# Thread:

1. ## A staggering algebra problem.

x+(300-2x)+(170-x)+(150-x)=500

Need help with this problem. I know the solution is 200 but do not know how to achieve it.

2. Originally Posted by GeoBlockage
x+(300-2x)+(170-x)+(150-x)=500

Need help with this problem. I know the solution is 200 but do not know how to achieve it.

the solution in the book is wrong from what i am getting. show me your work.

3. x+(300-x)+(170-x)+(150-x)=500

620x-4x=500

616x=500

x=116

4. Originally Posted by GeoBlockage
x+(300-x)+(170-x)+(150-x)=500

620x-4x=500

616x=500

x=116
you must use the distributive law outside the brackets. when there is no number present in front of the bracket, you must add an imaginary 1.

$x+(300-x)+(170-x)+(150-x)=500$

$<br /> x+1(300-x)+1(170-x)+1(150-x)=500$

$x+300-x+170-x+150-x=500$

$x-x-x-x=500-300-170-150$

$-2x=-120$

$<br /> x=60$
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