text:
\section{Introduction}
One of the famous results in random graph theory establishes that $p=\frac{log n}{n}$ is a threshold for the connectivity of Erd\H os and R\'enyi random graphs~\cite{erdos}. A $2$-dimensional analogue of Erd\H os and R\'enyi's result was obtained by Linial-Meshulam in~\cite{linial}. Meshulam-Wallach, in~\cite{meshulam}, presented a $d$-dimensional analogue for $d\geq 3$. In particular, Linial-Meshulam-Wallach theorem yields that $p=\frac{d log n}{n}$ is the threshold for the vanishing of the $(d-1)$-st homology of the random simplicial complex $G_d(n,p)$ with coefficients in a finite abelian group. Here, the random simplicial complex $G_d(n,p)$ is a $d$-dimensional simplicial complex on $[n]$ with a full $(d-1)$-dimensional skeleton and with $d$-dimensional faces are chosen independently each with probability $p$.

The topology of clique complexes of random graphs has been studied in~\cite{babson, costa, Kahle, kahle1, kahle3} and see also~\cite{kahle2} for a survey on random simplicial complexes. The analogue $\Delta_d(X)$ has been considered in~\cite{Babson}.

In this generalization, the $d$-clique complex $\Delta_d(X)$ of a finite simplicial complex $X$ is the simplicial complex on vertex set $V(X)$ of $X$ consisting of all the subsets $F\subseteq V(X)$ with $\binom{F}{d+1} \subseteq X$. As a matter of definition, $\Delta_d(X)$ contains $X$ and the full $(d-1)$-skeleton of the simplex with vertices $V(X)$.

The following is among the problems proposed by Eric Babson in the First Research School on Commutative Algebra and Algebraic Geometry (RSCAAG):

\begin{question}\cite{Babson}\label{Question: Problem on finding threshold}
Find thresholds for $H_k(X;\mathbb{Q})$ to vanish with $X\in \Delta_d(G_d(n,n^{-\alpha}))$.
\end{question}

An idea suggested by Babson for this problem is to try the techniques used for the clique complexes $\Delta_1(G_1(n,n^{-\alpha}))$ of random graphs $G_1(n,n^{-\alpha})$ and is that there may be analogues of the theorems about $\Delta_1(G_1(n,n^{-\alpha}))$ (see~\cite{Babson}). We provide here a partial answer to Problem~\ref{Question: Problem on finding threshold}. In particular, we have the following.

\begin{thm}\label{thm: vanishing results on d-clique complex of random simplicial complexes}
If $p = n^{\alpha}$ then

\begin{enumerate}[label=(\roman*)]
\item if $\alpha < \max\{\frac{-1}{k-d +1},-\frac{d+1}{\binom{k}{d}}\}$ or $\alpha > \frac{-1}{\binom{2k+2}{d}}$ then for the $k$-th reduced homology group of the $d$-clique complex $\Delta_d(G_d(n,p))$ of the random simplicial complex $G_d(n,p)$ we have asymptotically almost surely $\tilde{H}_k(\Delta_d(G_d(n,p)), \mathbb{Z}) = 0$,
\item and if $\frac{-1}{t}<\alpha < \frac{-1}{t+1}$ with $t = (\frac{(d+1)(k+1)}{\binom{(d+1)(k+1)}{d+1}-(k+1)})^{-1}$ then asymptotically almost surely $\tilde{H}_{(k+1)d-1} (\Delta_d(G_d(n,p)), \mathbb{Z}) \neq 0$ holds.
\end{enumerate}
\end{thm}

We note that when $d = 1$, Theorem~\ref{thm: vanishing results on d-clique complex of random simplicial complexes} reduces to Corollary 3.7 in~\cite{Kahle} with one difference: Kahle, in~\cite{Kahle}, improves the sufficient condition $\alpha > \frac{-1}{2k+2}$ for vanishing homology of $\Delta_1(G_1(n,p))$ to $\alpha > \frac{-1}{2k+1}$.

\section{Preliminaries}\subsection{Simplicial Complexes}\label{preliminaries: simplicial complex}
An \emph {abstract simplicial complex} $\Delta$ on a finite vertex set $V$ (or $V(\Delta)$) is a set of subsets of $V$, called \emph{faces}, satisfying the following properties:
\begin{enumerate}
\item $\{v\}\in \Delta$ for all $v\in V$.
\item If $F\in\Delta$ and $H\subseteq F$, then $H\in\Delta$.
\end{enumerate}

For a given a subset $U\subset V$, the complex $\Delta[U]:=\{\sigma\colon \sigma\in \Delta\;\textrm{,}\;\sigma\subseteq U\}$ is called the \emph{induced subcomplex} by $U$. The number of $i$-dimensional faces of a simplicial complex $\Delta$ will be denoted by $f_i(\Delta)$ and the dimension of $\Delta$ by $\dim(\Delta)$. A $d$-dimensional simplex and its boundary are denoted by $\Delta_{d+1}$ and $\partial(\Delta_{d+1})$, respectively.

The join of two simplicial complexes $\Delta_0$ and $\Delta_1$ is denoted by
$\Delta_0*\Delta_1$. An $n$-fold join $\underbrace{\Delta*\Delta*\dots*\Delta}_{n\; \text{times} \;\Delta}$ and $k$-dimensional skeleton of a simplicial complex $\Delta$ will be denoted by $*_{n-1} \Delta$ and $\Delta^{(k)}$, respectively.

Let $\Delta$ be a simplicial complex. For a given face $\sigma$, the \emph{link} $\operatorname{link}_\Delta(\sigma)$ and the star $\operatorname{star}_\Delta(\sigma)$ are defined respectively by $\operatorname{link}_\Delta(\sigma)=\{\tau\in\Delta\colon\tau\cap \sigma=\emptyset\;\textrm{and}\;\tau\cup\sigma\in\Delta\}$ and $\operatorname{star}_\Delta(\sigma) = \{\tau\in\Delta\colon\tau\cup\sigma\in\Delta\}$. For a vertex $x$ in $\Delta$, we abbreviate $\operatorname{link}_\Delta(\{x\})$ and $\operatorname{star}_\Delta(\{x\})$ to $\operatorname{link}_{\Delta}(x)$ and $\operatorname{star}_{\Delta}(x)$ (or simply $\operatorname{link}(x)$ and $\operatorname{star}(x)$ if no confusion arises), respectively.

A \emph{strongly connected} simplicial complex is a pure simplicial complex in which for each pair of facets $(\sigma, \tau)$ there is a sequence of facets $\sigma = \sigma_0,\sigma_1,\dots,\sigma_{n-1} = \tau$ such that the intersection $\sigma_i\cap \sigma_{i+1}$ of any two consecutive elements in the sequence is a codimension one face of both $\sigma_i$ and $\sigma_{i+1}$.

We refer the reader to~\cite{hatcher} for background on simplicial homology. For a $d$-chain $C$ of a simplicial complex $\Delta$, the set of all $d$-simplices appearing in $C$ with non-zero coefficients is called the~\emph{support} $\operatorname{supp}(C)$ of $C$. We denote the simplicial complex obtained by taking the downwards closure of $\operatorname{supp}(C)$ with respect to containment by $\Delta(\operatorname{supp}(C))$. The \emph{vertex support} $\operatorname{vsupp}(C)$ is the vertex set of $\Delta(\operatorname{supp}(C))$.

For any minimal representative $\gamma$ of a class in the reduced homology groups $\tilde{H}_{d}(\Delta;\mathbb{Z})$ of a simplicial complex $\Delta$ with coefficients in $\mathbb{Z}$, the associated simplicial complex $\Delta(\operatorname{supp}(\gamma))$ is a strongly connected $d$-dimensional subcomplex of $\Delta$.

Let $\gamma$ be a nontrivial $k$-cycle in a simplicial complex $\Delta$, with minimal vertex support. Then $\gamma\cap \operatorname{link}_{\Delta}(v)$ for $v\in \operatorname{vsupp}(\gamma)$ is defined as a $\mathbb{Z}$-linear combination of $(k-1)$-dimensional faces appearing in $\Delta(\operatorname{supp}(\gamma))\cap \operatorname{link}_{\Delta}(v)$. See~\cite{Kahle} for further details.

\begin{lem}\label{lem: nontrivial cycles on strongly connected simplicial complexes} \cite{Kahle}
If $\gamma$ is a nontrivial $k$-cycle in a simplicial complex $\Delta$, with minimal vertex support, then $\gamma\cap \operatorname{link}_{\Delta}(v)$ is a nontrivial $(k-1)$-cycle in $\operatorname{link}_{\Delta}(v)$ for any element $v$ in the vertex support $\operatorname{vsupp}(\gamma)$ of $\gamma$.
\end{lem}

For $k\geq 0$, a topological space $X$ is said to be \emph{$k$-connected} if for every $i\leq k$, every continuous function $f$ from an $i$-dimensional sphere $S^i$ into $X$ is homotopic to a constant map. By convention, $(-1)$-connected means nonempty. The connectivity $\operatorname{conn}(X)$ of a topological space $X$ is the largest $k$ for which $X$ is $k$-connected.

Aharoni and Berger, in~\cite{aharoni}, introduce a domination parameter $\tilde{\gamma}(\Delta)$ of a simplicial complex $\Delta$ on $V$, which is defined as the minimal size of a set $A\subseteq V$ such that $\tilde{sp}_{\Delta}(A) = V$ where $\tilde{sp}_{\Delta}(A) =\{v\in V\colon \textrm{there exists some face}\; \sigma\subseteq A\;\textrm{such that}\; \sigma\cup \{v\} \notin \Delta\}$. Call a set $A\subseteq V$ with the property that $\tilde{sp}_{\Delta}(A) = V$ a \emph{strong dominating set} of $\Delta$. The following result which relates the connectivity $\operatorname{conn}(\Delta)$ of a simplicial complex $\Delta$ to the parameter $\tilde{\gamma}(\Delta)$ is due to Aharoni and Berger~\cite{aharoni} and see also~\cite{meshulam2,meshulam3} for the particular case where $\Delta$ is a flag simplicial complex.

\begin{thm}\cite{aharoni}\label{thm: homotopic connectivity bound-aharoni} Let $\Delta$ be a simplicial complex on $V$. Then we have $conn(\Delta)\geq \frac{\tilde{\gamma}(\Delta)}{2}-2$.
\end{thm}

An event that depends on $n$ is said to occur~\emph{asymptotically almost surely (a.a.s.)} if the probability of the event approaches to $1$ as $n\rightarrow \infty$.

\begin{thm}\label{thm: threshold for a subcomplex containment}\cite{Babson}
Let $\Delta$ be a simplicial complex on $V$. If $\Delta$ is $d$-lumpless (i.e. $\frac{|S|}{f_d(\Delta[S])} > \frac{|V|}{f_d(\Delta)}$ for every $\emptyset \subset S \subset V$) then $-\frac{|V|}{f_d(\Delta)}$ is a threshold for the event that $\Delta$ is a subcomplex of $\Delta_d(G_d(n,n^{\alpha}))$. If $\Delta$ is a $d$-lumpless $d$-complex then $-\frac{|V|}{f_d(\Delta)}$ is a threshold for $G_d(n,n^{\alpha})$ to contain a copy of $\Delta$.
\end{thm}

(Recall that $\alpha = a$ is called a ~\emph{threshold} for an event if it occurs a.a.s. for $\alpha >a$ and fails a.a.s. for $\alpha < a$).

