Given that the x-intercept of a line is twice the y-intercept of its y-intercept and that the line passes thru the intersection between the lines 3y+x=3 and 4y-3x=5, find the eqn of the line. i found the intersection of the line and use the point to find the gradient of the the two point at the x-intercept and x-intercept so that i can eqate them and find the intercept. however i got a large fraction and is very confusing. Did i do wrongly? or is there another method to solve this?
Given that the x-intercept of a line is twice the y-intercept,
. . and that the line passes thru the intersection of the lines
find the equation of the line.
The lines intersect at: .
The line has y-intercept and x-intercept
The slope of line is: .
The line thorugh with slope has the equation: