1. The problem statement, all variables and given/known data An empty barometer tube,1m long is lowered vertically, mouth downwards, into a tank of water. what will be the depth of the top of the tube when the water has risen 20cm inside the tube?(atmospheric pressure may be assumed to be equal to 10.4m head of water) 2. Relevant equations boyle's states p1v1= p2v2 assuming temperature remains constant. 3. The attempt at a solution p1=10.4 m in m of water v1= (1 x A) cubic meter p2= (10.4 +h) in m of water v2= (0.8 x A) cubic meter where a is area of cross section of tube. substitute: (10.4 +h) (0.8A)= 10.4 x 1 x A 10.4 +h = 10.4 divided by 0.8 = 13 and so the pressure due to the water coloum should be 13.10.4= 2.6 after this i cant get it right becase if the pressure is 2.6 then we should be able to use the formula pressure=ht x densityx g to find height of the water but the answer you get is not the answer in the book which says that the top of the tube is 1.8 m below the surface. It shows it as 2.6-0.8= 1.8 how exactly do you get 1.8 and why do you have to subtract 0.8 from 2.6 ???