\section{vanishing and nonvanishing homology}

In this section, we discuss the topology of the random $d$-clique complexes $\Delta_d(G_d(n,p))$. For comparison purposes, we keep in mind that the threshold for $G_d(n,n^{\alpha})$ to contain a copy of the $d$-skeleton of a $k$-dimensional simplex $\Delta_{k+1}^{(d)}$ is $-\frac{d+1}{\binom{k}{d}}$. More precisely, since the $d$-skeleton of a $k$-dimensional simplex is $d$-lumpless, Theorem~\ref{thm: threshold for a subcomplex containment} gives that if $p = n^{\alpha}$ with $\alpha > -\frac{d+1}{\binom{k}{d}}$ then a.a.s. $\dim(\Delta_d(G_d(n,n^{\alpha})))\geq k$, and if $\alpha < -\frac{d+1}{\binom{k}{d}}$ then a.a.s. $\dim(\Delta_d(G_d(n,n^{\alpha}))) < k$.

\begin{lem}\label{lem: domination number and d-clique complex}
If $p = (\frac{m \log n +\omega(n)}{n})^{\frac{1}{\binom{m}{d}}}$ and $\omega(n)\rightarrow \infty$ then a.a.s. $\tilde{\gamma}(\Delta_d(G_d(n,p))) \geq m +1$.
\end{lem}

\begin{proof}
Let $X$ be the number of strong dominating sets of $\Delta_d(G_d(n,p))$ with cardinality $m$. For any fixed $m$-subset $D$ of $[n]$, a vertex $v\in [n]$ is contained by the set $\tilde{sp}_{\Delta_d(G_d(n,p))}(D)$ if and only if there exists some $(d-1)$-dimensional face $\sigma\subseteq D$ of $\Delta_d(G_d(n,p))$ such that $\sigma\cup \{v\}$ is a minimal non-face of $\Delta_d(G_d(n,p))$. It thus follows that the probability that $v$ is contained by $\tilde{sp}_{\Delta_d(G_d(n,p))}(D)$ is $1 - p^{\binom{m-1}{d}}$ or $1 - p^{\binom{m}{d}}$ according to the condition that $v$ is contained by $D$ or not. Hence, the probability that $D$ is a strong dominating set of $\Delta_d(G_d(n,p))$ is at most $(1 - p^{\binom{m}{d}})^n$.  Therefore, for the expectation $\mathbb{E}(X)$ of $X$, we have \begin{align*} \mathbb{E}(X) &\leq \binom{n}{m}(1-p^{\binom{m}{d}})^n\\
&\leq n^{m}e^{-p^{\binom {m}{d}}n}\\
&= n^{m}e^{-m\log n -\omega(n)}\\
&= e^{-\omega(n)} = o(1),
\end{align*}
since $\omega(n)\rightarrow \infty$. Thus, $X=0$ a.a.s. and so a.a.s. $\tilde{\gamma}(\Delta_d(G_d(n,p))) \geq m +1$.
\end{proof}

\begin{thm}\label{thm: connectivity result for d-clique complex}
If $p = (\frac{(2k + 2) \log n +\omega(n)}{n})^{\frac{1}{\binom{2k+2}{d}}}$ and $\omega(n)\rightarrow \infty$ then a.a.s. the simplicial complex $\Delta_d(G_d(n,p))$ is $k$-connected.
\end{thm}

\begin{proof}Lemma~\ref{lem: domination number and d-clique complex} taken together with Lemma~\ref{thm: homotopic connectivity bound-aharoni} gives $\operatorname{conn}(\Delta_d(G_d(n,p))) \geq k-\frac{1}{2}$.
\end{proof}

\begin{rem}
We note that Theorem~\ref{thm: connectivity result for d-clique complex} reduces to Corollary 3.3 in~\cite{Kahle} when $d=1$.
\end{rem}

\begin{lem}\label{lem: number of d-1 faces in nontrivial cycle}
If $\gamma$ is a nontrivial $k$-cycle in the $d$-clique complex $\Delta_d (\Gamma)$ of a simplicial complex $\Gamma$, then $f_{d-1}(\Delta_d (\Gamma)(\operatorname{supp}(\gamma))) \geq (d+1)(k-d+1) + d +1$ holds.
\end{lem}

\begin{proof} Let $\gamma$ be a nontrivial $k$-cycle in $\Delta_d (\Gamma)$ with minimal vertex support. The assertion is true in the case $k = d-1$. Indeed, if $\sigma$ is a $(d-1)$-dimensional face in the support of $\gamma$, then each $(d-2)$-dimensional face of $\sigma$ must be contained by a distinct $(d-1)$-dimensional face different from $\sigma$ in the support of $\gamma$, since otherwise the coefficient of $\sigma$ would be $0$ in $\gamma$.

We assume now that $k \geq d$ and apply induction. Suppose to the contrary that $f_{d-1}(\Delta_d (\Gamma)(\operatorname{supp}(\gamma))) \leq (d+1)(k-d+1) + d$ holds. If $v\in \operatorname{vsupp}(\gamma)$ then $\gamma\cap \operatorname{link}(v)$ is a nontrivial $(k-1)$-cycle in $\operatorname{link}(v)$ by Lemma~\ref{lem: nontrivial cycles on strongly connected simplicial complexes}. It follows by induction hypothesis that $f_{d-1}(\Delta_d (\operatorname{link}(v))(\operatorname{supp}(\gamma\cap \operatorname{link}(v)))) \geq (d+1)(k-d) + d +1$. We note that the number of $(d-1)$-dimensional faces in $\Delta_d (\Gamma)(\operatorname{supp}(\gamma))$ belonging to $\operatorname{star}(v)$ but not to $\operatorname{link}(v)$ is at least $\binom{k}{d-1}$. Note then that we must have $d = 1$ or $k = d$ so that $f_{d-1}(\Delta_d (\operatorname{link}(v))(\operatorname{supp}(\gamma\cap \operatorname{link}(v)))) = (d+1)(k-d) + d + 1$ and $f_{d-1}(\Delta_d (\Gamma)(\operatorname{supp}(\gamma))) = (d+1)(k-d) + 2d + 1$ hold. If $d = 1$, then $\Delta_d (\Gamma)(\operatorname{supp}(\gamma))$ is a $2k$-dimensional simplex, a contradiction (see~\cite{Kahle} for details). If $d = k$, then  $f_{d-1}(\Delta_d (\operatorname{link}(v))(\operatorname{supp}(\gamma\cap \operatorname{link}(v)))) = d + 1$ and $f_{d-1}(\Delta_d (\Gamma)(\operatorname{supp}(\gamma))) = 2d + 1$ hold, which is impossible. This completes the proof.

\end{proof}

\begin{rem}
We note that, in the case of a flag simplicial complex $\Delta$, Lemma~\ref{lem: number of d-1 faces in nontrivial cycle} reduces to the well-known fact that any representative of a class in $\tilde{H}_{k}(\Delta;\mathbb{Z})$ is supported on at least $2k + 2$ vertices. See Lemma 5.3 in~\cite{Kahle}.
\end{rem}

\begin{lem}\label{lem: homology is generated by cycles on small vertex sets}
If $\alpha < \frac{-1}{\binom{k}{d}}$ and $0 < \frac{k}{\binom{k}{d}N} < \frac{-1}{\binom{k}{d}}- \alpha$, then the vertex support of any strongly connected $k$-dimensional subcomplex of the $d$-clique complex $\Delta_d (G_d(n,p))$ of $G_d(n,p)$ a.a.s. has at most $N + k$ vertices, where $p = n^{\alpha}$.
\end{lem}

\begin{proof}
Let $\Delta$ be a strongly connected $k$-dimensional subcomplex of $\Delta_d (G_d(n,p))$. Let the vertices of $\Delta$ are ordered as $v_1,v_2,\dots,v_n$ so that the first $k + 1$ vertices $v_1,v_2,\dots,v_{k + 1}$ forms a $k$-face and for any other vertex $v_i$ there is at least $k$ vertices $v_j$ such that $\{v_i,v_j\}\in\Delta$ where $j < i$ (See \cite{Kahle} for more details). With this ordering, suppose to the contrary that $\Delta$ has $N + k + 1$ vertices (Here $k + 1$ is the number of vertices in a $k$-dimensional face and $N$ is the number of vertices get added in total). It then follows that the number of $d$-dimensional faces in $\Delta$ is at least $\binom{k + 1}{d + 1} + \binom{k}{d}N$. Since the $d$-skeleton of any subcomplex of $\Delta_d (G_d(n,p))$ is also a subcomplex of $G_d(n,p)$, we have
\begin{align*} \prob (C_{\Delta}) &\leq (N + k + 1)! \binom{n}{N + k + 1} p^{\binom{k+1}{d+1} + N\binom{k}{d}} \\
&=  (N + k + 1)! \binom{n}{N + k + 1} n^{\alpha(\binom{k+1}{d+1} + N\binom{k}{d})}
\end{align*}
for the total probability, where $C_{\Delta}$ denotes the event that $\Delta_d(G_d(n,p))$ contains a simplicial complex isomorphic to $\Delta$. By the assumption $0 < \frac{k}{\binom{k}{d}N} < \frac{-1}{\binom{k}{d}}- \alpha$, we can choose $N$ and $\epsilon$ such that $\frac{k}{\binom{k}{d}N} < \epsilon < \frac{-1}{\binom{k}{d}}- \alpha$ holds. It then follows that $p = n^\alpha < n^{-(\frac{1}{\binom{k}{d}} + \epsilon )}$ and $k < \binom{k}{d}N\epsilon$. We therefore get that
\begin{align*} \prob (C_{\Delta}) &\leq (N + k + 1)! \binom{n}{N + k + 1} n^{\alpha(\binom{k+1}{d+1} + N\binom{k}{d})} \\
&<  (N + k + 1)! \binom{n}{N + k + 1} n^{{-(\frac{1}{\binom{k}{d}} + \epsilon )}(\binom{k+1}{d+1} + N\binom{k}{d})} \\
& \leq n^{N + k + 1}  n^{{-\frac{1}{\binom{k}{d}}}(\binom{k+1}{d+1} + N\binom{k}{d})} n^{-\epsilon (\binom{k+1}{d+1} + N\binom{k}{d})} \\
& =  n^{N + k + 1}  n^{-\frac{1}{\binom{k}{d}} \binom{k+1}{d+1} - N} n^{-\epsilon \binom{k+1}{d+1}  -\epsilon N \binom{k}{d}} \\
& =  n^{k + 1}  n^{-\frac{k+1}{d+1}} n^{-\epsilon \binom{k+1}{d+1}  -\epsilon N \binom{k}{d}} \\
& < n^{1-\frac{k+1}{d+1}-\epsilon \binom{k+1}{d+1}}\\
& \leq  n^{-\epsilon}\\
& = O(n^{-\epsilon}) = o(1),
\end{align*}
since $k\geq d$. This, taken together with the facts that the number of non-isomorphic strongly connected $k$-dimensional simplicial complexes on $N + k + 1$ vertices is finite and any strongly connected $k$-dimensional simplicial complex on more than $N + k + 1$ vertices contains a strongly connected $k$-dimensional simplicial complex on $N + k + 1$, implies that asymptotically almost surely the vertex support of every strongly connected $k$-dimensional subcomplex of the $d$-clique complex $\Delta_d (G_d(n,p))$ of $G_d(n,p)$ has at most $N + k$ vertices. This completes the proof.
\end{proof}

\begin{thm}\label{thm: a vanishing homology result}
If $p = n ^{\alpha}$ with $\alpha < \frac{-1}{k-d +1}$ then a.a.s. $\tilde{H}_k(\Delta_d(G_d(n,p)), \mathbb{Z}) = 0$ holds.
\end{thm}

\begin{proof}
Let $\gamma$ be a nontrivial $k$-cycle in $\Delta_d(G_d(n,p))$ with minimal vertex support. Then $\gamma\cap \operatorname{link}(v)$ is a nontrivial $(k-1)$-cycle in $\operatorname{link}(v)$ for any $v\in \operatorname{vsupp}(\gamma)$ by Lemma~\ref{lem: nontrivial cycles on strongly connected simplicial complexes}. Therefore, we have that $f_{d-1}(\Delta_d (\operatorname{link}(v))(\operatorname{supp}(\gamma\cap \operatorname{link}(v)))) \geq (d+1)(k-d) + d +1$ for any $v\in \operatorname{vsupp}(\gamma)$.

