rb2d.velocity; // save base Velocity
    var direction = Mathf.Sign(baseVelocity.x);
    var time = dashingTime;
    tr.emitting = true;
    while (time > 0)
    {
        rb2d.velocity = baseVelocity + new Vector2(direction * dashingPower, 0); // reference base Velocity for dash
        time -= Time.deltaTime;
        yield return new WaitForEndOfFrame();
    }
    // Finishing..

    tr.emitting = false;
    rb2d.velocity = Vector2.zero;
    rb2d.gravityScale = originalGravity;
    isDashing = false;
    yield return new WaitForSeconds(dashingCooldown);
    canDash = true;
}

Also, to avoid misalignment of frames in the Update and Fixed Update, it is better to move them all to one event.
private void Update()
{
    if (isDashing) return;

    if (Input.GetKeyDown(KeyCode.LeftShift) && canDash) StartCoroutine(Dash());

    /// Moving input motion to Update

    moveInput = Input.GetAxisRaw("Horizontal");

    rb2d.velocity = new Vector2(moveInput * speed, rb2d.velocity.y);

    ///.....
}

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HALFORD – Soul Prostitute
by Paul Kearns
(…this article is in English…)
From the sad wings of destiny to SOUL PROSTITUTION
The Lagacy Of Halford
Fucking kudos to Judas Priest and their announcement of their final tour.
Not before time it has to be said. Not to sound disrespectful or anything but when it's time to go, it's time to go.
Their «Angel Of Retribution» comeback was generally received rather warmly, reflection and it's 20/20 vision affords us a clearer picture where we can see that it was more that the songs were not as poor as they could have been rather than the songs being as good as they could have been that moved people to their praise of the album.
«Nostradamus» didn't fare so well. There is the bonus that a project seen as being so mammoth will be given special dispensation under the critical microscope because folk will generally show appreciation for the sheer size of it's undertaking, even in failure.
Truth is that the Priests simply put the cart a few blocks ahead of the horse. It is truly commendable to take your songs and dress them up in a concept of depth like this in hope of making the finished effort into a big complete fan wetting package. However, if you order a sandwhich with 'everything on it' you need the bread first, right? Well Priest seemed to forget that for this whole «Nostradamus» project to work they would need to begin with songs. Decent songs. Anyway……
Priest have overstayed their welcome in my opinion. They are far from alone though, none of their peers really seem to take the hints either. This considered I think Priest should get a gold star for at least laying down their studs in favour of the pipe and the slippers now.
For those in disagreement though, there is always the continuing solo career of Priest frontman Rob Halford. His latest effort «Made Of Metal» was released last year and is sure to please all who crave the musical equivalent of 'Will and Grace'.
Priest are rightly seen as being largely responsible for the evolution of Metal as it is today and particularly for the cast iron edge that many harsher bands are about.
There is no denying that bands such as Zepplin and Sabbath are the true fathers, more or less, of our beloved genre but I think it was Priest who were largely responsible for taking the burgoning Metal sound and filtering out some of the overt Blues elements that the Zepplins and the Sabbaths had.
Halford himself is a vocalist held in incredibly high regards. His trademark five billion octave scream laid a foundation that vocalists such as Manowar's Eric Adams among others have clearly been inspired by.
He very nearly qualified himself to have a broze statue of his very own image placed outside the gates of hell for having the balls…sorry, let's say…the guts to stand up to a culture (that culture being the Metal culture) known for it's conservatism in such arenas as sexuality and saying that 'YES' you can be just as devout a Metal maniac as the next bloke even if you do love cock.
Come on folks, the Metal scene is about as close as one can get to a sausage fest without actually killing any pigs. For a typical Metal guy to stand at, say, a Priest show and say he hates 'fags' is like a white boy to be in his element at a Public Enemy show and say he hates 'niggers'.
Queue outside a Metal gig
It was well over-fucking-due and on paper Halford woulda been the i-fucking-deal candidate to make that stand.
'Woulda been'? I imagine most would think that it were obvious that he simply 'WAS' the ideal man to stand upon that podium of tolerance and break down those walls of conservatism. However, I disagree. I disagree, yes I do.
The reason I disagree is becuase I truly, truly feel that this moment (when Halford 'came out' on MTV in 1998) was the very moment when his bald bonce had placed on it the crown worn by the King of all soul prostitutes.
http://www.mtv.com/videos/misc/101216/rob-halford-comes-out.jhtml
Look at it like this. If we chronologically trace Halford's career from around 1991 when his Priest days were over to his return to the metallic comforts (until he had run out of options anyway), it does not paint a pretty picture.
After the shock to the system album and comeback that was «Painkiller» people would have expected almost anything but Halford's departure…however, he bailed.
Without much further ado Halford dusted himself off and set about ridding himself of the Priest albatross that hung heavily around his neck.
Now personally I have no issue with someone wanting to further broaden musical horizons, in fact it is something I have great respect for when it is for nothing but genuine reasons, like when someone feels a truly artistic craving and then decides it must be followed. It's commendable.
In Halford's case though, it is astounding how his moves post-Priest were so obvious and disgusting.
Cold and calculated but above all they were so incredibly blatant that it still makes my head spin to this very day.
Each of Halford's three full length albums in between «Painkiller» and his «Retribution» fascade (the desperation soaked return to Metal) were, in my opinion, nothing more than sad attempts to attach his name to whatever sound/style was 'hot' right then. A word like integrity was quickly demoted to four letter status and possibly banished entirely in a transparent attempt to bribe a doorman and gain entrance to the C-list celebrity club.
Pathetic.
And for a man who was hailed as a 'Metal God'?
Rob….you aren't Madonna.
Fight – War Of Words 1993
Fight «War of Words»
1992 saw the release of Pantera's classic «A Vulgar Display Of Power» album and the face of hardened Metal changed completely.
People always mention Grunge and particularly Nirvana as being the nails that sealed shut the coffin of the 80's, excess and most of all the Hair/Glam/Party Metal scene that saw bands such as Motley Crue picking up platunum albums as if they were going out of fashion.
I would also credit the emergence of Pantera as playing a none too insignificant role in this musical extinction event, ironic considering Pantera's own beginnings but that's how it is sometimes.
«Rob Halford is a man with his finger on the pulse» was a headline I remember from those days. This was in reference to the debut album by Fight, Halford's then new band.
Their sound was strikingly current considering their frontman was the same guy who had been singing in Judas Priest for close to twenty years at that point, but he had left Priest at a high point so maybe he was genuinely following his heart? Doubtful.
Fight and Pantera
The 1992 revolution had seen the likes of Pantera as we mentioned. Another band who had jumped into the spotlight and who, like Pantera, had become one of the acts responsible for making chugga chugga power chords equal to big album sales were Biohazard. There were few more manly that these Noo York bruisers – this is the same band who promoted spitting on public footpaths (as could be seen the following year in their «Tales From The Hardside» video) and brought Evan Seinfeld, one of the most stupid men to ever be associated with the Metal genre, to the spotlight.
Whether it was desperation to be accepted, not realising that he was just a bit too old to be hanging with the high school kids or just the very first seeds of Soul Prostitution being laid Halford went out and pulled all the moves with Fight – thing was those moves just happened to be what was currently in fashion at that very time.
This was his first strike at showing the world he obviously had little regard for credibility.
Fight – A Small Deadly Space 1995
Fight «A Small Deadly Space»
1994 saw Pantera and Biohazard release follow up albums to their respective breakthrough discs. Both sold very well but the buzz died down as the albums were considered to be slightly disappointing given their pre-release hype.
In the meantime something happened with the Grunge scene. After the very mainstream explosions of the likes of Pearl Jam, Nirvana etc came a newer breed of chart smashers like Bush and Stone Temple Pilots who seemed to attract a more Metal or at least Metal tolerant audience. Given that the words Heavy and Metal when strung together were still highly unfashionable to the likes of the MTV Nazis it came to be that a Metal fan could admit to liking this stuff behind closed doors without fearing a nuclear wedgie.
Times were a'changing? Seems they were.
It was probably Alice In Chains with their dark materpiece 'Dirt' who showed the world that it was possible to write platinum selling Grunge with a darkness that wasn't aimed at winning the hearts of sixteen year old girls still mourning the fact that Kurt Cobain was offed by his Mrs (possibly offed by her).
Having nothing more in common with these young girls than finding Eddie Vedder wank worthy seems to have been more than enough for old Rob because it appears to have woken the Nostradmus in him (pun alert).
Where's Halford?
Fight released their sophomore album. And what the fuck do you know? It just happens AGAIN to reflect that very sound that the Rock/Metal world is getting a serious boner for at that time.
«Has the man no shame?» Well, he doesn't now and he clearly didn't then.
It was beginning to get fucking embarrassing.
The Fight album sunk without trace, more or less, and Halford retired into a small deadly space where he either cried himself to sleep thinking about just how sad it was that Kurt had ruined that hair by taking a headshot…or…undeterred, he began plotting his next move.
Realising, I imagine, that he would need to be even more vulgar, blatant and shameless in his next move he stood over the corpse of his Epic Records contract and shouted «I, Rob Halford, will…I repeat…WILL be relevant even if it means going so low as to use my very own sexuality as a publicity tool».
«Hold on a fucking minute» he said and paused, looking down at his cut off Anselmo combat pants he borrowed from his nephew Brian, «That is not a bad fucking idea»
2wo – Voyeurs 1998
2wo «Voyeurs»
Halford went through another metamorphosis in the three years between Fight's sophomore effort ¨and the release of 2wo's debut album.
At this point it had to be completely obvious to most that it was more than mere coincidence that this made three image/sound changes over three post Judas Priest albums. No?
If anyone is doubtful just look at the bare and basic facts.
Halford around 1993
Album #1 was Aggro Metal when that sound was at it's absolute peak.
Album #2 was more intrispective and dark and pretty much in line with all those Grunge lads who just happened to be selling gazillions of albums at that time.
Album 3# was more in the Goth/Industrial vein of Marilyn Manson when Manson and his band were on just about every lip in the western world.
Is there a pattern?
Yes Ma'am, 1996 had seen Manson ex-fucking-plode with their «Antichrist Superstar» album and grip the world in their fever. Frontman Brian Warner (his parents called him Marilyn Manson) and his face were adorning the cover of just about every Rock and music publication at that time to the point where….well, it's safe to say that the Industrial/Goth crossover thing was very much in.
I still find it mind boggling that a man who had seen his previous band (not Fight) evolve and grow into a musical entity that more or less redefined one corner of the music world was so desperate to fit in when he had achieved so much and had already attained near legendary status for the right reasons.
Halford was already more than financially secure through Judas Priest so I find it very unlikely that a working class Brummie would give away so much for a few quid more.
That leaves only a dreadfui, desperate need for acceptance with the 'now crowd' and all other factors cosmetic that sadly follow as collatoral damage in the music world. Those very same factors that really do mock the very existance of art in music
Weren't these actions, no matter how conscious or not, showing all who would see that he obviously had no real concern for that art of music. The very soul that surely drives it and our desire to make it?
"Where are all my ideas? I know I left them here somewhere"
Another very, very important point is the glamourous side of the coin that became more than acceptable in this Industrial/Goth circle and beyond. Guys wearing make up suddenly would not have to cross the road into hiding when their paths were to cross with Heavy Metal folk.
Girating, hip shaking and other such activities, once frowned upon severely and carrying a 'guilty until proven otherwise' condemnation had been almost legalised such was Manson's use of them to steal the breath of the religious right and others who believed fully in the concept of the nuclear family, apple pies and picket fences that could be no other colour than pure white.
More than anything was the once unthinkable was becoming fact. It seemed that to be one who worshipped the holy trinity of Marshall, Distortion and Double Bass Drumming accepting homosexuality was actually fine. Moreso, it seemed that loving that holy trinity and actually being gay was fine too.
These changes in attitude were seismic, they made Karkatoa and her foundation shaking explosion seem trivial by comparison. Could this really be?
Let's not forget either the then much publicised incident when Nine Inch Nails still held the throne Marilyn Manson would soon conquer. During a live show Manson (still a relative unknown to Dr. Phil and peers) lept onstage, approached a member of NIN mid concert and simulated oral sex.
There were people who swore blind that they witnessed Manson get a mouthful of prison hot dog whilst others were more dismissive.
Point is that both the feller from Rezner's band (aka NIN) and Brian Warner/Marilyn Manson were, and indeed are still, blokes. This was, implied or executed, a gay act. It was also accepted.
It didn't cause Jim Bob in Kentuckey to break away from explaining to his eight kids why he and Ma' had the same surname and the eight kids only ever had one set of grandparents to condemn Manson etc as «God damned homosapians».
It was accepted.
That it was an obvious publicity stunt by Warner matters not in the context of this rant, what matters is that he was first.
Times were a'changing folks. Rob Halford and his ever keen eye were realising fast that…well, there are two obvious scenarios by my thinking here as to how Halford processed these changes.
The first is one that I find less likely.
In this scenario Halford, weighed down by years of hiding in that old closet saw the light at the end of the tunnel. He saw the Mardigras parade approach, stop outside his door and shout a collective «Come on Rob, the football team said they'd pull out unless you join in this year». He saw his shoulders, released of this weight finally, rise higher than they had ever risen. Finally, Halford thought, I can be me.
The second scenario is one that I find far, far more likely. So much so that I am willing to uncharacteristically proclaim this to be turth.
Upon seeing the acceptance of homosexual men in the Rock/Hard Rock/Heavy Metal world Halford reached into his pocket and pulled out his magic 'Coolness Calculator'.
Data regarding the freshly opened minds of the new Manson led brigades, their influence on the old guard and the general overall loosening of the Gay Laws in Metal was entered.
Halford then entered his own orientation as being homosexual.
Sal, as the coolness computer is known…sister of Hal from «A Space Odyssey», had a couple of variables to consider before giving an answer.
1. Was it common knowledge to the world that Halford was gay?
He replied that it was not. Sal returned an answer – that this fact was unkown gave his situation far more media value than if his orientation were previously know
2. Was he prepared to adopt an appearance that would make it seem that Marilyn Manson was in fact his Mother and dressed him every day before schol? This would mean suddenly wearing eye liner, feather boas (including pink) and basically making it extremely obvious that he was disposing any traces of integrity in order to fit in with what was hot at the moment?
Halford laughed and asked «Haven't you seen what I have been doing since I left Priest?» He chose 'Yes'.
3. Would he be prepared to use his coming out, use his sexuality, use his lifelong secret as a marketing tool for his new kid friendly band?
'Yes' answered Halford without even a millisecond's thought.
4. Was he aware that this was Soul Prostitution, considered by some to be a crime unforgivable?
Halford paused. Was this the one straw he was not able to commit to the camels back?
Seemingly not.
«Duh…..are you fucking nuts….Of Fucking Course. I couldn't give a fuck. As long as I can get into a Manson or a NIN show without needing a ticket like all those losers on the independant labels or queueing like all those loser kids I desperately hope will now accept me and buy my albums.
And so it was done.
Shortly after this, with the stars having alligned to give Halford's 2wo band a deal with the ultra hip Nothing Records helmed by Trent Reznor of Nine Inch Nails and give him a band featuring an array of young men who were most definitely worthy of place in The Spooky Kids generation, it was announced that Halford was to reappear yet again for the public.
Details of band and album followed, no doubt met by many raied eyes brows.
Then Halford dropped the bomb.
His own Hiroshima came during an interview on MTV, itself the mecca of the all things shallow but also the one place where careers were truly made or broken. It was here that Halford mentioned those words «Speaking as a gay man…..» and so it was that the first of endless five dollar bills was passed to the pimp they called 'Acceptance' and Halford's poor soul bent down to it's knees to take it first of many a penis into it's mouth and begin life as a working girl…..or boy….or soul.
According to Halford himself, it came out accidentally during the interview.
Let's repeat that.
OK. So, in all those years pervious, in all those countless interviews, in all those thousands upon thousands of situations where it could have just slipped out……it didn't?
OK. So now as he was putting out an album in a scene that was new to him but had taken commercial America by storm. One that outwardly flaunted cross dressing, androgeny. One that held open arms out to homosexuality, implied or actual…..is when it just happen to 'accidentally slip out'??
I suggest that this is one of the most disgusting acts of, as you may have noticed, what I like to call soul prostitution ever commited.
I am naturally referring to the Hard Rock/Heavy Metal scenes and their relevant offshoots. It rendered every single musical effort Halford took part in before and after as being competely worthless in my opinion, such is the bare faced and shameless soul fucking prostitution Rob 'Metal God/Chugga Chugga God/Grunge God/Goth God/Industrial God' Halford displayed.
From mimicking Pantera, to mimicking whatever worked in the grunge scene to this, the ultimate insult to his legion of fans. Halford disgusts in showing that he will go to any lengths to be lauded. To be 'in'.
Music, not matter which way you look at it, is a form of art.
Art not commerce.
Just because you play in a band does not make you an artist exactly such is the entertaining level of rubbish out there but that does not change the fact that music itself is an artform.
Commercial success and it's benefits are not artforms although success in a particular artform can bring about the bonus of enjoying those benefits.
This is all pretty standard stuff, right? We should all know this from before.
So when someone uses an artform, in Halford's case it's music, not for artistic expression but as a vehicle for monetary success or for accetance amongst others who abuse an artform just to enjoy those same benefits then I believe that renders that person and any, so called, artistic endeavous of theirs completely irrelevant.
Not surprising is that Halford seemed to fall victim of the three strike rule (three vanity attempts post Judas Priest). He was out.
Less surprising again is that he returned to 'Metal' soon after.
Bruce Dickinson had success with «Accident Of Birth» and «The Chemical Wedding» in 1997 and 1998. Both albums were very much Heavy Metal and had Roy Z. onboard as song writer/producer. Realising that he had, pretty much, no options left Halford again put someone elses idea to work for himself releasing a so called comeback album called «Retribution» in 2000.
With Maiden reunited, pulling in massive crowds so Metal began to enter public consiousness again, Halford embraced his part with all he was worth and again threw himself into an artform he surely has no love for.
Merry Christmas me arse? Ohhhh Rob
The Priest reunion followed soon after of course. Halford continued to disgrace himself and his past by making like 1993 – 1998 never happened……he even released a fucking Christmas album…no bullshit.
At this point nothing can be shocking though.
It is very, very pleasing however to know that true legends such as KK Downing and Glen Tipton will soon be where they truly deserve to be – far, far away from Rob Halford lest he would steal their souls from right over their flying V's.
As usual, the bad guys win. Halford recently hooked up with Ozzy Osbourne for some touring, if ever there were two more like minded souls?
Ozzy's only defence is that it was his Mrs. who did all the soul selling, his biggest crime was merely being too stupid to prevent it. Regardless, let's hope they all live happily ever after together.
Dedicated to SS Turnip and his atlas testicle
IMPERIUM DEKADENZ – Atmospheric and poetic Black Metal
TOMMY DAHLSTRÖM (Aeon) – …och skriker skiten ur mig

