A restaurant has one type of milk that has 2% fat and another that has 7% fat. How many quarts of each type does the restaurant need to make 40 quarts of a milk mixture that is 5% fat?
let the no. of quarts required of 2% fat milk be "x" and no. of quarts required of 7% fat milk be "y"as per problem, Total no. of quarts should be 40,so, x+y=40.....(1)Now, the total percentage of fat should be 5%so, 5% of 40 = 2% of x + 7 % of y5*40/100 =2*x/100+7*y/1002 = 2x/100+7y/100or, 2x+7y =200or,2x+7y=200...(2)now from equation (1),x+y=40x=40-yplugging the value of x in (2), we get2(40-y)+7y=20080-2y+7y=2005y=120y=24and x = 40-24 = 16so, 16 quarts of 2% fat milk and 24 quarts of 7% milk is required.Please appreciate my help, by selecting my answer as the best, and add me as your tutor, Thanks!
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