13Diode :- Clamper Positive Clamper Vo Vm+ Vm = 2 Vm The circuit for a positive clamper is shown in the figure. During the negative half cycle of the input signal, the diode conducts and acts like a short circuit. The output voltage Vo 0 volts . The capacitor is charged to the peak value of input voltage Vm. and it behaves like a battery. During the positive half of the input signal, the diode does not conduct and acts as an open circuit. Hence the output voltage Vo Vm+ Vm This gives a positively clamped voltage.Vo Vm+ Vm = 2 Vm
15Diode :- Clamper Negative Clamper During the positive half cycle the diode conducts and acts like a short circuit. The capacitor charges to peak value of input voltage Vm. During this interval the output Vo which is taken across the short circuit will be zero During the negative half cycle, the diode is open. The output voltage can be found by applying KVL.
18Diode :- ClamperThe circuit of a positively biased clamper is shown in the figure. During the negative half cycle of the input signal the diode is forward biased and acts like a short circuit. The capacitor charges to Vi + Vs . Applying the KVL to the input sideDuring the positive half cycle of the input signal, the diode is reverse biased and it acts as an open circuit. Hence Vs has no effect on Vo. Applying KVL around the outside loop.
19How Does A Clamp Circuit Work? In the positive half cycle C gets charged through D to 10V (peak of sine wave + 5 V) with the straight plate of C at a higher potential. D Clips the output to a maximum of -5V.In the negative half cycle D is reverse biased. The output can reach a minimum of –15V (-VC + negative peak of sine wave).LP3