1. The problem statement, all variables and given/known data A 2.6-uC charge is at the center of a cube 7.5cm on each side. What is the electric flux through one face of the cube? q_enclosed = 2.6*10^-6 C a = .075m 2. Relevant equations flux = E*A = integral(E*dA*cos(theta)) = E*integral(dA) flux = q/(e_0) surface area of a cube: 6*a^2 3. The attempt at a solution flux = E*int(dA) = E*6(.075)^2 = .03375E .03375E = (2.6*10^-6)/(e_0) => E = 6.8*10^-16 N/C So the flux = q/(e_0). ... you know what. I just figured it out. flux = q/(e_0) => (2.6*10-3C) / (e_0) = 294053 Nm^2/C (1/6)(294053 Nm^2/C) = 4.9*10^4 Nm^2/C So the flux through one side of the cube (any cube!) with the enclosed charge of 2.6-uC is 294053 Nm^2/C. No integral is necessary. edit: I was going to not post this but maybe it will help someone out.