content: package codingquestions.leetcode;
  import java.util.*;
  /*
  165. Compare Version Numbers
  Solved
  Medium
  Topics
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  Companies
  Hint
  Given two version strings, version1 and version2, compare them. A version string consists of revisions separated by dots '.'. The value of the revision is its integer conversion ignoring leading zeros.
  
  To compare version strings, compare their revision values in left-to-right order. If one of the version strings has fewer revisions, treat the missing revision values as 0.
  
  Return the following:
  
  If version1 < version2, return -1.
  If version1 > version2, return 1.
  Otherwise, return 0.
   
  
  Example 1:
  
  Input: version1 = "1.2", version2 = "1.10"
  
  Output: -1
  
  Explanation:
  
  version1's second revision is "2" and version2's second revision is "10": 2 < 10, so version1 < version2.
  
  Example 2:
  
  Input: version1 = "1.01", version2 = "1.001"
  
  Output: 0
  
  Explanation:
  
  Ignoring leading zeroes, both "01" and "001" represent the same integer "1".
  
  Example 3:
  
  Input: version1 = "1.0", version2 = "1.0.0.0"
  
  Output: 0
  
  Explanation:
  
  version1 has less revisions, which means every missing revision are treated as "0".
  
   
  
  Constraints:
  
  1 <= version1.length, version2.length <= 500
  version1 and version2 only contain digits and '.'.
  version1 and version2 are valid version numbers.
  All the given revisions in version1 and version2 can be stored in a 32-bit integer.
  */
  class CompareVersionNumbers {
      private List<Integer> revisions(String s){
          List<Integer> res = new ArrayList<>();
          int cur = 0;
          for(int i = 0; i < s.length(); i++){
              if(s.charAt(i) != '.')
                  cur = cur * 10 + (s.charAt(i) - '0');
              else{
                  res.add(cur);
                  cur = 0;
              }
          }
          res.add(cur);
          return res;
      }
  
      public int compareVersion(String version1, String version2) {
          List<Integer> l1 = revisions(version1), l2 = revisions(version2);
          for(int i = 0; i < Math.max(l1.size(), l2.size()); i++){
              int cp1 = (i >= l1.size() ? 0 : l1.get(i)), cp2 = (i >= l2.size() ? 0 : l2.get(i));
              if(cp1 > cp2)
                  return 1;
              
              if(cp1 < cp2)
                  return -1;
          }
          return 0;
      }
  }
  