User: I want to know more about the molecule with SMILES CCCCC[C@H](O)/C=C/[C@H]1[C@H](O)CC(=O)[C@@H]1CCCCCCC(=O)O.
Assistant: That sounds interesting, how can I help?
User: How many aromatic rings does this compound have?
Assistant: 0
User: I want to know more about the {#molecule|chemical|compound!} with {SMILES__description} {SMILES#}.
Assistant: {#Sure, what is your question?|How can I help?|That sounds interesting, how can I help?|Interesting, how can I help?!}
User: {quest#}
Assistant: {#The answer is |!}{answ#}
CCCCC[C@H](O)/C=C/[C@H]1[C@H](O)CC(=O)[C@@H]1CCCCCCC(=O)O
CCCCC[C@H](O)/C=C/[C@H]1[C@H](O)CC(=O)[C@@H]1CCCCCCC(=O)O
7-[(1R,2R,3R)-3-hydroxy-2-[(E,3S)-3-hydroxyoct-1-enyl]-5-oxocyclopentyl]heptanoicacid
How many aromatic rings does this compound have?
0