1. The problem statement, all variables and given/known data A 50.0 kg 6.00m awning is held up by a wire in the middle. A 15kg sign hangs at the end. Calculate the tension in the massless wire and the magnitude of the net force from the wall acting on the awning. The cable forms a 40 degree angle with the awning at the bottom right corner. 2. Relevant equations Sum or Torque 3. The attempt at a solution Sum of Torque=0=(mg)(L)+(Mg)(L/2)-(T)(L/2)Sin40) L's cancel (mg)+(Mg/2)=Tsin40/2 (mg)+(Mg)/sin40=T ((15*9.81)+(50*9.81)/sin40)=T T=992N ??? I'm not sure what the question means by net force from the wall. Is it just the normal force of the wall or do I have to use the tension to find it?