# Thread:

1. ## Equation of circles

So, I've attached both the question and my working inside.

for part 1, I'm not sure how to get the radius and for part 2, how to get the point?
Attached Thumbnails

2. ## Re: Equation of circles

Originally Posted by Thorpelizts
So, I've attached both the question and my working inside.

for part 1, I'm not sure how to get the radius and for part 2, how to get the point?
In part 1, complete the square on the x terms and complete the square on the y terms. Then move any extra constants to the right. You should then be able to write the equation in the form $\displaystyle \begin{align*} (x - h)^2 + (y -k )^2 = r^2 \end{align*}$.

As for part b), the y axis is where x = 0, so let x = 0 in your equation and solve for y.

3. ## Re: Equation of circles

I didn't look at your work, I don't care for images of hand-written work.

We are given the equation:

$x^2+y^2-6x-8y+16=0$

You want to complete the square on the two variables:

$(x^2-6x+9)+(y^2-8y+16)=-16+9+16$

Now, you want to get this into the form:

$(x-h)^2+(y-k)^2=r^2$

where the center is at $(h,k)$ and the radius is $r$.

Can you proceed?

For part b), what is the equation of the $y$-axis?

edit: sorry, I didn't see your post Prove It.
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