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text:
\section{Introduction}
We study the positivity properties of direct images of adjoint line
bundles. We get

\begin{thm} \label{semi-ample}
Let $\phi~:~Y\lra X$ be a projective submersion between two complex
manifolds.  Let $L$ be a semi-ample line bundle on $Y$.  Then the
vector bundle $\phi_\star(K_{Y/X}\otimes L)$ has a continuous metric
with Griffiths semi-positive curvature.
\end{thm}

\begin{thm} \label{ample}
Let $\phi~:~Y\lra X$ be a submersion between two complex projective
manifolds.  Let $L$ be an ample line bundle on $Y$.  Then the vector
bundle $\phi_\star(K_{Y/X}\otimes L)$ has a smooth metric with
Griffiths positive curvature.
\end{thm}

 On grassmanian manifolds, abelian varieties and toric varieties,
these results were already proved either by the Castelnuovo-Mumford
criterion for global generation or by trying to mimic the Frobenius
morphisms over $\mathbb{C}} \def\nb{\mathbb{N}} \def\nbs{\mathbb{N}^\star$ (\cite{ma}, \cite[Th{\'e}or{\`e}me 3]{mo}).  These
theorems should be compared with by now classical results due to
Fujita, Kawamata and others in algebraic geometry setting (see for
example~\cite[Chapter 6.3.E]{laz}).  These constructions may help to
find some topological properties of algebraic sub-varieties under
ampleness assumptions for the normal bundle (see for
example~\cite{ful} and~\cite{laz} part two).  The interesting outcome
is that metrics could be used to construct Morse functions, whose
indices are computed by the curvature.

For the main application, we consider a holomorphic vector bundle $E$
on a compact complex manifold, and intend to construct metrics on
vector bundles associated to $E$ which would reflect algebraic
positivity properties of~$E$.  Just note that on the variety
$\pi~:~\pbe\lra X$ of rank one quotients of $E$ the direct image
$\pi_\star(K_{\pbe/X}\otimes \oce (k+r))$, where $r$ is the rank of
$E$, is $S^kE\otimes\det E$ to infer

\begin{cor}
Let $E$ be a semi-ample vector bundle on a complex manifold.
Then for all positive integer $k$, the vector bundles $S^kE \otimes
\det E$ have continuous metrics with Griffiths semi-positive
curvature.
\end{cor}

\begin{cor}
Let $E$ be an ample vector bundle on a complex projective manifold.
Then for all positive integer $k$, the vector bundles $S^kE \otimes
\det E$ are Griffiths positive.
\end{cor}
The theory of resolution of the $\overline{\partial}$-equation with $L^2$-estimates
for example shows that Griffiths positivity and ampleness are
equivalent for line bundles. This implies through the curvature
computation of $\oce(1)$ that Griffiths positive vector bundles are
ample.  The converse is a problem raised by Griffiths~\cite[problem
(0.9)]{Gr}, and solved positively on curves by Umemura~\cite{um} using
the concept of stability (see also~\cite{campana}).  Our results
provide a weak answer to Griffiths's problem.  The appearance of the
determinant line bundle has the same origin than its appearance in the
vanishing theorem of Griffiths for the cohomology of ample vector
bundles.

The first idea in the proof is to use natural cyclic coverings to be
able to use Hodge metrics on the direct image of the relative
canonical sheaf under a proper K{\"a}hler surjective map between two complex
manifolds.  This may be seen as a metric aspect of Ramanujam's idea to
reduce vanishing theorem to topological properties~\cite{ra} (see
also~\cite{ko}).

