Don't laugh if this basic stuff and has already been discovered centuries ago but I am just in basic Calculus. Here is what I have came up w/. In y=x^odd number(just pick any) graph, the greater the coeffecient, the closer it is to the graph x=0. But if we were to imagine what the graph of y=infinityx^odd number(just pick any) look like, I believe it will look like a vertical line at x=0.(you can check this theory by finding greater and greater secant line from the origin of this graph to a farther and farther point, the slope keeps increasing.) Same thing happens w/ the graph of y=x^infinity. Just at an exponentially faster rate but as long as you have a vertical line, I don't think slower and faster matters. So I think that y=infinityx^odd number(just pick any) is equivalent to y=x^infinity which is equivalent to the graph x=0. Now, y=smallestpositive#x^2 is equal to y=0 graph. And same w/ exponent but I think we all know that already; y=x^0. Which equals to y=1 graph. I am like an infinitologist, always trying to understand infinity in other ways, I have read so many books and articles over infinity that you won't even believe it. I think if we can understand infinity, we well get answers to all our questions. What do you think?