a. Propose a mechanism for the following reaction.
b. Explain why two products are formed.
c. Explain why methanol substitutes for only one of the bromines.
Step 1 of 5</p>
Mechanism for the formation of product 1:
This reaction follows mechanism. The -2,3-dibromochroman loses bromide ion to form oxonium ion. It can rearrange to form a more stable carbocation.
Step 2 of 5</p>
Methanol attacks at carbocation to form another oxonium ion derivative. Methanol abstracts a proton from oxonium ion derivative to form -3-bromo-2-methoxychroman.
Step 3 of 5</p>
Mechanism for the formation of product 2:
This reaction follows mechanism. Methanol attacks at carbon of bond to form -3-bromo-2-methoxychroman.