First of all, I searched the forums and couldn't really find one on how to approach a quadratic equation that has brackets. Here is the equation: y=(x+1)2 - 2 My teacher told me to factorize by sight in pairs and i used this equation for it: ax2+bx+c. I think c=-2 but I don't know how to get "a" and "b". When I worked on the brackets it came to (x+1)2=2x+x2+1 and I don't know which is "a" and "b" 2. Relevant equations. Oops! I forgot that the purpose is to find the turning point for the quadratic function. I really HATE the ones with brackets. If anyone can help me that would be very much appreciated.