Q: How many heavy (non-hydrogen) atoms does this compound have?
Constraint: The Molecule can be represented with the SMILES COc1ccc(CN(CCN(C)C)c2ccccn2)cc1.O=C(O)/C=C\C(=O)O.
Answer: 21
{#Question|Q!}: {quest#}
{#Constraint:|Description:|!} The {#Molecule|Compound|Chemical!} {#has the|can be represented with the!} {SMILES__description} {SMILES#}.
{#Answer|Result|Answer!}: {answ#}
COc1ccc(CN(CCN(C)C)c2ccccn2)cc1.O=C(O)/C=C\C(=O)O
COc1ccc(CN(CCN(C)C)c2ccccn2)cc1.O=C(O)/C=C\C(=O)O
(Z)-but-2-enedioic acid;N'-[(4-methoxyphenyl)methyl]-N,N-dimethyl-N'-pyridin-2-ylethane-1,2-diamine
How many heavy (non-hydrogen) atoms does this compound have?