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The Marines have Lower Physical Requirements for Women they're Integrating into Combat
Women serving in the military in Iraq were issued rape whistles. To protect themselves from their fellow soldiers. They needed the whistle to call for help. As they could not depend on being strong enough to fight off a rapist. Or a gang of rapists. Which illustrates a point about men and women. They're different. Men are bigger and stronger than women. So women were given rape whistles to call for help when a bigger and stronger man tried to rape her.
Of course, that whistle won't do much good in combat. Which is where the left wants to put women in the military. In roles that have been until now reserved solely for physically strong men. Who can do 3 pullups. Or more (see Marines delay female fitness plan after half fail by AP posted 1/2/2014 on USA Today).
Starting with the new year, all female Marines were supposed to be able to do at least three pullups on their annual physical fitness test and eight for a perfect score. The requirement was tested in 2013 on female recruits at Marine Corps Recruit Depot, Parris Island, S.C., but only 45 percent of women met the minimum, Krebs said.
The Marines had hoped to institute the pullups on the belief that pullups require the muscular strength necessary to perform common military tasks such as scaling a wall, climbing up a rope or lifting and carrying heavy munitions.
Officials felt there wasn't a medical risk to putting the new standard into effect as planned across the service, but that the risk of losing recruits and hurting retention of women already in the service was unacceptably high, she said.
Because the change is being put off, women will be able to choose which test of upper-body strength they will be graded on in their annual physical fitness test. Their choices:
• Pullups, with three the minimum. Three is also the minimum for male Marines, but they need 20 for a perfect rating.
• A flexed-arm hang. The minimum is for 15 seconds; women get a perfect score if they last for 70 seconds. Men don't do the hang in their test…
Military brass has said repeatedly that physical standards won't be lowered to accommodate female applicants. Success for women in training for the upcoming openings has come in fits and starts.
But you are. If you have different requirements for men and women you have lowered the standards for women. Which will not only put their fellow Marines at risk. But it will put these women at a disadvantage with the enemy. Because blowing your rape whistle won't stop the enemy from beating you to death.
There are many roles women can serve in the armed forces. Even in combat zones. From pilots to sappers. And they have. So close to the combat that they've been getting killed and maimed serving their country just like men. But putting them into infantry units will get a lot of them killed. Imagine a wounded Marine outside a foxhole exposed to enemy fire. Who can drag that Marine safely into the foxhole quicker? The Marine who can't do 3 pullups? Or the Marine that can do 20 pullups? If a man is in that foxhole he may be able to reach out and grab that wounded Marine with one hand. And drag him quickly into the foxhole. While if it's a woman in that foxhole she may have to get out completely and expose herself to enemy fire as she uses both hands to slowly drag that wounded Marine to safety. And likely getting shot in the process.
Soldiers need to be strong. The stronger the better. And the more likely he or she will kill the enemy before the enemy kills him or her. There should not be different requirements for men and women. There should be only one requirement. For Marines. If women want to fight in combat they should be as strong as men. Or they shouldn't be there. Just like we don't have women in the NFL. Which isn't as hard as being a soldier.
Posted in Military, Week in Review, Women - Comments Off on The Marines have Lower Physical Requirements for Women they're Integrating into Combat
Tags: combat, enemy fire, female Marines, infantry, Marines, pullups, rape whistle, soldier, upper-body strength, women
The Left Hates the Military, Repeals 'Don't Ask, Don't Tell'
Posted by PITHOCRATES - December 31st, 2010
The Effete Left Retaliates for all those Wedgies
The liberal left hates the military. Always have. Always will. It's the manliness of the soldier these effeminate men hate. Being weak on testosterone, the effete male tucks his tail between his legs and scurries away in the presence of the alpha male. When they were in grade school getting wedgies. When girls rejected them in high school. Or when a woman's husband caught them in an adulterous act. They ran away. They didn't fight. Which is why they hate the military. Because they will fight to protect themselves. Their fellow soldiers. Their family. God. And country.
The Left has always had the military in their crosshairs. To defund it as much as possible. To boot ROTC off college campuses. To protect the rights of a Muslim extremist in the U.S. Army that went on a murdering rampage on an Army post. Anything to destroy the military. They just don't like it. So when they fought to repeal 'don't ask, don't tell', they didn't do it to help gays who want to serve in the military. They did it to further damage the military. At least, that is their hope.
They hate gay soldiers as much as they hate straight soldiers. Because a gay soldier is still an alpha male. A tough guy. Willing to fight to protect himself, his fellow soldiers, his family, God and country. Everything that the effete left hates. They see a gay soldier as just another tough guy that probably kicked their ass back in high school. No, they pushed for this because a lot in the military were against it. Not because they're all homophobes. But because it will radically change the military.
War is Hell and not for the Effete
To take boys and make them into soldiers in a short time requires a little shock and awe. Training is hard. And horrible. The more horrible it is the less horrible actual combat will be. That's how you make boys into men. Desensitize them. How you keep them from panicking while chaos reigns all around them. It's how you keep soldiers alive in combat.
Marine basic training was pretty harsh during the Vietnam War. They've since lightened up a little since that time portrayed by R. Lee Ermey in Full Metal Jacket. Ermey was in fact a drill instructor in the U.S. Marine Corps. And he served in Vietnam. Much of his lines in that movie were ad lib. Drawn from his personal experience. He was a real bastard in the movie. But a great drill instructor. I met Ermey at an air show one summer. While I waited in line to get his autograph, there were Marines ahead of me past and present. What did they want? They wanted Ermey to tell them to drop and give him 20. And he did. It was a high honor indeed for these Marines. He's a god to them. Because he made tough Marines. Ermey's the real deal. And, though retired, he still serves his beloved Corps. Once a Marine, always a Marine.
So what did these men go through in basic training? Something like this (WARNING: The following video contains explicit language and adult content):
http://www.youtube.com/watch?v=TLDaZvTfU9k
Now, imagine Sergeant Hartman dressing down an openly gay man in that scene. And how fast the ACLU would file suit.
You can say that much of what he said and done was inappropriate. But when you're training killers, you emphasize the chest thumping, testosterone teeming, alpha-male manly stuff. So you call recruits ladies. And homosexuals. Until they prove themselves lean, mean and tough as mother [deleted expletive] who want to cut out the enemy's living guts and use them to grease the treads of their tanks. That last was borrowed from the movie Patton. And that classic George C. Scott scene can be seen here:
War is hell. And a manly thing. It is not for the faint of heart. As William Tecumseh Sherman said, the more horrible it is, the quicker it will be over. And the less lives lost. An effete liberal male, on the other hand, disdains such brutality. They'd prefer to sit down with our enemies and resolve our differences through diplomacy. Like the Allies did with Hitler. Who lied. We gave him the Sudetenland. And he took the rest of Czechoslovakia. Then Poland, launching World War II. After we got his word that he wouldn't.
The Ivy League Hates the Military and ROTC
There are some tough gay mother [deleted expletive] serving in the military. But they've been hiding their sexuality. Which for the above reasons is a good thing. Now they've repealed 'don't ask, don't tell'. So now when a drill instructor slips and calls a recruit a lady or a homosexual, it'll be a problem. The Left will slip someone into basic training for just that reason. So they can sue the military. Because they hate the military. It's all that pent up frustration from all those wedgies.
The Ivy League hates the military. They've kept ROTC off their campuses. Because, they said, the military discriminates against gays. Now that Obama has repealed 'don't ask, don't tell', will they welcome ROTC onto their campuses? No. Because they hate the military (see 'Don't ask, don't tell' has been repealed. ROTC still shouldn't be on campus. by Colman McCarthy posted 12/30/2010 on The Washington Post).
To oppose ROTC, as I have since my college days in the 1960s, when my school enticed too many of my classmates into joining, is not to be anti-soldier. I admire those who join armies, whether America's or the Taliban's: for their discipline, for their loyalty to their buddies and to their principles, for their sacrifices to be away from home. In recent years, I've had several Iraq and Afghanistan combat veterans in my college classes. If only the peace movement were as populated by people of such resolve and daring.
Bull [deleted expletive]. He may admire a Taliban soldier, for they are killing American soldiers, but he hates American soldiers. Who was it spitting on U.S. troops returning from Vietnam and calling them 'baby killers'? He and his fellow college students. That's who.
ROTC and its warrior ethic taint the intellectual purity of a school, if by purity we mean trying to rise above the foul idea that nations can kill and destroy their way to peace. If a school such as Harvard does sell out to the military, let it at least be honest and add a sign at its Cambridge front portal: Harvard, a Pentagon Annex.
Taint the intellectual purity of a school? Give me a break. The pompous and condescending Ivy League has tainted the intellectual and moral purity of a nation. These people haven't done a damn thing to make America great. It's the soldiers that have done that. As Charles Province says so well:
It Is The Soldier
It is the Soldier, not the minister
Who has given us freedom of religion.
It is the Soldier, not the reporter
Who has given us freedom of the press.
It is the Soldier, not the poet
Who has given us freedom of speech.
It is the Soldier, not the campus organizer
Who has given us freedom to protest.
It is the Soldier, not the lawyer
Who has given us the right to a fair trial.
It is the Soldier, not the politician
Who has given us the right to vote.
It is the Soldier who salutes the flag,
Who serves beneath the flag,
And whose coffin is draped by the flag,
Who allows the protester to burn the flag.
Charles Michael Province, U.S. Army
The Left Hopes Gays will Hurt the Military
God bless the soldiers. The Marines. The sailors. The airmen. And all who serve.
If you hate the military you hate the people in the military. No matter how you try to spin it. Do you think a liberal would let his daughter marry a soldier? Would Colman McCarthy welcome a soldier into his family? Or would he sneer with contempt? I'm guessing the contempt thing. So they don't like the military. Or the people serving. And if you do, everything you do is against the military.
And so it is with their fight to repeal 'don't ask, don't tell'. They're probably laughing and making gay jokes just waiting for all the trouble to start.
Posted in Equal Opportunity, War and Peace - Comments Off on The Left Hates the Military, Repeals 'Don't Ask, Don't Tell'
Tags: alpha male, American soldiers, basic training, Charles Province, don't ask don't tell, drill instructor, effeminate men, effete left, effete male, Ermey, gay soldiers, gays in the military, God bless the soldiers, It is the Soldier, liberal Left, military, military discriminates against gays, openly gay, Patton, R. Lee Ermey, ROTC, Sergeant Hartman, soldier, the Left, U.S. Army, U.S. Marine Corps, war is hell


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Vincent Brümmer (30 December 1932 – 30 March 2021) was a South African-born Christian theologian who worked for most of his career in the Netherlands. From 1967 to 1997 he was the Professor of Philosophy of Religion at the University of Utrecht.