Consider an arbitrary simplicial complex $\Delta$ on $m$ vertices in which the number of $(d-1)$-dimensional faces in $\operatorname{link}(v)$ for any vertex $v\in V(\Delta)$ is at least $(d+1)(k-d) + d +1$. Note then that the number of $d$-dimensional faces $f_d(\Delta)$ of $\Delta$ is at least
\begin{align*} \frac{m((d+1)(k-d +1))}{\binom{d + 1}{d}} = m(k-d +1).
\end{align*}
It then follows that the probability that $\Delta$ is a subcomplex of $\Delta_d(G_d(n,p))$ is at most
\begin{align*} m!\binom{n}{m}p^{m(k-d +1)} &\leq n^m n^{\alpha m(k-d +1)}\\
& = n^{m ( 1 + \alpha (k-d +1))}\\
& = o(1),
\end{align*}
since $\alpha (k-d +1) < -1$. Note that $\frac{-1}{k-d +1}\leq \frac{-1}{\binom{k}{d}}$ whenever $d\leq k$. We therefore have a.a.s. no $k$-dimensional cycles on more than $N + k + 1$ vertices by Lemma~\ref{lem: homology is generated by cycles on small vertex sets}. We also note that the number of non-isomorphic simplicial complexes $\Delta$ on $N + k$ vertices in which the number of $(d-1)$-dimensional faces in $\operatorname{link}(v)$ for any vertex $v\in V(\Delta)$ is at least $(d+1)(k - d + 1)$ is finite.  It thus follows that there are asymptotically almost surely no vertex minimal nontrivial $k$-dimensional cycles in the $d$-clique complex $\Delta_d(G_d(n,p))$ and so a.a.s. $\tilde{H}_k(\Delta_d(G_d(n,p)), \mathbb{Z}) = 0$ holds.
\end{proof}

\begin{rem}Lemma~\ref{lem: number of d-1 faces in nontrivial cycle}, Lemma~\ref{lem: homology is generated by cycles on small vertex sets}, Theorem~\ref{thm: a vanishing homology result} generalize Lemma 5.3, Lemma 5.1, Theorem 3.6 in \cite{Kahle}, respectively.
\end{rem}

Lemma~\ref{d-skeleton of joins of boundaries of d-simplexes} provides us with an example of a lumpless simplicial complex.

\begin{lem}\label{d-skeleton of joins of boundaries of d-simplexes} For $d,k\geq 1$, the $d$-skeleton of the $(k+1)$-fold join $K:= *_k\partial(\Delta_{d+1})$ of boundaries of $d$-dimensional simplexes is $d$-lumpless, i.e. $\frac{f_0(K^{(d)}[S])}{f_d(K^{(d)}[S])}> \frac{f_0(K^{(d)})}{f_d(K^{(d)})}$ for every subset $\emptyset\neq S\subset V(K)$.
\end{lem}

\begin{proof}

Suppose that $S$ is a non-empty subset of the vertex set $V(K)$ of $K$. The claim is obviously true if $|S| = 1$. Assume now that $2\leq |S| = (d+1)(k+1)-n$, where $k + 1 > n \geq 1$. Clearly, we have
\begin{align*}
\frac{f_0(K^{(d)}[S])}{f_d(K^{(d)}[S])}\geq \frac{(d+1)(k+1)-n}{\binom{(d+1)(k+1)-n}{d+1} -(k+1-n)}.
\end{align*}
Thus we need only show that
\begin{align*} \frac{(d+1)(k+1)-n}{\binom{(d+1)(k+1)-n}{d+1} -(k+1-n)} > \frac{f_0(K^{(d)})}{f_d(K^{(d)})}
\end{align*}
holds. Note that
\begin{align*}&\frac{(d+1)(k+1)-n}{\binom{(d+1)(k+1)-n}{d+1} -(k+1-n)}\\
&\qquad =\frac{(d+1)!}{\underbrace{(dk + d + k - n)(dk + d + k - n -1) \dots(dk + k - n + 1 )}_{d\;\text{factors}} - d! + \frac{ndd!}{(d+1)(k+1)-n}}\\
&\qquad\geq \frac{(d+1)!}{(dk + d + k - n)(dk + d + k - n -1)\dots(dk + k - n + 1 ) - d! + \frac{ndd!}{2}}.
\end{align*}
This last line holds, since $(d+1)(k+1)-n\geq 2$ by our assumption on $S$. We then have that
\begin{align*}&\frac{(d+1)!}{(dk + d + k - n)(dk + d + k - n -1) \dots(dk + k - n + 1 ) - d! + \frac{ndd!}{(d+1)(k+1)-n}} \\
&\qquad > \frac{(d+1)!}{(dk + d + k - n)(dk + d + k - n -1)\dots(dk + k - n + 1 ) - d! + \frac{n(d+1)!}{2}}.
\end{align*}
For the expression
\begin{align*}&(dk + d + k - n)(dk + d + k - n -1)\dots(dk + k - n + 1 )
\end{align*}
in the denominator, we have
\begin{align*}&(dk + d + k - n)(dk + d + k - n -1)\dots(dk + k - n + 1 )  \\&\quad= (dk + d + k)(dk + d + k - n -1) \dots(dk + k - n + 1 ) \\ &\qquad- n (dk + d + k - n -1) \dots(dk + k - n + 1 ).
\end{align*}
Consider now the expression $-n(dk + d + k - n -1) \dots(dk + k - n + 1)$.
Note that there are $d-1$ factors in the product $(dk + d + k - n -1) \dots(dk + k - n + 1 )$ and the occurence of an $i$.th factor in the product $(dk + d + k - n -1) \dots(dk + k - n + 1 )$ yields that $d\geq i +1$. We next rewrite the expression
\begin{align*}&-n (dk + d + k - n -1)(dk + d + k - n -2)\\
&\qquad (dk + d + k - n -3) \dots(dk  + d + k - n -(d-1))
\end{align*}
as
\begin{align*}&\underbrace{-n}(\underbrace{(d +1)} +dk + k - n -2)\\
&\qquad (\underbrace{d} +dk + k - n -2)(\underbrace{(d-1)} + dk + k - n -2) \dots(\underbrace{3} + dk + k - n -2).
\end{align*}
Clearly, it contains the term $\frac{-(n)(d+1)!}{2}$ and the expression $dk + k - n -2$ is contained by every factor in the product. If $d\geq 2$ then $dk + k - n -2 \geq 0$ holds and thus we have
\begin{align*}&\frac{(d+1)!}{(dk + d + k - n)(dk + d + k - n -1)\dots(dk + k - n + 1 ) - d! + \frac{n(d+1)!}{2}}\\
&\qquad \geq \frac{(d+1)!}{(dk + d + k)(dk + d + k - n -1)\dots(dk + k - n + 1 ) - d!}.
\end{align*}
Since
\begin{align*}&\frac{(d+1)!}{(dk + d + k)(dk + d + k - n -1)\dots(dk + k - n + 1 ) - d!}\\
&\qquad > \frac{(d+1)!}{(dk + d + k)(dk + d + k - 1)\dots(dk + k + 1 ) - d!},
\end{align*}
it follows that
\begin{align*}&\frac{(d+1)!}{(dk + d + k - n)(dk + d + k - n -1)\dots(dk + k - n + 1 ) - d! + \frac{n(d+1)!}{2}}\\
&\qquad > \frac{(d+1)!}{(dk + d + k)(dk + d + k - 1)\dots(dk + k + 1 ) - d!}\\
&\qquad = \frac{f_0(K^{(d)})}{f_d(K^{(d)})}.
\end{align*}
If $d =1$, then we obviously have that
\begin{align*}\frac{2}{2k + 1 - n - 1 + n} = \frac{f_0(K^{(1)})}{f_1(K^{(1)})}.
\end{align*}

Suppose now that $2\leq |S| = (d+1)(k+1)-n$, where $n\geq k+1$. Then
\begin{align*}&\frac{f_0(K^{(d)}[S])}{f_d(K^{(d)}[S])}\geq \frac{(d+1)(k+1)-n}{\binom{(d+1)(k+1)-n}{d+1}}
\end{align*}
holds. We have that
\begin{align*}&\frac{(d+1)(k+1)-n}{\binom{(d+1)(k+1)-n}{d+1}}\\
&\qquad = \frac{(d+1)!}{\underbrace{(dk + d + k - n)(dk + d + k - n -1) \dots(dk + d + k -d - n +1)}_{d\;\text{factors}}- d! + d!}.
\end{align*}
It then follows that
\begin{align*}&\frac{(d+1)(k+1)-n}{\binom{(d+1)(k+1)-n}{d+1}} \geq \frac{(d+1)!}{(dk + d - 1)(dk + d -2) \dots(dk + d -d)- d! + d!},
\end{align*}
since $n\geq k+1$. The expression $(dk + d - 1)(dk + d -2) \dots(dk + d -d)$ is equal to $(dk + d)(dk + d -2) \dots(dk + d -d) - (dk + d -2)(dk + d -3) \dots(dk + d -d)$. Note that the expression
\begin{align*}&- (dk + \underbrace{d} -2)(dk + \underbrace{(d-1)} -2) (dk + \underbrace{(d-2)} -2)\dots(dk + \underbrace{(2)} -2)
\end{align*}
contains the term $-(d!)$ and $dk-2\geq 0$ whenever $d\geq 2$. We therefore get that \begin{align*}&\frac{(d+1)(k+1)-n}{\binom{(d+1)(k+1)-n}{d+1}}\\
&\qquad  \geq \frac{(d+1)!}{(dk + d - 1)(dk + d -2) \dots(dk + d -d)- d! + d!} \\
&\qquad \geq \frac{(d+1)!}{(dk + d)(dk + d -2)(dk + d -3) \dots(dk + d -d)- d!}  \\
&\qquad > \frac{(d+1)!}{(dk + d + k)(dk + d -2 + (k+1))(dk + d -3 + (k+1)) \dots(dk + (k+1))- d!} \\
&\qquad  = \frac{f_0(K^{(d)})}{f_d(K^{(d)})}.
\end{align*}
This completes the proof.

\end{proof}

\begin{rem} Recall that a $k$-dimensional octahedral sphere is a $(k+1)$-fold join of two isolated points. It is well-known in random graph theory that the $1$-skeleton of a $k$-dimensional octahedral sphere is a strictly balanced graph and $n^{\frac{-1}{k}}$ is a sharp threshold function for the random graph $G_1(n,p)$ to contain the $1$-skeleton of a $k$-dimensional octahedral sphere. We remark that Lemma~\ref{d-skeleton of joins of boundaries of d-simplexes}, taken together with Theorem~\ref{thm: threshold for a subcomplex containment} reduces to this fact when $d = 1$.
\end{rem}

It was shown by Kahle that if $p^{k} n \rightarrow  \infty$ and $p^{k+1} n \rightarrow 0$ as $n\rightarrow \infty$ then $\Delta_1(G_1(n,p))$ a.a.s. retracts onto a sphere $S^k$ and so $\Delta_1(G_1(n,p))$ a.a.s. has nonvanishing integer $k$-th homology (see Theorem 3.5. in~\cite{Kahle}). We generalize this argument by Theorem~\ref{thm: vanishing results on d-clique complex of random simplicial complexes} (ii) so that it applies to the random $d$-clique complexes:

\begin{proof}[{\bf The proof of Theorem \ref{thm: vanishing results on d-clique complex of random simplicial complexes}}] Claim (i) is immediate from Theorem~\ref{thm: connectivity result for d-clique complex} and Theorem~\ref{thm: a vanishing homology result} by taking into account the threshold for the dimension of the random $d$-clique complex $\Delta_d(G_d(n,n^{\alpha}))$. To prove (ii), consider the $(k+1)$-fold join $K:= *_k\partial(\Delta_{d+1})$ of boundaries of $d$-dimensional simplexes. Recall that $n^{-\frac{f_0(K^{(d)})}{f_d(K^{(d)})}} = n^{-\frac{(d+1)(k+1)}{\binom{(d+1)(k+1)}{d+1}-(k+1)}}$ is a threshold function for $G_d(n,p)$ containing the $d$-skeleton of the complex $K$ as a subcomplex by Lemma~\ref{thm: threshold for a subcomplex containment} together with Lemma~\ref{d-skeleton of joins of boundaries of d-simplexes}; i.e. if $\alpha > -\frac{f_0(K^{(d)})}{f_d(K^{(d)})}$ then $G_d(n,p)$ a.a.s. contains the $d$-skeleton of $K= *_k\partial(\Delta_{d+1})$ as a subcomplex, and if $\alpha < -\frac{f_0(K^{(d)})}{f_d(K^{(d)})}$ then $G_d(n,p)$ a.a.s. does not contain $K= *_k\partial(\Delta_{d+1})$. By the assumption $\alpha > \frac{-1}{t}$, we conclude that $G_d(n,p)$ a.a.s. contains the $d$-skeleton of $K= *_k\partial(\Delta_{d+1})$. Let us choose a $(d-1)$-dimensional face $F_m$ from each of the factor $\partial(\Delta^m_{d+1})$ of the $(k+1)$-fold join $K= *_k\partial(\Delta_{d+1})$, where $1\leq m\leq k+1$. Set
\begin{align*}&\mathcal{A} =\{F_m\colon 1\leq m \leq k + 1\},\end{align*}
\begin{align*}&S_\mathcal{A}= \bigcup_{m\in [1,k+1]} F_m
\end{align*}
and
\begin{align*}&\mathcal{N}(\mathcal{A}): = \{x\in \Delta_d(G_d(n,p))\colon F\cup \{x\} \in \Delta_d(G_d(n,p))\;\textrm{for each}\;d-\textrm{subset}\; F\subseteq S_\mathcal{A}\}.
\end{align*}
It then follows that the conditional probability that $\mathcal{N}(\mathcal{A})\neq \emptyset$ for $\mathcal{A}$ is no more than
 \begin{align*} p^{\binom{(k+1)d}{d}}(n-(k+1)(d+1)) + p (k+1) \leq p^{t+1} (n-(k+1)(d+1)) + p (k+1) = o(1).
\end{align*}
So a.a.s. $G_d(n,p)$ contains the $d$-skeleton of $K= *_k\partial(\Delta_{d+1})$ in which $\mathcal{N}(\mathcal{A}) = \emptyset$. Note that in this case this subcomplex is indeed an induced subcomplex of $G_d(n,p)$, since we must have that $\{x^m_{d+1}\} \cup F_m \notin G_d(n,p)$ for any choice of $m$, where $x^m_{d+1} \in V(\Delta^m_{d+1})\setminus F_m$ and $F_m\in \mathcal{A}$. Note also that $\Delta_d(K)$ is a subcomplex of $\Delta_d(G_d(n,p))$ and  $\Delta_d(K)$ is homeomorphic to $S^{(k+1)d -1}$.
\end{proof}

\begin{rem}
In the proof of Theorem~\ref{thm: vanishing results on d-clique complex of random simplicial complexes} (ii), we have used the inequality $t + 1\leq \binom{d(k+1)}{d}$. To observe this, it is enough to see that $\binom{(d+1)(k+1)-1}{d} + d - (d+1) \binom{(k+1)d}{d}\leq 0$. Let $K:= *_k\partial(\Delta_{d+1})$ be the $(k+1)$-fold join of boundaries of $d$-dimensional simplexes and let $\{F_{mi}\colon 1\leq i\leq d+1\}$ denote the set of all $(d-1)$-dimensional faces in the factor $\partial(\Delta^m_{d+1})$ of the $(k+1)$-fold join $K$, where $1\leq m\leq k+1$. Set $X_i= F_{11}\cup \bigcup_{l=2}^{k+1} F_{li}$ with $1\leq i\leq d+1$. Let $K'$ denote the subcomplex of $K$ obtained by removing the vertex $x$ from $\partial(\Delta^1_{d+1})$ with $x\notin F_{11}$. Note that $\binom{d(k+1)}{d}$ counts the number of $(d-1)$-dimensional faces in each $X_i$ and thus $(d+1) \binom{d(k+1)}{d}$ counts the number of $(d-1)$-dimensional faces in $K'$ with some repetations-in particular the face $F_{11}$ is repeated $(d+1)$ times. On the other hand, $\binom{(d+1)(k+1)-1}{d}$ counts the number of $(d-1)$-dimensional faces in $K'$. We therefore have that $\binom{(d+1)(k+1)-1}{d} \leq (d+1) \binom{(k+1)d}{d} - d$.
\end{rem}

