A block slides with constant velocity down an inclined plane with slope angle [itex] \theta [/itex]. The block is then projected up the same plane with an initial speed [itex] v_o [/itex]. How far up the plane will it move before coming to rest, and after coming to rest, will it slide down the plane again?
F = ma.
[tex] f = \mu mg [/tex]
The Attempt at a Solution
The block will travel a distance of [tex] v^2_0/(4g\sin\theta) [/tex]. But the second part of this problem is not clear to me. I am inclined to say there isn't enough information to answer this, but if pressed, I would say that it would probably slide back down. I would say this because the coefficient of kinetic friction in this problem is [tex] \tan\theta [/tex]. If the box would not move, then it would seem that [tex] \mu_s = \mu_k [/tex], which contradicts the usual situation where [tex] \mu_s > \mu_k [/tex]. The book answer is no.
I would appreciate any insights offered.