Applying Griffiths method of computing metrics on Hodge bundles, we
will be able to compute the curvature of direct image of the structure
sheaf for proper K{\"a}hler submersions. It turns out that the metric on the
top direct image of the structure sheaf of the source manifold is
semi-negatively curved.

We then have to determine the singularities of the Hodge metrics.  For
 a proper surjective map $f~:~Z^{n+r}\lra X^n$, the Jacobian ideal
 $Jac_f$ is the ideal of $\mathcal{O}} \def\oce{\mathcal{O}_E} \def\xc{\mathcal{X}_Z$ generated by the $n\times n$- minors
 of the matrix of the differential of $f$ (computed in any chart). The
 discriminant locus $\Delta_f \subset X$ is defined to be the image
 under $f$ of the sub-scheme of $Z$ where the map $f$ is not
 submersive, that is the sub-scheme cut out by $Jac_f$. Denote
 $X-\Delta_f$ by $X^0$ and $f^{-1}(X^0)$ by $Z^0$. The map $f^0
 :=f_{|Z^0}~:~Z^0\lra X^0$ is then a projective submersion.  With
 these notations, our main technical lemma generalizes Fujita's
 observation~\cite[lemma 1.12]{fu}.

\begin{lem}\label{mainlemma}
Let $f~:~Z\lra X$ be a proper K{\"a}hler surjective map between two
complex manifolds.
\begin{enumerate}
\item Then, the Hodge metric on $(f^0)_\star (K_{Z^0/X^0})$ extends as
  a metric with poles on $f_\star (K_{Z/X})$.
\item The Hodge metric on $(f^0)_\star (K_{Z^0/X^0})$ extends as a
  smooth metric on $f_\star (Jac_f \otimes K_{Z/X})$.
\end{enumerate}
\end{lem}
 This is far simpler than general results obtained by Kawamata,
Z{\"u}cker, Koll{\'a}r and Cattani-Kaplan-Schimd.

This paper is a revised and expanded version of our preprint
\cite{mt}.  Shortly before we ended the writing of our text, Bo
Berndtsson gave a nice proof of the Nakano positivity of the direct
image of adjoint ample line bundle in the same setting than
ours~\cite{be}.  We nevertheless feel worth to display our techniques
for these are different from his.

{\it Acknowledgment}. The first named author warmly thanks Indranil
Biswas for a collaboration in an attempt to prove similar results.

\section{The tools}

\subsection{Ampleness and positivity}
\label{ap}

We refer to~\cite{H-66} or~\cite[\S 6]{laz} for basics about ample
vector bundles and to~\cite{Gr} or~\cite[chapter VII]{de-book} for
basics about positive vector bundles.  All vector bundles are assumed
to be holomorphic.

A vector bundle $E$ on a compact complex manifold $X$ is said to be
{\it semi-ample}\/ if for some positive integer $k$, its symmetric
power $S^k E$ is generated by its global sections.  Associated to $E$,
we have $\pi~:~\pbe\lra~X$ the variety of rank one quotients of $E$
together with its tautological quotient line bundle $\oce (1)$.  The
semi-ampleness of $E$ is rephrased that for every $x \in X$, every
section $s_x$ of $\oce (k)$ over the fiber $\mathbb{P}} \def\pbe{\mathbb{P}(E)} \def\rb{\mathbb{R} (E_x)$ extends to a
global section of $\oce (k)$ over $\mathbb{P}} \def\pbe{\mathbb{P}(E)} \def\rb{\mathbb{R} (E)$.  This in particular
implies that $\oce (k)$ is generated by its global sections.  A vector
bundle $E$ is said to be {\it ample}\/ if its associated line bundle
$\oce (1)$ is ample on $\pbe$.  This in particular implies the
existence of an integer $k$ such that for every $x \in X$, every
section $s_x$ of $\oce(k)$ over the first infinitesimal neighborhood
of the fiber $\mathbb{P}} \def\pbe{\mathbb{P}(E)} \def\rb{\mathbb{R} (E_x)$ extends to a global section of $\oce (k)$
over $\mathbb{P}} \def\pbe{\mathbb{P}(E)} \def\rb{\mathbb{R} (E)$.

Recall the formula for the curvature of the Chern connection of the
quotient metric $h_q$ on $\oce (1)$ of a chosen metric $h$ on
$E$. Here $a^\star$ parametrizes rank one quotients of $E$ and
$FS(h_x)$ is the Fubini-Study metric of the hermitian form $h_x$ on
$E_x$.
\begin{eqnarray*}
\nonumber \Theta (\oce (1),h_q)&=& \sqrt{-1}\partial\!\overline{\partial} \log \n
e^\star_0+z_1e^\star_1+\cdots z_{r-1}e^\star_{r-1}\n^2\\ &=& \Theta
(\mathcal{O}} \def\oce{\mathcal{O}_E} \def\xc{\mathcal{X}_{\mathbb{P}} \def\pbe{\mathbb{P}(E)} \def\rb{\mathbb{R} (E_x)} (1), FS (h_x)) -\frac{\langle
\pi^\star\Theta(E^\star, h^\star) a^\star, a^\star\rangle} {\langle
a^\star,a^\star\rangle}.
\end{eqnarray*}

A vector bundle $E$ is said to be {\it Griffiths positive}, if it can
be endowed with a smooth hermitian metric $h$ such that for all $x\in
X$ and all non-zero decomposable tensors $v \otimes e\in TX_x\otimes
E_x$, the curvature term
$\langle\Theta(E,h)(v,\overline{v})e,e\rangle_h$ is positive, where
$\Theta(E,h)\in \mathcal{C}_{1,1}^{\infty}(X,Herm (E))$ is the
curvature of the Chern connection $\nabla_{E,h}$ of $(E,h)$.

A continuous hermitian metric $h$ on a vector bundle $b~:~E\lra X$ is
said to be {\it Griffiths positive}, if there exists a smooth positive
real $(1,1)$-form $\omega_X$ on $X$ such that in the sense of currents
$$ -\sqrt{-1}\d\!\overline{\partial}\log h(\xi) \geq b^\star \omega_X,
$$ where $h$ is seen as a continuous quadratic function on the total
space $E-X\times \{0\}$.  At the points where the metric $h$ is
smooth, these two notions of Griffiths positivity coincide.

\subsection{Cyclic covers}
\label{sec2}

A reference for this part is~\cite[\S~3]{es}.  Take a semi-ample line
bundle $L$ on a complex manifold $Y$ and fix a positive integer $k$
such that the tensor power $L^k$ is generated by its global sections.
Then Bertini's theorem~(see for example~\cite[ page 137]{gh}) insures
that a generic section $s$ of $L^k$ over $Y$ is transverse to the zero
section (i.e. $ds_{|D_s}~:TY_{|D_s}\lra L^k_{|D_s}$ is surjective),
and defines a smooth divisor $D_s:=(s=0)$.  Let
$$ p = p_s~: \tly_s\lra Y
$$ be the cyclic covering of $Y$ obtained by taking the $k$-th root
out of $D_s$.  The space
$$ \tly_s := \{l\in L / l^k=s(p(l)) \}
$$ is a smooth hypersurface of the total space $L$, and the map $p$ is
a finite cover of degree $k$ totally ramified along the zero locus
$D_s$ of $s$.  The space $\tly_s$ may also be described as the
spectrum $\spec \mathcal{A}} \def\rc{\mathcal{R}} \def\mc{\mathcal{M}_s$ of the algebra
$$ \mathcal{A}} \def\rc{\mathcal{R}} \def\mc{\mathcal{M}_s~:=\frac{\oplus_{i=0}^{+\infty} L^{-i}} {\left(l^\star
-\check{s} (l^\star)\ , \ \l^\star\in L^{-k}\right) }
$$ where $\check{s}$ is the sheaf inclusion $L^{-k}\stackrel{\times
s}\rightarrow\mathcal{O}} \def\oce{\mathcal{O}_E} \def\xc{\mathcal{X}_{Y}$.  The direct image of the structure sheaf
$\mathcal{O}} \def\oce{\mathcal{O}_E} \def\xc{\mathcal{X}_{\tly_s}$ is hence $p_\star \mathcal{O}} \def\oce{\mathcal{O}_E} \def\xc{\mathcal{X}
_{\tly_s}=\mathcal{A}} \def\rc{\mathcal{R}} \def\mc{\mathcal{M}_s\simeq\oplus_{i=0}^{k-1} L^{-i}$.

In our setting, we consider a projective submersion $\phi~:~Y\lra X$
of relative dimension $r$
 between two complex manifolds and $L$ a semi-ample line bundle on
 $Y$. A generic section of $L^k$ gives rise to a covering of $Y$ which
 we in fact regard as a family of coverings of the fibers of $\phi$.
 Because $p_s$ is a finite morphism, the spectral sequence of
 composition of direct image functors reduces to the following:
\begin{eqnarray*}
\nonumber \rc ^{r} (\phi\circ p_s)_\star \mathcal{O}} \def\oce{\mathcal{O}_E} \def\xc{\mathcal{X}_{\tly_s} &=&\rc ^{r}
\phi_\star \left(\rc ^0 p_\star \mathcal{O}} \def\oce{\mathcal{O}_E} \def\xc{\mathcal{X}_{\tly_s} \right) \\ \nonumber
&=&\rc ^{r} \phi_\star \left(\oplus_{i=0}^{k-1} L^{-i}\right)
=\oplus_{i=0}^{k-1} \phi_\star\left(K_{Y/X}\otimes L^{i}\right)^\star.
\end{eqnarray*}
Here we have used Serre duality on the fibers of the smooth morphism
$\phi$.

