[SOLVED] collision and impulse 1. The problem statement, all variables and given/known data A 1.0 kg ball drops vertically onto a floor, hitting with a speed of 20 m/s. It rebounds with an initial speed of 5 m/s. (a) What impulse acts on the ball during the contact? kg·m/s (b) If the ball is in contact with the floor for 0.020 s, what is the average force exerted on the floor? N 2. Relevant equations p=m*v deltap=J F=m(deltav)/deltat 3. The attempt at a solution For (a) i used p=m*v and deltap=J so I got (1*-20)-(1*5)=-25 and for (b) i used that F=(m*deltav)/deltat which came out to be... 1(-25)/.020=0.5 N both answers were wrong and I'm not sure what is wrong with the formulas I used... Any help is appreciated! Thanks!