Because when you scale the radius by a factor of , the perpendicular (sine value) is also scaled by a factor of .
So to find the sine value, you have to divide by the radius.
We ofcourse know that given a unit circle, certain values of trigonometric functions apply ( , for example).
However, if we were to take a circle with a bigger radius, that would automatically lead the values of such functions to change.
Whenever i used sin(pi/4) in a problem i always took its value as the one mentioned in terms of a unit circle, when in fact it varies according to the lengths of the triangle.
So my question would be: How can we take as having a standard value of when in fact it varies. What am i missing here?
Sorry for my mistake, i was used to the unit circle where the radius was 1, thus the sine was actually the perpendicular itself. When i went to a bigger circle i forgot to divide it by the hypothenuse of the drawn triangle and i was still taking the value of the sine as being equal to the perpendicular itself. Also since sine is a ratio between the sides of a triangle it would have been illogical to exceed one. I'm sorry for my stupid question.
Thank you for the reply.