\subsection{The Hodge metric}
We recall the basics on geometric variations of Hodge structures and
Griffiths's computations (\cite[theorem 6.2]{gr}) of the curvature the
Hodge metric (see also~\cite[$\S$ 7]{sc} and~\cite[chapter~10]{vo}).
Here we assume that $f : Y \lra B$ is a proper K{\"a}hler submersion of
relative dimension $r$,
in particular we regard
$f : Y \lra B$ as a smooth family of compact K{\"a}hler
manifolds of dimension $r$.  Fix a non-negative integer $d$.  The
local system $\rc^df_\star\mathbb{C}} \def\nb{\mathbb{N}} \def\nbs{\mathbb{N}^\star$ can be realized as the sheaf of germs
of the flat sections of the holomorphic vector bundle $\bold{H}} \def\fb{\bold{F}} \def\eb{\bold{E}^d_\mathbb{C}} \def\nb{\mathbb{N}} \def\nbs{\mathbb{N}^\star$
associated with the locally free sheaf $(\rc^df_\star\mathbb{C}} \def\nb{\mathbb{N}} \def\nbs{\mathbb{N}^\star)\otimes\mathcal{O}} \def\oce{\mathcal{O}_E} \def\xc{\mathcal{X}_B$
endowed with the flat holomorphic connection~$\nabla~:\bold{H}} \def\fb{\bold{F}} \def\eb{\bold{E}^d_\mathbb{C}} \def\nb{\mathbb{N}} \def\nbs{\mathbb{N}^\star\lra
\Omega^1_B\otimes\bold{H}} \def\fb{\bold{F}} \def\eb{\bold{E}^d_\mathbb{C}} \def\nb{\mathbb{N}} \def\nbs{\mathbb{N}^\star$, the Gauss-Manin connection.  By
semi-continuity and Hodge decomposition, the vector spaces
$H^{p,d-p}(Y_b,\mathbb{C}} \def\nb{\mathbb{N}} \def\nbs{\mathbb{N}^\star)$ ($b\in B$) have constant dimension. By elliptic
theory they hence form a differentiable sub-bundle $\bold{H}} \def\fb{\bold{F}} \def\eb{\bold{E}^{p,d-p}$ of
$\bold{H}} \def\fb{\bold{F}} \def\eb{\bold{E}^d_\mathbb{C}} \def\nb{\mathbb{N}} \def\nbs{\mathbb{N}^\star$.  Denote by $\fb^p$ the differentiable sub-bundle $\oplus
_{i\geq p} \bold{H}} \def\fb{\bold{F}} \def\eb{\bold{E}^{i,d-i}$ of $\bold{H}} \def\fb{\bold{F}} \def\eb{\bold{E}^d_\mathbb{C}} \def\nb{\mathbb{N}} \def\nbs{\mathbb{N}^\star$.  By a theorem of Griffiths,
the $\fb^p$ have natural structure of holomorphic sub-vector bundles
of $\bold{H}} \def\fb{\bold{F}} \def\eb{\bold{E}^d_\mathbb{C}} \def\nb{\mathbb{N}} \def\nbs{\mathbb{N}^\star$.  A relative Dolbeault theorem identifies $\eb^p:=
\fb^p/\fb^{p+1}$ with the holomorphic vector bundle associated with
the locally free sheaf $\rc^{d-p}f_\star\Omega_{Y/B}^p$.

We now recall the construction of the Hodge metric on the primitive
part of $\eb^p$. We fix a family $\eta_b$ ($b\in B$) of polarizations
given by a section of $\rc^2f_\star \mathbb{Z}$ (e.g.\ the family of Chern
classes $c_1(L_{|Y_b})$ for an ample line bundle $L$ on $Y$).  By the
hard Lefschetz theorem, the bilinear form on the fibers of $\bold{H}} \def\fb{\bold{F}} \def\eb{\bold{E}^d_\mathbb{C}} \def\nb{\mathbb{N}} \def\nbs{\mathbb{N}^\star$
given by
$$S(c_1,c_2):=(-1)^{\frac{d(d-1)}{2}}\int_{Y_b}\eta_b^{r-d}\wedge
c_1\wedge c_2$$ is non-degenerate. We define the primitive cohomology
to be $\bold{P}^d:=Ker (\eta^{r-d+1}~: \bold{H}} \def\fb{\bold{F}} \def\eb{\bold{E}^d \lra \bold{H}} \def\fb{\bold{F}} \def\eb{\bold{E}^{2r-d+2})$, which is
also a differentiable sub-bundle of $\bold{H}} \def\fb{\bold{F}} \def\eb{\bold{E}^d$.  By the Hodge-Riemann
bilinear relations, the differentiable sub-bundles $\bold{H}} \def\fb{\bold{F}} \def\eb{\bold{E}^{p,d-p}$ and
$\bold{H}} \def\fb{\bold{F}} \def\eb{\bold{E}^{p',d-p'}$ are orthogonal unless $p+p'=d$ and
$$h(c):=(\sqrt{-1})^{p-q} S(c,\overline{c})$$ defines a positive
definite metric on $\bold{H}} \def\fb{\bold{F}} \def\eb{\bold{E}_{prim}^{p,d-p}:=\bold{H}} \def\fb{\bold{F}} \def\eb{\bold{E}^{p,d-p}\cap \bold{P}^d$. We
set $\fb^p_{prim}:=\fb^p\cap \bold{P}^d$. Those bundle also have natural
holomorphic structures.  We also set
$\eb^p_{prim}:=\fb^p_{prim}/\fb^{p+1}_{prim}$.  The fiber-wise
isomorphism of $(\eb^p_{prim})_b$ with
$H_{prim}^{p,d-p}(Y_b,\mathbb{C}} \def\nb{\mathbb{N}} \def\nbs{\mathbb{N}^\star)\subset H^d(Y_b,\mathbb{C}} \def\nb{\mathbb{N}} \def\nbs{\mathbb{N}^\star)$ enables to equip the
holomorphic vector bundle $\eb_{prim}^p$ with a smooth positive
definite hermitian metric, called the Hodge metric.

We need some definitions in order to express the curvature of the
corresponding Chern connection.  First recall the transversality
property of the Gauss-Manin connection $\nabla
\fb^p\subset\Omega^1_B\otimes \fb^{p-1}$ which accounts for the
Cartan-Lie formula of the derivative of a family of cohomology classes
(see~\cite[proposition 9.14]{vo}).  Denote by
$\overline{\nabla}} \def\n{|\!|} \def\spec{\textrm{Spec}\,^p~:\eb^p\lra\Omega^1_B\otimes\eb^{p-1}$ the $\mathcal{O}} \def\oce{\mathcal{O}_E} \def\xc{\mathcal{X}_B$-linear map
built by first lifting to $\fb^p$ applying the Gauss-Manin connection
and projecting to $\eb^{p-1}$.  The second fundamental form in
$\mathcal{C}_\infty} \def\d{\partial^{1,0}(B,Hom(\fb^p, \bold{H}} \def\fb{\bold{F}} \def\eb{\bold{E}^d_\mathbb{C}} \def\nb{\mathbb{N}} \def\nbs{\mathbb{N}^\star/\fb^p))$ of the sequence
$$ 0 \lra \fb^p \lra \bold{H}} \def\fb{\bold{F}} \def\eb{\bold{E}^d_\mathbb{C}} \def\nb{\mathbb{N}} \def\nbs{\mathbb{N}^\star \lra \bold{H}} \def\fb{\bold{F}} \def\eb{\bold{E}^d_\mathbb{C}} \def\nb{\mathbb{N}} \def\nbs{\mathbb{N}^\star/\fb^p \lra 0
$$ with respect to the Gauss-Manin connection (or equivalently with
the flat metric on $\bold{H}} \def\fb{\bold{F}} \def\eb{\bold{E}^d_\mathbb{C}} \def\nb{\mathbb{N}} \def\nbs{\mathbb{N}^\star$) actually induces
$\overline{\nabla}} \def\n{|\!|} \def\spec{\textrm{Spec}\,^p~:\eb^p\lra\Omega^1_B\otimes\eb^{p-1}$.  Formulas for the
curvature of quotient hermitian holomorphic vector bundles then lead
to

\begin{thm} \label{Gr1} \cite[theorem 5.2]{gr}\,
The curvature $\Theta (\eb_{prim}^p)$ of the holomorphic vector
bundle~$\eb_{prim}^p$ endowed with its Hodge metric is given by
\begin{eqnarray*}
\langle \Theta (\eb_{prim}^p)(V,\overline{V})\sigma,\sigma
\rangle_{Hodge} = \langle \overline{\nabla}} \def\n{|\!|} \def\spec{\textrm{Spec}\,^p_V \sigma, \overline{\nabla}} \def\n{|\!|} \def\spec{\textrm{Spec}\,^p_V \sigma
\rangle_{Hodge} -\langle(\overline{\nabla}} \def\n{|\!|} \def\spec{\textrm{Spec}\,^{p+1}_V)^\star
\sigma,(\overline{\nabla}} \def\n{|\!|} \def\spec{\textrm{Spec}\,^{p+1}_V)^\star \sigma \rangle_{Hodge}
\end{eqnarray*}
where $V$ is a local vector field on $B$ and $\sigma$ a local section
of $\eb^p$.
\end{thm}

We now apply this result in the case of the family of the cyclic
covers $\phi\circ p_s~: {\tly_s} \lra X$ obtained by taking the $k$-th
root of a section $s$ of $L^k$ transverse to the zero section as in \S
~\ref{sec2}.  We have to restrict the study over Zariski open sets
outside the discriminant locus $\Sigma_s$ of $\phi\circ p_s$. It is
the set of $x\in X$ where $s_{|Y_x }\in \Gamma (Y_x , L^k)$ is not
transverse to the zero section. We set $X^0:=X-\Sigma_s$ and
$\tly_s^0:=(\phi\circ p_s)^{-1}(X-\Sigma_s)$ so that $\phi\circ p~: {\tly_s^0}
\lra X^0$ becomes a smooth family.  Then, since $\overline{\nabla}} \def\n{|\!|} \def\spec{\textrm{Spec}\,^0$ vanishes, the
above theorem implies the following

\begin{cor} \label{Gr2}
The vector bundle $\eb^0_{prim}=\eb^0=\rc^{r} (\phi\circ
p_s)_\star\mathcal{O}} \def\oce{\mathcal{O}_E} \def\xc{\mathcal{X}_{\tly_s^0/X^0}= \oplus_{i=0}^{k-1}\rc ^{r} \phi_\star
\left( L^{-i}\right)$ with the Hodge metric is
Griffiths (actually even Nakano) semi-negative.
\end{cor}

\subsection{Singularities of the Hodge metric}

We now deal with the general case, namely $f : Y \lra B$ may not be
smooth.  We first recall the method of Fujita~\cite{fu}. We therefore
assume that the base $B$ is one dimensional.

The Hodge metric on the direct image of the relative canonical sheaf
is described as follows.  Let $b \in B$ be a point and let $(U, t)$ be
a local coordinate centered at $b = \{t= 0\}$.  A section $\om \in
\Gamma (U, f_\star K_{Y/B})$ -- when regarded as a section in $\Gamma
(U, f_\star Hom (f^\star K_B, K_Y))$ and applied to $f^\star dt$ --
gives a section of $K_Y$ on $f^{-1}(U)$ which we denote by $\om \cdot
dt$.  If $\varphi_b\in\Gamma (Y_b,K_{Y_b})$ fulfills the relation $\om
\cdot dt=\varphi_b\wedge f^\star dt$ over $Y_b$ (which amounts to
saying that in the differentiable trivialization $Y_{|U}\simeq
Y_b\times U$, the section $\om$ is sent to $\varphi_b$), then the
Hodge norm at $b \in B$ of the section $\om$ is
$$ \n \om \n^2_{Hodge} = (\sqrt{-1})^n (-1)^{\frac{n(n-1)}{2}}
        \int_{Y_b}\varphi_b\wedge\overline{\varphi_b},
$$ here $n = \dim Y -1$.  Fujita checked that in this setting in case
$\dim B =1$ the Hodge metric on $f_\star K_{Y/B}$ is bounded from
below by a positive quantity and hence that the only possible
singularities of the Hodge metric on $f_\star K_{Y/B}$ are poles
(see~\cite[lemma 1.12]{fu}).

