Write an equation in slope intercept form of the line that passes through
How to find the equation of a line with two points
They've given me the value for m, along with values for an x and a y. Slope-intercept form linear equations Video transcript A line goes through the points -1, 6 and 5, 4. That's 0 coma 13 over 3 or 0 coma 4 and 1 thirds. This right here is y2, our ending y and this is our beginning y This is y1. That's where the negative 10 comes from. So that's going to be, let me do it over here We take a common denominator. So we are done. And we go down 4, So 1, 2, 3, 4 So it's right over there. So let's find its equation. So our change in y, to go we started at y is equal to six, we started at y is equal to 6. From the left handside and subtracted from the rigth handside And then we get, what's 6 minus 5 thirds. That is equal to negative So y is equal to six when x is equal to negative 1 So negative 5 thirds times x, when x is equal to negative 1 y is equal to 6. We started at x is equal to negative 1 and we go all the way to x is equal to 5. So we literally just substitute this x and y value back into this and know we can solve for b.
Point-Slope Form Parallel, Perpendicular Lines Purplemath Straight-line equations, or "linear" equations, graph as straight lines, and have simple variable expressions with no exponents on them.
From the left handside and subtracted from the rigth handside And then we get, what's 6 minus 5 thirds. It's negative 1 and 2 thirds. Remember, we want, we can find the equation y is equal to mx plus b.
Let's just try to visualize this. So we started at x is equal to negative 1, and we go all the way to x is equal to 5. And to do that, we can use the information that we know in fact we have several points of information We can use the fact that the line goes through the point -1,6 you could use the other point as well.
So our change in y, to go we started at y is equal to six, we started at y is equal to 6. So it's this point, rigth over there, it's -1, 6.
Finding the equation of a line given two points worksheet
Line will draw a rough approximation. So we literally just substitute this x and y value back into this and know we can solve for b. So we are done. So let's see, this negative 1 times negative 5 thirds. We can first try to solve for m. This is the slope-intercept form where m is the slope and b is the y-intercept. There is, ironically, no standard definition of "standard form". We know We know the slope and we know the y-intercept. Just plug in your x-value; the equation is already solved for y. Nowadays, you likely needn't worry too much about the "standard" forms; this lesson will only cover the more-helpful forms. You can look at that visually there or you can use this formula same exact idea, our ending x-value, our ending x-value is 5 and our starting x-value is negative 1. I like slope-intercept form the best. So let's find its equation. And the slope negative 5 thirds that's the same thing as negative 1 and 2 thirds. We can find the slope of this line.
This right here is y2, our ending y and this is our beginning y This is y1. So we can look at this graph over here.
That is equal to negative
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