Problem 11.16 analyzed the number of weekly hours worked per person at five different plants. An F value of 3.10 was obtained with a probability of .0266. Because the probability is less than .05, the null hypothesis is rejected at α = .05 There is an overall difference in the mean weekly hours worked by plant. Which pairs of plants have significant differences in the means, if any? To answer this question, a Minitab computer analysis was done. The data follow. Study the output in light of problem 11.16 and discuss theresults.
Answer to relevant QuestionsUse ANOVA to analyze the data from the randomized block design given here. Let α = .05. State the null and alternative hypotheses and determine whether the null hypothesis isrejected.In recent years, the debate over the U.S. economy has been constant. The electorate seems somewhat divided as to whether the economy is in a recovery or not. Suppose a survey was undertaken to ascertain whether the ...Children are generally believed to have considerable influence over their parents in the purchase of certain items, particularly food and beverage items. To study this notion further, a study is conducted in which parents ...Analyze the following data, gathered from a randomized block design using α = .05. If there is a significant difference in the treatment effects, use Tukey’s HSD test to do multiplecomparisons.Analyze the following Minitab output. Describe the design of the experiment. Using α = .05 determine whether there are any significant effects; if so, explain why. Discuss any other ramifications of theoutput.
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