We just give the typical example which occurs for a local model of our
cyclic covers (for some positive integer $m$).
$$
\begin{array}{ccccc}
\tly_s = \{(t,z,l)\in\mathbb{C}} \def\nb{\mathbb{N}} \def\nbs{\mathbb{N}^\star^3 / l^k=t+z^m\} & \stackrel{p_s}\lra &
        Y&\stackrel{\phi}\lra&X = \{ t \in \mathbb{C}} \def\nb{\mathbb{N}} \def\nbs{\mathbb{N}^\star \}\\ (t,z,l) &
        \mapsto&(t,z) & \mapsto & t
\end{array}
$$
The cotangent bundle $\Omega^1_{Y_s}$ is generated by $dt, dz, dl$
subject to the relation $kl^{k-1}dl-dt-mz^{m-1}dz=0$.  If $\om \cdot
dt$ is written as $\eta(z,l) dz\wedge dl$ for a holomorphic function
$\eta(z,l)$, then $\varphi_0$ may be chosen to be $\varphi_0 = k^{-1}
l^{1-k} \eta(z,l) dz$ with a pole of order $k-1$ on the fiber over
$t=0$ and no singularities elsewhere.

We can now go back to the proof of our main lemma.
\begin{proof}[Proof of lemma~\ref{mainlemma}]
Let $f~:~Z^{n+r}\lra X^n$ be a proper K{\"a}hler surjective map between
two complex manifolds of relative dimension $r$.  Let
$z=(z_1,z_2,\cdots, z_{n+r})$ and $x=(x_1,x_2,\cdots,x_n)$ be local
holomorphic coordinates on $Z$ and $X$ around $z_0$ and $x_0:=f(z_0)$.
The map $f$ is locally given by $(f_i(z))_{1\leq i\leq n}$. Let
$\Psi\in f_\star (K_{Z/X})$ and write
\begin{eqnarray*}
\Psi\cdot f^\star (dx_1\wedge dx_2\wedge\cdots\wedge dx_n) &=&\psi
dz_1\wedge dz_2\wedge\cdots\wedge dz_{n+r}\\ &=&\psi \det\left(
\frac{\d f_i}{\d z_j}\right)_{1\leq i\leq n\atop 1\leq j\leq n}
^{-1}f^\star (dx_1\wedge dx_2\wedge\cdots\wedge dx_n) \wedge
dz_{n+1}\wedge\cdots\wedge dz_{n+r}
\end{eqnarray*}
the Hodge norm of $\Psi$ is hence
\begin{eqnarray}\label{hodge.metric}
\n \Psi\n_{Hodge}^2=\int_{Z_x} |\psi|^2 \left|\det\left( \frac{\d
f_i}{\d z_j}\right) _{1\leq i\leq n\atop 1\leq j\leq n}\right|^{-2}
(\sqrt{-1})^r dz_{n+1}\wedge d\overline{z_{n+1}}\cdots\wedge dz_{n+r}
\wedge d\overline{z_{n+r}}.
\end{eqnarray}
The Hodge metric can hence only acquire poles, located furthermore
over the discriminant locus of $f$.  If now $\Psi$ belongs to $f_\star
(Jac_f\otimes K_{Z/X})$ then $\psi$ is a combination $\displaystyle
\psi=\sum
\psi_J\det\left( \frac{\d f_i}{\d z_j}\right)_{1\leq i\leq n\atop j\in
  J}$,
where the sum is taken over all multi-indexes $J \subset \{ 1,2,\cdots
, n+r\}$ of length $|J| =n$, manely $J = \{j_1, j_2, \ldots, j_n\}$
with $ 1 \leq j_1 < j_2 < \ldots < j_n \leq n+r$.  It follows that
$$ \Psi \cdot f^\star (dx_1\wedge dx_2\wedge\cdots\wedge dx_n)
=f^\star (dx_1\wedge dx_2\wedge\cdots\wedge dx_n)\wedge \bigg(\sum
\psi_J dz_{m_1}\wedge \cdots\wedge dz_{m_r}\bigg).
$$ Here the last sum is taken over all multi-indexes $J \subset \{
1,2,\cdots , n+r\}$ of $|J| =n$, and $\{m_1, \ldots, m_r\} = \{
1,2,\cdots , n+r\} \setminus J$.
\end{proof}

In our setting, we take a global section $s$ of $L^k$ transverse to
the zero section and consider the corresponding cyclic cover $\tly_s$
of $Y$. Note that if the section $s$ is locally given by $\sigma
(x_1,x_2,\cdots, x_n,y_1,y_2,\cdots,y_r)$ and the map $\phi$ by
$(x_1,x_2,\cdots, x_n, y_1,y_2,\cdots,y_r)\mapsto (x_1,x_2,\cdots,
x_n)$, then there is an $j$ such that $\displaystyle \frac{\d s}{\d
y_j}(p_0)\not =0$ and the functions $(x_1,x_2,\cdots,x_n,
y_1,y_2,\cdots, y_{j-1},t,y_{j+1},\cdots,y_r)$ can be chosen as
coordinates on $\tly_s$ near $y_0\in p_s^{-1}(y_0)$, or there is an
$i$ such that $\displaystyle\frac{\d s}{\d x_i}(p_0)\not =0$ and the
coordinates on $\tly_s$ near $y_0$ can be chosen to be
$(x_1,x_2,\cdots x_{i-1},t,x_{i+1},\cdots ,x_n,y_1,y_2, \cdots ,
y_r)$.  In the first case, $\phi\circ p_s$ is a submersion at $y_0$
and its Jacobian ideal is $\mathcal{O}} \def\oce{\mathcal{O}_E} \def\xc{\mathcal{X}_{\tly_s}$ at $y_0$. In the second case
the Jacobian ideal contains
\begin{eqnarray}\label{sing}
\frac{\d x_i}{\d t}=\frac{\d s}{\d t} \left( \frac{\d s}{\d
x_i}\right)^{-1}\sim t^{k-1}.
\end{eqnarray} In
any case it contains $\displaystyle p_s^\star \mathcal{O}} \def\oce{\mathcal{O}_E} \def\xc{\mathcal{X}
(-\frac{k-1}{k}D_s)$.  This has to be compared with the formula
$K_{Y_s/Y}=p_s^\star ((k-1)L)$.
\section{Proof of Theorems}

\begin{proof}[Proof of Theorem~\ref{semi-ample}]
Let $\phi~:~Y\lra X$ be a projective submersion of relative dimension
$r$ between two complex manifolds and $L$ be a semi-ample line bundle
on $Y$.  Note that the relative projectivity condition is only used to
ensure the local freeness of $\phi_\star(K_{Y/X}\otimes L)$.

We take a positive integer $k$ so that $L^k$ is generated by its
global sections. Take a global section $s$ of $L^k$ transverse to the
zero section and consider the corresponding cyclic cover $\tly_s$ of
$Y$.
We have seen that the Hodge metric on $\rc^r (\phi\circ p_s)_\star
\mathcal{O}} \def\oce{\mathcal{O}_E} \def\xc{\mathcal{X}_{\tly_s}$ is smooth (as a Hodge metric on a smooth family)
non-degenerate and semi-negatively curved outside the discriminant
locus $\Sigma_{s_\alpha}$, is continuous on $X$, and may acquire zeros
at the points $x$ over which the section $s_{|\mathbb{P}} \def\pbe{\mathbb{P}(E)} \def\rb{\mathbb{R} (E_x)}$ is
identically zero.  We now explain how the semi-ampleness assumption on
the line bundle $L$ helps to remove those singularities of the Hodge
metric.

When $L$ is semi-ample, $D\in |L^k|$ moves.  We choose $n+r+1$ generic
sections $s_\alpha$ that generate $L^k$.  The metric $h=\sum_{\alpha =
1}^{n+r+1} h_\alpha$ on $\rc^r \phi_\star ( L^{-1})\subset \rc^r
(\phi\circ p_s)_\star \mathcal{O}} \def\oce{\mathcal{O}_E} \def\xc{\mathcal{X}_{\tly_s}$ is continuous on $X$, smooth
outside $\Sigma_h:=\cup_\alpha \Sigma_{s_\alpha}$ and without zeros.

Next let us discuss its curvature property.  Recall the formula
\begin{eqnarray}
\label{formule}
\frac{\langle\Theta (E,h)\xi,\xi\rangle}{\n \xi\n ^2} &=&
-\sqrt{-1}\d\!\overline{\partial}\log\n \xi\n ^2 +\frac{\langle \nabla_{E,h}
\xi,\nabla_{E,h} \xi\rangle}{\n \xi\n ^2} -\frac{\sqrt{-1}\d \n \xi\n
^2\wedge\overline{\partial}\n \xi\n ^2}{\n \xi\n ^4}\\ \nonumber &\geq&
-\sqrt{-1}\d\!\overline{\partial}\log\n \xi\n ^2
\end{eqnarray}
for a nowhere zero local holomorphic section $\xi$ of a holomorphic
vector bundle $E$ equipped with a smooth hermitian metric $h$. The
last two terms give the norm at $x$ of the fundamental form of the
inclusion $\mathcal{O}} \def\oce{\mathcal{O}_E} \def\xc{\mathcal{X}_X \xi\subset E$.  Take a point $x_0$ in $X-\Sigma_h$, a
non-zero vector $\xi_0 \in \rc^r \phi_\star ( L^{-1})_{x_0}^\star$,
and a nowhere zero local holomorphic section $\xi\in\Gamma (U,\rc^r
\phi_\star ( L^{-1}))$ achieving the value $\xi_0$ at $x_0$ and normal
at $x_0$ for the metric $h$ (i.e. $\nabla_h \xi(x_0)=0$).  Then, the
last two terms in the formula~(\ref{formule}) vanish at $x_0$.
The corollary~\ref{Gr2} now asserts the function
$\log\n\xi\n_{h_\alpha} ^2$ -- whose complex Hessian (or Levi form) is
the opposite of the curvature of a line sub-bundle of $\rc^r
\phi_\star ( L^{-1})$ -- is plurisubharmonic on $U$.  It then follows
that $\log\n \xi\n^2_h = \log(\sum_\alpha \n\xi\n_{h_\alpha} ^2)$ is
plurisubharmonic also on $U$. This gives the Griffiths semi-negativity
of $\rc^r \phi_\star ( L^{-1})$ on $X -\Sigma_h$.  Since $h$ is
continuous and $\Sigma_h$ is an analytic subset (of zero Lebesgue
measure), we can conclude that the continuous metric $h$ on $\rc^r
\phi_\star ( L^{-1})$ is Griffiths semi-negative on the whole of $X$.
\end{proof}

\begin{proof}[Proof of Theorem~\ref{ample}]
We now assume that $L$ is ample. Here, the ampleness assumption
ensures the vanishing of $\mathcal{R}^{1}\phi_\star(K_{Y/X}\otimes L)$
which in turn easily ensures the local freeness of
$\phi_\star(K_{Y/X}\otimes L)$.

