2. A candy machine has 10 grape, 6 green apple, and 16 mango gumballs. What is the probability of selecting a grape and a mango gumball as fraction in simplest form and a percent?
P(A and B) = P (A) * P (B)
10/32 * 16/32 = 80/512 = 5/32 simplest form
The probability of choosing a grape and a mango gumball is 5/32 or 15.625%.
That depends :(
If you do not put the grape back, you only have 31 in the machine when you draw the mango.
You assumed the two events were independent. They may not be.
I would have said:
10/32 * 16/31 not 32
So it's dependent event because you don't replace it, so instead of having a total of 32 it's 31?