1. The problem statement, all variables and given/known data A train starts from a station with a constant acceleration of at = 0.40 m/s2. A passenger arrives at the track time t = 6.0s after the end of the train left the very same point. What is the slowest constant speed at which she can run and catch the train. Sketch curves for the motion of the pasenger and the train as functions of time 2. Relevant equations x=x0+v0t+1/2at2 3. The attempt at a solution let origin be when the person reaches the tracks (at t=6). let h = the distance the train has already traveled in the first 6 seconds) PERSON x=vop(initial of person)t TRAIN x=h+vot(initial of train+att2/2 let position of both objects equal each other vopt=h+vopt+att2/2 what do i do now? i am stuck. i have to find vop, but i cant seem to find out how to find t.... i know the vlaues of h,vot, and at.