A 1.2 kg grindstone in the shape of a uniform cylinder of radius 0.25 m acquires a rotational rate of 1800 rev/s from rest over a 6.0 s interval at constant angular acceleration. Calculate the torque delivered by the motor.© BrainMass Inc. brainmass.com June 3, 2020, 10:07 pm ad1c9bdddf
M = 1.2 kg, R = 0.25 m, w1 = 0, w2 = 1800 rev/s = 1800 (2pi) rad/s
= 11309.7 ...
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