what is the LR when 10mol iron sulfide reacts 200g oxygen FeS2+o2
The chemical reaction is as follows:
4 FeS2 + 11 O2 = 2 Fe2O3 + 8 SO2
n(FeS2) = 10 mol / 4 = 2.5 mol
n(O2) = m(O2) / (11 × Mr[O2]) = 200 g / (11 × 32) = 0.57 mol
Since, the number of moles of O2 is lower than the number of moles of FeS2, oxygen is a limiting reactant.
Answer: Oxygen (O2)