content: /*
  In this challenge, we test your knowledge of using if-else conditional statements to automate 
  decision-making processes. An if-else statement has the following logical flow:
  
  Task
  Given an integer, n, perform the following conditional actions:
  
  1. If n is odd, print Weird
  2. If n is even and in the inclusive range of 2 to 5, print Not Weird
  3. If n is even and in the inclusive range of 6 to 20, print Weird
  4. If n is even and greater than 20, print Not Weird
  
  Complete the stub code provided in your editor to print whether or not n is weird.
  
  Input Format
  A single line containing a positive integer, n.
  
  Constraints
  
  Output Format
  Print Weird if the number is weird; otherwise, print Not Weird.
  
  Sample Input 0
  3
  
  Sample Output 0
  Weird
  
  Sample Input 1
  24
  
  Sample Output 1
  Not Weird
  
  Explanation
  
  Sample Case 0:
  n = 3
  n is odd and odd numbers are weird, so we print Weird.
  
  Sample Case 1:
  n = 24
  n > 20 and n is even, so it isn't weird. Thus, we print Not Weird.
  */
  
  import java.io.*;
  import java.math.*;
  import java.security.*;
  import java.text.*;
  import java.util.*;
  import java.util.concurrent.*;
  import java.util.regex.*;
  
  public class java_if_else {
  
      private static final Scanner scanner = new Scanner(System.in);
  
      public static void main(String[] args) {
          int N = scanner.nextInt();
          scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");
  
          scanner.close();
          if(N%2 == 1)
              System.out.println("Weird");
          else if(N%2 == 0 && N >= 2 && N <= 5)
              System.out.println("Not Weird");
          else if(N%2 == 0 && N >= 6 && N <= 20)
              System.out.println("Weird");
          else if(N%2 == 0 && N > 20)
              System.out.println("Not Weird");
      }
  }
  