Thread:  Relativity of Simultaneity 		 		View Single Post

Recognitions:
Gold Member

Quote by DaleSpam 					 				 				Now, transforming to the primed coordinates using the above formulas (v=0.5) gives $(t'_A,x'_A)=(0,0)$, $(t'_B,x'_B)=(-.5,1)$, and $(t'_C,x'_C)=(1,-.5)$.  So we see that $t_A \ne t_B$ meaning that simultaneity is relative, and the time between A and C is still 1 meaning that time does not dilate.
What happened to gamma?

The way I calculate the three transformed events, I get:

A' = (0,0)
B' = (-0.577,1.1547)
C' = (1.1547,-0.577)

So A and C do not have the same time coordinates so they are not simultaneous.

EDIT: I see that wasn't your point. I should have said, the time between A and C is not the same as before, it's longer in the primed frame. But I wouldn't call that time dilation, it's just different coordinates for a pair of events.
{"extraction_info": {"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 4, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0}, "config": {"markdown_headings": true, "markdown_code": true, "boilerplate_config": {"ratio_threshold": 0.3, "absolute_threshold": 10, "end_threshold": 15, "enable": true}, "remove_buttons": true, "remove_image_figures": true, "remove_link_clusters": true, "table_config": {"min_rows": 2, "min_cols": 3, "format": "github"}, "remove_chinese": true, "remove_edit_buttons": true, "extract_latex": true}, "english_confidence": 0.9500042796134949, "perplexity_flag": "middle"}