\section*{Acknowledgement}
I would like to thank all the contributers of the ``First Research School on Commutative Algebra and Algebraic Geometry'' (RSCAAG) organized by the Institute for Advanced Studies in Basic Sciences (IASBS) and the Institute for Research in Fundamental Sciences (IPM).

I would like to express my particular thanks to Eric Babson through whom I learnt about  random simplicial complexes for his amazing lectures in the research school  RSCAAG, as well as for the research sessions and the problems, among one of all is the subject of this note, for his time to look over my draft and for his invaluable comments.

redpajama_set_name: RedPajamaArXiv


A delicious tour through the variegated world of Gelato!
The perfect workshop for the most curious gelato lovers. Instructors from Carpigiani Gelato University will present the wide range of gelato products: sorbets, milk-based gelato, express gelato and gelato treats!
The museum is open from Tuesday to Saturday from 9am to 6pm.
Reservation required for both workshops and visits. Choose your preferred day and time and you will be contacted for the activity confirmation.
When you book your experience please specify any allergies or intolerances.
Carpigiani Gelato University is an international training center at the service of those who already work or want to work in the field of ice cream and homemade pastries.
d) For the use of my image, name, and/or voice, which may be the subject of photographic and/or audiovisual recording.


Welcome! We are happy to guide you along to our event registration.
Please know that Expedition Day Camp is for children who are were enrolled in 2nd through 6th grade of the 2018/2019 school year.
1. What is Expedition Day Camp?
Expedition Day Camp is an interactive hands-on experience for children in grades 2-6. These one-day camps will cultivate and nurture a love of learning in the lives of those who attend while encouraging them to discover the fascinating things in the world around them.
Regardless of whether your family attends church or has a church home, your children are welcome to participate.
2. When/where is Expedition Day Camp happening?
Expedition Day Camp's will take place right here at, First CRC (2175 Leoni Drive) on Saturday from 1:00 PM-4:00 PM with check-in beginning at 12:45 PM . There will be four separate events, each unique in design and experience.
It's going to be an adventure of a lifetime!
3. How much does it cost for my child/children to attend?
4. My child has allergies. Will there be food provided?
A family BBQ will follow each of the day camps. If your child has any allergies, please let us know on the registration form.
5. I still have questions. Who do I contact?
You may contact: Sarah Zonneveld, Director of Children's Ministries.


Watch this awesome drag racing compilation video – ( Author Description drag racing event should always be safe. The rider was not able to control his bike after a wheelie.
◄ http://www.youtube.com/watch?v=uQ6BPz4bQjY&t=30s&hd=1 ) Thanks to the creator of video. OLD CAR TV hopes you enjoyed the video and leave a review below in comments.


text:
Dr Søren Rud Kristensen
Faculty of Medicine, Institute of Global Health Innovation
Senior Lecturer in Health Economics
s.kristensen Website
1021Queen Elizabeth the Queen Mother Wing (QEQM)St Mary's Campus
Dr. Søren Rud Kristensen is a Senior Lecturer in Health Economics at the Centre for Health Policy at the Institute of Global Health Innovation. He holds an MSc in Economics (2008) and a PhD in Economics (2012) from the University of Southern Denmark. Prior to joining Imperial College he was a Research Fellow and later Lecturer in Health Economics at the University of Manchester where he is now an Honorary Senior Lecturer. He is an Adjunct Associate Professor at the University of Southern Denmark and has been a visiting scientist at the Harvard T.H. Chan School of Public Health.
Dr Kristensen's primary research interest is the design and effects of performance incentives in health care. His research takes point of departure in the economic theory of incentives and is conducted using microeconometric analyses of large data sets. His current research interests include the intended and unintended effects of using financial penalties to incentivise quality improvement in health care, payment models for integrated care, and value for money in patient safety.
Stokes J, Lau Y-S, Kristensen SR, et al.Stokes J, Lau Y-S, Kristensen SR, Sutton M close, 2019, Does pooling health & social care budgets reduce hospital use and lower costs?, Soc Sci Med, Vol:232, Pages:382-388
Stokes J, Lau Y-S, Kristensen SR, et al.Stokes J, Lau Y-S, Kristensen SR, Sutton M close, 2019, Corrigendum to "Does pooling health & social care budgets reduce hospital use and lower costs?" [Soc. Sci. Med. 232 (2019) 382-388]., Soc Sci Med
Kluge H, Kelley E, Swaminathan S, et al.Kluge H, Kelley E, Swaminathan S, Yamamoto N, Fisseha S, Theodorakis PN, Kristensen S, Anderson M, Mossialos E close, 2018, After Astana: building the economic case for increased investment in primary health care., Lancet, Vol:392, Pages:2147-2152
Oxholm AS, Kristensen SR, Sutton M, 2018, Uncertainty about the effort-performance relationship in threshold-based payment schemes, Journal of Health Economics, Vol:62, ISSN:0167-6296, Pages:69-83
Stokes J, Struckmann V, Kristensen SR, et al.Stokes J, Struckmann V, Kristensen SR, Fuchs S, van Ginneken E, Tsiachristas A, van Molken MR, Sutton M close, 2018, Towards incentivising integration: A typology of payments for integrated care, Health Policy, Vol:122, ISSN:0168-8510, Pages:963-969
Centre for Health Policy
Patient Safety Translational Research Centre
Tweets by soerenrk

redpajama_set_name: RedPajamaCommonCrawl


Super news coming from Subaru for their car fans. Recently the company has unveiled one of their much awaited for models. Subaru Forester tS has been presented in Japan.
For the new Subaru production will be limited to 300 units and pricing starts at ¥4,350,000 ($36,875 / €29,565 / £23,495). Wonder what makes the new model different from the standard one? Well magic is found in the aggressive look.
First let's take a look under the hood to see the goodies that the new Subaru brings. Power is given by a turbocharged 2.0-liter four-cylinder engine equipped with an optimized ECU that produces 280 PS (206 kW) and 350 Nm (258 lb-ft) of torque.
Feature list counts an STI-branded grille and 19-inch forged aluminum wheels, front and rear spoilers, a tailgate-mounted spoiler, black accents and a sport-tuned suspension that reduces the ride height by 15mm.
Not quite covinced by the arsenal that producers offer? No need to worry as styling just might be the definitory factor. More to the point magic continues inside the cabin where leather / Ultrasuede sport seats with red contrast stitching and embossed STI logos await future drivers and passengers.
No only this but the model also has carbon fiber trim and piano black accents, a leather-wrapped sport steering wheel, a push-button ignition, additional sound deadening material and an STI-branded speedometer. Also it's important to mention that he Forester tS has a strut tower brace, a flexible rear subframe support and flexible front / rear draw stiffeners and a retuned suspension.
This entry was posted in Subaru and tagged Forester tS, Japan, Revealed, Subaru, Subaru Forester tS. Bookmark the permalink.


Human bodies are quite interesting, right? No matter how much we look alike with one another, possessing most of our similar features, such as eyes, noses, ears, there are certain quirks in each and every one of us that remind us how we have a uniqueness in our sameness.
Look no further than your own ears. In their essence, they serve as the organ that allows us to connect with the world through sounds. And maybe you didn't know this, but there are people out there in the world that have tiny holes near where their ear connects with the rest of their head.
No, it is not an unfortunate mishap while piercing their ears. Those people were born with that little hole, and it is quite interesting when you find out why.
We refer to it as preauricular sinus. In most cases, it appears only on one side. However, the possibility for it to appear on both sides exists. Preauricular sinus appears while the fetus is in the early development stages.
Fun fact: if you live in the United Kingdom or the United States, there is less than one percent chance that you have one.
The first reported occurrence of the preauricular sinus was documented back in 1864 by a scientist known as Van Heusinger. The study was published in the US National Library of Medicine. However, we can safely assume that it was around for hundreds of years before that.
Sooo, why exactly do some people have this hole? Well, it is not known for sure, however the evolutionary scientist, Neil Shubin, thinks that it is a 'leftover' from our humankind past. He claims that they could be an "evolutionary remnant of fish gills". Interesting, right?
However, preauricular sinuses are completely harmless. At times they can get infected but can be adequately handled with surgery.
So, there you go. It is simply a reminder that you are a unique human being.
However, preauricular sinuses should not be considered as piercings, so do not try to slip an earring there.


text:
Overview of Vietnamese economy in 2006 and prospect in 2007
Although faced with severe difficulties and challenges, results attained in 2006 are satisfactory. The successful 14th APEC Meeting, full WTO membership and the Permanent Normal Trade Relations with the US acquired by Vietnam are promoting a new wave of foreign investment to Vietnam. To maximize the prospects for 2007, at the beginning of the year, all branches and administrative levels and enterprises of all sectors should strictly follow the direction of the Government by implementing various solutions to problems, making good use of opportunities, addressing inherent weaknesses and overcoming challenges in order to successfully achieve the planned targets for 2007.
The Party and people of Quang Ninh province with the political tasks in 2007
2007 is an important and the hinge year for the provincial Party organization and people of Quang Ninh province in the implementation process of resolution of the 12th provincial Party Congress. A number of tasks are set forth in 2007 in order to materialize targets laid down at the provincial Party Congress: 1/ Maintaining economic development; 2/ Properly implementing social policies; 3/ Strengthening and improving the effectiveness of the operation of political system, well protecting security, social order and safety. Quang Ninh is confident that it will be able to fulfill these key task and other important duties in the implementation of 2007 development plan when the orientation has been clearly defined.
Hoa Binh after 15 years of the re-establishment of the province
Being a province of long history as well as a cradle of culture, and following many upheavals with different names, on 1st October 1991 Hoa Binh province was re-established. It is the native land of more than 820.000 people of 7 ethnic groups: Muong, Kinh, Thai, Tay, Hmong, and Chinese. Having overcome various difficulties related to being a mountainous province, after 15 years of re-establishment, the people of Hoa Binh province are steadily implementing the resolution of the 10th Party Congress and the resolution of the 14th provincial Party Congress in order to build a province which is prosperous, socio-politically stable, and strong in security and defense.
Quang Nam – 10 years after the split of the province and the prospects for the future
Over the past 10 years, Quang Nam has overcome many difficulties and begun to register initial important development which lays the foundations for further advancement. Targets ahead are more challenging and severe and different from those of the initial period after the split. The current difficulties are at higher level and cannot be dealt with purely by determination which is, although, the first and necessary condition. In recent years, Quang Nam has registered lively development but still remains a poor province. The percentage of poor households stands at the average level of the country. Economic efficiency remains low in comparison with other provinces in the country.
Binh Phuoc in 10 years of renovation
Peaceful springs in a border province
Referring to Tay Ninh province, people often remember a land with the glorious history of being a revolutionary base of the Southern Commanding Board in the two legendary national resistant wars. Tay Ninh also has famous landscapes such as Ba Den Mountain and Tay Ninh Cathedral. Tay Ninh is also known as the sugar capital of the country as the largest sugar production in the country is located in the province. More than 30 years after the liberation of the South, Tay Ninh has overcome various difficulties and challenges and brought into full play the loyal and courageous tradition of a border province. The provincial Party organization and the people of the province has maintained close cooperation to build lasting peace and friendship in this border area.
Kon Plong in 5 years of development
On 31st January 2002 Kon Plong district of Kon Tum province was established. With a geographical area partitioned by rivers, streams and hills, 3 out of 6 communes do not have a road to the centre of the commune and all 6 communes do not have electricity. In addition, people's knowledge is low. These are difficulties which have hindered the transformation of cultivation and the breeding of domestic animals, intensive farming, and the application of scientific and technological progress. After 5 years of bringing into full play revolutionary traditions and constant efforts, the district Party organization and people, Kon Plong district has changed for the better and attained some achievements in economic, political, cultural and social areas, as well as in local defense and security.
Catholic followers emulate for peaceful and fine religious life
Contrary to some erroneous opinions that in Vietnam there is religious suppression and non-existence of religious belief etc, religious followers in Vietnam in general and Catholic believers in particular have freedom, equality and a peaceful life. It is an undeniable truth. Recently, the Vietnam Fatherland Front has launched an emulation campaign: "All people are to build a new life in the neighborhood with peaceful and fine religious activities" which contains concrete and realistic contents. The campaign has gained strong support from Catholic followers and attained great success.