Brummer was born in Stellenbosch. He held degrees from Stellenbosch University, Harvard, and Utrecht University, also working as a research assistant at the University of Oxford for a year (1961-1962). On 27 May 1994 Brümmer received an honorary doctorate from the Faculty of Theology at Uppsala University, Sweden. In 1998, he received an honorary doctorate in divinity from Durham University.

Brümmer died on 30 March 2021, aged 88.

Further reading
 Brümmer on meaning and the Christian faith: collected writings of Vincent Brümmer. Vincent Brümmer, Ed. John R. Hinnells. Ashgate Publishing, 2006. .
 Christian faith and philosophical theology: essays in honour of Vincent Brümmer presented on the occasion of the twenty-fifth anniversary of his professorship in the philosophy of religion in the University of Utrecht. Eds. Gijsbert van den Brink, Luco J. van den Brom, Marcel Sarot. Kok Pharos Pub. House, 1992. .
 Theology and Philosophical Inquiry: an Introduction. Vincent Brümmer. Westminster John Knox, 1982. .
 Speaking of a Personal God: an Essay in Philosophical Theology. Vincent Brümmer. Cambridge University Press, 1992. .
 The Model of Love: a Study in Philosophical Theology. Vincent Brümmer. Cambridge University Press, 1993. .
 Atonement, Christology and the Trinity: Making Sense of Christian Doctrine. Vincent Brümmer. Ashgate Publishing, 2005. .
 What are we doing when we pray? a Philosophical Inquiry. Vincent Brümmer. (1st published SCM, 1984). Ashgate Publishing, 2008. .
 Interpreting the Universe as Creation: a Dialogue of Science and Religion. Vincent Brümmer. Kok Pharos Pub. House, 1991. .
 Transcendental Criticism and Christian Philosophy: a Presentation and evaluation of Herman Dooyeweerd's "philosophy of the cosmonomic idea" (University Utrecht, Ph.D. thesis, 1961)

References

Brümmer's Worldcat identity
Brümmer's bio

1932 births
2021 deaths
South African philosophers
Philosophers of religion
Academic staff of Utrecht University
People from Stellenbosch
Harvard University alumni
Utrecht University alumni
South African expatriates in the Netherlands
Afrikaner people

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COHEN, RANDY
COHEN, RANDY. [1997] The ethicist behind "The Ethicist," a weekly column in The New York Times Magazine. Cohen penned these entries for Slate shortly after being fired as head writer of The Rosie O'Donnell Show. They were published in The Slate Diaries, edited by Jodi Kantor, Cyrus Krohn, and Judith Shulevitz. Introduction by Michael Kinsley. New York, Perseus Book Group, 2000. Copyright © 2000 by Michael Kinsley. Reprinted by permission of Public Affairs, a member of the Perseus Books Group.

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Home » Musicals » The Wrong Man
Songwriter Ross Golan and Hamilton's director Thomas Kail come together to tell a contemporary story of a man framed for murder starring the extraordinary Joshua Henry.
Posted on October 10, 2019 by Sheila Kogan in Musicals, Off-Broadway
Ciara Renée and Joshua Henry in a scene from the new musical "The Wrong Man" Robert W. Wilson MCC Theater Space's Newman Mills Theater (Photo credit: Matthew Murphy)
The Wrong Man is a new musical by multi-platinum songwriter Ross Golan with Hamilton's director Thomas Kail. Like Hamilton, it began as a concept album and grew into a stage performance. Unlike Hamilton's epic sweep of history, this subject is contemporary and has a narrower focus, following the fortunes of one man, Duran, who is down on his luck in Reno, Nevada. The intimate setting of The Robert W. Wilson MCC Theater Space's Newman Mills Theater is a good place to show off the production.
There is no spoken dialogue. Does that make The Wrong Man a modern opera or a dramatic concert? It's difficult to categorize. However, the story that Ross Golan devised is told entirely through the poetic lyrics that he wrote, to the music that he composed – a triple threat. It means that one has to concentrate a little more than usual for the dramatic intention to become clear. At first, there's little about this guy, Duran, that might make an audience care. He's just struggling to get by, and seems to have a lot of bad luck – but even a loser doesn't deserve to be arrested for a murder he didn't commit. The clever, unexpected twist of plot ratchets up emotional investment.
The music includes a variety of styles, more rhythmic than tuneful. Sometimes a song seems ethnic, for instance, the way the mandolin might give an Italian feel. The songs are often subtle, but rich, which suggests that listening to a cast recording could reveal layers and additional aural discoveries. No doubt the music is enhanced by the arrangements and orchestrations of Alex Lacamoire. But the best reason the songs work is because they are sung-through by the extraordinarily talented Joshua Henry who plays the main character, Duran. Henry is on stage and singing during most of the performance in this intense role. He has a glorious voice and is a powerhouse of emotion and stage presence; his vocal stamina is astonishing. If you saw him as Billy Bigelow in the recent production of Carousel, then you may be aware of his abilities. If not, then you'd better get to the MCC Theater Space before this limited run is over.
Ryan Vasquez (center) and the cast of the new musical "The Wrong Man" Robert W. Wilson MCC Theater Space's Newman Mills Theater (Photo credit: Matthew Murphy)
Ciara Renée, who has a clarion voice and a contemporary sexiness, provides a good dramatic match for Henry. And Ryan Vasquez, who plays Man in Black, creates a strong character – one of those you love to hate. (He plays Duran during specific performances during the run and it would be interesting to see him in that role.)
Similar to Hamilton, there is always movement. Is this director Thomas Kail's signature trait? It's an effective, creative staging technique that provides a cohesiveness as well as non-verbal clues to the action. Sometimes it's the moving of chairs that indicates a change of location, or synchronized gestures by the small, diverse ensemble of actors. Occasionally, it's paralleled action or comment through the sharp, taunt choreography of Travis Wall performed by the excellent, trained dancers, Tilly Evans-Kruger and Kyle Robinson. The stage never seems completely still.
The minimalist set, designed by Rachel Hauck, is in place as the audience enters, with no curtain. At the center back is a glass booth where the drums can be seen (and perhaps heard less). Next to it are the chairs for the musicians who play a variety of instruments. There are risers on two sides for audience members, and the back walls on three sides are striped with neon lights that artfully change colors and patterns throughout the performance. The few moveable chairs and benches are the only physical props. Otherwise, the playing areas are created by the dramatic use of highlighted light, shadow and spotlights, designed by Betsy Adams.
Joshua Henry (center) and the cast of the new musical "The Wrong Man" Robert W. Wilson MCC Theater Space's Newman Mills Theater (Photo credit: Matthew Murphy)
The costumes by Jennifer Moeller and Kristin Isola have an off-the-street, everyday sensibility that fit well with the story and characters.
This pared-down, spare production may not be for those who prefer glitzy Broadway shows or old-fashioned book musicals, but it is for Ross Golan fans, for those who admire theatrical craftmanship, for those who may want to keep current in theater trends, and especially for those who will want to say that they saw this very special bravura performance of Joshua Henry.
The Wrong Man (extended through November 24, 2019)
The Robert W. Wilson MCC Theater Space's Newman Mills Theater, 511 West 52nd Street in Manhattan
For tickets, call 646-506-9393 or visit http://www.mcctheater.org
Running time: 90 minutes with no intermission
Alex Lacamoire
Betsy Adams
Jennifer Moeller
Joshua Henry
Kristan Isola
Kyle Robinson
Matthew Murphy
Rachel Hauck
Ryan Vasquez
The Robert W. Wilson MCC Theater Space's Newman Mills Theater
Thomas Kail
Tlilly Evans-Kruger
Travis Wall
About Sheila Kogan (11 Articles)
Writer Sheila Kogan has written theater, film and dance reviews for Zealnyc.com, Cinespect.com and Script Magazine. As a writer and producer, she has worked on film and television projects all around the world, from New York to China. A member of the Writers Guild of America East, she is currently developing her own projects.
Fanciful and poetic play about dreams and dreaming in the city of Paris will either make you love it or hate it.
An entertaining but flawed new musical, one that probably won't be mentioned in theater history books as an artistic advance.
Curvy Widow
The always-reliable Nancy Opel in a new, autobiographical musical by Bobby Goldman, about coping with the death of her husband, the playwright James, when she was 55 years old.
Mlima's Tale
A heart-breaking examination of the illegal trade in ivory by two-time Pulitzer Prize winning playwright Lynn Nottage.
Tick, Tick… BOOM!
Jonathan Larson's revised autobiographical work is a minor but pleasant curiosity. This fitfully compelling revival is well staged and amiably performed.


text:
[![Build Status](https://travis-ci.org/AzureAD/azure-activedirectory-library-for-ruby.png?branch=master)](https://travis-ci.org/AzureAD/azure-activedirectory-library-for-ruby)
[![Code Climate](https://codeclimate.com/github/AzureAD/azure-activedirectory-library-for-ruby/badges/gpa.svg)](https://codeclimate.com/github/AzureAD/azure-activedirectory-library-for-ruby/badges/gpa.svg)

The ADAL for Ruby library makes it easy for Ruby applications to authenticate to AAD in order to access AAD protected web resources.

