content: package codingquestions.leetcode;
  /**
   * 2109. Adding Spaces to a String
   * Solved
   * Medium
   * Topics
   * Companies
   * Hint
   * You are given a 0-indexed string s and a 0-indexed integer array spaces that describes the indices in the original string where spaces will be added. Each space should be inserted before the character at the given index.
   * <p>
   * For example, given s = "EnjoyYourCoffee" and spaces = [5, 9], we place spaces before 'Y' and 'C', which are at indices 5 and 9 respectively. Thus, we obtain "Enjoy Your Coffee".
   * Return the modified string after the spaces have been added.
   * <p>
   * <p>
   * <p>
   * Example 1:
   * <p>
   * Input: s = "LeetcodeHelpsMeLearn", spaces = [8,13,15]
   * Output: "Leetcode Helps Me Learn"
   * Explanation:
   * The indices 8, 13, and 15 correspond to the underlined characters in "LeetcodeHelpsMeLearn".
   * We then place spaces before those characters.
   * Example 2:
   * <p>
   * Input: s = "icodeinpython", spaces = [1,5,7,9]
   * Output: "i code in py thon"
   * Explanation:
   * The indices 1, 5, 7, and 9 correspond to the underlined characters in "icodeinpython".
   * We then place spaces before those characters.
   * Example 3:
   * <p>
   * Input: s = "spacing", spaces = [0,1,2,3,4,5,6]
   * Output: " s p a c i n g"
   * Explanation:
   * We are also able to place spaces before the first character of the string.
   * <p>
   * <p>
   * Constraints:
   * <p>
   * 1 <= s.length <= 3 * 105
   * s consists only of lowercase and uppercase English letters.
   * 1 <= spaces.length <= 3 * 105
   * 0 <= spaces[i] <= s.length - 1
   * All the values of spaces are strictly increasing.
   */
  
  public class AddingSpacestoaString {
  
      public String addSpaces(String s, int[] spaces) {
          char[] a = s.toCharArray();
          char[] b = new char[s.length() + spaces.length];
  
          if (spaces.length == 0) return s;
          int j = 0;
          int k = 0;
          for (int i : spaces) {
              while (j < i) {
                  b[k++] = a[j++];
              }
              b[k++] = ' ';
          }
  
          while (j < s.length()) {
              b[k++] = a[j++];
          }
  
          return String.valueOf(b);
  
      }
  }
  