What is Y Y1 M X X1?
Best Answer: that is the formula to find the equation of a linear graph. if you are given one set of co-ordinates (x and y), you subsitute them both into y1 and x1, then substitue the gradient into m and expand the equation algebraically. eg. co-ordinates (2, 3) gradient 2 y - 3 = 2 ...
Given point (x1,y1) and slope m and you want point-slope form: 1) substitute values into the equation (y-y1) = m(x-x1) 2) you're done Given point (x1,y1) and slope m and you want standard form: Option 1 1) get point-slope equation through above steps 2) use algebra to ...
Best Answer: That's called the point-slope form for the equation of a line. You use it when you know the slope of a line and one point on it. y - y1 = m(x - x1) m is the slope, (x1, y1) is the point. In your problem, you just plug in the numbers: m = -2/3 (x1, y1) = (6, 1) So, y - 1 ...
Best Answer: it is a equation of line passing through points 'y1 and x1' suppose we have a straight line. starting points are 'x1, y1' and end points are 'x2, y2' then the straight line equation is- [y-y1=((y2-y1)/(x2-x1))(x-x1)] here m=((y2-y1)/(x2-x1)) ; m represents by howmuch ...
linear equation [′lin·ē·ər i′kwā·zhən] (mathematics) A linear equation in the variables x 1, … , x n, and y is any equation of the form a 1 x 1 + a 2 x 2 + … + a n x n = y.
Best Answer: The point-slope form for the equation of a line is this: y - y' = m(x - x'). Let the given point (-6, 6) be (x', y'). Also, convert the slope from decimal form to fractional form first: 3.5/3 = 7 (0.5) / 6 (0.5) = 7/6. Now plug them into the point-slope equation to get ...
A linear equation is an algebraic equation in which each term is either a constant or the product of a constant and (the first power of) a single variable. Linear equations can have one or more variables. Linear equations occur with great regularity in most subareas of mathematics and especially ...
Added by Frost on September 07, 2001 at 01:03:55: just like y=mx+b slope formula. www.thefrost.cc
linear equation. n. An algebraic equation, such as y = 2x + 7 or 3x + 2y - z = 4, in which the highest degree term in the variable or variables is of the first degree.
Best Answer: X= [(y-y1)+x1] / m If you are trying to write y^1 or x^1 then answer is 0 To denote "1" is power of a variable, you have to use ^ . example. 3^2 = 9 Also if you are trying to write x1 or y1 where variable is multiplied by 1, it's obviously variable itself and again answer ...
y - y1 = m (x - x1) Let's write the equation of the line passing through the point (5,9) with slope 4. So, x1 = 5, y1 = 9, and m = 4. y - 9 = 4 (x - 5) y - 9 = 4x - 20. y = 4x - 11. Let's write the equation of the line passing through the points (2,7) and (3,4).
How do you change 2x + 3y = 7 into y – y1 = m(x-x1)? This is for a 10th grade algebra class so if you can answer it quickly, I’d be very appreciative.
Best Answer: You already have the co-ordinates (6,-1) (2,5) use the equation y-y1=m(x-x1) on any of these co-ordinates for example (6,-1) gives y-(-1)=-3/2(x-6) multiply by 2 2y+2=-3x+18 taking x to lhs and 2 to rhs 2y+3x=16 or 3x+2y=16
Example 1 Find the equation of a line (slope-intercept form) that has a slope of 4 and passing through the point (3, 2). Solution: To find our equation we will use the formula: y – y1 = m(x – x1), where m is the slope and (x1, y1) is the point.
Best Answer: Think of the slope: m = (rise)/run Run is expressed as the difference in the x values so, the run from a given point(a,b) to any point on the line is "x - a" Rise is expressed as the difference in the y values so the rise from that given point to any point on the line is ...
1 year ago. Point-Slope: (y-y1) = m(x-x1), m is the slope, (x1,y1) is the given point (some point on the line). Standard: y = mx+b, m is the slope, b is the y-intercept (the value of y when x=0)
y - y1 = m(x - x1) The formula y - y1 = m(x - x1) is usually described as the 'point-slope form' for the equation of a line. It is useful because if you know one point on a certain line and the slope of that certain line, then you can define the line with this type of formula and, thus, find all ...
It's the Point-Line Slope formula. ... Log in with Facebook to save your favorite definitions and share them with friends.
SOLUTION: find the equation of the line that passes through (-2,3) and (4,-1). the formula I believe is y-y1 = y2-y1/x2-x1 (x-x1) I'm not quite sure as to how to set that up. do I solve as
Best Answer: Hey there! The point-slope form of a line is: y-y1=m(x-x1), where (x1,y1) is the point and m is the slope. The standard form of a line is: Ax+By=C, where A>0. Here's some examples. A line is passing through point (3,5) with the slope of 2. What is the equation of the line ...
how do you do this i dont under stand. ... MathHomeworkAnswers.org is a free math help site for student, teachers and math enthusiasts.
(y-y1)/m=x-x1 (y-y1)/m-x1=x Is that what you were looking for? ... x=y-y1+mx1 ----- m
4 years ago. Point-Slope Equation of a Line y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line.
m = the slope of a line is defined as the ratio of its increase in y coordinate (y-y1) and its increase in the x coordinate (x-x1) ... Let the line have slope m as given, and suppose it passes through the given point (x1,y1). Let (x,y) be an arbitrary point on the line. Then the slope ...