We will cover Data organization in spreadsheets and Open refine, R Basics, Data Visualization in R and SQL. Participants should bring their laptops and plan to participate actively. By the end of the workshop learners should be able to more effectively manage and analyze data and be able to apply the tools and approaches directly to their ongoing research.
Where: USDA/ARS/Southern Regional Research Center 1100 Robert E. Lee Blvd. New Orleans, LA 70124. Get directions with OpenStreetMap or Google Maps.
Contact: Please mail OP.Perera@ars.usda.gov for more information.


Summer is in full swing and there are plenty of things to do on Catalina Island. From bingo on the beach to dancing in the streets, the Catalina calendar is filled to overflowing.
The Catalina Island Museum keeps bringing us back with their amazing programs. First Fridays has become a don't-miss-it activity every month and Aug. 4 is no exception. The Endless Summer is the quintessential surf film and the museum will be showing it along with live surf music by the perfectly named Neptune Cocktail. Feel free to bring a snack, beer, wine, soda and water will be available for purchase.
Another favorite Catalina Museum activity is Movies at the Museum. Regular screenings of movies with a Catalina connection showcase the museum's outdoor amphitheater and give attendees the opportunity to see the Chihuly glass exhibit in a whole new light – after dark. Coming up August 9 A League of Their Own celebrates the all-women baseball league that entertained sports fans during World War II. William Wrigley Jr, although not depicted in the movie, played an integral role in the league.
We've been enjoying the recent remodel at Steve's, which has also renamed itself Steve's Steakhouse and Seafood to better represent the diversity of its menu. They are still serving up favorites like Shrimp Avalon, filet mignon and those irresistible coconut shrimp we showcase on the Catalina Tasting and Cultural Walking Tour.
The Catalina Concert Series continues Aug. 26 with a tribute to ABBA, always one of the highlights of the series as far as dancing in the streets. As usual, a beer garden will be set up near Wrigley Stage an hour before showtime. Get their early for a chance to win Catalina Food Tour tickets and gift certificates to Catalina Coffee and Cookie Co., along with several other great prizes.
Speaking of prizes, summer just wouldn't be summer without a few evenings of Beach Bingo on South Beach. Cards are just $1 and you can play every Tuesday and Thursday at 6 p.m.
Steve's Steakhouse and Seafood was recently remodeled.


The Knot GenieTM Detangling Brush was created for every mom that has endured the foot stomping and screaming matches that come with brushing their child's hair. With the Knot Genie, even the curliest, most knotted up hair practically slips through the unique bristle configuration - gently and painlessly. Try the Knot Genie on your kids (or on yourself) - you'll be amazed by the ease of brushing, as well as how it virtually stops breakage and split ends. You've wished for hair brushing standoffs to end. Wish granted.
The Tennie Genie is the same as the original Knot Genie but slightly smaller, ideal for child sized hands who want to brush their own hair.


Results from SigFit may be graphically visualized within popular finite element post processors allowing users to view and publish graphical results with software already familiar to them. In addition, graphical results may be exported from SigFit directly in the form of PNG files.
Figure 1: PNG plot created by SigFit pre/post-processing software.
Figure 2: SigFit results plotted after import to FEA.


SAUR-18D: Encode the instant messages in Beyluxe Messenger online free / Protect torrents or plaintext in your Intex Aqua Raze.
SAUR-18D: Protect torrents or plaintext in your Intex Aqua Raze.
Decode and encode a short text for Wippien using SAUR-18D and send it to aMSN / free encryption tool.


text:
Stop Being Evil: A Proposal for Unbiased Google Search
Joshua G. Hazan, University of Michigan Law School
Since its inception in the late 1990s, Google has done as much as anyone to create an "open internet." Thanks to Google's unparalleled search algorithms, anyone's ideas can be heard, and all kinds of information are easier than ever to find. As Google has extended its ambition beyond its core function, however it has conducted itself in a manner that now threatens the openness and diversity of the same internet ecosystem that it once championed. By promoting its own content and vertical search services above all others, Google places a significant obstacle in the path of its competitors. This handicap will only be magnified as search engines become increasingly important and the internet continues to expand. In order to mitigate the potential damage to competition, we must prevent Google from leveraging its power in core search to steal market share for its downstream vertical search services. Requiring Google core search to integrate its competitors' vertical offerings would promote competition without intrusive administrative interference. But action must come soon. Search is taking shape very quickly. Once the next generation of online search emerges, the dominant players will have already cemented their positions. Let us hope that when the dust settles it isn't too late.
Joshua G. Hazan, Stop Being Evil: A Proposal for Unbiased Google Search, 111 Mich. L. Rev. 789 (2013).
Antitrust and Trade Regulation Commons, Business Organizations Law Commons, Internet Law Commons


text:
A Land I Know as Well as Myself: Cheyenne Rain LeGrande ᑭᒥᐊᐧᐣ's MASKEKEWAPOY ᒪᐢᑫᑫᐊ
By Sanaa Humayun
Issue 022, Volume Six | Fall 2020
Cheyenne Rain Legrande ᑭᒥᐊᐧᐣ, Maskekewapoy ᒪᐢᑫᑫᐊ, 2019.
Still Courtesy of the artist.
Cheyenne Rain LeGrande ᑭᒥᐊᐧᐣ stands in a field of long, yellow grass in Deer Lake, Burnaby. Her movements aren't rehearsed. She allows her body to relate to the land instinctively. Beside her is a pile of nettle. She rubs the nettle on her arms and legs, allowing impulse to guide her actions. Though nettle may seem spiky and uninviting, it has often been used in traditional Indigenous healing practices, including for arthritis and blood flow.
She learns from her friend, Nicole Priessl, who has ancestors from and around Deer Lake: "Nicole brought me to Deer Lake prior to performing and she shared the knowledge of her Ancestors and that territory. I am forever grateful for her teachings, knowledge and the sharing of a traditional medicine. When I performed that day, I invited her to join me and together we picked the medicine I use in the performance. When performing in that space I moved with the land and felt the generosity and beauty in shared knowledge. I was surrounded by love and the healing brought by the land."1
LeGrande is a Nehiyaw Isko artist from Bigstone Cree Nation who was living in the territory of Sḵwx̱wú7mesh (Squamish), Stó:lō and Səl̓ílwətaʔ/Selilwitulh (Tsleil-Waututh) and xʷməθkʷəy̓əm (Musqueam) Nations(so-called Vancouver)at the time. She was trying to understand how to relate to a land that wasn't hers. Her video, titled Maskekewapoy ᒪᐢᑫᑫᐊ, meaning Medicine Water, records a performance done as part of a2019 group show called What We Bring With Us. The series, curated by Maria Margaretta, invited seven different Indigenous artists to create works about what it means to exist on territories as guests.
LeGrande's performance begins with her standing in a field of tall, yellow grass. She is wearing a slightly transparent robe, and a crown of sticks. LeGrande explains these choices: "The markings on my face and the way I have presented my body is a reflection of thinking through ideas around cleansing and healing one's body. The sheer fabric stands in as a sort of spiritual skin. A type of protection that floats in the space with me."2
In her hands, she holds soft, green nettle. She begins to rub it up and down her arms and legs with careful, gentle motions, as though she is washing them. She maintains eye contact with the camera while she does this, and it feels like she is looking directly at me. It feels like we are learning something together about the land. As she moves around the space it begins to feel disjointed –her actions are cut off mid-movement. Her exploration is not linear, instead, it is made up of fragmented moments. She touches the tall grass around her, running her fingers through it –it's a tactile level of understanding. Throughout this performance she uses her body, her sense of touch, to understand the land.
As she walks towards the camera, she stands directly in front, making eye contact again, and begins to gently caress her face. It seems that she is using this same sense of touch to understand herself, connecting her understanding of herself to the land. The backs of her hands and arms are covered with raw, red hives. What does it mean that her body has responded to the land in this way? There is a level of understanding that goes all the way into a physiological response –just as she understands that she is a stranger trying to make sense of a new land, her body understands this too, reacting in redness and bumps to this new and alien environment.
"This is a recurring theme throughout LeGrande's body of work - her body is a method of discovery [...] There is something beautiful, vulnerable and tender about understanding and expressing with one's whole self."
I think about this idea a lot. I'm Pakistani by heritage, born and raised on stolen land. I live in Alberta, knowing that Whiteness has claimed this land as its own, and thus I am twice displaced. I exist between two cultures, not Pakistani enough to feel at home there, and not White enough to blend in here. I wonder if there is a way to merge these two identities. I wonder if my body understands what my mind does, and if it feels this displacement on a physiological level.
Culture and land feel explicably tied together. Alberta's identity is associated with its wide-open prairies. When I drive through, I often consider how I relate to these lands and how I exist in this space. The places I've felt at home in Alberta are few and far between. I often think back to something written by art critic Amy Fung: "The Prairies... create in me a nostalgia for a life that was never mine."3 When I get to experience the prairies, outside of the city, I think about a life that I almost had.
Being an Albertan and being a brown-skinned person often feel impossible to combine into a single identity. There's an idea of an old-stock, White Albertan that owns this land -a good, hard-working, honest farmer. His skin doesn't look like mine. In contrast, I have to exist in public places with eyes in the back of my head, hackles up. I have conversations with people where I intentionally throw in the fact that I was born in Canada, as if it makes my claim to the land more legitimate. When I get a glance in public that lasts just a second too long, I prepare imaginary arguments just in case. There are very few places that exist for me without being hyper-aware of my surroundings, out of survival, out of necessity, and out of experience. I have spent so much of my life as a chameleon -shifting who I am to blend in as much as possible. It's a terrible and deep-seated instinct to overcome. Eventually, I realized that I can find home here by establishing spaces for myself, by creating homes that are filled with the people I love, the people that keep me safe.
When LeGrande attended Emily Carr University, she lived in Skwachay's Lodge, an Indigenous artist in residence program in Vancouver. In the many connections she made there, she met a Gitsxanman who taught her about Ha ums: "The crown I wore was made from the remains of a medicine called Ha Ums. Ha Ums is a traditional tea medicine which was generously shared with me by Ya'YaHeit."4 Together, they harvested the wood, scraped off the top layer of bark, and boiled the green inner bark under it into tea that they drank together. In this moment he imparted knowledge of that territory with her and allowed her to keep the remnants to create the crown she wears in Maskekewapoy ᒪᐢᑫᑫᐊ, a reminder of what remains of the medicine and the community she's been a part of.
LeGrande reminds me that connection to place isn't always inherent. When she found herself in a strange land, she reached out to those around her to build community. She shared knowledge, learned about the land, and figured out how to exist within it. Her performance is informed by the actions of her friends, peers, and mentors -their knowledge and support are with her as she moves through the land, informing her actions as she uses her body to find home there: "I often use my body in my practice as a way to speak directly to my identity as an Indigenous person. There is a point in the performance I come close to the camera and embody two things I often feel as an Indigenous person. Pain and strength. Using my own body allows me to feel, express, and to release."5
This is a recurring theme throughout LeGrande's body of work - her body is a method of discovery. In LeGrande's work, Nehiyaw Isko, her body allows her to explore and understand generational trauma, and healing. There is something beautiful, vulnerable and tender about understanding and expressing with one's whole self. This is what LeGrande does in her work, over and over again, allowing her body to lead her exploration, and to find healing.
"I exist between two cultures, not Pakistani enough to feel at home there, and not White enough to blend in here. I wonder if there is a way to merge these two identities. I wonder if my body understands what my mind does, and if it feels this displacement on a physiological level."
When I moved to Edmonton nine years ago, alone, I worked as a tutor -I found little pockets of home in the mother of one girl I tutored. She would bring us fruit every week while we worked and send me home with a home-cooked meal. I moved cities last summer, and for the first time in nine years I am living in the same city as my mom. Sometimes she brings me food when she makes something particularly delicious -sharing food is an instinct that runs deep. For a minute, when I eat her cooking, I feel like a kid again. She teaches me how to make the dishes I remember from my childhood and get a brief glimpse of home–this, too, is an exploration led by my body –it remembers what home tastes like.
I'm a guest on stolen land, and I often feel like I'm drifting with no roots. LeGrande's work reminds me that we find connection through our families, our friends, our loved ones, and ourselves. Even when I feel alone, even when I can't see them, my roots are there.
Interview with Cheyenne Rain LeGrande, August 20, 2020
Amy Fung, Before I Was a Critic I Was a Human Being. Toronto: Book*hugPress, 2019, pg. 86.
Interview with Cheyenne Rain LeGrande.
The Instability of Place: Kevin Lee Burton, Paul Wong & Amanda Strong on grunt gallery's Urban Screen
BY Kate Barry


