Task: Please create a description for a molecule based on its representation.
SMILES: C[C@@H]1O[C@@H](Oc2c(-c3ccc(O)cc3)oc3cc(O)cc(O)c3c2=O)[C@H](O)[C@H](O)[C@H]1O
Constraint: Answer the question with complete sentences.
Result: The molecule is a glycosyloxyflavone that is kaempferol attached to an alpha-L-rhamnosyl residue at position 3 via a glycosidic linkage. It has a role as a plant metabolite, an antibacterial agent and an anti-inflammatory agent. It is a glycosyloxyflavone, a trihydroxyflavone and a monosaccharide derivative. It derives from a kaempferol. It is a conjugate acid of an afzelin(1-).
Task: Please create a {#text |!}description for a molecule{# based on its representation|!}.
{#Molecule |!}{SMILES__description}: {SMILES#}
Constraint: Answer the question with {#full|complete!} sentences.
Result: {description#}
C[C@@H]1O[C@@H](Oc2c(-c3ccc(O)cc3)oc3cc(O)cc(O)c3c2=O)[C@H](O)[C@H](O)[C@H]1O
5,7-dihydroxy-2-(4-hydroxyphenyl)-3-[(2S,3R,4R,5R,6S)-3,4,5-trihydroxy-6-methyloxan-2-yl]oxychromen-4-one
The molecule is a glycosyloxyflavone that is kaempferol attached to an alpha-L-rhamnosyl residue at position 3 via a glycosidic linkage. It has a role as a plant metabolite, an antibacterial agent and an anti-inflammatory agent. It is a glycosyloxyflavone, a trihydroxyflavone and a monosaccharide derivative. It derives from a kaempferol. It is a conjugate acid of an afzelin(1-).