## Installation

You can install the ADAL gem with Rubygems.

```
gem install adal
```

Alternatively, you can build the gem from scratch.

```
git clone git@github.com:AzureAD/azure-activedirectory-for-ruby.git
cd azure-activedirectory-for-ruby
gem build adal.gemspec
gem install adal
```

## Samples

The `samples` folder contains several applications demonstrating different ways to authenticate. None of the samples will work out of the box, they require set-up and configuration through the Azure portal. Make sure to check out the README for each sample to get them running.

## How to run tests

The tests in this repo use the RSpec framework for behavior-driven testing. RSpec can be invoked directly or as a Rake task. The preferred way to execute the test suite is

Checkout the repo

`git clone git@github.com:AzureAD/azure-activedirectory-library-for-ruby`

Install the dependencies

`bundle install`

Run the tests

`bundle exec rake spec`

## How to run Rubocop

This gem abides by the [Rubocop](https://github.com/bbatsov/rubocop) defaults. Rubocop is set up as a Rake task. The preferred way to execute Rubocop for this repo is

Checkout the repo

`git clone git@github.com:AzureAD/azure-activedirectory-library-for-ruby`

Install the dependencies

`bundle install`

Run Rubocop

`bundle exec rake rubocop`

## Diagnostics

**Logs, correlation ids and timestamps are required with all requests for help in debugging.**

You can configure ADAL to generate log messages that you can use to help diagnose issues. The log outputs are standard to Ruby's built-in logger. An example ADAL log message looks like this:

```
I, [2015-08-18T06:58:12.767490 #9231]  INFO -- 969f3e30-8f42-4342-b135-f5c754a6b4a8: Multiple WS-Trust endpoints were found in the mex response. Only one was used.
```

The `I` is a shorthand for `INFO` that makes parsing logs easier. ADAL supports five different logging levels, `VERBOSE`, `INFO`, `WARN`, `ERROR` and `FATAL`. The timestamp is taken from the client machine. The GUID before the message is a correlation id that is used to track logs from the client to the server.

To set the lowest log level to output, include something like this in your configuration:

```
ADAL::Logging.log_level = ADAL::Logger::VERBOSE
```

By default, ADAL logs are printed to `STDOUT`. To change the log output, pass a Ruby `IO` object to ADAL like this in your configuration:

```
ADAL::Logging.log_output = File.open('/path/to/adal.logs', 'w')
```

## Community Help and Support

We leverage [Stack Overflow](http://stackoverflow.com/) to work with the community on supporting Azure Active Directory and its SDKs, including this one! We highly recommend you ask your questions on Stack Overflow (we're all on there!) Also browse existing issues to see if someone has had your question before.

We recommend you use the "adal" tag so we can see it! Here is the latest Q&A on Stack Overflow for ADAL: [http://stackoverflow.com/questions/tagged/adal](http://stackoverflow.com/questions/tagged/adal)

## Security Reporting

If you find a security issue with our libraries or services please report it to [secure@microsoft.com](mailto:secure@microsoft.com) with as much detail as possible. Your submission may be eligible for a bounty through the [Microsoft Bounty](http://aka.ms/bugbounty) program. Please do not post security issues to GitHub Issues or any other public site. We will contact you shortly upon receiving the information. We encourage you to get notifications of when security incidents occur by visiting [this page](https://technet.microsoft.com/en-us/security/dd252948) and subscribing to Security Advisory Alerts.

## Contributing

All code is licensed under the MIT license and we triage actively on GitHub. We enthusiastically welcome contributions and feedback. You can fork the repo and start contributing now. [More details](https://github.com/AzureAD/azure-activedirectory-library-for-ruby/blob/master/contributing.md) about contributing.

## License

Copyright (c) Microsoft Corporation. Licensed under the MIT License.

## We Value and Adhere to the Microsoft Open Source Code of Conduct

This project has adopted the [Microsoft Open Source Code of Conduct](https://opensource.microsoft.com/codeofconduct/). For more information see the [Code of Conduct FAQ](https://opensource.microsoft.com/codeofconduct/faq/) or contact [opencode@microsoft.com](mailto:opencode@microsoft.com) with any additional questions or comments.

redpajama_set_name: RedPajamaGithub


Title of the website for www.junglee.com is Buy and Sell: Refurbished, Used, Unboxed Mobiles, Books and more at Junglee by Amazon. Beside site title it's has description Online Shopping and Selling: Refurbished, Used, Unboxed Mobiles, Books and more at Junglee by Amazon in Bangalore. Post free ad, sell old mobiles, books, tablets, laptops with fast delivery by amazon. Buy used mobiles, books, tablets, laptops and more with cash on delivery (COD). Free Classifieds. In the keywords cloud for this site most using keyword is used. Site language is and it's located in 178.236.4.113. This site looks like running fast and mc speed is 906.