The Food Diary is a must-have worksheet for structuring your client sessions. When a client tracks his/her food, mood and hunger level on the Food Diary worksheet, it is a starting point for the two of you to have a "day-in-their-life" conversation about both "primary" and "secondary" food.
As a coach, you will find that your clients' completed daily Food Diary provides clues and pieces of their unique puzzle to help uncover food sensitivities and create awareness of their relationship with food.Use the Food Diary tool with all of your clients to help them make "good, better and best" changes to their food and lifestyle choices and keep them on track toward reaching their goals.


text:
The Best Camera and Photography Deals for Cyber Monday
Scott Gilbertson
We dove deep into this week's discounts to find the best sales on cameras, lenses, drones, and related gear.
Illustration: WIRED Staff
Note: Cyber Monday is over and most deals have ended. If you're still hunting for discounts, check our Best Cyber Monday Deals Still Available (as of Dec. 3) post. As always, we hope we helped you sift through the sales madness and find great products. Check our Holiday Buying Guides for the latest reviews and recommendations.
Black Friday is behind us, but now the Cyber Monday floodgates have opened and there are some new deals on cameras of all shapes and sizes—not to mention lenses, SD cards, tripods, and back-up hard drives.
Whether you'd looking for a nice pocketable point-and-shoot, a full-frame, 4K-video-capable mirrorless system, or an action camera that can go anywhere and record anything, there are deals for every skill level, aspiration, and budget. We've sifted through the craziness and curated this collection of deals we think are worth checking out.
We will update this post with new deals as we find them. If an item is no longer at its deal price or sold out, we cross it out. Deal prices sometimes return and items come back in stock faster than we can update, so it never hurts to check for yourself.
Update December 2: We've added the Switchpod Tripod and expired a few deals.
WIRED's Cyber Monday Coverage
Absolute Best Cyber Monday Deals
Camera and Drone Deals (You are here!)
Laptop and Tablet Deals
TV and Soundbar Deals
Videogame and Console Deals
Headphone and Speaker Deals
Smartphone and Gadget Deals
Outdoor and Fitness Deals
Home, Kitchen, and Mattress Deals
Deals That Make Great Gifts
Google Deals and Amazon Deals
Deals: OLED TV, Wirefree Earbuds, iPad 10.2
All Our Cyber Monday Articles, Tips, and Holiday Guides
1-Year Print + Digital WIRED Subscription for $5 (Cyber Week Discount. Please support our work!)
When you buy something using the links in our stories, we may earn a small affiliate commission. Here's how it works.
Compact, Instant, and Action Cam Deals
Photograph: GoPro
We recently overhauled our guides to the best compact cameras and best action cameras. Check them out to learn more.
Panasonic Lumix ZS100 for $398 ($300 off)
Amazon, Adorama
If you want telephoto reach in a compact package, Panasonic's Lumix ZS100 delivers. Rather than the 3X or 4X optical zoom found in most competitors, this camera has a lens with 10X. The camera's 1-inch sensor is on par with some of the best compact cameras. Standard 4K video and Wi-Fi, along with a great touchscreen interface, make this camera feature-full and easy to use.
Canon PowerShot G9 X Mark II for $399 ($80 off)
B&H Photo, Adorama
This little Canon hits the sweet spot for price, features, and image quality (8/10, WIRED Recommends). It's compact, the tilting touchscreen is a standout feature in this class, and the autofocus is surprisingly speedy.
GoPro Hero 8 Black $349 ($50 off)
Amazon (with SD card), Walmart, Best Buy
The GoPro Hero 8 Black (8/10, WIRED Recommends) brings some major changes to the Hero line. You no longer have to deal with a mounting cage, and some new add-ons make for easier vlogging. But the real highlight is the new customizable menu system, which simplifies using the camera in extreme conditions.
Photograph: Olympus
Olympus Tough TG-6 Waterproof Camera for $349 ($100 off)
The Olympus TG-6 is a tough little camera that soars where smartphones crash (8/10, WIRED Recommends). It offers excellent image quality for a small camera (complete with support for RAW images), and it's nearly indestructible. If you want a camera that's a GoPro-style, go-anywhere machine but retains the lens and sensor quality of a point-and-shoot, the TG-6 is your best bet. The only thing I don't like about it is the inscrutable menu system. Spend some time with the manual, and make sure you learn all the TG-6's tricks.
GoPro Hero 7 Black for $300 ($30 off)
$300 (No Accessories): Walmart, Best Buy
$330 (With 2 Batteries and a MicroSD Card): Amazon, Adorama
A similar deal has been going on for a while now, but the price has dropped another $30 for Cyber Monday. The Hero 7 is a very capable action camera with 4K video (8/10, WIRED Recommends). It lacks the custom menu features of the Hero 8 Black, but the sensor and lens are the same.
DJI Osmo Action for $279 ($100 off)
DJI, Amazon ($254), Best Buy, Adorama
DJI's Osmo Action is my favorite action cam (8/10, WIRED Recommends), and at this price it's an even sweeter deal. The front screen makes shooting yourself easier, and the frame rates for video match what you get out of DJI's drones, saving you some headaches in postproduction if you're combining drone and handheld footage.
DJI Osmo Pocket for $309 ($90 off)
One part camera, one part gimbal, the Osmo Pocket put a stabilized, drone-style camera into a handheld grip (8/10, WIRED Recommends). The result is an easy way to get super smooth video as you run, walk, ski, even skydive. The downside is that it's pricey, even on sale. If you have a mobile device capable of quality video, the DJI Osmo Mobile (8/10, WIRED Recommends) is worth considering. (Unfortunately, it's not on sale.)
Fujifilm Instax Mini 90 Neo Classic for $120 ($30 off)
Amazon, B&H Photo, Adorama
Fujifilm's Instax prints are a breath of fresh air in a digital world. The miniature Polaroid-style prints aren't the highest-quality images, but they sure are fun. The Instax Mini 90 is the best Instax camera the company makes. The Mini 90 Neo Classic is compact, comes with a long-lasting rechargeable battery, and gives you more creative control with a push-button close-up lens and a double exposure mode. It's also super easy to take a selfie from just about any angle.
Polaroid Originals Onestep 2 with film for $80 ($50 off)
Best Buy, B&H Photo ($99, no film)
There are instant cameras we like better, but if you want a Polaroid, and the larger prints you get with Polaroids, this is our top pick (6/10, WIRED Review).
Fujifilm Instax Mini 9
Fujifilm Instax Mini 9 Instant Camera with film for $50 ($35 off)
Amazon, Best Buy
Fujifilm's Mini 9 is an affordable way into the instant camera world. It's a great gift for kids too, because at this price you won't feel quite so bad if your kids drop it or blaze through an entire pack of film in 10 seconds.
Fujifilm Mini LiPlay Hybrid Instant Camera for $130 ($10 off)
This elegant, pocketable camera is Fujifilm's latest Instax (8/10 WIRED Review). As a fun bonus, you can print out photos from your phone with an app. It's not the steepest discount, but it's a new camera, and we haven't seen it on sale before now.
Mirrorless and DSLR Deals
Photograph: Sony
Be sure to check out our guide to mirrorless cameras for some added context.
Sony Alpha A7 II Mirrorless Camera with 28–70mm lens for $998 ($600 off)
This Sony A7 II kit deal is one of the best I've seen this holiday. You get a great camera (albeit one that's a few years old) with one of the best kit lenses I've used. No, it's not a fast prime, but it's better than you think. If you've been looking to get into the full-frame mirrorless camera system, you'd be hard-pressed to find a cheaper way to do it.
Sony Alpha A7R III Camera Body for $2,498 ($300 off)
B&H Photo, Amazon, Best Buy, Adorama
Sony recently released the A7R IV, which we have not had a chance to play with yet, but honestly, it's hard to imagine what could top the previous version. The A7R III offers a 42-megapixel full-frame sensor with fantastic dynamic range and great clarity in the details. This camera is also no slouch when it comes to video.
Panasonic Lumix G9 Mirrorless Camera Body for $998 ($500 off)
The Panasonic Lumix G9 features a 20.3-megapixel Micro Four Thirds sensor but can also do an in-camera JPEG or RAW composite image for an 80-megapixel combined image. You also get five-axis dual image stabilization and 4K video at up to 60p.
Panasonic Lumix GH5 Camera Body for $1,298 ($700 off)
The Panasonic GH5 features a 20-megapixel Micro Four Thirds sensor with no low-pass filter and stabilized 4K 60P video capabilities. The slightly higher-end GH5S is also on sale for $1,998 ($500 off). This model is the video camera to beat.
Nikon Z50 with two lenses for $1,200 ($150 off)
Best Buy, Adorama
Nikon's newest APS-C mirrorless camera uses Nikon's Z lens mount. Aimed at those looking to step up from the world of smartphone photography, the Z50 is still reasonably light and compact but gives you the power of a much larger sensor and interchangeable lenses. I've played with it a bit and like what I've captured so far, especially using the very compact 16-50mm lens. This deal includes a 50–250mm, giving you a huge focal-length range in a small two-lens setup.
Canon EOS 6D Mark II for $1,199 ($400 off)
B&H Photo (with accessories), Amazon, Adorama
Canon's long-awaited sequel to the 6D brings a much better 45-point autofocus system, a larger 26-megapixel sensor, and an articulating touchscreen. The 6D continues to be a great choice for the "prosumer"—someone who wants a great Canon but doesn't need the pro-oriented features of the more expensive 5D Mark IV, which is also on sale at $2,500 ($1,600 off).
Nikon D750 DSLR Camera With Accessories for $997 ($700 off)
Is it still worth buying this five-year-old camera? At this price, definitely. It's capable of turning out fantastic images, the low-light performance is excellent, and the autofocus, while not on par with the current top of the line, is very good. The D750 is a great way to hop on the full-frame Nikon train.
Sony Alpha A6000 Mirrorless Cam with 16–50mm Lens and Accessories for $448 ($200 off)
B&H Photo, Amazon (no accessories), Adorama
Sony's A6000 was an underrated gem of a camera when it was first released, and even now, a couple of years on, it's still a great option. It's light, compact, and delivers fantastic images. At this price you're getting a quality APS-C interchangeable lens system for the cost of a point-and-shoot. If you're not interested in the kit lens (and unlike the kit lens for the A7 II above, this one is just so-so), you can get the A6000 body alone for $398 ($150 off).
Panasonic Lumix GX85 Mirrorless Camera with two lenses for $448
The GX85 is a great rangerfinder-style Micro Four Thirds camera (7/10, WIRED Review). It's a couple of years old, but the 20-megapixel sensor is very sharp even by today's standards. The only downside is the electronic viewfinder, which is not great. But this kit is well-suited for travel, with two lenses that cover a huge range of photo situations.
Deals on Lenses
Adorama and B&H Photo have some great deals on lenses for just about every camera system.
For Canon, there's a great deal on the Canon EF 17-40mm f/4L $499 ($300 off). I also love the 40mm f/2.8 STM pancake for $129 ($70 off).
Fujifilm's 16mm F1.4 lens is on sale for $899 ($100 off), and my favorite Micro Four Thirds lens, the Panasonic Lumix G 20mm f/1.7, gets a minor discount at $268 ($30 off) (it's a great deal at full price).
Moment's telephoto lenses are now $90 ($30 off), for the loyal phone photo enthusiasts.
Olloclip's phone photography package is on sale for $100 ($50 off) and includes a phone clip, two lenses, a Bluetooth shutter release, and a microfiber bag.
Drones and Accessories Deals
Photograph: DJI
DJI Mavic 2 Pro for $1,379 ($350 off)
DJI, Best Buy, Adorama
DJI's Mavic 2 Pro is one of the best drones you can buy (9/10, WIRED Recommends). It's easy to fly, has tons of safety features—like omnidirectional obstacle avoidance—so you don't crash, and the camera is capable of some great 4K footage. There are two limitations to be aware of: Hyperlapse video is limited to 1080p (HD), and the zoom only goes to 2X when shooting 4K.
Fujifilm Instax SP-3 Mobile Printer for $110 ($35 off)
B&H Photo, Amazon
The Instax SP-3 can turn your photos into mini Polaroid-style prints. We print everything from not-so-great phone images to heavily processed images from a Sony full-frame camera. The SP-3 handles it all and spits out surprisingly nice prints you can pin up around the house.
SanDisk Extreme 128 GB MicroSD Card for $20 ($46 off)
You can never have too many memory cards, and you should never pay full price for them. Deals like this one happen frequently, but if you're like me, you never remember to grab them when they're on sale. Get one now and have it ready to go when you need it. This one isn't the best for video, but it's plenty fast for photos.
DJI Ronin Gimbal for $479 ($80 off)
The Ronin Gimbal is our favorite way to get that Steadicam look on a budget. The Ronin is big enough for a mirrorless rig, like the Sony A7 cameras above, but is small enough that it's not a pain to tote to your shoot.
Western Digital 12 TB External Hard Drive for $180 ($100 off)
With 12 terabytes of storage, this monster of a drive should be able to keep up with even the most prolific of videographers.
SanDisk 2 TB Extreme Portable External SSD for $200 ($50 off)
This solid-state drive doesn't drop in price often. This one-day deal matches the one we saw last Prime Day. The lack of moving internal parts means superfast transfer speeds, while the ruggedized enclosure can withstand rain, dust, and falls. This deal is part of a larger one-day sale on SanDisk and WD gear.
Manfrotto 61-inch Travel Tripod for $50 ($20)
With a universal mount and a smartphone clip, this tripod can stabilize just about any camera. It's a little small and light for a giant DSLR with a huge telephoto lens, but I use it with a Sony A7ii with a 300mm lens all the time, and it works great. I like that the leg extensions are clips rather than twist-style locks, which I find less sturdy.
Switchpod Tripod for $80 ($10 off)
Adorama, B&H, Moment
Trying to get into vlogging? It can be tricky holding and facing the camera toward you. The Switchpod alleviates this problem by extending the camera a little further back. Better yet, its magnetic legs can snap out to turn it into a tripod, and it mounts to your camera directly. There are two threads you can use to attach a microphone or a light, and the padded feet makes sure the tripod won't slip around.
Joby GorillaPod Phone Tripod for $14 ($10 off))
We're fond of this affordable, portable, and durable phone camera stand.
Cyber Monday Retailer Sales Pages
We've sifted through most of these major sales for you. But if you prefer to browse for more deals, here are some retailers to check.
B&H Photo Audio
Everybody loves Rey, a Star Wars story
25 amazing gift ideas under $25
Drawing with drones over the salt flats of Bolivia
Here's the evidence that links Russia's most brazen cyberattacks
How the dumb design of a WWII plane led to the Macintosh
👁 A safer way to protect your data; plus, the latest news on AI
🎧 Things not sounding right? Check out our favorite wireless headphones, soundbars, and Bluetooth speakers
Scott Gilbertson is a product reviewer for WIRED, specializing in portable technology. He was previously a writer and editor for WIRED's Webmonkey.com, covering the browser wars, web standards, the independent web, and all aspects of internet culture. He studied at the University of Georgia.
John Cena & Keegan-Michael Key Explore Their Impact on the Internet
TopicsShoppingDealsblack fridayCyber Monday


