


'''simple docstring'''







from __future__ import annotations

import random
import string


class 				__lowerCamelCase				:
    """simple docstring"""


    def __init__(						self    :							Optional[int]   ,							SCREAMING_SNAKE_CASE    :							str | None = None):
           _A  :			Optional[Any]											=      passcode or self.__passcode_creator()
           _A  :			Tuple											=      self.__make_key_list()
           _A  :			List[Any]											=      self.__make_shift_key()


    def __str__(						self    :							Optional[Any]):
           return "".join(self.__passcode)


    def      A					(						self    :							int   ,							SCREAMING_SNAKE_CASE    :							list[int]):
           for i in range(1   ,							len(SCREAMING_SNAKE_CASE)   ,							2):
                  iterlist[i] *= -1
           return iterlist


    def      A					(						self    :							Dict):
           _A  :			Union[str, Any]											=      string.ascii_letters + string.digits
           _A  :			str											=      [random.choice(SCREAMING_SNAKE_CASE) for _ in range(random.randint(10   ,							20))]
           return password


    def      A					(						self    :							List[str]):
           _A  :			List[str]											=      (
               string.ascii_letters + string.digits + string.punctuation + ' \t\n'
           )

           _A  :			str											=      []

           # creates points known as breakpoints to break the key_list_options at those
           # points and pivot each substring
           _A  :			int											=      sorted(set(self.__passcode))
           _A  :			list[str]											=      []

           # algorithm for creating a new shuffled list, keys_l, out of key_list_options
           for i in key_list_options:
                  temp_list.extend(SCREAMING_SNAKE_CASE)

                  # checking breakpoints at which to pivot temporary sublist and add it into
                  # keys_l
                  if i in breakpoints or i == key_list_options[-1]:
                         keys_l.extend(temp_list[::-1])
                         temp_list.clear()

        # returning a shuffled keys_l to prevent brute force guessing of shift key
           return keys_l


    def      A					(						self    :							List[Any]):
           _A  :			Tuple											=      sum(self.__neg_pos([ord(SCREAMING_SNAKE_CASE) for x in self.__passcode]))
           return num if num > 0 else len(self.__passcode)


    def      A					(						self    :							Tuple   ,							SCREAMING_SNAKE_CASE    :							str):
           _A  :			int											=      ''

           # decoding shift like Caesar cipher algorithm implementing negative shift or
           # reverse shift or left shift
           for i in encoded_message:
                  _A  :			List[str]											=      self.__key_list.index(SCREAMING_SNAKE_CASE)
                  decoded_message += self.__key_list[
                      (position - self.__shift_key) % -len(self.__key_list)
                  ]

           return decoded_message


    def      A					(						self    :							Tuple   ,							SCREAMING_SNAKE_CASE    :							str):
           _A  :			Any											=      ''

           # encoding shift like Caesar cipher algorithm implementing positive shift or
           # forward shift or right shift
           for i in plaintext:
                  _A  :			Optional[Any]											=      self.__key_list.index(SCREAMING_SNAKE_CASE)
                  encoded_message += self.__key_list[
                      (position + self.__shift_key) % len(self.__key_list)
                  ]

           return encoded_message






def    lowerCAmelCase__ (       lowerCamelCase  :    str = "Hello, this is a modified Caesar cipher"     ):
       _A  :			List[str]											=      ShuffledShiftCipher()
       return cipa.decrypt(cipa.encrypt(lowerCamelCase     )     )


if __name__ == "__main__":
   import doctest

   doctest.testmod()










'''simple docstring'''







import itertools






def    lowerCAmelCase__ (       lowerCamelCase  :    int = 1000000     ):
       _A  :			str											=      [1]

       for i in itertools.count(len(lowerCamelCase     )     ):
              _A  :			Optional[Any]											=      0
              for j in itertools.count(1     ):
                     _A  :			int											=      -1 if j % 2 == 0 else +1
                     _A  :			Optional[Any]											=      (j * j * 3 - j) // 2
                     if index > i:
                            break
                     item += partitions[i - index] * sign
                     item %= number
                     index += j
                     if index > i:
                            break
                     item += partitions[i - index] * sign
                     item %= number

              if item == 0:
                     return i
              partitions.append(lowerCamelCase     )

       return 0


if __name__ == "__main__":
   import doctest

   doctest.testmod()

   print(f"""{solution() = }""")






