Question: Please describe this drug.
 The Molecule has the SMILES C=C(C)[C@@H]1CC[C@]2(C)CC[C@]3(C)[C@H](CC[C@@H]4[C@@]5(C)CC[C@H](O)C(C)(C)[C@@H]5CC[C@]43C)[C@@H]12.
Answer: Lupeol is a pentacyclic triterpenoid that is lupane in which the hydrogen at the 3beta position is substituted by a hydroxy group. It occurs in the skin of lupin seeds, as well as in the latex of fig trees and of rubber plants. It is also found in many edible fruits and vegetables. It has a role as an anti-inflammatory drug and a plant metabolite. It is a secondary alcohol and a pentacyclic triterpenoid. It derives from a hydride of a lupane.
{#Question|Q!}: {quest#}
{#Constraint:|Description:|!} The {#Molecule|Compound|Chemical!} {#has the|can be represented with the!} {SMILES__description} {SMILES#}.
{#Answer|Result|Answer!}: {answ#}
C=C(C)[C@@H]1CC[C@]2(C)CC[C@]3(C)[C@H](CC[C@@H]4[C@@]5(C)CC[C@H](O)C(C)(C)[C@@H]5CC[C@]43C)[C@@H]12
CC(=C)[C@@H]1CC[C@]2([C@H]1[C@H]3CC[C@@H]4[C@]5(CC[C@@H](C([C@@H]5CC[C@]4([C@@]3(CC2)C)C)(C)C)O)C)C
(1R,3aR,5aR,5bR,7aR,9S,11aR,11bR,13aR,13bR)-3a,5a,5b,8,8,11a-hexamethyl-1-prop-1-en-2-yl-1,2,3,4,5,6,7,7a,9,10,11,11b,12,13,13a,13b-hexadecahydrocyclopenta[a]chrysen-9-ol
Please describe this drug.
Lupeol is a pentacyclic triterpenoid that is lupane in which the hydrogen at the 3beta position is substituted by a hydroxy group. It occurs in the skin of lupin seeds, as well as in the latex of fig trees and of rubber plants. It is also found in many edible fruits and vegetables. It has a role as an anti-inflammatory drug and a plant metabolite. It is a secondary alcohol and a pentacyclic triterpenoid. It derives from a hydride of a lupane.