- Joined Jan 10, 2007
i was watching this and im confused about how this work.. what are the capacitors here for.. pllease someone explain me why you need each coponent in this circuit?
Pretty much. The "current flow" in a capacitor is due to the changing voltage across the capacitor: i(t) = C(dV/dt)OK I am new to electronics, but as I understand it a capacitor blocks dc and allows ac to pass.
Also I dont think caps act as a wire when charged do they?
Dont they charge and discharge so there would not be a steady flow of current. I am speculating but I hope someone can correct me.
Thinking of a DC application, then when the capacitor is charged, the voltage across the capacitor is constant, i.e. dv/dt = 0 and therefore i = 0. The situation changes for AC application, because the opposing plates of the capacitor are constantly charging and discharging, i.e. dv/dt /= 0 and therefore i /= 0.But, if the capacitor is charged and its still current flowing will the capacitor discharge or it will only discharge if the current stop flowing (if u disconnect the battery)
|Thread starter||Similar threads||Forum||Replies||Date|
|DC step up module problem||Power Electronics||12|
|Step up or step down transformer will they work either way||Power Electronics||1|
|AC-AC step down voltage + frequency converter simulation (LT Spice), file provided||PCB Layout , EDA & Simulations||10|
|Next step of my parenting journey... sending kids to college (or not)||Off-Topic||72|
|Y||Designing a DCDC Step-Down Switching Power Supply||General Electronics Chat||10|
|DC step up module problem|
|Step up or step down transformer will they work either way|
|AC-AC step down voltage + frequency converter simulation (LT Spice), file provided|
|Next step of my parenting journey... sending kids to college (or not)|
|Designing a DCDC Step-Down Switching Power Supply|
by Jake Hertz