Physics Forums

Significance of kinematic and dynamic viscosity

It is stated that kinematic viscosity is the ratio of dynamic viscosity to density. can anyone elaborate it further that what are the uses of both types of viscosities and why we differentiate them.does dynamic viscosity reates with static fluid?

PhysOrg.com  engineering news on PhysOrg.com  >> Researchers use light projector and single-pixel detectors to create 3-D images>> GPS solution provides 3-minute tsunami alerts>> Single-pixel power: Scientists make 3-D images without a camera

It is really just a term of convenience. Oftentimes, the equations of fluid mechanics are manipulated such that you end up with $\mu/\rho$ terms, so it is simply much easier to carry around a $\nu$ instead of a fraction. This is commonly seen with the Reynolds number, which has a $\mu/\rho$ term in it.

then how kinematic viscosity is termed as momentum diffusivity, i m very confused with these terms.

Significance of kinematic and dynamic viscosity

Well, as with any sort of viscosity, it is really a measure of how momentum is diffused through a fluid. If you are familiar with the heat equation, you should notice some analogs between it and the Navier-Stokes equations.

The heat equation:
$$\frac{\partial \phi}{\partial t} = c^2\nabla^2 \phi$$

The incompressible Navier-Stokes equation:
$$\frac{\partial \mathbf{v}}{\partial t} + \mathbf{v}\cdot\nabla\mathbf{v}=-\frac{1}{\rho}\nabla p + \nu\nabla^2\mathbf{v} + \mathbf{f}$$

The heat equation is a simplified version of the diffusion equation that describes the diffusion of basically any quantity through a material. In heat transfer, $c^2=\alpha=\frac{k}{\rho c_p}$ is the thermal diffusivity.

In the Navier-Stokes equations, notice that the $\nu\nabla^2\mathbf{v}$ term takes the same form, only the N-S equations are a momentum balance, so the kinematic viscosity, $\nu$, is essentially a diffusivity constant that describes how momentum diffuses through the medium. In other words, it describes one particle's ability to affect the momentum of the adjacent particles.

i have understand. thanxx for your help boneh3ad. :)

Thread Tools

|                                                                      |                        |         |
|----------------------------------------------------------------------|------------------------|---------|
| Similar Threads for: Significance of kinematic and dynamic viscosity |                        |         |
| Thread                                                               | Forum                  | Replies |
|                                                                      | General Physics        | 5       |
|                                                                      | Classical Physics      | 3       |
|                                                                      | Mechanical Engineering | 0       |
|                                                                      | Mechanical Engineering | 3       |
|                                                                      | General Physics        | 5       |
{"extraction_info": {"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 6, "mathjax_display_tex": 2, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0}, "config": {"markdown_headings": false, "markdown_code": false, "boilerplate_config": {"ratio_threshold": 0.18, "absolute_threshold": 10, "end_threshold": 15, "enable": true}, "remove_buttons": true, "remove_image_figures": true, "remove_link_clusters": true, "table_config": {"min_rows": 2, "min_cols": 3, "format": "github"}, "remove_chinese": true, "remove_edit_buttons": true, "extract_latex": true}, "english_confidence": 0.8974674940109253, "perplexity_flag": "middle"}