def check_if_anagram(word1, word2):
    counter = Counter()
    
    for c in word1:
        counter[c] += 1
    
    for c in word2:
        counter[c] -= 1
        
    for values in counter.values():
        if values <= 0:
            return False

    return True
dataset/ETHPy150Open bt3gl/Python-and-Algorithms-and-Data-Structures/short_phone_interview_problems/check_anagram.py/check_if_anagram/operator `!=` -> `<=`