1. The problem statement, all variables and given/known data 1. A 1250 Kg piledriver falls from an initial height of 1.30m above the ground onto a 15kg spike the top of which is initially 0.30m above the ground. The top of the spike finishes at ground level. Determine the average force exerted on the piledriver by the spike. *Pd=Piledriver S=Spike mass of piledriver= 1250kg h1= 1.3m h2=0m g=9.8m/s2 mass of spike=15kg h1=0.30m 2. Relevant equations Fnet=F1+F2... 3. The attempt at a solution Fnet=Fn(S) + Fg(Pd) = (15*9.8) + (1250*9.8) =12397 N Average= (FnS –FgPd) = FgPd 2 = FnS /2 = (15*9.8) /2 =73.5 N Fnet=Fn(S) + Fg(Pd) = (15*9.8) + (1250*9.8) =12397 N therefore, the average force applied on the piledriver by the spike is 73.5N * i really,reallly, really could use some assistance on this one. its grade 11 physics, so i know it can't be that hard. Any Suggestions?