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I believe that the quantity of energy found in E=hv is just the smallest unit of energy for that particular frequency. It might help to think of the equation as E=(number of photons)*hv and, so, if your number of photons is just 1, then you're left with E=hv. You could then take that energy and multiply it by a greater number of photons to see how many Joules of energy would be in several photons rather than just one.
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