Why do I collaborate with Fundación Málaga?
Málaga is my home and I want my city and province go further.
I think that individuals from all statums must commit ourselves to this task.
Also we can do it from an private non-profit organization that pursues the common good.
Being aware of the importance of providing a clearer, more supportive and open image of our city and province.
Recovering and increasing the heritage of our buildings, works by our artists that we would like to have in Málaga.
Helping the neediest groups always behind public or private organizations that have these objectives entrusted to them, covering, if we are able, some of the gaps that always remain.
Making known the city of Málaga through meetings that empower us: conferences and congresses associated to the most dynamic aspects of our economy, our culture and our way of life by creating forums for debate to guide us on the right paths of progress and also by teaching us what is good in other places.
From my company and my private activity I have been able to see that good intentions and ideas, without the support of material means and personal effort and dedication, do not go very far.
Furthermore, I think that if we strengthen Fundación Málaga, it will be able to be independent and supportive and will honour those of us who launch and support it, giving service and encouragement to Málaga and its most interesting projects.


Fashion-focused nail polish in a gorgeous array of inspiring colours and effects. The application is quick and easy – one coat of the high-gloss formula provides a rich, flawless finish.
How to use: Apply over base coat and finish with a top coat for extra protection and shine.
Tea Tree essential oil has been a staple in my skin & hair care routine for the past few years and I ain't going to stop using it anytime soon. Not only essential oil, I own at least one skin care product be it toner or moisturizer infused with the majestic Tea Tree oil as well! This oil is my warrior, my soldier which has that ability to fight with devil acne breakouts ALONE 😍 My love for this beauty led me to Fabindia outlet last year, where I purchased a few skincare products along with the Tea Tree Essential oil. So to know more about this product, kindly read ahead!
This oil helps combat dandruff and acne. Vapours help in easing nasal congestion.
Hope all of you are having a great time with your family and friends 💕 Today, I am going to talk about a glitter pencil eyeliner that belongs to Take Me Out Liner range of the brand Hard Candy. I received the shade Truffle as a surprise gift (freebie) in my Lady Raga Subscription bag last year. Read ahead to know whether this pencil eyeliner is worth trying or not!
Last year, I did a mini haul from Qtrove website and bought a few natural skin care products; Areev Oil of Olives body lotion was one of them. You know, after its first usage only I realized, this would be a perfect product for the summer time, so saved it till March. Now, after using it for a good period of time, I think this is the appropriate time to share my view on this excellent skin care product. Keep scrolling down to know more!


Featuring Demonias Embroidered Heart Eyeglasses on Vamp, Ruffle Lace Trim, Pyramid Studs & Piping Detail. 3 1/4' Platform'(7cm) Platform Mary Jane Style: shoes-wedges-plsr-click-02-1blkcanvas This item is FINAL SALE and is not eligible for return or exchanges. NOTE: This item is an Expanded Assortment*. Please allow 3-4 business days for item to leave the warehouse. NOTE: This item is exluded from discounts and promotions, if eligable may be subject to a restocking. See our store policy.


Today just got a little sweeter! Uber is giving away free ice cream through their app from 11AM-3PM today, August 11 in 10 cities. Not only will lucky recipients score free ice cream for up to 4 friends, you'll also get a collectible cone you can take to your local McDonald's for a free soft serve every Friday through the rest of the summer. An Uber account is required.


100% fresh seasoned beef grilled to perfection with the works! Add tasty toppings like bacon, cheese, avocado or even fried egg. YUM!
Strips of seasoned grilled chicken rolled in to a warm flour tortilla with roasted red peppers, crisp romaine lettuce, fresh spring mix, our signature spinach spread and baby swiss cheese. Fresh & Healthy!
Chopped grilled chicken, tomatoes, avocado, applewood bacon, egg, peppers, cheddar cheese and scallions served over a bed of mixed greens with crispy iceberg. Comes with creamy house ranch.
Al dente linguine pasta topped with our house-made tomato basil sauce, freshly grated parmesan cheese and parsley.
Add Garlic Bread to complete the dish.


CHARLES, Mo.– Patrice Billings, a former SWAT sniper and retired chief pilot who served in the St. Louis County Police Department Metro Air Support Unit, is announcing her candidacy for State Senate in Missouri's 2nd Senate District in the 2018 general election. She launched her campaign on Sundayin O'Fallon, MO at Civic Park.
Billings has seen firsthand the issues affecting disenfranchised Missourians through her involvement with national and local nonprofit organizations such as Zonta International, Safe Connections and the St. Charles Equality Coalition. She is an advocate for women, children, and seniors especially.
A nationally-known speaker with a distinguished career of public service, Billings was awarded a Purple Heart medal and has been recognized as the first female police officer in the country to become a helicopter pilot for a law enforcement agency. She was a precision marksman having been trained by FBI and Navy SEAL experts.
She is currently a jewelry designer and a co-owner of a small business called Butterfly & Moon in historic St. Charles and a "Beyond the Best" winner named by Streetscape Magazine.
Learn more at BillingsforSenate.com or on Twitter: @Billings4Senate.


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Q: insert number in sql database with vb.net (like student ID, Employee ID) I want to make an auto generating transaction no. in sql database like student ID, or Employee ID every time i insert data in sql database. all i can do now is to insert data. but i dont have idea how to create transaction no. in everytime i add data.
Dim query As String = String.Empty
        query = "insert into marketingLog(TransCode,Endorser,Enrollee_Name,Course,Rebates,Trans_Date,CreatedBy,Status)" _
            & "values(@transcode,@endorser,@name,@course,@rebates,@transdate,@user,@status)"

        Using conn As New SqlConnection(dbUse.db)
            conn.Open()
            Using comm As New SqlCommand
                With comm
                    .Connection = conn
                    .CommandType = CommandType.Text
                    .CommandText = query

                    .Parameters.Add("@endorser", SqlDbType.VarChar).Value = cmbEndorser.Text 'Endorser
                    .Parameters.Add("@name", SqlDbType.VarChar).Value = txtEnrolleeName.Text 'Enrolle_Name
                    .Parameters.Add("@course", SqlDbType.VarChar).Value = cmbCourse.Text 'Course
                    .Parameters.Add("@rebates", SqlDbType.Int).Value = lblRebate.Text 'Rebates
                    .Parameters.Add("@transdate", SqlDbType.DateTime).Value = DateAndTime.Now
                    .Parameters.Add("@user", SqlDbType.VarChar).Value = lblUsername.Text
                    .Parameters.Add("@status", SqlDbType.VarChar).Value = "Standby"
                End With
                Try
                    comm.ExecuteNonQuery()
                    conn.Close()
                    loadmyGrid()
                    loadDefault()
                Catch ex As Exception
                    MessageBox.Show(ex.Message.ToString(), "Error Message")
                End Try
            End Using
        End Using

TransCode is my column name. i want to add like 1,2,3,4,5 every transaction. i use it as my transaction no.

A: What could you problely do before insert data into the table you find the
Select Max(TranCode) From marketingLog

and it will return some int number or 0 for the first time.
you just increment it with 1.
and then perform your insert.
actually i don't know how to code in vb but i am trying to write logic in your code please refer it and try to apply using vb
for e.g.
    Dim query As String = String.Empty

    query = "Select Max(TranCode) From marketingLog";

    Dim dtb As New DataTable;

    Using conn As New SqlConnection(dbUse.db)
    conn.Open()

    Using dad As New SqlDataAdapter(query, conn)
    dad.Fill(dtb)

    Dim intTransNo As Integer  =  Int32.Parse(dtb.Rows(0)(0).ToString()) + 1;

    query = "insert into marketingLog(TransCode,Endorser,Enrollee_Name,Course,Rebates,Trans_Date,CreatedBy,Status)" _
        & "values(@transcode,@endorser,@name,@course,@rebates,@transdate,@user,@status)"

        Using comm As New SqlCommand
            With comm
                .Connection = conn
                .CommandType = CommandType.Text
                .CommandText = query
                .Parameters.Add("@transcode", SqlDbType.VarChar).Value = intTransNo
                .Parameters.Add("@endorser", SqlDbType.VarChar).Value = cmbEndorser.Text 'Endorser
                .Parameters.Add("@name", SqlDbType.VarChar).Value = txtEnrolleeName.Text 'Enrolle_Name
                .Parameters.Add("@course", SqlDbType.VarChar).Value = cmbCourse.Text 'Course
                .Parameters.Add("@rebates", SqlDbType.Int).Value = lblRebate.Text 'Rebates
                .Parameters.Add("@transdate", SqlDbType.DateTime).Value = DateAndTime.Now
                .Parameters.Add("@user", SqlDbType.VarChar).Value = lblUsername.Text
                .Parameters.Add("@status", SqlDbType.VarChar).Value = "Standby"
            End With
            Try
                comm.ExecuteNonQuery()
                conn.Close()
                loadmyGrid()
                loadDefault()
            Catch ex As Exception
                MessageBox.Show(ex.Message.ToString(), "Error Message")
            End Try
        End Using
    End Using

A: CREATE TABLE Persons
(
ID int NOT NULL AUTO_INCREMENT,
LastName varchar(255) NOT NULL,
FirstName varchar(255),
Address varchar(255),
City varchar(255),
PRIMARY KEY (ID)
)

You can use an AUTO_INCREMENT column in your table. you don't need to specify any data for  this column. Data for this column will be automatically inserted on new record insert.
INSERT INTO Persons (FirstName,LastName)
VALUES ('Lars','Monsen')