Sometimes golf gets a little repetitive and boring, to make your next round of golf a little more interesting, try one of these fun golf games to help even the most amateur golfer stay interested in the next 18 holes.
There are many types of games to play on the golf course : 2-player golf games, 3-player golf games, 4-players golf games, partner golf games, and games where everyone competes against everyone. If you can't make it through tour qualifying school, have some fun with your friends the next time you tee it up.
If you have a game that you play on the golf course that you would like to add to this list, please describe it in the guestbook at the bottom of the page. My golf buddies and I love to try out new games.
This is a great golf game to play with equal or unequal talents. This is not a good game to play if one golfer is significantly better than others. The premise of the game is that someone is the wolf and gets to pick their partner. As each golfer tees off, the wolf decides whether to pick that golfer as their partner, or wait for the next golfer to tee off.
When the first golfer tees off, the wolf decides if that will be their partner.
When the second golfer tees off, the wolf can no longer pick the first golfer and decides if the second golfer is their partner.
When the third golfer tees off, the wolf can no longer pick the first nor second golfer as their partner. The wolf makes a decision at this point whether to pick the third person as their partner or to go it alone as the lone wolf.
The wolf tees off last.
If the wolf picks a partner, the wolf and the partner must beat, no ties, the other two players to win the hole otherwise the other pair win the hole.
If the wolf decides to be the lone wolf, the wolf's score must beat, no ties, all the other players to win the hole, otherwise the other three win the hole.
Keep track of the winner(s) on each hole and add up at the points at the end. The player with the most points is the Lone Wolf winner.
Every player has a length of string equal to their current handicap eg 28 feet = 28 handicap and so on. Each player can use the string to get themselves out of trouble eg out of a trap, a bad lie, back in bounds, from behind a tree etc. However, every time the string is used the player has to cut off, or tie a knot the distance the ball is moved. For example, the golfer moves a ball from a sand trap and uses 5 feet of string. He cuts off 5 feet and if the golfer's handicap was 15, the golfer now only has 10 feet of string left. String can't be used on the green or the tee! Rewards for the end of the ran can be players with no string used or most times used, or devise other devious methods of punishment!
This next game is called, golf game badges, as each "bad" thing that happens on a golf course is assigned a badge. Each badge is assigned a point value and at the end the person with the least amount of points wins.
For example, let's say there are four badges and each badge is worth 1 point. If at the end of the round, a single golfer has all four badges, he has all four points and loses, and the other three players in the foursome wins. If every golfer ends up with one badge each, no one wins as everyone is tied with one point.
If Golfer 1 has two badges, Golfer 2 has one badge, Golfer 3 has one badge, and Golfer 4 has no badges. Golfer 1 has two points, Golfer 2 and Golfer 3 has 1 point each, and Golfer 4 has no points. Golfer 4 wins.
To make it more interesting you can assign different point amounts to each badge.
The Snake Badge - Given to the last golfer to 3-putt a hole.
This game turns around in the blink of an eye. I played this game and had the Fish, OB, Crab, and Snake badges going into the 18th hole. When the hole was finished, I had none.
The skins game is played with three or four golfers.
The PGA puts on a skins event every year after the season, usually aired over the Thankgiving weekend. The skins game is played exactly like this.
Each hold is assigned a point value. Usually the first six holes are assigned a low value, the middle six holes are assigned a middle value, and the last six holes are assigned a higher value.
The premise is that if you beat all members of your foursome you win a skin. The game starts on the first hole. If someone in the foursome beats all others in the foursome the golfer wins the value of the skin for that hole. If at least two players tie, the skin carrys over to the second hole and all members of the foursome have a chance to win the 2nd hole value in addition to the 1st hole value on the 2nd hole.
Keep track of the value of each skin a golfer wins. The golfer with the highest number of points wins.
Scramble is usually played during a golf outing where everyone in the foursome is on the same team and you are playing against the other foursomes in the golf outing. This can also be a 4-player game, where two players are teamed up, either way the rules are the same.
You start off on the tee, and each player hits his/hers tee shot. The team decides what shot was the best, and everyone plays their next shot from this point on the golf course. This goes on until the ball is in the hole. You essentially get four shots from the same place.
In a golf outing, low round is declared the winner.
For two-man game in a foursome, you can play low round and low hole similar to the doubles scoring.
Variations on scramble include, minimums for using each players ball on the tee or putting. For example, you have to use each player's ball off the tee a minimum of 3 times.
Scoring with doubles...most points wins after 18.
Aggregate score of doubles partners, with low score winning the hole.
Low individual score wins the hole for the partners.
Use both methods for 2 points per hole.
Variation on scoring: If a birdie wins the hole doubles the number of points. If an eagle wins the hold quadruples the number of points.
6-pack method - Every six holes switch partners, everyone in the foursome plays with everyone else in the foursome.
Vegas - Partners change every hole based on the position of the balls. The two golf balls on the left are partners against the two golf balls on the right.
Same partner throughout the round. Partners are picked based on golf ability.
This one is pretty simple. At the beginning of the round, pick three golf clubs from your bag which become the only clubs you can use the entire round. Strategy here is to pick a low iron, a mid iron, and maybe your putter. Or pick your three wood and use it as your putter. The game helps you think about managing your way around the golf course and being creative with your golf shots.
Play your normal round of golf, but when you get on the green you can either putt for the flag. OR you can putt over where the hole USED to be. It's fun for people that cannot chip that well. If you miss the flag and have a 20 foot putt to the flag, look around for a former hole and putt over that. You can slavage a couple bad shots with a Stinky par or a stinky birdie.
In the matter of honors on the next tee box a normal par or bogey takes precedent over a stinker.
Ok, here's one that I don't think you can play in the middle of the round, and I'm pretty sure if the golf marshall sees you do this, you'll be kicked off of the course.
"There is a driver of the golf cart, and a rider. All the carts line up in a row in front of the tee box. Someone counts down from 3 to start. The rider stands up, holds on to the cart, drops their golf ball on to the side, and hits it with a golf club of their choosing. Usually a chipper of some sort. Everyone tries not to run in to one another with their golf carts. If you come across someone else's golf ball you can hit it back. When you finally get on the green the driver jumps off (rider must sit on cart) and he/she runs up to try to hit their ball in. If they find an opponents ball they can throw it, kick it, hit it with their putter. Whatever! The first one to get their ball in wins. Obviously, you wouldn't want to be drinking EXCESSIVELY to play this golf game, as it's easy to run into someone else's cart. We usually do just one hole as a grand finale to our round. It's a lot of fun."
What was the last fun game you played on the golf course?
Bingo Bango Bongo is a great one too! It doesn't really matter if the talent level in your foursome is different as there are three ways to get a point on each hole. The first one on the green gets Bingo, after everyone is on the green whoever is closest to the pin gets Bango and whoever scores the best score gets Bongo. One point for each gives everyone a chance to get points. Sometimes being just off the green on your approach gives you a better chance at scoring Bango but maybe less of a chance of getting Bingo or Bongo.
Great lens. I do play sometimes and the Golf Cart Polo sounds like fun.
I don't play, but I do drive the cart for my husband... Hmmmm, Golf Cart Polo??? I'll remember that next time I have a rebellious streak! Great lens!
A great game if you have more than one group is 4,3,2,1. You "must" have an even number of players as in 8, 12, 16, etc. On each 9 you have to count the net scores of your team as follows: on 1 hole you count all 4 scores, on 3 holes you count 3 scores, on 3 holes you count 2 scores and on 2 holes you count 1 score. What makes it interesting is that you have to decide when you finish each hole what you are using. Hint - don't leave your 4 counter to the last hole, it can be disaster.
This is great for changing up the game a bit. Fun!
Loving the ideas - I get really bored sometimes, so this'll help alleviate that boredom.Thanks!
Great ideas for adding creativity on the golf course.
Awesome! I need to try these out soon!
Some good ideas here. Thanks for sharing.
Some cool ideas here. But a point about your "best ball" game. You are actually describing a scramble. The term "best ball" is used to describe a game where the player who has the best score for a given hole counts for the team. Each player plays their own ball throughout.
The nice thing about best ball is that you can keep track of your individual score while still having the team score.
A variation is the Texas Scramble in which all 4 players in a foursome tee off. They pick the best tee shot of the 4 but play individually for the rest of the hole. This can be helpful if you have some players who hit into the woods, water, OB. There is less time spent looking for lost balls.
Me and my friends love to enter Four Man Scramble tournaments. You can shoot really low, our lowest score was -18 at a course in Orlando, FL. It takes the pressure away as everybody hits from the same spot after choosing the best previous shot.
Ever hear of RED ball? Each team plays with a red ball, taking turns hitting it on each hole. At the end the team who has not lost their red ball puts it in a jar for a drawing. The balls are numbered with the team number in advance.
I had no idea, thanks!
Best Ball as you define it is called a scramble. Best ball is as it sounds, the lowest score on each hole is counted for the score of the team.
Golf cart polo sounds fun, but I agree you'd get kicked off pretty handily. Thanks for the great list.
I've been golfing for many years and have not heard of most of these game variations. Sounds like they could be fun though.
Great lens. It does get especially boring if you go to the same golf course and do the same thing over and over. My friends and I used to do three way best ball and have the loser buy the winner a meal. The middle man neither won or loss.
Some good ones in there, I'll have to try them out.
Great ideas... Thanks for sharing. I always play best ball.
I really liked your article. Best Ball is our favorite game on the course!
Will definitely give some of these a try with my foursome this spring.
I love golf so much, I never get bored out on the course. However you have discussed several games that I have never heard of before.
I have enjoyed reading your lens. I am a golfer and I just love the game. My youngest son who is 15 plays the game now. He has only been playing for 18 months and is down to a 5 handicap already. He want's to become a Pro.
I really enjoyed your article about golf games and will be back to read more.
Some great ideas here, will be having a chat with my friends this weeks and hopefully they will get involved with one or two of them.
I AM LOOKING FOR A PROGRAM THAT WILL GENERATE INSTRUCTIONS, PRINT SCORECARDS AND DISPLAY WINNERS WITH VARIOUS GAMES INCLUDED IN THE SOFTWARE. ANYONE KNOW OF A WINDOWS PACKAGE?
Great lens will try one of these games out on Saturday with my buddies.
has anyone come across a fun golf game called Monopoly where you have cards giving instructions for forfeits or bonuses i.e. play this hole with one club only or you have just won the Club championship - take 5 extra points, etc.??
Great lens! Some of these games I do/have played. Some I haven't heard of and are great ideas for future golf outings!
I love best ball! Actually lets me reach par.
Red ball is played with two foursomes or more. You mark a golf ball (red) or any color. Each foursome has to rotate the red ball so each player has to play the red ball the full hole. The next hole it is passed to the next player and that order is kept until game is complete. You compare the "red ball" score card and lowest score wins. One catch is you can't lose the red ball. If all groups lose the red ball the team holding it the longest is the winner.
Love your Lens, fantastic tips on varying up a round of golf, especially when playing with people of different levels. Thanks for the new ideas and best wishes!
These are nice element of fun to the golf games with some hilarious mulligan golf cards. Such lenses can boost the mindset of an amateur by having a good knowledge about the game of golf. Nice lens and best of luck for the future!
@anonymous: Why don't you play a tin whistle or stapleford. It works for all handicap ranges, I just did it for 12 gals with handicaps ranging from 10 to 40. You give them their strokes where they fall and for example you are a 40 handicap playing a par five, the player gets two strokes and they have an eight. Their net score was a six for a bogey and so they get one point. 1 point for a net bogey, 2 points for a net par, 3 for a net birdie, 4 for a net eagle. At the end of the round the person with the most points wins the $$$ or prize.
Interesting lens. Very informative. Best ball is still my favourite game.
These are great. I had never heard of them before. Can't wait to try some of these.
@anonymous: To speed up play - play step aside. All 4 hit and whichever shot you take that person steps aside until the next shot..
@anonymous: I just added a game called "Strings", which seems to be a good game if there are golfers with varying handicaps.
Usually when my friends and I go out golfing. We decide that we can only use one club for each hole. You don't have to tell your friends what club your using either. For example, you can tee off on a par 4 with a 6 iron, hit your approach with a 6 iron, and try to putt with a 6 iron. Or else we designate a club for a hole that we all must use during a hole. One time we designated a 52 degree on a par 5. It took 5 shots to get close to the green but it was fun.
When I was playing golf we enjoyed playing Best Ball but these other games are new to me. I enjoyed reading about them.
if you cant get to the course, then if you have the time & inclination, try the latest tiger woods 13 video game - it's almost as frustrating as playing the real game.
nice lens - see you on the 19th.
Great lens! I like the three club game.
It's called "Stink Hole". You play your normal round, but when you get on the green you can either putt for the flag. OR you can putt over where the hole USED to be. It's fun for people that cannot chip that well. If you miss the flag and have a 20 foot putt to the flag, look around for a former hole and putt over that. You can slavage a couple bad shots with a Stinky par or a stinky birdie.
Fitzs best ball. 1 point awarded to whose best is used including putt.Best shot always hits next.If the best sinks their putt, they add an extra point,2 points for a birdie,3 for an eagle and 4 for a double eagle. The difference between the high and other scores is paid to the high pointer by the others. Point value should be kept low($0.25/point) so as not to bankrupt new or struggling players.After all, this is to be fun.
Since I'm a terrible golfer and get bored at about the half way point...my favorite golf game is find the lost balls. It's like Easter Egg hunting for grown-ups.
I enjoyed this lens. I am passing it on to my two brother's who live at the golf course.
I live on a golf course. I might actually start to play now with these fun ideas!
Hi I do not know much about golf but we sure have some nice golf course in Al.I enjoyed reading this.
I don't play or know much about golf, but this was an interesting read and I like the idea of creating games within a game. Thank you for sharing those ideas.
I don't know much about golf. So, I don't have a favorite golf game, but I think this is a great lens. God bless!
LOL!!! I play "three clubs" a LOT!!! I'm not a good golfer, so I end up using my driver (no matter how close the green), my four hybrid and my putter! (I guess I do throw my pitching wedge in there from time to time too!) Thanks for sharing!
The only golf I play is miniature golf, but I found this lens to very interesting. I have friends who play "regular" gold and will share some of these games with with them.
My fiancee plays golf , I do not but I like to watch and ride. I really like the badges game:)!
I'm not much of a golfer, but these games sound fun.
Bingo, Bango, Bongo - There are 3 points available on each hole - First on the green gets a point, closest to the hole, first to sink their putt. The player with the most points at the end wins. You can build variations of this.
I will have to show this to my friend! He is an avid golfer!
Someone just recently suggested I start playing golf. Squidoo is a great resource!!!
Nice lens, thanks for the golf game ideas.
I played miniature golf once. The games you've showcased look like a lot of fun.
Thanks for this great lens and info. Add another element of fun to your golf games with my hilarious mulligan golf cards. Go here to download some free ones and try them out right away http://www.mulligangolfsite.com Here's wishing you fun on the golf course!
will try playing some of these on my next round!
I never played golf, but interested to try.
Thanks for some great ideas on this topic.


