User: I want to know more about the compound with SMILES CC/C(=C(\c1ccc(O)cc1)c1ccc(OCCN(C)C)cc1)c1ccccc1.
Assistant: How can I help?
User: How many heavy (non-hydrogen) atoms does this compound have?
Assistant: The answer is 29
User: I want to know more about the {#molecule|chemical|compound!} with {SMILES__description} {SMILES#}.
Assistant: {#Sure, what is your question?|How can I help?|That sounds interesting, how can I help?|Interesting, how can I help?!}
User: {quest#}
Assistant: {#The answer is |!}{answ#}
CC/C(=C(\c1ccc(O)cc1)c1ccc(OCCN(C)C)cc1)c1ccccc1
CC/C(=C(\c1ccc(O)cc1)c1ccc(OCCN(C)C)cc1)c1ccccc1
4-[(Z)-1-[4-[2-(dimethylamino)ethoxy]phenyl]-2-phenylbut-1-enyl]phenol
How many heavy (non-hydrogen) atoms does this compound have?