User: I want to know more about the molecule with SMILES CCOC(=O)C1=C(COCCN)NC(C)=C(C(=O)OC)[C@@H]1c1ccccc1Cl.O=C(O)/C=C\C(=O)O.
Assistant: Sure, what is your question?
User: Is this compound an acid, a base, or neutral?
Assistant: BASE
User: I want to know more about the {#molecule|chemical|compound!} with {SMILES__description} {SMILES#}.
Assistant: {#Sure, what is your question?|How can I help?|That sounds interesting, how can I help?|Interesting, how can I help?!}
User: {quest#}
Assistant: {#The answer is |!}{answ#}
CCOC(=O)C1=C(COCCN)NC(C)=C(C(=O)OC)[C@@H]1c1ccccc1Cl.O=C(O)/C=C\C(=O)O
CCOC(=O)C1=C(COCCN)NC(C)=C(C(=O)OC)[C@@H]1c1ccccc1Cl.O=C(O)/C=C\C(=O)O
(Z)-but-2-enedioic acid;3-O-ethyl 5-O-methyl (4S)-2-(2-aminoethoxymethyl)-4-(2-chlorophenyl)-6-methyl-1,4-dihydropyridine-3,5-dicarboxylate
Is this compound an acid, a base, or neutral?
BASE