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Under our unique Government Aggregation Program, immixGroup serves as a centralized, neutral aggregation point for all sales into the public sector. Orders are sourced through immixGroup either as the sole source of supply or as a portal to an existing distributor at the direction of the manufacturer.
Regardless of the model used, our goal is the same: to provide you with access to our contracts and value-added resources to grow your business while minimizing administrative hassles, mitigating risk, and giving the manufacturer greater insight into channel activities.


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NUCLEAR PROPERTIES
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Development of Indian Press
"Press" generally refers to any media that provides news on national and international issues and various scientific developments. press is the voice of people living in a democratic nation like India. It plays a vital role in bringing the real picture of the society.
Freedom of press refers to freedom of speech and expression which is a fundamental right of every citizen. Liberty of people is not complete without this right. Press keeps an eye on the liberty of the people. Press serves the best in removing any harsh Government or to stand against dictatorship, anarchy and malpractices. it is because of these functions that press sometimes also referred as the necessary pre-condition to the fulfilment of democratic ideologies. The evolution of Indian Press are discussed below:
Coriolis Force–Derivation
In the previous article we discussed about some basics of Coriolis force which is an imaginary force experienced by an object moving relative to a rotating frame of reference. In the present article we have derived the formula for coriolis force and coriolis acceleration.
Rotating Frame of Reference
In rotating frame of reference which is considered as a special case of non-inertial frame of reference rotating relative to an inertial frame of reference. In this case the frame of reference is accelerating with respect to an inertial frame just a boy is rotating a stone tied to a string.
Rotating frame of reference is basically defined using three fictitious forces namely,
Books for IFS mains–Physics
India is the First country in the world which has initiated scientific management of its forests. The main aim of IFS is to implement the national forest policies which includes scientific management of forests to exploit them in an efficient manner along with maintaining environment stability and proper ecological balance which is essential for the sustenance of all flora n fauna including human beings. The responsibilities of an IFS officer are conservation, protection and development of wildlife and forests along with providing livelihood opportunities to various forest dependent tribes and communities. Read More…
AN INTRODUCTION TO LASERS
Lasers play a pivotal role in our daily life. One can find their use in everything from dental drills to high speed cutting machines. Laser beams are very much different from ordinary beam of light. In this article I would like to discuss about some of the fundamental facts about lasers like mechanism behind lasers operation, properties of laser, components of lasers and their uses in various fields.
by Gora
INDIAN FOREST SERVICES : PAPER ANALYSIS (PHYSICS)
India is one of the First countries in the world to have stated scientific management of its forests.The Indian Forest Service, one of the three All India Services, was constituted in the year 1966 under the All India Services Act, 1951 by the Government of India.The main mandate of the service is the implementation of the National Forest Policy which envisages scientific management of forests and to exploit them on a sustained basis for primary timber products, among other things. Since 1935 the management of the forests remained in the hands of the Provincial Governments and even today the Forest Departments are managing the forests of the country under the respective State governments.
All top positions in state forest department are held by IFS officers. Positions like Divisional Forest Officer (DFO), Conservator of Forests (CF) and Principal Chief Conservator of Forests (PCCF) etc are some examples.


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text:
Q: Ajax call uri for different url if condition I tried to create an ajax call POST url depend on the text input field from json response, here the current my ajax post
<script>
    $('#MyForm').submit(function(e){
        var service_type2 = document.getElementById('type').value;
        if(service_type2=== 'post'){
          $.ajax({
          type: "POST",
          url: services/post.php,
          data: $(this).serialize(),
          success: success
        });
        }else{
          $.ajax({
          type: "POST",
          url: services/pre.php,
          data: $(this).serialize(),
          success: success
        });

        }
        .done(function(data){

            // show the response

            $('#success__params').html("You data will be saved");

        })
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        });
        e.preventDefault();

        // to prevent refreshing the whole page page
        return false;

    });
</script>

If the input text value for #service has a value response "post", thank the first URL will execute (vice versa).
Tried using a buttons not working, and I tried above code but the page keep refresh, any suggestion? I tried following this discussion, but still not working
Sorry for bad english :(.

A: You've got a variable name mismatch:
var service_type2 = document.getElementById('type').value;
if(service_type2 === 'post'){ // service_type2, not type

And you must to pass a string (wrapped by quotes) to the url property: url: 'services/post.php'
And success property must be a function
success: function(data){
  // show the response
  $('#success__params').html("You data will be saved");
},

You probably have to remove .done() and fail() and add error property
error: function() {
  // just in case posting your form failed
  alert( "Posting failed." );
}

Final code:
<script>
    $('#MyForm').submit(function(e){
        e.preventDefault();
        var service_type2 = document.getElementById('type').value;
        if(service_type2 === 'post'){
          $.ajax({
            type: "POST",
            url: "services/post.php",
            data: $(this).serialize(),
            success: function(data){
              // show the response
              $('#success__params').html("You data will be saved");
            },
            error: function() {
              // just in case posting your form failed
              alert( "Posting failed." );
            }
          });
        }else{
          $.ajax({
            type: "POST",
            url: "services/pre.php",
            data: $(this).serialize(),
            success: function(data){
              // show the response
              $('#success__params').html("You data will be saved");
            },
            error: function() {
              // just in case posting your form failed
              alert( "Posting failed." );
            }
          });
        }
    });
</script>

redpajama_set_name: RedPajamaStackExchange


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We are constantly surrounded by negativity and it can affect our health if we don't know how to handle it. To live a happy, balanced life we must learn how to control our emotions and become a positive person.
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text:
\subsection*{Acknowledgements}
The authors appreciate the hospitality of NCTS, Taiwan, where parts of this work were carried out.
The first and third
authors were partially supported by JSPS KAKENHI Grant Numbers 25400112 and 26400093, respectively, and the second author by MOST 104-2115-M-009-003-MY2.

\section{Preliminaries}\label{S_Pre}
First of all, we will review the geometric Lorentz flow briefly.
See \cite{wi1,gw,wi2} for details.

Consider the square $\Sigma=\{(x, y)\in \mathbb{R}^2\,;\, |x|, |y|\leq 1\}$ and the vertical
segment $\Gamma=\{(0, y)\in \mathbb{R}^2\,;\, |y|\leq 1\}$ in $\Sigma$.
Let $\Sigma_\pm$ be the components of $\Sigma\setminus \Gamma$ with $\Sigma_\pm\ni (\pm1, 0)$.
A map $L:\Sigma\setminus \Gamma\to \Sigma$ is said to be a \emph{Lorenz map} if it is a
piecewise $C^2$ diffeomorphism which has the form
\begin{equation}\label{eqn_Lxy}
L(x, y) =(\alpha(x),\beta(x, y)),
\end{equation}
where $\alpha:[-1, 1]\setminus \{0\}\to [-1, 1]$ is a piecewise $C^2$-function with symmetric property
$\alpha(-x) = -\alpha(x)$ and satisfying
\begin{equation}\label{eqn_alpha}
\lim_{x\rightarrow 0+}\alpha(x) = -1,\ \alpha(1) < 1,\
\lim_{x\rightarrow 0+}\alpha'(x) = \infty,\ \alpha'(x) >\sqrt2
\end{equation}
for any $x \in (0, 1]$
(see Figure \ref{fig_1}\,(a)), and $\beta:\Sigma\setminus \Gamma\to [-1, 1]$ is a contraction in the $y$-direction.
Moreover, it is required that the images $L(\Sigma_+)$, $L(\Sigma_-)$ are mutually disjoint cusps in
$\Sigma$, where the vertices $\boldsymbol{v}_+$, $\boldsymbol{v}_-$ of $L(\Sigma_\pm)$ are contained in $\{\mp 1\}\times[-1, 1]$ respectively (see Figure \ref{fig_1}\,(b)).
\begin{figure}[hbt]
\centering
\scalebox{0.6}{\includegraphics[clip]{fig1}}
\caption{}
\label{fig_1}
\end{figure}

\begin{remark}[Historic behavior for the 1-dimensional Lorenz map]\label{r_Lorenz_map}
We denote the forward orbit of $x\in [-1,1]$ under $\alpha$ by $O^+(x,\alpha)$.
By Hofbauer \cite{ho}, the dynamics of $\alpha$ on $[-1,1]$ is described by a Markov partition on finite
symbols.
Let $s'$ be a periodic sequence of these symbols and $s''$ a sequence such that, for the point $x''$ of $[-1,1]$
corresponding to $s''$, the partial averages $\frac1{n+1}\sum_{i=0}^n\delta_{\alpha^i(x'')}$ converge
to the Lebesgue measure.
As in Takens \cite[Section 4]{ta1}, there exists a sequence $s_0$ of these symbols in which long initial
segments of $s'$ and those of $s''$ appear alternately and such that, for the point $x_0$ of $I$
corresponding to $s_0$, $O^+(x_0,\alpha)$ is dense in $[-1,1]$ and has historic behavior.
Then, by Dowker \cite{do}, there exists a historic initial set which is residual in $[-1,1]$.
\end{remark}

