How to solve system of quadratic linear equations algebraically with y=3x+12 and y=x2-2x-18?
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
substitute y as 3x+12 in the second equation and solve for x.
Yes sorry, I meant, when you're trying to find out the plotting points, the number pair, what do you do?
They are both written as y = ... So knowing that y = y, the other sides are equal to each other too, so set the other sides equal to each other: 3x + 12 = x^2-2x-18
Not the answer you are looking for? Search for more explanations.
...Then solve for x, and once you know x, use the simpler equation to find y.
you find out x and y. then you plotting poitns are (x,y)
I don't know what you mean, because there is only only point (x,y) or at most two, which satisfies both these equations. You have to find that point by substituting the first equation in the second equation.