An Earth satellite moves in a circular orbit 605 km above the Earth's surface. The period of the motion is 96.6 min.
What is the speed of the satellite?
The Attempt at a Solution
First, I know that it is orbiting 605 km above earth's surface. So, that number plus the radius of earth gives a total for the radius of the motion. That comes out to be about 6976000 meters.
Then, I used the equation:
T = (2pir)/(v)
96.6 = (2pi(6967000)) / (v)
v = 453742.24
But it's marking it as incorrect. Any ideas?