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I got A
First the least distance is a perpendicular from the centre of the circle to a point on the line minus redius.
The point of intersection of the line with the x-axis is 4, with y-exis - -3
So we have a right triangle (3,4,5).
Then we draw the height from centre of the circle (this is also point (0,0)) and it will be the least distance between (0,0) and a poit on the line.
We find the height and then deduct radius 1.
The most time-consuming part for me was to calculate the height.
Is there any shortcut to calculate the height of a right triangle if we know all its sides?
Plotting the points, you get a circle with r=1, and a 3,4,5 triangle. The shortest point between them would be a line drawn 45 degrees from the origin... when plotting this line, you can deduct that it must be slightly smaller than 2.5. Calculating you get 2 2/5 or 2.4... 2.4-1 gives you 1.4
On the actual GMAT, I think they would space these answers out a bit more to make 1 clear answer... distinguishing between sqrt2, and 1.4 seems a bit trivial.