Check the fiddle here.
Your Code:  You simply need to skip putting data into the Auto_Increment column.
Dim query As String = String.Empty

    //query = "Select Max(TranCode) From marketingLog";

    Dim dtb As New DataTable;

    Using conn As New SqlConnection(dbUse.db)
    conn.Open()

    query = "insert into marketingLog(Endorser,Enrollee_Name,Course,Rebates,Trans_Date,CreatedBy,Status)" _
        & "values(@endorser,@name,@course,@rebates,@transdate,@user,@status)"

        Using comm As New SqlCommand
            With comm
                .Connection = conn
                .CommandType = CommandType.Text
                .CommandText = query
                                .Parameters.Add("@endorser", SqlDbType.VarChar).Value = cmbEndorser.Text 'Endorser
                .Parameters.Add("@name", SqlDbType.VarChar).Value = txtEnrolleeName.Text 'Enrolle_Name
                .Parameters.Add("@course", SqlDbType.VarChar).Value = cmbCourse.Text 'Course
                .Parameters.Add("@rebates", SqlDbType.Int).Value = lblRebate.Text 'Rebates
                .Parameters.Add("@transdate", SqlDbType.DateTime).Value = DateAndTime.Now
                .Parameters.Add("@user", SqlDbType.VarChar).Value = lblUsername.Text
                .Parameters.Add("@status", SqlDbType.VarChar).Value = "Standby"
            End With
            Try
                comm.ExecuteNonQuery()
                conn.Close()
                loadmyGrid()
                loadDefault()
            Catch ex As Exception
                MessageBox.Show(ex.Message.ToString(), "Error Message")
            End Try
        End Using
    End Using

redpajama_set_name: RedPajamaStackExchange


Watching Family Guy tonight and saw Brian doing the Peanut Butter Jelly Time song. This is one of Pickle's all-time favorite Internet things. My dear husband had never seen it. *smacking self on head* Go check out the one featuring Brian doing the Family Guy Peanut Butter Jelly Time song.


If a child has atopic dermatitis, he wants medicinal therapy - both internal and external. Typically, doctors prescribe into a second generation antihistamines. The efficacious ingredients do not cause position effects like drowsiness, dryness of mucous membranes, decreased learning ability. There are drugs that can be given to babies with 2 years old, and preparations with a active substance desloratadine may be given to babies from one year along.These medicine are more effective: they cut a itching, swelling and flushing of the skin. How a effect, a rash becomes pale and may later go completely. In atopic dermatitis, you should not use herbs in the form of baths or creams. Alone a medical man can help understand the causes rashes and find the rightly medication. Therapy of atopic dermatitis should be comprehensive and involve not only food and antihistamines, but also outside of therapy.Outdoor therapy depends on a lot of factors: the total area of face lesions baby, from rashes, very dry or moist, there is local swelling. If the face is dry with scaling, it is necessary to further moisturize, and if weeping - it must very dry a little. Improving with ration and therapy - is a favorable scenario for a easy flow of atopic dermatitis. But often a disease retsidiruet and enhanced. Therefore, a treatment need necessarily be not only complex but also time consuming.Allergies in KidsA causes of allergies in infantsMeals for allergies in kidsDiet for AllergiesDietary allergy Leaving of a newborn. Similar articles:Baby. Food allergies in children Baby. May a nursing mum persimmon Baby. Hardening of infants .


text:
Q: How can I merge two associative arrays that are being looped? I am trying to run two queries from the database. I need the two queries to create an array with the same column names and then merge the two arrays together.
Here are my two queries:
## Order History
$q47 = "SELECT OCODT AS COMPDT, ORDNO AS ORDER, ORQTY AS OQTY,
               QTYRC AS RQTY FROM AMFLIBP.MOHMST WHERE FITEM='$id' AND FITWH='$wh'";
$stmt47 = db2_prepare($con, $q47);
$result47 = db2_execute($stmt47);

$q48 = "SELECT DOKDT AS COMPDT, ORDNO AS ORDER, QTYOR AS OQTY,
               DKQTY AS RQTY, VNDNR AS VNDR FROM AMFLIBP.POHISTI
        WHERE ITNBR='$id' AND HOUSE='$wh'";
$stmt48 = db2_prepare($con, $q48);
$result48 = db2_execute($stmt48)

I want to do a while statement on both of the queries.
So, something that looks like this:
while($fin47 = db2_fetch_assoc($stmt47));

and

while($fin48 = db2_fetch_assoc($stmt48));

After the while statements have been completed,
I want to take the results from both of the while statements and
put them in to an array sorted by COMPDT.
I have tried doing this:
## Order History
$q47 = "SELECT OCODT AS COMPDT, ORDNO AS ORDER, ORQTY AS OQTY, QTYRC AS RQTY
        FROM AMFLIBP.MOHMST
        WHERE FITEM='$id' AND FITWH='$wh'";

$stmt47 = db2_prepare($con, $q47);
$result47 = db2_execute($stmt47);
while($fin47 = db2_fetch_array($stmt47));

$q48 = "SELECT DOKDT AS COMPDT, ORDNO AS ORDER, QTYOR AS OQTY, DKQTY AS RQTY,
               VNDNR AS VNDR FROM AMFLIBP.POHISTI
        WHERE ITNBR='$id' AND HOUSE='$wh'";

$stmt48 = db2_prepare($con, $q48);
$result48 = db2_execute($stmt48);
while($fin48 = db2_fetch_array($stmt48));

$array = array_merge($fin47, $fin48);
print_r($array);

From the print_r($array);
I get nothing but the following error in my php.log:
[29-Dec-2013 09:17:03 Antarctica/Mawson] PHP Warning:
array_merge(): Argument #1 is not an array in
     /www/zendsvr6/htdocs/views/test.php on line 42

I know the while statements are causing the problem cause I've done array_merge's before.
It's something with my syntax. Any ideas? Thanks in advance!
ADDED INFORMATION:
By doing this:
## Order History
$q47 = "SELECT OCODT AS COMPDT, ORDNO AS ORDER, ORQTY AS OQTY, QTYRC AS RQTY
        FROM AMFLIBP.MOHMST WHERE FITEM='$id' AND FITWH='$wh'";

$stmt47 = db2_prepare($con, $q47);
$result47 = db2_execute($stmt47);
while($fin47 = db2_fetch_array($stmt47))
{var_dump($fin47);}

I get:
array(4) { [0]=> string(7) "1090225" [1]=> string(7) "M703760"
           [2]=> string(6) "20.000"
           [3]=> string(6) "20.000" } array(4) { [0]=> string(6) "960614"
           [1]=> string(7) "M802110"     [2]=> string(7) "340.000"
           [3]=> string(4) ".000" }

Also, When I try what was suggested bellow:
$q47 = "SELECT OCODT AS COMPDT, ORDNO AS ORDER, ORQTY AS OQTY, QTYRC AS RQTY
        FROM AMFLIBP.MOHMST WHERE FITEM='$id' AND FITWH='$wh'";

$stmt47 = db2_prepare($con, $q47);
$result47 = db2_execute($stmt47);
while($fin47 = db2_fetch_array($stmt47))
{$array[] = $fin47;}
print_r($array);

I get this:
Array ( [0] => Array ( [0] => 1090225 [1] => M703760 [2] => 20.000 [3] => 20.000 )
        [1] => Array ( [0] => 960614 [1] => M802110 [2] => 340.000 [3] => .000 ) )

Which works but loses my column names?

A: This line:
while($fin47 = db2_fetch_array($stmt47));

is overwriting each value of $fin47 with the next row from your SELECT. What you should have done is:
$fin47 = array();
while($fin47[] = db2_fetch_array($stmt47));

However, this seems a needlessly complex way to do things. You can extract your data in the form you want with one query, meaning all your PHP code is not required.
$fin47 = array();
$query = "SELECT OCODT AS COMPDT, ORDNO AS ORDER, ORQTY AS OQTY, QTYRC AS RQTY, null as VNDR FROM AMFLIBP.MOHMST WHERE FITEM='$id' AND FITWH='$wh'".
" UNION ALL ".
"SELECT DOKDT AS COMPDT, ORDNO AS ORDER, QTYOR AS OQTY, DKQTY AS RQTY, VNDNR AS VNDR FROM AMFLIBP.POHISTI WHERE ITNBR='$id' AND HOUSE='$wh'".
" ORDER BY COMPDT";
$stmt = db2_prepare($con, $query);
$result = db2_execute($stmt);
while($fin47[] = db2_fetch_array($stmt));

Note: I've added a dummy value for VNDR in the first SELECT to match the number of columns for the UNION. In the resulting array these will appear as null values.

A: This loop will overwrite your variable on each run. It won't collect the rows. And in the last run it will leave with false assigned.
while($fin47 = db2_fetch_array($stmt47));

What you ought to be doing is:
while($fin47 = db2_fetch_array($stmt47)) {
    $array[] = $fin47;
}

And in your second while you could append to the same array. Thus your merging becomes redundant.

A: What is the raw output of $fin47 and $fin48?
Have you tried doing a simple + on the values:
$array = $fin47 + $fin48;

EDIT Then why not do this. I have added arrays called $fin47_results and $fin47_results and set the while loop in each query to add the values from $fin47 and $fin48 to them:
## Order History
$q47 = "SELECT OCODT AS COMPDT, ORDNO AS ORDER, ORQTY AS OQTY, QTYRC AS RQTY FROM AMFLIBP.MOHMST WHERE FITEM='$id' AND FITWH='$wh'";
$stmt47 = db2_prepare($con, $q47);
$result47 = db2_execute($stmt47);
$fin47_results = array();
// while($fin47 = db2_fetch_assoc($stmt47)) {
while($fin47 = db2_fetch_array($stmt47)) {
  $fin47_results[] = $fin47;
}

$q48 = "SELECT DOKDT AS COMPDT, ORDNO AS ORDER, QTYOR AS OQTY, DKQTY AS RQTY, VNDNR AS VNDR FROM AMFLIBP.POHISTI WHERE ITNBR='$id' AND HOUSE='$wh'";
$stmt48 = db2_prepare($con, $q48);
$result48 = db2_execute($stmt48);
$fin48_results = array();
// while($fin48 = db2_fetch_assoc($stmt48)) {
while($fin48 = db2_fetch_array($stmt48)) {
  $fin48_results[] = $fin48;
}

$array = array_merge($fin48_results, $fin48_results);
print_r($array);

If you notice I also added—but commented out—calls for db2_fetch_assoc since your end goal & raw dataset is unclear. But this should work.


Councils and town halls up and down the country are facing average cuts of 1.8 per cent in central government funding next year it has been announced.
But Birmingham is expecting to be among the worst hit by cuts of more like six per cent, which it is claimed have a greater impact on major cities and urban areas.
Local Government minister Kris Hopkins told MPs that councils would still have 'considerable spending power' under the funding agreement, before adding that no single council will lose more than 6.4 per cent of its spending power in 2015/16.
Councillor Sir Albert Bore, leader of the council said Birmingham was, as expected, set for cuts of about £100 million.
He said: "The figures are broadly in line with what we were fearing, so we will still need to make the level of cuts that were set out recently in our White Paper. I am extremely disappointed that the Government has not responded to Birmingham's proposal, which had cross-party support, for a fairer approach to the distribution of grant cuts.
"The cuts confirmed today are equivalent to almost £160 per dwelling and the cut is the greatest of all eight core cities in the country. This essentially echoes the warnings we issued when our budget white paper was published last week.
The majority of bulk of local authorities' spending power comes from grants from central government, with around a quarter raised from council tax. By contrast Birmingham, with high levels of deprivation and a proportionately low number of high value properties, raises just eight per cent of its funding from council tax.
Tory minister Mr Hopkins said: "In the context of this unprecedented challenge to public finance we have yet again delivered a settlement that is fair for all parts of the country, whether North or South, urban or rural.
"English local government is expected to spend over £114 billion this year, around a quarter of all public spending.
"This settlement therefore recognises that local authorities continue to make a vital contribution in helping pay off the deficit.
He added that council's facing the highest demands for services will receive more funding.
Birmingham City Council last week announced plans for a £117 million cut in spending on services in 2015/16. Of which £72 million were new cuts resulting the loss of about 1,100 jobs. Finance chiefs, who are today looking at the Government figures, do not expect this to change significantly following the Government announcement.
Speaking at a budget consultation event at The Mac in Cannon Hill Park, council leader Sir Albert Bore said: "The £117 million in cuts to come is on top of £462 million in earlier cuts.
The national body representing town hall bosses, the Society of Local Authority Chief Executives and Senior Managers (SOLACE) warned councils are at breaking point.
Solace director Graeme McDonald said: "This settlement reminds us that the financial challenge facing local government is immense. Cuts of up to 6.4 per cent will push some authorities to breaking point.