# Thread:

1. ## Implicit Differentation

$e^y+24-e^-1 = 5x^2+4y^2$

I can't figure this out....

I believe this stage is correct $e^y+e^-1=10x+8y*y'-y'$

But Need help on further solving it.

Help appreciate.

2. Actually the first step should be $y'e^y = 10x + 8yy'$

3. Where did you put the $e^-1$?

4. $e^{-1}$ is a constant and its derivative is 0.

5. I thought it was -e^-1.

Anyway, in case of constant I get $(10x)/(-1*e^y-8y)$. Where could I have gone wrong there?

6. I get $y' = \frac{10x}{e^y - 8y}$

7. The reason i have negative 1 is because there are two y', and when i place it ont he other side (-y') I factored and assumed 1. Why is this not correct?

Thanks however.
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