Let us recall Legendre-type formula applied for a metric $h =
\sum_{\alpha = 1}^\ell h_\alpha $ on $\rc^r \phi_\star ( L^{-1})$
gotten from different cyclic coverings $Y_{s_\alpha}$ (for a
$(1,0)$-form $u$, $|u|^2$ denotes $\sqrt{-1}u\wedge\overline{u}$)~:
$$ \sqrt{-1}\d\!\overline{\partial} \log(\sum_\alpha \n \xi\n_{h_\alpha} ^2) =
\frac{\sum_\alpha \n \xi\n_{h_\alpha} ^2 \sqrt{-1}\d\!\overline{\partial}\log\n
\xi\n_{h_\alpha} ^2} {\sum_\alpha \n \xi\n_{h_\alpha} ^2} +
\frac{\sum_{\alpha<\beta} \left|\d\log\n \xi\n_{h_\alpha} ^2 -
\d\log\n \xi\n_{h_\beta} ^2\right|^2 \n \xi\n_{h_\alpha}^2\n
\xi\n_{h_\beta}^2} {(\sum_\alpha \n \xi\n_{h_\alpha} ^2)^2}.
$$ Applying Griffiths curvature formula (Corollary~\ref{Gr2}) for
individual covering and the formula (\ref{formule}) for a line
sub-bundle we infer that in the right hand side, the first term is
semi-positive.  We need to add further Hodge metrics $h_\alpha$ to
make the second term -- hence the left hand side -- strictly positive.

The explicit expression in formula~(\ref{hodge.metric})
and~(\ref{sing}) will help to translate the algebraic ampleness
assumption on $L$ into a negativity property for a well chosen metric
on $\rc^r \phi_\star ( L^{-1})$.  Hence, we have for $\Psi \in
(\phi\circ p_s)_\star (K_{Y_s/Y})$
\begin{eqnarray*}
\d\log h_s(\Psi) &=& \d\log\int_{(\phi\circ p_s)^{-1}(x)} |\psi|^2
 \left|\left( \frac{\d s}{\d t} \right)^{-1} \frac{\d s}{\d
 x_i}\right|^{2} (\sqrt{-1})^r dz_{n+1}\wedge
 d\overline{z_{n+1}}\cdots\wedge dz_{n+r} \wedge d\overline{z_{n+r}}\\
 &=&\d\log\int_{Y_x } |\psi|^2 |s|^{-2k+2} \left|\frac{1}{k}\frac{\d
 s}{\d x_i}\right|^{2} (\sqrt{-1})^r dz_{n+1}\wedge
 d\overline{z_{n+1}}\cdots\wedge dz_{n+r} \wedge d\overline{z_{n+r}}
\end{eqnarray*}
We now take a positive integer~$k$ so large that the map
\begin{eqnarray*}
H^0(Y,L^k)&\lra&
H^0\left(Y,L^k\otimes\phi^\star(\mathcal{O}} \def\oce{\mathcal{O}_E} \def\xc{\mathcal{X}_X/\mc^3_{x})\right)
\end{eqnarray*}
is surjective for every $x \in X$.  By the compactness of $Y$, we can
henceforth choose enough, but a finite number of sections $s_\alpha
\in H^0(Y,L^k)$ to ensure positivity in all the directions in the
Legendre formula. This gives continuous hermitian metrics on
$\phi_\star(K_{Y/X}\otimes L)$ with Griffiths positive
curvature. Using a regularization process as described in~\cite{mo}
these metrics may be smoothed keeping Griffiths positivity of the
curvature.
\end{proof}

\begin{rem}
Griffiths \cite[proposition 2.16]{gr} showed that the operator
$\overline{\nabla}} \def\n{|\!|} \def\spec{\textrm{Spec}\,^p~:\eb^p\lra\Omega^1_B\otimes\eb^{p-1}$ can be expressed as a
cup product with the Kodaira-Spencer class $\rho\in
\Omega^1_{B,b}\otimes H^1(Y_b,TY_b)$ of the family $f : Y \lra B$
coupled with a natural pairing.  In our setting, this in turn can be
related with the infinitesimal displacement of the hypersurfaces
$D_{s,x}$ of $Y_x $ given by the vanishing of the section $s_{|Y_x }$,
namely (see~\cite[chapter 5.2 (c)]{kodaira})
$$\begin{array}{cccccc} TX&\lra&H^0(D_{s,x}, \mathcal{O}} \def\oce{\mathcal{O}_E} \def\xc{\mathcal{X}
(D_{s,x})_{|D_{s,x}})&\Big( \stackrel{\delta^\star}\lra &H^1(D_{s,x},
TD_{s,x})&\Big)\\ v&\mapsto& (\partial_{\widetilde{v}}
s)_{|D_{s,x}}&\Big(\mapsto&\rho (v)&\Big)
\end{array}$$
where $\widetilde{v}$ is a holomorphic vector field lifting $v$ on
$Y_x$. The map $\delta^\star$ is the co-boundary map in the long exact
sequence associated with the short exact sequence for the normal
bundle of the divisor $D_{s,x}$
$$0\lra TD_{s,x}\lra (TY_x)_{|D_{s,x}}\lra \mathcal{O}} \def\oce{\mathcal{O}_E} \def\xc{\mathcal{X}
(D_{s,x})_{|D_{s,x}}\lra 0.$$ Our computations make explicit the idea
that $L$ being ample, the sections $s_{|Y_x}$ move sufficiently to
make the operator $\overline{\nabla}} \def\n{|\!|} \def\spec{\textrm{Spec}\,^p~:\eb^p\lra \Omega^1_B\otimes\eb^{p-1}$ have
non-zero contribution in the curvature formula.
\end{rem}

redpajama_set_name: RedPajamaArXiv


text:
Tag Archives: Younus Khan
Yasir gives Pakistan control after Misbah 99 not out
KINGSTON: A brilliant spell by Yasir Shah late on day four has given Pakistan control of the first Test against West Indies in Kingston. Yasir (4-33) dominated before stumps on Monday as the Windies were reduced to 93-4 in their second innings, still trailing by 28 runs. Opener Kieran Powell ...
'Unique' Younus eyes final Test milestone
KARACHI: When Younus Khan hangs up his bat at the end of Pakistan's tour of the West Indies, it will likely be with a final Test milestone against his name. Younus is just 23 runs away from becoming the first Pakistan player to score 10,000 Test runs. With the first ...
Former ICC president all praise for Pakistan team
LONDON: Former International Cricket Council (ICC) president Zaheer Abbas lauded Pakistan cricket team for winning the ODI series against West Indies and hoped they will do well in the Test series and win it for Misbah. Zaheer said: "One must understand a simple fact before unleashing unwanted and uncalled for ...
Bright chances of winning ODI, Test series: Mushtaq
LAHORE – National Cricket Academy (NCA) head coach Mushtaq Ahmad has said that Pakistan's chances of winning ODI and Test series against the West Indies are quite bright. Talking to the reporters here at the Gaddafi Stadium on Wednesday, Mushtaq said: "I am quite confident that after giving excellent performances ...
If given chance, I'll deliver: Shahzad
ISLAMABAD: Opening batsman Ahmad Shahzad is optimistic about his return to the national team and vows if given chance, he will deliver. Shahzad said: "I am keeping eyes on West Indies matches, let's see if given chance, I will prove my worth and play leading role in helping my team ...


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Home › TIME Magazine The Science of Creativity
TIME Magazine The Science of Creativity
Creativity is one of the most human of qualities. But what is creativity, and what makes us creative? The Science of Creativity takes a look at both the science and the art of this world-changing trait—how we define it, how we measure it and what encourages it. With insights from the editors of TIME, this new Special Edition features thought-provoking articles on the meaning of creativity, its part in human history and its role in our future. Four distinct sections—"The Creative Animal," "The Creative Mind," "Creativity in Action" and "Creativity at Any Age"—are filled with clear explanations of scientific theory, insights into human psychology and tips on learning and parenting to encourage creativity in our children and ourselves.
With dozens of illuminating full-color photos, illustrations and infographics, this Special Edition is a must-have for anyone who wants to understand the human mind and its capacity for ideas and connections. Please note that this product is an authorized edition published by Meredith Corporation. This edition is printed using a high quality matte interior paper and printed on demand for immediate fulfillment.
Fitness Gurls Swimsuit Issue Winter 2020
Esquire Magazine Winter 2021 - BTS
Time Magazine March 30, 2020 Coronavirus
Esquire Magazine (Winter, 2020) The Michael B. Jordan Story
ROLLING STONE MAGAZINE MAY 2020 ANDREW CUOMO


that will help the U.S. oil and gas producer accelerate drilling.
today by the Denver-based oil company.
Market. The gain was Delta's biggest since October 2002.
Roger Parker said today on a conference call with investors.
gas equivalent. Its 2007 drilling budget was $250 million.
will total about $64 million.
sales,'' Parker said on the conference call.
expanded to accommodate Kerkorian's nominees.
Tesoro without paying a premium for all of its shares.
provisions of the rights plan,'' Tracinda said in a Nov. 27 statement.
with Renault SA and Nissan Motor Co. failed.
Kerkorian Seeking 9% Stake in G.M.


text:
Q: ADF: Table contains comma and I want to output using delimiter text I need some help with using delimited text as a sink. I have a SQL table and one of the columns contains a comma. However, I want to export the data as a delimited text file using comma as column delimiter.
In my source I am using an inline linked service to my database. Then in my source options I have added my select query statement to select the required data.
I do not want any of the data to have double quotes or any other characters. I can't seem to find a way around this problem. Can anyone help?
Database table example:
Name Age Address
Tom  10  100 London Road, London UK
Expected delimited file:
Tom,10,100 London Road, London UK
Current output:
Tom,10,100 London Road~,London UK

A: I am able to achieve your expected output using DataFlow activity.
Step1: Select DataFlow activity

Step2:
Below is Source SQL Table

Add SQL as Source.

Step3: Use Select activity for mapping.

Step4: Use Sink as CSV file.

Expected Output:

Edit - My Sink Configuration


Calls from an influential group of MPs for cigarette-style health warnings to be introduced on alcohol packaging to warn people about the health risks, are being welcomed by Swanswell.
The national recovery charity, which wants to achieve a society free from problem alcohol and drug use, is responding to a host of recommendations made by the All-Party Parliamentary Group (APPG) on Alcohol Misuse, as part of their 2015 Manifesto.
MPs from the APPG are calling on political parties to commit to ten measures to effectively minimise alcohol-related harm in the UK, which costs the economy around £21 billion a year to deal with.
The group has said clear health warnings should be placed on drinks labels to highlight the risks of alcohol, similar to those on cigarette packets that warn about the risk of cancer and other related problems.
Calls to introduce alcohol minimum unit pricing, strengthen marketing regulations to protect children and young people, and for an increase in funding for treatment are also among the recommendations being welcomed by Swanswell.
In addition, MPs have asked for public health to be introduced as a fifth licensing objective to help local authorities make licensing decisions, based on the local population's health need and the density of existing outlets that sell alcohol.
Swanswell has been a regular guest at the APPG on Alcohol Misuse this year and is pleased with the widespread recommendations included in the 2015 Manifesto.
Debbie Bannigan, Swanswell's Chief Executive, said: 'Education is key to helping people make informed choices about their relationship with alcohol, so we welcome calls for clear and more prominent health warnings on labels.
'Other measures suggested by the APPG, including introducing minimum unit pricing and increased funding for treatment, will also make a big difference to the lives of millions of people drinking at harmful levels, so we hope politicians will take this seriously.
The APPG has also asked for a reduction in the drink-drive limit in England and Wales – from 80mg per 100ml of blood to 50mg/100ml of blood, in line with the rest of Europe, starting with drivers under 21.
In September and October, Swanswell will be raising awareness of the consequences of drink-driving, particularly the morning after, while it's at the Labour, Conservative and Liberal Democrats fringe events. It'll debate a solution to end deaths linked to drink-driving.


