Task: Please create a description for a molecule based on its representation.
SMILES: CC/C=C\C/C=C\C/C=C\C/C=C\C/C=C\C/C=C\CCC(=O)OC[C@@H](O)COP(=O)([O-])OCC[N+](C)(C)C
Constraint: Answer the question with complete sentences.
Result: The molecule is a lysophosphatidylcholine 22:6 in which the remaining acyl group is (4Z,7Z,10Z,13Z,16Z,19Z)-docosa-4,7,10,13,16,19-hexaenoyl. It has a role as a human metabolite and a mouse metabolite. It derives from an all-cis-docosa-4,7,10,13,16,19-hexaenoic acid.
Task: Please create a {#text |!}description for a molecule{# based on its representation|!}.
{#Molecule |!}{SMILES__description}: {SMILES#}
Constraint: Answer the question with {#full|complete!} sentences.
Result: {description#}
CC/C=C\C/C=C\C/C=C\C/C=C\C/C=C\C/C=C\CCC(=O)OC[C@@H](O)COP(=O)([O-])OCC[N+](C)(C)C
[(2R)-3-[(4Z,7Z,10Z,13Z,16Z,19Z)-docosa-4,7,10,13,16,19-hexaenoyl]oxy-2-hydroxypropyl] 2-(trimethylazaniumyl)ethyl phosphate
The molecule is a lysophosphatidylcholine 22:6 in which the remaining acyl group is (4Z,7Z,10Z,13Z,16Z,19Z)-docosa-4,7,10,13,16,19-hexaenoyl. It has a role as a human metabolite and a mouse metabolite. It derives from an all-cis-docosa-4,7,10,13,16,19-hexaenoic acid.