Solved Examples Based On Finding Forces In The Member Of The Truss
Example: Find the forces in the members of the truss shown in figure.
Step 1:Consider the free body diagram of joint B
ΣFx = 0
⇒ FBA – FBC cos 60o = 0 …(1)
FBC sin 60o – 10 = 0 …(2)
FBC × 0.866 = 10
FBC = 11.54 kN (Tensile)
From equation (1)
FBA = FBC cos 60o = 11.54 × 0.5
FBA = 5.77 kN (Compressive)
Step 2: Consider the free body diagram of joint C
ΣFy = 0 Þ FCA sin 60o – FCB sin 60o = 0 .,.(3)
FCA = FCB = 11.54 kN (Compressive)
ΣFx = 0 Þ FCD – FCA cos 60o – FCB cos 60o = 0 …(4)
FCD = FCA cos 60o + FCB cos 60o
= 11.54 × 0.5 + 11.54 × 0.5
= 5.773 + 5.773 = 11.54 kN (Tensile).
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