assignment, which contains a specific response of the writer to the main essay prompts question(s) or an analysis of the specific argument. There are more things to explore to answer, What is a thematic essay? In this article, the student can find all answers to the questions regarding this type of academic essay writing along with the helpful hints and great topic ideas. It gets complicated as a good thesis statement must be concise (a single-sentence statement and thematic essay requires a plenty of points. How to make essay writing easy drawings research paper intro paragraph journal wade edwards essay writing cognitive psychology memory language and thought essay harvard llm application essay jan 2010 global regents thematic essay how to write a short essay for college board 4 paragraph essay. Ancient Rome - Part 4 - Mr Ott's Classroom Wiki Ancient Rome - Part.
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In a soft, lilting accent very unlike Wysocki's tough tones, Clarke talks about his time filming CODE in Chicago, including some startling incidents that he observed while doing research, accompanying real Chicago cops on their rounds. [Editor's Note: This interview took place before the recent announcement of the show's cancellation].
ASSIGNMENT X: In BROTHERHOOD, your character Tommy Caffee was a politician who had a brother in the local mob. In CHICAGO CODE, your Chicago Police Detective Wysocki is trying to bring down a politician with ties to organized crime. Did you have any thoughts about ways in which the two shows share some of the same themes?
JASON CLARKE: Yeah. I mean, I didn't really sit down and think about it – you think about other things in terms of whether you're going to commit to a series, but this is action-based, whereas with Tommy Caffee, he was totally aware of his moral problems, and that was part of who he was. With Wysocki, his moral problem is somebody else's decision. He reminded me of Gary Cooper in HIGH NOON – the bad guy was coming to town and he was just going to go out and meet him on his own and that's why I love the character. I think it's almost a throwback to the classic Gary Cooper/John Wayne, let's just move [and fight] and may the best man win and then everything else that comes into it is your opinion. It's the audience [coming to moral conclusions], rather than the character.
AX: Do you feel like Delroy Lindo's Alderman Gibbons character is at all similar to your Tommy?
CLARKE: [Lindo] is playing a politician. [Gibbons] is not as morally troubled by [his own actions as Tommy was]. I guess he's a better politician into older age, because he's made a decision and he still knows that he does do good. But it's funny, because Rhode Island was such a small town that everybody knew everybody, everybody knows everybody. So you get access, then, to everybody within that state. And you've got to give everybody access, otherwise, they won't vote for you. In Chicago, even though it's a massive city, it's still open enough for us to shoot wherever we want to shoot, even with the politicians that are there, and [Gibbons has] set up camp there, he knows his constituents. The police are much more open, and friendly, but you can see how it has become this city that works. It works, but it works as [Gibbons] says in a number of different ways.
AX: The people on SOUTHLAND have said that one of the differences between L.A. and New York is, in Los Angeles, there are ten thousand cops for a city of six million, whereas in New York, they've got forty thousand cops and fewer people. Does Chicago fall somewhere within those ratios?
CLARKE: Yes, but it's also a difference in the attitudes of the cops, I think, as well. New York's so massive – it's New York, it's one of the biggest cities in the world. In L.A. I find the police much more distant here as well, whereas I guess in Chicago, I've found them much more open, much more [does Chicago accent], "Yo, buddy, what's goin' on, huh?" [back to Australian accent] That's their style. There's a style in policing, I think and the Chicago style is a much more in your face, open style.
AX: What are Australian cops like?
CLARKE: A mix between New York and L.A. They're very distant [laughs]. They're busy handing out speeding fines. In Chicago, they've got their hands full dealing with crime. They really do. There isn't as much booking people for the wrong speed on the road, because they've got proper things to solve.
AX: What are some of the questions you had for CHICAGO CODE's police advisor John Folino?
CLARKE: You go through your basics, you know, where you were and how'd you get here, just your graph of [things] like, what are your hours? And we talked a lot, but basically, John showed me. I mean, I went on thirty ride-alongs. There were people [at the police officers] on our ride-alongs. It's the same thing with them taking me out and putting me on a search warrant. I went on a search warrant and that would lead to see it and experience it, rather than just kind of hear it. I mean, I'd ask John how do you hold a gun, how do you do this, how do you clear a room? It's the big things, but it's also the small things, it's always the small things. You just hang out with the dudes.
AX: Was there anything that really surprised you in the ride-alongs?
CLARKE: Always. Always. In any crisis situation – I mean, I saw people shot, I saw people dying. We were in a house with guns everywhere. But I'm always surprised at the police officers' ability to deal with pressure and how they react to it and how they're generous within it. I spent a lot of time hanging out with John.
AX: Anything else you'd like to say about THE CHICAGO CODE?
CLARKE: We [the cast and crew] had a lot of fun and I had a lot of fun. Cops that I know have a lot of fun in their job, and if you don't, you get out of the way, and. I think you'll see that in the show, that they really enjoy kicking the door in.
Let us know what you think – leave your comment below.


Contemporary clocks do far more than just tell the time. These are unique, stylish and often even ironic time telling pieces. Many of the wall clocks in the Bonluxat collection are often designed to bring a smile or laugh to the onlooker. These modern clocks offer beauty, poetry and allusions. Some of these pieces are more than just decorative clocks; they also fill some sort of dual purpose. Often our collection of contemporary clocks even offers us a profound statement about the nature of time itself.


Europrop International GmbH (EPI) is consisting of a European Collaboration Programme between the four European engine manufacturers (ITP, MTU Aero Engines, Rolls-Royce and Safran Aircraft Engines) to develop and produce the TP400 turboprop engine.
Based in Munich, EPI manages the TP400 engine programme produced to power the Airbus A400M Military Transport, built by Airbus Defence and Space.
The TP400-D6 is the most powerful engine in production.


text:
Ridiculous rule: Gambhir on WC final being decided on boundaries
short by Anmol Sharma / 10:45 pm on 15 Jul 2019,Monday
Reacting to England defeating New Zealand in the 2019 World Cup final on the virtue of scoring more boundaries after tied match and tied Super Over, ex-India cricketer Gautam Gambhir tweeted, "A ridiculous rule. It should've been a tie." "Don't understand how the game of such proportions, the #CWC19Final, is finally decided on who scored the most boundaries," he wrote.
short by Anmol Sharma / 10:45 pm on 15 Jul
read more at Twitter
Williamson reacts to overthrow incident in 2019 World Cup final
Reacting to a throw from touching Ben Stokes' bat and racing towards boundary when England needed nine runs to win the 2019 World Cup final off three balls, New Zealand captain Kane Williamson called it a "shame". "Such things...happen from time to time. I don't wish to nitpick, just hope it never happens in such moments ever again," he added.
Right time for Rohit to become ODI captain: BCCI functionary
Amid rumours of a rift between captain Virat Kohli and vice-captain Rohit Sharma, a BCCI functionary said the board is mulling split captaincy. "This would be the right time for Rohit to take over ODI captaincy. We all know some areas need a re-look," he added. He further said that the board will get to bottom of the rumours.
Don't know how much time will I take to get fit: Shaw before WI tour
Batsman Prithvi Shaw on Monday said that he wasn't sure when he would recover from his hip injury. "I'm working with the physios to get back to fitness but can't put a timeline on it right now," he added. Shaw is yet to feature in any international match for India since making his debut against the West Indies in October.
read more at Cricket Country
Williamson's reaction on being named Player of World Cup goes viral
New Zealand captain Kane Williamson's reaction on being named Player of the 2019 World Cup has gone viral. On being told by an official from the organising team that he had won the award, Williamson looked seemingly surprised and asked, "Me?" "A bit of a LOL for you after a tough result!" New Zealand Cricket tweeted while sharing the video.
I'm probably most hated father in NZ: Stokes' father after WC final
England all-rounder Ben Stokes father Ged, who stays in New Zealand, joked that he's the most hated father in New Zealand after his son's performance in 2019 World Cup final. "I really am disappointed for the Black Caps...Hand on heart, I am overjoyed for Ben and the team, but I am still a New Zealand supporter," Ged added.
read more at CricTracker
I have the capacity to play in the shorter format of the game: Pujara
Batsman Cheteshwar Pujara has said he has the capacity to play in the shorter format of the game as he has been performing well in Tests. "I am improving my skills in ODIs and T20Is and in domestic matches...I want to play all the formats," he added. "It would've been nice play the World Cup," he further said.
Some rules definitely need a serious look in: Rohit on WC final
Referring to 2019 World Cup final winner being decided on boundaries, the tournament's highest run-scorer Rohit Sharma tweeted, "Some rules in cricket definitely need a serious look in." England won the final on virtue of scoring more boundaries than New Zealand after the match and Super Over both ended in a tie. It was England's first ever World Cup victory.
ICC announces Team of World Cup, two Indians feature on the list
The ICC on Monday named the Team of the 2019 World Cup, which features two Indians, opener Rohit Sharma and fast bowler Jasprit Bumrah. New Zealand skipper Kane Williamson, who won the player of the tournament award, has been named the captain of the team. The 12-member team includes four players from the tournament-winning side, England.
read more at Cricket World Cup
Ali, Rashid run away as England celebrate WC victory with champagne
A video of England all-rounder Moeen Ali and leg-spinner Adil Rashid running away from champagne spray during England's World Cup final celebrations has gone viral. Reacting to it, a fan tweeted, "Well done to them sticking to their beliefs. Top blokes, top players." "I love how Adil's pushing Moeen to move faster whilst still looking over his shoulder!" wrote another.
ICC criticised for calling Stokes 'greatest' in pic with Sachin
The ICC has been criticised for calling Ben Stokes 'the greatest cricketer of all time' in picture with Sachin Tendulkar. "Agree, because Sachin isn't a cricketer but God of cricket," a user tweeted. "Really?? It should be other way around...Congratulations Stokes for winning the Cup," wrote Harbhajan Singh. Sachin presented Stokes with Man of the 2019 World Cup final award.
Allah was also with us: Eoin Morgan on 'luck' in World Cup final
On being asked whether "the luck of an Irishman" got England over the line in World Cup final, Dublin-born England captain Eoin Morgan said, "We had Allah with us as well." "I spoke to Adil Rashid. He said...'Allah is definitely with us'. It's the rub of the green. It actually epitomises our team. Quite diverse backgrounds and cultures," he added.
India squad for West Indies tour to be announced on July 19
India squad for next month's tour of West Indies will be announced on July 19. Captain Virat Kohli and pacer Jasprit Bumrah are expected to be rested for limited-overs leg comprising three T20Is and three ODIs, as per reports. Talking about MS Dhoni's future, a BCCI official said, "Only he can decide whether he wants to carry on or not."
Olympian accidentally runs over and kills son on his 1st birthday
Sprinter Isaac Ntiamoah, who represented Australia in 2012 Olympics, accidentally ran over and killed his son while reversing his car out of his driveway. The incident happened when Ntiamoah was leaving the house to collect supplies for his son's first birthday party. New South Wales Police are investigating circumstances of the incident, which is being treated as a tragic accident.
read more at Daily Mail
BCCI to invite applications for coach, Shastri will have to reapply
The BCCI will soon invite fresh applications for the Indian cricket team's support staff, including the head coach. Ravi Shastri will need to reapply once his contract expires after India's next month's tour of the West Indies. Shastri was appointed India chief coach in 2017 after Anil Kumble's tenure ended prematurely.
It was a day when sport won: Sania on World Cup, Wimbledon finals
Reacting to 2019 World Cup and Wimbledon men's singles final which took place on Sunday, Sania Mirza tweeted, "What a day...It was a day when sport won." England defeated New Zealand on boundaries after the match and Super Over both ended in a tie. Meanwhile, Djokovic defeated Federer in four hours and 57 minutes to win his fifth Wimbledon title.
Sebastian Vettel apologises to Max Verstappen, admits mistake
short by Dishant Sharma / 05:06 pm on 15 Jul 2019,Monday
Ferrari's Sebastian Vettel apologised to Red Bull's Max Verstappen immediately after Sunday's British Grand Prix after he had rammed into the Red Bull car after the Dutchman had passed him. Following the incident, Vettel had to make a pit stop while Verstappen rejoined the race and finished fifth, missing out on a possible podium finish.
short by Dishant Sharma / 05:06 pm on 15 Jul
Mochizuki first Japanese player to win boy's Grand Slam title
Shintaro Mochizuki on Sunday became the first Japanese player to win a boy's Grand Slam title, beating Carlos Gimeno Valero of Spain 6-3, 6-2 in the Wimbledon final. The 16-year-old, who was playing just his third grass-court tournament, said he had learned a lot from his compatriot, 2014 US Open finalist Kei Nishikori.
British PM Theresa May to host World Cup-winning England team
British Prime Minister Theresa May will host the World Cup-winning England cricket team at her Downing Street office later on Monday. "Yesterday was a brilliant performance by a brilliant team. They showed flair, courage and an absolute determination to become world champions. The achievement... on home soil will live forever in our sporting history," May's spokesman said.
All who watched at home will try to be the next Stokes: Morgan
Praising Ben Stokes, England captain Eoin Morgan said, "[E]verybody watching at home will hopefully try and be the next Ben Stokes." Morgan further said, "It is almost superhuman. He has really carried the team and our batting line-up." Stokes ended the 2019 edition of the World Cup with a total of 465 runs and seven wickets.
Looking forward to the Davis Cup tie in Pak: Rohan Bopanna
Tennis player Rohan Bopanna said he has no security concerns about playing Davis Cup matches in Pakistan. Bopanna said, "I am looking forward to the Davis Cup tie in Pakistan. I have spoken to Aisam-ul-Haq Qureshi, he is a very good friend of mine and he said it will be fine." Bopanna and Qureshi were runners-up in US Open 2010.
Queen sends congratulatory message to WC-winning Eng team
Queen Elizabeth II sent her congratulations to the England team after they beat New Zealand to lift their maiden World Cup title on Sunday. "Prince Philip and I send our warmest congratulations to the England Men's Cricket team after such a thrilling victory in today's World Cup final," wrote The Royal Family official Twitter account.
No exemption for Phogat, Punia from WC trials: WFI
The Wrestling Federation of India (WFI) has specified that there will be no exemption for Vinesh Phogat and Bajrang Punia for the World Championship trials. WFI will conduct the men's trails on July 25 in Sonipat while the women will compete on July 26 in Lucknow. The World Championship will be held in Kazakhstan from September 14.
Vinesh Phogat wins gold medal at Yasar Dogu International
Indian wrestler Vinesh Phogat on Sunday beat Russia's Ekaterina Poleshchuk to win the gold medal at Yasar Dogu International in the 53 kg category. Phogat, who was the third wrestler to win gold in the women's competition for India, tweeted, "Strong performance over the last couple of days at the #YasarDogu here in Istanbul."
Not worried about outrage over same-sex relationship: Dutee
Indian sprinter Dutee Chand has revealed that the outrage over her relationship with a girl does not bother her anymore. Chand has returned after winning a gold medal in the 100m event in the World University Games at Napoli. "I got so many encouragements from eminent personalities which boost up my self-confidence to achieve this prestigious recognition," Chand added.
read more at India.com