We identify the square $\Sigma$ and any subset of $\Sigma$ with their images
in $\mathbb{R}^3$ via the embedding $\iota:\mathbb{R}^2\to \mathbb{R}^3$ with $\iota(x,y)=(x,y,1)$.
A $C^2$-vector field $X_L$ on $\mathbb{R}^3$ is said to be a \emph{geometric Lorenz vector
field controlled by} the Lorenz map $L:\Sigma\setminus \Gamma\to \Sigma$ (\ref{eqn_Lxy}) if it satisfies the
following conditions (i) and (ii).
\begin{enumerate}[(i)]
\item
For any point $(x, y, z)$ in a neighborhood of the origin $\mathbf{0}$ of $\mathbb{R}^3$,
$X_L$ is given by the differential equation
\begin{equation}\label{eqn_Lf}
\dot x=\lambda x,\quad \dot y=-\mu y,\quad \dot z=-\nu z
\end{equation}
for some $\lambda>0$, $\mu>\nu>0$.
Moreover, $\Gamma$ is contained in the stable manifold $W^s(\mathbf{0})$ of $\mathbf{0}$.
\item
All forward orbits of $X$ starting from $\Sigma\setminus \Gamma$ will return to
$\Sigma$ and the first return map is $L$.
\end{enumerate}
Note then that $\mathbf{0}$ is a singular point (an equilibrium) of saddle type, the local
unstable manifold of $\mathbf{0}$ is tangent to the $x$-axis, and the local stable manifold
of $\mathbf{0}$ is tangent to the $yz$-plane, see Figure \ref{fig_2}.
\begin{figure}[hbt]
\centering
\scalebox{0.6}{\includegraphics[clip]{fig2}}
\caption{}
\label{fig_2}
\end{figure}
The $C^2$-map $\varphi_L :\mathbb{R}^3\times \mathbb{R}\to \mathbb{R}^3$
defined by $\varphi_L(\boldsymbol{x}, 0) = \boldsymbol{x}$ and
$(\partial/\partial t)\varphi_L(\boldsymbol{x}, t) = X_L(\varphi_L(\boldsymbol{x}, t))$
is called the \emph{geometric Lorenz flow} associated with the vector field $X_L$.
The closure of $\bigcup_{\boldsymbol{z}\in \Sigma\setminus\Gamma}\varphi_L(\boldsymbol{z}, [0,\infty))$ in
$\mathbb{R}^3$ is homeomorphic to a genus two handlebody as
illustrated in Figure \ref{fig_2}, which is called the \emph{trapping region} of
$\varphi_L$ and denoted by $T_{\varphi_L}$ or $T_L$.
Any forward orbit for $\varphi_L$ with its initial point in $T_L$ cannot escape from $T_L$.

For simplicity, we suppose moreover that the geometric Lorenz flow satisfies the differential equation
(\ref{eqn_Lf}) on
$$V_L=T_L\cap [-0.1,0.1]\times [-1,1]\times [0,1].$$
In fact, this assumption is not crucial and our subsequent argument still works for any geometric Lorenz flow which satisfies (\ref{eqn_Lf}) only on an arbitrarily small neighborhood of $\mathbf{0}$ in $T_L$.

\section{Historic behavior for the geometric Lorenz flow}\label{S_L_flow}

Let $\varphi_L$ be the geometric Lorenz flow given in the previous section.
Suppose that $g:T_L\to \mathbb{R}$ is a continuous function on the trapping region $T_L$.
For $\tau>0$ and $\delta>0$, the forward orbit $\varphi_L(\boldsymbol{x},t)_{t\geq 0}$ emanating from $\boldsymbol{x}\in T_L$
is said to have $(\tau,\delta)$\emph{-historic
behavior} with respect to $g$ if there exist $\tau_0$, $\tau_1$ with $\tau_0,\tau_1\geq \tau$ such that
$$\left|\frac1{\tau_0}\int_0^{\tau_0}g(\varphi_L(\boldsymbol{x},t))\,dt-\frac1{\tau_1}\int_0^{\tau_1}g(\varphi_L(\boldsymbol{x},t))\,dt \,\right|\geq \delta.$$
In particular, $\varphi_L(\boldsymbol{x},t)_{t\geq 0}$ has historic behavior if and only if
there exists $\delta>0$ and a continuous function $g$ on $T_L$ such that, for any $\tau>0$,
$\varphi_L(\boldsymbol{x},t)_{t\geq 0}$ has $(\tau,\delta)$-historic behavior with respect to $g$.

For any $\boldsymbol{y},\boldsymbol{z}\in T_L$ contained in the same forward orbit $\varphi_L(\boldsymbol{x},[0,\infty))$ with
$\boldsymbol{x}\in\Sigma$,
the sub-arc of $\varphi_L(\boldsymbol{x},[0,\infty))$ connecting $\boldsymbol{y}$ with $\boldsymbol{z}$ is denoted by $\Phi_L(\boldsymbol{y},\boldsymbol{z})$
or $\Phi_L(\boldsymbol{z},\boldsymbol{y})$.
Let $t_{\boldsymbol{x}}(\boldsymbol{y})\geq 0$ be the number with $\varphi_L(\boldsymbol{x},t_{\boldsymbol{x}}(\boldsymbol{y}))=\boldsymbol{y}$.
We set $\tau(\boldsymbol{y},\boldsymbol{z})=|t_{\boldsymbol{x}}(\boldsymbol{y})-t_{\boldsymbol{x}}(\boldsymbol{z})|$.
Note that $\tau(\boldsymbol{y},\boldsymbol{z})$ is independent of $\boldsymbol{x}\in \Sigma$ with $\varphi_L(\boldsymbol{x},[0,\infty))\ni \boldsymbol{y},\boldsymbol{z}$.
We also set $\tau(\boldsymbol{y},\boldsymbol{z})=\tau(\gamma)$ if $\gamma=\Phi_L(\boldsymbol{y},\boldsymbol{z})$.
Let $A$ be a compact subset of $T_L\setminus \{\mathbf{0}\}$ such that $\Phi_L(\boldsymbol{y},\boldsymbol{z})\cap A$ is a disjoint union of finitely many arcs $\gamma_1,\dots,\gamma_n$.
Then the total sum $\sum_{i=1}^n \tau(\gamma_i)$ is denoted by $\tau(\boldsymbol{y},\boldsymbol{z})|_A$.

Take a periodic point $x_{\mathrm{per}(2)}$ of $\alpha$ with period two.
Let $\pi:\mathbb{R}^3\to \mathbb{R}^2$ be the orthogonal projection defined by $\pi(x,y,z)=(x,z)$.
For any point $\boldsymbol{x}$ of $\Sigma$ with $\boldsymbol{x}_{[1]}=
x_{\mathrm{per}(2)}$,
the the image $Q(x_{\mathrm{per}(2)})=\pi(\varphi_L(\boldsymbol{x},[0,\infty)))$ is a closed curve in the $xz$-plane
disjoint from the origin of $\mathbb{R}^2$.
Here we denote the first entry of an element $\boldsymbol{a}$ of $\mathbb{R}^3$ by $\boldsymbol{a}_{[1]}$, that is,
$(a,b,c)_{[1]}=a$.
Though $Q(x_{\mathrm{per}(2)})$ depends on $x_{\mathrm{per}(2)}$, it is
independent of the $y$-entry of $\boldsymbol{x}$.
See Figure \ref{fig_3}.
\begin{figure}[hbt]
\centering
\scalebox{0.6}{\includegraphics[clip]{fig3}}
\caption{}
\label{fig_3}
\end{figure}

For $\eta>0$, the rectangular solid $[-\eta,\eta]^2\times [0,\eta]$ is denoted by $\Pi(\eta)$.
By taking the $\eta$ sufficiently small, one can suppose that
$\Pi(\eta)\cap T_L\subset V_L$ and
 $\Pi(2\eta)\cap \varphi_L(\boldsymbol{x},[0,\infty))=\emptyset$ for any $\boldsymbol{x}\in \Sigma$ with
$\boldsymbol{x}_{[1]}=x_{\mathrm{per}(2)}$.
Consider the subspaces
$$\partial_{\mathrm{side}}\Pi(\eta)=
\{-\eta,\eta\}\times [-\eta,\eta]\times [0,\eta]\quad\text{and}\quad
\partial_{\mathrm{top}}\Pi(\eta)=
[-\eta,\eta]^2\times \{\eta\}$$
of the boundary $\partial \Pi(\eta)$.

