# Thread:

1. ## Getting to the root of the equation

The equation has two roots. Find the smaller and larger one?

so I came up with 2x2e-5x(3-3x)=0

Just not sure where to go from here?

2. ## Re: Getting to the root of the equation

Originally Posted by M670
The equation has two roots. Find the smaller and larger one?

so I came up with 2x2e-5x(3-3x)=0

Just not sure where to go from here?
You need to use the zero product principle. This would give

$2x^2=0 \quad e^{-5x}=0 \quad 3-3x=0$

Only two of these equations have solutions.
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