I'm working on an exciting new project called 'Better Births' which aims to improve maternity services in England. I'm one of fifteen mums in north-central London who have been recruited to find out what women and families need and want from antenatal, birth, and postnatal care.
I'm working as part of the Haringey team and we need to talk to a range of people in the local community to gather their views and suggestions. We've been trained in participatory action research methods in order to engage with parents in a dynamic and interactive way and to hear their voice, stories, and opinions more directly.
So far, it's been a fascinating project to be involved in. The group of fifteen mums alone are an inspiring and powerful group of women to be working alongside. We all have such diverse and different backgrounds, vary in age and ethnicity, speak multiple languages, and have children of all ages. The one thing we all have in common is that we gave birth in one of the hospitals covered in the north-central London Better Births remit. Hearing their birth stories and journey into motherhood has been a fascinating and eye-opening experience in itself.
Out in the field, it's been just as fascinating. It's been a privilege to hear parents talk about one of the most life-transforming moments of their life. It's also very hard to hear about traumatic experiences, when events didn't go to plan, or when mums have been discriminated against or mistreated in some way. But it's good to know this is exactly what the research aims to address and that the data we gather will help tackle these issues.
The project is a perfect match of my research background, interest in motherhood, and keenness to engage with the local community. It's great to be working on a project where the commissioners are eager to hear the data and feedback (almost in real time) and want to implement change, which will ultimately have a positive impact on one of the most memorable events in a person's life. It's a refreshing contrast to the constraints of academia where the research takes years to be printed, is behind an expensive paywall, that nobody reads or engages with. I look forward to seeing how the next few months unfold and where the project goes.


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Europcar Enters 3-Year Partnership with Live Nation
April 7, 2015 • by Staff
Photo via Wikimedia.
Europcar Australia and New Zealand has entered a three-year partnership with Live Nation Australasia, a Live Nation Entertainment Inc. company. Across Australia and New Zealand, Europcar will be Live Nation's preferred car rental supplier.
This partnership will also offer Europcar customers access to Live Nation benefits such as the "Money Can't Buy" experiences and VIP ticketing to Live Nation events. Additional benefits will be available to Europcar Privilege members, according to the company.
"This relationship is highly valuable to Europcar customers, our Privilege members and Live Nation ticket holders," said Ron Santiago, managing director of Europcar Australia and New Zealand. "Travel and live events belong together, and we want to ensure these special experiences are memorable. Because of this, Live Nation ticket holders will have access to exclusive Europcar car rental offers and enjoy the convenience of booking their car of choice to get to their live event of choice."
"We welcome Europcar to the family of brand partners and look forward to working with them on enhancing their customer value proposition and loyalty program," said Michael Coppel, president and CEO of Live Nation Australia and New Zealand.
Related Article: Europcar Grows Revenue 3.4% in Past Year
Read more about International Rentals Europcar Live Nation


Minecraft PE Snow Seeds for all versions of MCPE, Minecraft Pocket Edition. Each seed spawn is in a snow/snowy biome.
Make your way from the warm island you spawned on over to the blacksmith snow village across the water. Minecraft PE Seed.
This Minecraft PE seed has a snow village right where the game starts. Snow villages are a amongst the rarest finds in MCPE!


Ecosure have now released their new water tank holding 1275 litres. With the new EcoPillar 1275 you can hold a lot of water in a small footprint. Tough and durable like other Ecosure water tanks, these are resistance against frost.


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Katherine Herzer Net Worth, Career, Personal And Early Life
Katherine Herzer was born on January 17, 1997, in Los Angeles, California, United States of America. She is of American nationality since she is a Capricorn. She is an actress who is best known for her roles in the films "Mr. and Mrs. Smith" and "A Lot like Love." She has also been on several television shows.
kaylina eileen
katie osborne
kay adams
katrina weidman
Her mother, Manuela Herzer, and her father, a taxi driver, raised Katherine Herzer in Los Angeles; however, Katherine's childhood was not happy. Her mother died in a fire accident when she was four years old, resulting in her father becoming a cab driver himself. Her two elder siblings, one of whom suffered from mental health issues after their mother's death, focus on this story. Their father worked most of the time and was seldom at home, which meant that Katherine had to take on the task of caring for her brother, who was compelled to drop out of school to escape the strain and stress of his job.
Katherine acquired an interest in the arts during her high school years in Los Angeles, but she had the financial wherewithal to enroll in classes. Instead, she watched and learned from other students. She worked as a waiter at a local restaurant to aid her father in providing for the family. She began studying at New York University's Tisch School of the Arts in 2015, and she finished with a bachelor's degree in 2019 from the institution. At the time of her interning in Vice President Al Gore's office, when she assisted him with an environmental project related to climate change and its repercussions, she was still in college.
She became interested in the arts during her final year of high school, and while she did not have the financial resources to enroll in programs, she watched and learned from other students. She worked as a waiter at a local restaurant to aid her father in providing for the family.
Mr. and Mrs. Smith, Katherine acted with Brad Pitt and Angelina Jolie, was Katherine's first acting role when she was six years old, marking the beginning of her professional acting career. The film was a box office success, grossing over $478 million in the United States alone. It is the story of a bored married couple who discover they are both hired assassins who are paid to kill one another in a game of cat and mouse. Her next role was in the film "A Lot Like Love," which starred Amanda Peet and Ashton Kutcher when she was eight years old. Throughout the film, Emily and Oliver follow their journey together to join the mile-high club and then cross paths for the next seven years.
Katherine has chosen to keep her personal life out of the public spotlight. However, she was spending a significant amount of her free time with an actress who had previously been in the television series "Madam Secretary." The two were seen together at parties and other events initially, but they later stressed that they were just close friends, and as a result, they spent less time together in the future. At the time of writing, Katherine is still single and seems to spend most of her leisure time with her two pet dogs, both of whom she often features in images and videos on her Instagram account.
Her net worth is estimated to be more than $1 million as of the beginning of 2021.


Mie Rose: Food, food and cake.
So a lot of things have been happening, but not that many would be interesting to blog about.
Monday the 16th I handed in my application for Chuo university, and everything was a okay, so now I just need a reply from them here in May/Juneish! I cannot really wait.
The official main building of the University of Copenhagen. Yes, old stuff, but still quite pretty.
What I wore on the big hand-in day! Aaand most of Copenhagen looked as me as I was walking down the treets naked or something. Really weird.
And OFC I did have some lovely TV watching time with him and the dogs. The Miniature dutchhound on the right belongs to my father and he hates my grandfathers normal dutchhound with a passion.
The following weekend I went over to Kami for some casual fun time as we do best. And look at the REALLY healthy food we make together. But it was really good and I regret nothing.
And just some random snaps from uni life. The left is a Kastello cake from Japan that the Japanese exchange student brought. It was really good!
Lastly rounding up all the food p0rn I went to a local Italian restaurant with my mother, stepfather and some of the TORS moving administration. It was really good food! And the conversation was really funny, we kinda made noise enough for the whole room... And quoted Monthy Python and Eddie Izzard, oh yes.
And now I shall leave you, going to Kamis again this weekend and then the Sakura Festival Saturday~ I cannot really wait to wear my yukata again.
Oh Uni Life. I'm shitting myself with fear about (hopefully) starting on CBS next year.
and nice to meet you too, I hope you will be just slightly entertained here!