Solved Examples Based On Work And Energy Method
Two bodies weighing 400 N and 600 N are hung to the ends of a rope passing over an ideal pulley as shown in Fig. (a). How much distance the blocks will move in increasing the velocity of system from 2 m/sec to 4 m/sec? How much is the tension in the string? Use work-energy method.
600N block moves down and 400 N block moves up. Both bodies move with same velocity and same distance. Let V be the distance moved. Writing work-energy equation for the system, we get
600s - 400s = 600/2 X 9.81 (43 - 22) + 400/2 X 9.81 (42 - 22)
∴ s = 3.058 m
Let T be the tension in the string. Consider work-energy equation for any one body as shown in Fig (b).
600s - Ts = [600/2 X 9.81] (42 - 22)
(600 - T) X 3.058 = 600/2 X 9.81 (12)
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