Given a problem, I can accurately use: y - y1 = m(x - x1) to get the answer, but I don't understand what its specific meaning is. Is it just another way of getting to a y = mx + b style formula suitable for graphing, or does it serve some other purpose?
question should be more explicit ... do you have to use y-y1 m(x-x1)? for those coordinates id prefer to use y=mx+c ok lets start. - coordinates (-10,-5), (9,-1) - A(-10,-5) - B (9,-1) y2-y1/x2-x1 = -1+5/9+10 4/19= m y=mx+c - use point -1,9 as i find it easier to work with less ...
This video talks about how to find the equation of a line. The first example is given a gradient and a coordinate. The second example if a line parallel to a given line through a particular coordinate. View my channel: http://www.youtube.com/jayates79
Explore This Topic: What does point - slope form look like? point-slope form looks like... y-y1=m(x-x1) these parts stay the same.... y- = (x- ) and you plug in the ordere4d pair you are given into it.
The point-slope formula is one way of expressing a linear equation. The equation is written as y-y1 = m(x-x1), where m is the slope of the line and the coordinates
User: how do you solve y-y1=m(x-x1) x1=3 y1=4 m=5? show me how to do this Weegy: PLUG THOSE VALUES IN you don't solve for anything, either put it in standard form or y = mx + b form y - (4) = (5)(x - (3)) y - 4 = 5(x - 3) distribute the 5 y - 4 = 5x - 15 add 4 to both sides y ...
This is point-slope form with slope m and point(x1,y1) Point (-4,-2) slope 3/2 y+2=(3/2)(x+4) Solve for y: y= (3/2)x +4 : Slope- intercept form
I guess the question is finding the equation of a straight line whose slope is 2/5 and which passes through the point (-20, 9). The equation of a straight line passing through a given point (x1, y1) and with a given slope, m, is
m = ( y - y ) / ( x - x ) = (-1 + 4 ) / ( 9 - 4 ) = 3/5 Hence, equation of line AB in Point-Slope Form is ... (y-y1)=m(x-x1) Where (x1,y1) are the point on the line that you are given.The other (x,y) are any x and y and m is the slope.So if we have a point (1,2) ...
Mejor respuesta: That is the slope formula. You write it incorrectly. It's supposed to be.. M=(y-y1/x-x1) ... Gosh, the guy above me. This is the more common way of writing the formula. I've never seen someone write it like you. ... to find the equation of a line, if you are given a ...
It does not correspond to any form at all. (There are no variables x and y.) Perhaps it is closest to point-slope form, where (x1, y1) is a point and m is the slope.
... the equation of the line can be written as y - y1 = m(x - x1). For example, if a line passes through the point (3, -2), and has a slope of 4, its equation can be written: y + 2 = 4(x - 3). From here, the equation can be converted to either slope-intercept or standard form.
Best Answer: Just put the points and slope into the point slope form: 3 is y_1 and 5 is x_1 m = 2/3 y - 3 = 2/3(x - 5) y - 3 = (2/3)x - 10/3 y = (2/3)x -1/3
(y-y1) = m(x-x1)... we get the same answer, and we don't have to explicitly solve for b! First, solve for slope. Second, substitute in values for slope and x1,y1, and then rearrange! slope = 6/5 (same thing we did above) so (y-y1) = m(x-x1).....
Answer Equation of a line passing thru (x1,y1) and (x2,y2) is given by (y-y1)/(x-x1)=(y2-y1)/(x2-x1) This becomes (after multiplying both sides with (x-x1))
Point-slope form question? Point slope form is: y-y1=m(x-x1), where m is the slope. Say that I were given two points: (2,7) and (-2,-7). The slope, then, is 7/2
The point-slope form of a line is y + y1 = m(x + x1), where m is the slope and (x1, y1) is a point on the line? true or false?
Answer to the points are (-3,1) and (9,2) Formula: y-y1 =m(x-x1) m = y2-y1/x2-x1 =2-1/9+3 = 1/12 Hence equation of line, y-9 = m(x.
Mejor respuesta: First of all you have to solve for m, which turns out to be negative two if you use the equation you first set up. Then, plug in an ordered pair, it does not matter which one, into the y-y1=m(x-x1) equation so you would get either y-7=(-2)(x+1) or y+3=(-2)(x-4). The ...
I am working on a project for my seventh grade math class and I was wondering how would I calculate the Y-Intercept of a graph with two points knowing the position of the two points. Here is what I...
You need to know the point-slope formula for a line. Given a point (x1, y1) that a line passes through and a slope m the equation for a line is: y - y1 = m(x - x1) For the first problem you have (-6, -3) and m=-1/2 y - (-3) = (-1/2)(x - (-6)) y + 3 = (-1/2)(x + 6) Since standard form is Ax + By ...
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Maths ... I was just wondering, which of these two methods for finding the equation of a line ... I pretty much always use y=mx+c ... never found anything that means I cannot use it ... if you want the answer in the form y=mx + c, then use that. if you want it in the form ax + by + c = 0, then ...
y1, x1, x2: Hi, The equation for a line can be written as: y - y1 = m(x - x1) where (x1,y1) is a point on the line and m is the slope. m = (y2 - y1)/(x2 - x1) Let the first point be point 1 and the second be point 2 so we have (x1,y1) = (0,5) (x2,y2)...
Write an equation in point slope form, y-y1=m(x-x1)? for the line through the point (3,-4) parallel to the line with equation 2x-5y=-10 First, solve for y: this
2. y −−−−y1 === m(x −−−−x1) m = slope, (x 1 ,y 1)is a point on the line Example 1: Find the y-intercept for: ...
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