content: /*
  Write a class called MyRegex which will contain a string pattern. You need to write a regular expression
  and assign it to the pattern such that it can be used to validate an IP address. Use the following definition
  of an IP address:
  
  IP address is a string in the form "A.B.C.D", where the value of A, B, C, and D may range from 0 to 255. Leading zeros are allowed.
  The length of A, B, C, or D can't be greater than 3.
  
  Some valid IP address:
  000.12.12.034
  121.234.12.12
  23.45.12.56
  
  Some invalid IP address:
  000.12.234.23.23
  666.666.23.23
  .213.123.23.32
  23.45.22.32.
  I.Am.not.an.ip
  
  In this problem you will be provided strings containing any combination of ASCII characters. You have to
  write a regular expression to find the valid IPs.
  
  Just write the MyRegex class which contains a String . The string should contain the correct
  regular expression.
  
  (MyRegex class MUST NOT be public)
  
  Sample Input
  000.12.12.034
  121.234.12.12
  23.45.12.56
  00.12.123.123123.123
  122.23
  Hello.IP
  
  Sample Output
  true
  true
  true
  false
  false
  false
  */
  
  import java.util.regex.Matcher;
  import java.util.regex.Pattern;
  import java.util.Scanner;
  
  class Solution{
  
      public static void main(String[] args){
          Scanner in = new Scanner(System.in);
          while(in.hasNext()){
              String IP = in.next();
              System.out.println(IP.matches(new MyRegex().pattern));
          }
  
      }
  }
  
  class MyRegex {
      String from0To255 = "(25[0-5]|2[0-4][0-9]|[01]?[0-9]?[0-9])";
      public String pattern = String.format("%s.%s.%s.%s", from0To255, from0To255, from0To255, from0To255);
  }
  