[SOLVED] Simple Acceleration Equation Help g=-9.80 m/s^2 t= 3.85 vi= 0.00 m/s d=? d=vi(t) + (1/2)gt^2 d=0 + (1/2)(-9.80m/s^2)((3.85s)^2) =-72.6 I'm trying to find the distance. So, this d represents displacement. Since in this case, this is also the distance, would there be any other work to show the sign change, since the d would be going from a vector to a scalar? Or should I have modified this equation beforehand to show d as a scalar, and not have taken into account the gravities negative? By the way, sorry, this must seem like a trivial matter really not worth time, but I hate not understanding it down to the tiny details. Thank you very much!