How do I find the limit as x goes to +infinity for (ln 2x)/(ln 3x)?
Also, how do I find the limit as x approaches 1 from the negative direction for ln (1-x)?
Thanks. I get the first one.
For the second, I'm still unclear. I notice that:
ln(1-x) = ln 1 - ln x = 0 - ln x = -ln x.
Does this help? How do I find the limit as x approaches 1 from the negative direction for -ln x?
Sorry for my clouded mind!
What I suggested in my first post may be called "composition of limits". The limit of , as tends to 1 from the right, is (0, reached by upper values). And the limit of when tends to 0 from the right is . So, composing these results, the limit of when tends to 1 from the left is .
Is it clearer now?