# Thread:

1. ## projectile

a projectile is shot upwards with an initial velocity of $30m/s$ , its height at time t is given by $h=30t-4.9t^2$, during what period of time is the projectile more then $40m$ above the ground? express your answer rounded to the nearest hundredths

my thinking: $40=30t-4.9t^2$ but can't go anywhere from there

2. Originally Posted by william
a projectile is shot upwards with an initial velocity of $30m/s$ , its height at time t is given by $h=30t-4.9t^2$, during what period of time is the projectile more then $40m$ above the ground? express your answer rounded to the nearest hundredths

my thinking: $40=30t-4.9t^2$ but can't go anywhere from there
So $4.9t^2-30t+40=0$
Use the quadratic formula: $t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
$a=4.9$ $b=-30$ $c=40$

3. Originally Posted by JeWiSh
So $4.9t^2-30t+40=0$
Use the quadratic formula: $t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
$a=4.9$ $b=-30$ $c=40$
so it was above 40m between 1.9 and 4.1 seconds?

4. Originally Posted by william
so it was above 40m between 1.9 and 4.1 seconds?
Correct
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