content: /*
  Given three values - Start Fahrenheit Value (S), End Fahrenheit value (E) and Step Size (W), you need to convert all Fahrenheit values from Start to End at the gap of W, into 
  their corresponding Celsius values and print the table.
  
  Input Format :
  3 integers - S, E and W respectively
  
  Output Format :
  Fahrenheit to Celsius conversion table. One line for every Fahrenheit and Celsius Fahrenheit value. 
  Fahrenheit value and its corresponding Celsius value should be separate by tab ("\t")
  
  Constraints :
  0 <= S <= 1000
  0 <= E <= 1000
  0 <= W <= 1000
  
  Sample Input 1:
  0 
  100 
  20
  Sample Output 1:
  0   -17
  20  -6
  40  4
  60  15
  80  26
  100 37
  
  Sample Input 2:
  120 
  200 
  40
  Sample Output 2:
  120 48
  160 71
  200 93
  
  Explanation for Sample Output 2 :
  Start value is 120, end value is 200 and step size is 40. Therefore, the values we need to convert are 120, 120 + 40 = 160, and 160 + 40 = 200. 
  The formula for converting Fahrenheit to Celsius is:
  Celsius Value = (5/9)*(Fahrenheit Value - 32)  
  Plugging 120 into the formula, the celsius value will be (5 / 9)*(120 - 32) => (5 / 9) * 88 => (5 * 88) / 9 => 440 / 9 => 48.88
  But we'll only print 48 because we are only interested in the integral part of the value.
  */
  
  import java.util.*;
  public TempConvTable {
  	public static void printFahrenheitTable(int start, int end, int step) {
  		/* Don't write main(). 
  		 * Don't read input, it is passed as function argument. 
  		 * Print the specified output in required format. 
  		 * Taking input is handled automatically. 
  		 */
          for (int i=start;i<=end;i=i+step)
          {
              double cel = (5*(i-32))/9;
              System.out.println(i + " " + (int)cel);
          }
  		
  	}
  }
  