"On the moon of a distant planet, an astrnaut measures the period of a simple pendulum, 0.85m long, and finds it is 4.7 seconds. Back on Earth, she could throw a rock 13m straight up (while wearing her spacesuit). With the same efoort, how far up can she throw the same rock at her present location? Ignore the effects of air resistance." I calculated the g on the distant planet to be 1.5191 m/s from using T=2*pi*(square root of L/g). Okay, maybe I'm thinking too much for the 2nd part of my work, but I can't seem to figure out how to calculate how high up the ball will travel on the distant planet. It should be higher than 13m because there's less gravitational force acting upon the ball to make it come back down, right?