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y-(-7)=m(x-5) so you just sub in the gradient and solve
i know how to write out the equation but after that im lost =(
What's the question? just to find the equation?
im sorry its for an online course
the question is find the equation of the line having the given slope and containing the given point
You sub it into the point-gradient formula, which is y-y1=m(x-x1) so using the given, sub in your gradient and your y and x-values to get: y-(-7)=(7/8)(x-5) 8(y+7)=7(x-5) 7x-8y-35-56=0 7x-8y-91=0
Does that help? :I
im trying to go over it
You need to find the slope of the original line because the new line is parallel to it and therefore must have the same slope. Then you can write the equation for the new line using the point slope formula \[y-y_0 = m(x-x_0)\] Where y0 and x0 are the y and x coordinates of a point on the line, and m is the slope of the line.
where do u get 56 from
8(y+7)=7(x-5) 8y+56=7x-35 0=7x-8y-35-56
its not the answer
I just threw everything over to one side..
answer is 7/8x-
Ohhh you get that answer if you don't get rid of the fraction
and leave 8 as the denominator
right whichs is what i wasnt understandin
When you leave it as a fraction: y-(-7)=(7/8)(x-5) y+7=(7x/8) - 35/8)
can someone type out the working, leaving it in fractional form, it's taking so long for me, ha
y = (7x/8) - (91/7) confirmed
\[y+7=[7/8](x-5) \rightarrow y = (7x)/8 - (7*5)/8 -7 \] \[\rightarrow y = (7/8)x - 35/8 - 56/8 = (7/8)x - 91/8\]