By the third equation of (\ref{eqn_Lf}) on $V_L$, any sub-arc $\gamma$ of an orbit
connecting $\Sigma$ with $\partial_{\mathrm{top}}\Pi(\eta)$ in
$T_L\cap [-\eta,\eta]\times [-1,1]\times [\eta,1]\subset V_L$ satisfies
\begin{equation}\label{eqn_tau_C'}
\tau(\gamma)=\frac{\log(\eta^{-1})}{\nu}.
\end{equation}

Note that the Lorenz flow does not have singular points in the compact set $\overline{T_L\setminus \Pi(\eta)}$, where $\overline A$ denotes the closure of a subset $A$ of $T_L$.
It follows from the fact that there exists a constant $C>0$ satisfying
\begin{equation}\label{eqn_tau}
\tau(\boldsymbol{x},L(\boldsymbol{x}))|_{\,\overline{T_L\setminus \Pi(\eta)}}\leq C
\end{equation}
for any $\boldsymbol{x}\in\Sigma\setminus \Gamma$.

\medskip

The following is our main theorem in this paper.

\begin{theorem}\label{t_1}
There exists a residual subset $\mathcal{H}$ of $\Sigma$ such that,
for any $\boldsymbol{x}\in \mathcal{H}$, the forward orbit $\varphi_L(\boldsymbol{x},t)_{t\geq 0}$
has historic behavior.
\end{theorem}

Here we fix a continuous function $g:T_L\to \mathbb{R}$ satisfying the following condition.
\begin{enumerate}[(1)]
\item
$0\leq g(\boldsymbol{x})\leq 1$ for any $\boldsymbol{x}\in T_L$.
\item
The support of $g$ is contained in $\Pi(2\eta)\cap T_L$ and
$g(\boldsymbol{x})=1$ on $\Pi(\eta)\cap T_L$.
\end{enumerate}

\medskip

The following lemma is crucial in the proof of Theorem \ref{t_1}.

\begin{lemma}\label{l_1}
For any positive integer $N$, any $0<\varepsilon<1$ and $\boldsymbol{x}_0\in \Sigma$,
there exists an open disk $U_{(\boldsymbol{x}_0,N,\varepsilon)}$ contained in the $\varepsilon$-neighborhood of $\boldsymbol{x}_0$ in $\Sigma$ and satisfying the following condition.
\begin{enumerate}[{\rm (H$_N$)}]
\item
For any $\boldsymbol{z}\in U_{(\boldsymbol{x}_0,N,\varepsilon)}$, $\varphi_L(\boldsymbol{z},t)_{t\geq 0}$ has $(N,1/2)$-historic behavior with respect to $g$.
\end{enumerate}
\end{lemma}

Here we note that the disk $U_{(\boldsymbol{x}_0,N,\varepsilon)}$ is not necessarily required to have $x_0$
as an element.

\begin{proof}
Since $0<\varepsilon<1$, $\lim_{\sigma\rightarrow\infty}\log (\varepsilon^{-\sigma})=\infty$.
Thus one can have a constant $\sigma\geq 1$ satisfying
\begin{equation}\label{eqn_loge}
\frac1{\lambda}\bigl(\log (\varepsilon^{-\sigma})+\log \eta\bigr)\geq \max\left\{N,\frac{6C\log(\varepsilon^{-1})}{\log 2}+\frac{4\log(\eta^{-1})}{\nu}\right\}.
\end{equation}

Set $(\boldsymbol{x}_0)_{[1]}=x_0$ and consider the interval $I(x_0,\varepsilon)=[x_0-\varepsilon,x_0+\varepsilon]$ in
the $x$-axis.
Let $n_0\in\mathbb{N}$ be the smallest non-negative integer such that $\alpha^{n_0}(I(x_0,\varepsilon))$ contains $0$.
We denote the length of an interval $I$ in the $x$-axis by $\ell(I)$.
Since $\ell(\alpha^{n_0}(I(x_0,\varepsilon))\leq 2$ and $|\alpha'(x)|> \sqrt2$ for any $x\in [-1,1]$ by (\ref{eqn_alpha}), we have $2\varepsilon(\sqrt2)^{n_0}\leq 2$ or equivalently
\begin{equation}\label{eqn_n_geq}
n_0\leq \frac{2\log (\varepsilon^{-1})}{\log 2}.
\end{equation}

On the other hand, since $\ell(\alpha^{n_0}(I(x_0,\varepsilon)))$ is at least $2\varepsilon$, $\alpha^{n_0}(I(x_0,\varepsilon))$ contains
either $[\varepsilon^\sigma/2,\varepsilon^\sigma]$ or $[-\varepsilon^\sigma,-\varepsilon^\sigma/2]$, say $[\varepsilon^\sigma/2,\varepsilon^\sigma]$.
Then $I(x_0,\varepsilon)$ contains an interval $J_0$ with $\alpha^{n_0}(J_0)=[\varepsilon^\sigma/2,\varepsilon^\sigma]$.
For any $\boldsymbol{y}_0\in \Sigma$ with $(\boldsymbol{y}_0)_{[1]}\in J_0$, set $\boldsymbol{y}_1=L^{n_0}(\boldsymbol{y}_0)$.
Let $\boldsymbol{y}_3$ be the first point in
$\varphi_L(\boldsymbol{y}_1,[0,\infty))$ meeting $\partial_{\mathrm{side}}\Pi(\eta)$.
From our setting of these points, we have a unique intersection point $\boldsymbol{y}_2$ of $\Phi_L(\boldsymbol{y}_1,\boldsymbol{y}_3)$ with $\partial_{\mathrm{top}}\Pi(\eta)$.
Then
\begin{equation}\label{eqn_y0y3}
\begin{split}
\tau(\boldsymbol{y}_0,\boldsymbol{y}_3)&=\tau(\boldsymbol{y}_0,\boldsymbol{y}_1)+\tau(\boldsymbol{y}_1,\boldsymbol{y}_2)+\tau(\boldsymbol{y}_2,\boldsymbol{y}_3)\\
&=\tau(\boldsymbol{y}_0,\boldsymbol{y}_1)|_{T_L\cap \Pi(\eta)}+\tau(\boldsymbol{y}_0,\boldsymbol{y}_1)|_{\,\overline{T_L\setminus \Pi(\eta)}} +\tau(\boldsymbol{y}_1,\boldsymbol{y}_2)+\tau(\boldsymbol{y}_2,\boldsymbol{y}_3).
\end{split}
\end{equation}
By (\ref{eqn_tau_C'}),
$$\tau(\boldsymbol{y}_1,\boldsymbol{y}_2)=\frac{\log(\eta^{-1})}{\nu}.$$
By (\ref{eqn_tau}) and (\ref{eqn_n_geq}),
$$\tau(\boldsymbol{y}_0,\boldsymbol{y}_1)|_{\,\overline{T_L\setminus \Pi(\eta)}}\leq \frac{2C\log (\varepsilon^{-1})}{\log 2}.$$
Since $\varepsilon^\sigma/2\leq (\boldsymbol{y}_1)_{[1]}\leq \varepsilon^\sigma$ and $(\boldsymbol{y}_3)_{[1]}=\eta$,
it follows from the first equation of (\ref{eqn_Lf}) and (\ref{eqn_loge}) that
\begin{equation}\label{eqn_tauy1y3}
\tau(\boldsymbol{y}_1,\boldsymbol{y}_3)\geq \frac1{\lambda}\bigl(\log (\varepsilon^{-\sigma})+\log \eta\bigr)\geq N.
\end{equation}
By the former inequality of (\ref{eqn_tauy1y3}) together with (\ref{eqn_loge}),
\begin{equation}\label{eqn_tauy2y3}
\begin{split}
\tau(\boldsymbol{y}_2,\boldsymbol{y}_3)&=\tau(\boldsymbol{y}_1,\boldsymbol{y}_3)-\tau(\boldsymbol{y}_1,\boldsymbol{y}_2)\geq
\frac1{\lambda}\bigl(\log (\varepsilon^{-\sigma})+\log \eta\bigr)-\frac{\log(\eta^{-1})}{\nu}\\
&\geq 3\left(\frac{2C\log(\varepsilon^{-1})}{\log 2}+\frac{\log(\eta^{-1})}{\nu}\right)\\
&\geq 3\bigl(\tau(\boldsymbol{y}_0,\boldsymbol{y}_1)_{\,\overline{T_L\setminus \Pi(\eta)}}+\tau(\boldsymbol{y}_1,\boldsymbol{y}_2)\bigr).
\end{split}
\end{equation}
Since $\Phi_L(\boldsymbol{y}_1,\boldsymbol{y}_2)\cap T_L\cap \Pi(\eta)$ is a single point of $\partial_{\mathrm{top}}\Pi(\eta)$, we have
$\tau(\boldsymbol{y}_1,\boldsymbol{y}_2)|_{T_L\cap \Pi(\eta)}=0$.
Since $\Phi_L(\boldsymbol{y}_2,\boldsymbol{y}_3)\subset T_L\cap \Pi(\eta)$,
$\tau(\boldsymbol{y}_2,\boldsymbol{y}_3)|_{T_L\cap \Pi(\eta)}=\tau(\boldsymbol{y}_2,\boldsymbol{y}_3)$.
This shows that
$$\tau(\boldsymbol{y}_1,\boldsymbol{y}_3)|_{T_L\cap \Pi(\eta)}=\tau(\boldsymbol{y}_1,\boldsymbol{y}_2)|_{T_L\cap \Pi(\eta)}+\tau(\boldsymbol{y}_2,\boldsymbol{y}_3)|_{T_L\cap \Pi(\eta)}=\tau(\boldsymbol{y}_2,\boldsymbol{y}_3).$$
It follows from (\ref{eqn_y0y3}) that
\begin{align*}
\frac{\tau(\boldsymbol{y}_0,\boldsymbol{y}_3)}{\tau(\boldsymbol{y}_0,\boldsymbol{y}_3)|_{T_L\cap \Pi(\eta)}}
&=\frac{\tau(\boldsymbol{y}_0,\boldsymbol{y}_3)}{\tau(\boldsymbol{y}_0,\boldsymbol{y}_1)|_{T_L\cap \Pi(\eta)}+\tau(\boldsymbol{y}_2,\boldsymbol{y}_3)}\\
&=1+\frac{\tau(\boldsymbol{y}_0,\boldsymbol{y}_1)|_{\,\overline{T_L\setminus \Pi(\eta)}}+\tau(\boldsymbol{y}_1,\boldsymbol{y}_2)}{\tau(\boldsymbol{y}_0,\boldsymbol{y}_1)|_{T_L\cap \Pi(\eta)}+\tau(\boldsymbol{y}_2,\boldsymbol{y}_3)}\\
&\leq 1+\frac{\tau(\boldsymbol{y}_0,\boldsymbol{y}_1)|_{\,\overline{T_L\setminus \Pi(\eta)}}+\tau(\boldsymbol{y}_1,\boldsymbol{y}_2)}{\tau(\boldsymbol{y}_2,\boldsymbol{y}_3)}\leq \frac43.
\end{align*}
Since $g$ is a non-negative continuous function with $g(\boldsymbol{x})=1$ on $T_L\cap \Pi(\eta)$,
\begin{equation}\label{eqn_3/4}
\frac1{\tau(\boldsymbol{y}_0,\boldsymbol{y}_3)}\int_0^{\tau(\boldsymbol{y}_0,\boldsymbol{y}_3)}
g(\varphi_L(\boldsymbol{y}_0,t))\,dt\geq \frac{\tau(\boldsymbol{y}_0,\boldsymbol{y}_3)|_{T_L\cap \Pi(\eta)}}{\tau(\boldsymbol{y}_0,\boldsymbol{y}_3)}\geq \frac34.
\end{equation}

Since $\bigcup_{n=1}^\infty\alpha^{-n}(x_{\mathrm{per}(2)})$ is dense in $[-1,1]$,
there exists an $n_1\in \mathbb{N}$ such that the interior of $\alpha^{n_1}([\varepsilon^\sigma/2,\varepsilon^\sigma])
=\alpha^{n_0+n_1}(J_0)$ contains $x_{\mathrm{per}(2)}$.
There exists a closed subinterval $J_1$ of $[\varepsilon^\sigma/2,\varepsilon^\sigma]$ such that $\mathrm{Int}\,\alpha^{n_1}(J_1)\ni x_{\mathrm{per}(2)}$
and $\bigcup_{i=1}^{n_1}\alpha^i(J_1)\cap \{0\}=\emptyset$.
There exists a point $\boldsymbol{y}_0$ in the interior of the $\varepsilon$-neighborhood of $\boldsymbol{x}_0$
such that the points $\boldsymbol{y}_1=L^{n_0}(\boldsymbol{y}_0)$ and $\boldsymbol{y}_4=L^{n_0+n_1}(\boldsymbol{y}_0)$ satisfy
$(\boldsymbol{y}_1)_{[1]}\in \mathrm{Int}J_1$ and $(\boldsymbol{y}_4)_{[1]}=x_{\mathrm{per}(2)}$ respectively.
Take a point $\boldsymbol{y}_5$ in $\varphi_L(\boldsymbol{y}_4,t)_{t\geq 0}$ with
$$\tau(\boldsymbol{y}_0,\boldsymbol{y}_5)\geq 5\tau(\boldsymbol{y}_0,\boldsymbol{y}_4).$$
Since $\psi_L(\boldsymbol{y}_4,[0,\infty))\cap \Pi(2\eta)=\emptyset$, $g(\boldsymbol{x})=0$ on $\Phi_L(\boldsymbol{y}_4,\boldsymbol{y}_5)$.
Since moreover $0\leq g(\boldsymbol{x})\leq 1$ on $T_L$, we have
$$\frac1{\tau(\boldsymbol{y}_0,\boldsymbol{y}_5)}\int_0^{\tau(\boldsymbol{y}_0,\boldsymbol{y}_5)}g(\psi_L(\boldsymbol{y}_0,t))\,dt
\leq \frac{\tau(\boldsymbol{y}_0,\boldsymbol{y}_4)}{\tau(\boldsymbol{y}_0,\boldsymbol{y}_5)}\leq \frac15.$$
By this inequality together with (\ref{eqn_3/4}), we have
\begin{align*}
\frac1{\tau(\boldsymbol{y}_0,\boldsymbol{y}_3)}\int_0^{\tau(\boldsymbol{y}_0,\boldsymbol{y}_3)}& g(\psi_L(\boldsymbol{y}_0,t))\,dt-
\frac1{\tau(\boldsymbol{y}_0,\boldsymbol{y}_5)}\int_0^{\tau(\boldsymbol{y}_0,\boldsymbol{y}_5)}g(\psi_L(\boldsymbol{y}_0,t))\,dt
\\
&\geq \frac34-\frac15=\frac{11}{20}.
\end{align*}
Then one can have a small open disk $U(\boldsymbol{x}_0,N,\varepsilon)$ centered at $\boldsymbol{y}_0$ and contained in the
$\varepsilon$-neighborhood of $\boldsymbol{x}_0$ such that, for any $\boldsymbol{z}\in U(\boldsymbol{x}_0,N,\varepsilon)$,
$$
\frac1{\tau(\boldsymbol{y}_0,\boldsymbol{y}_3)}\int_0^{\tau(\boldsymbol{y}_0,\boldsymbol{y}_3)} g(\psi_L(\boldsymbol{z},t))\,dt-
\frac1{\tau(\boldsymbol{y}_0,\boldsymbol{y}_5)}\int_0^{\tau(\boldsymbol{y}_0,\boldsymbol{y}_5)}g(\psi_L(\boldsymbol{z},t))\,dt
\geq \frac12.
$$
By (\ref{eqn_tauy1y3}), we also have
$$\tau(\boldsymbol{y}_0,\boldsymbol{y}_5)>\tau(\boldsymbol{y}_0,\boldsymbol{y}_3)>\tau(\boldsymbol{y}_1,\boldsymbol{y}_3)\geq N.$$
It follows that $\psi_L(\boldsymbol{z},t)_{t\geq 0}$ has $(N,1/2)$-historic behavior
with respect to $g$.
\end{proof}

\begin{proof}[Proof of Theorem \ref{t_1}]
For any $N,m\in \mathbb{N}$ and any $\boldsymbol{x}\in \Sigma\setminus \Gamma$,
let $U_{(\boldsymbol{x},N,1/(m+1))}$ be
the open disk given in Lemma \ref{l_1} with $\varepsilon=1/(m+1)$.
Then the union $\mathcal{U}_N=\bigcup_{m\in \mathbb{N},\boldsymbol{x}\in \Sigma\setminus \Gamma}U_{(\boldsymbol{x},N,1/(m+1))}$ is an open dense subset of $\Sigma$, and hence
$\mathcal{H}=\bigcap_{N=1}^\infty \mathcal{U}_N$ is a residual subset of $\Sigma$.
Since each element $\boldsymbol{z}$ of $\mathcal{H}$ satisfies the condition (H$_N$) of Lemma \ref{l_1}
for any $N\in \mathbb{N}$,
the forward orbit $\varphi_L(\boldsymbol{z},t)_{t\geq 0}$ has historic behavior.
This completes the proof.
\end{proof}

redpajama_set_name: RedPajamaArXiv


Theka the Martyr is a level 49 elite undead sand troll mini-boss found in Zul'Farrak. A historical figure in Sandfury society who sacrificed himself for the benefit of his people, those who persecuted him were forever cursed into the form of scarabs. Yeh'kinya wants the tablet that Theka possesses.
Long ago, the martyr Theka was slain in the brutal war between the qiraji and the trolls. Zul'Farrak still stands because of his brave sacrifice. Even in death he maintains a vigil over his beloved city, and it is said that the dozens of insectoid warriors who killed him were cursed to live as mindless scarabs, scuttling at the martyr's side.
Fevered Plague — Inflicts 250 Nature damage to an enemy, then an additional 11 damage every 3 sec. for 30 sec.
Theka Transform — When Theka the Martyr reaches 30% remaining health, he transforms, making him immune to Physical and Shadow damage for 15 sec.
His fight is a simple one, same as fighting a standard trash mob, but with a twist. At about 25% HP he becomes immune to physical and shadow damage. However, if you stunlock him from 25-0% he will NOT become immune. The immunity is a buff that wears off after 30 seconds. AoE damage must be avoided as the numerous scarabs surrounding him can overwhelm a party. Note that Theka is an undead target and can be hit with spells such as [Exorcism], [Shackle Undead], [Holy Wrath], and [Turn Undead].
Drops [First Mosh'aru Tablet] for the quest [47D] The Prophecy of Mosh'aru.
Patch 1.12.0 (2006-08-22): Theka's immunity is no longer permanent.