# Thread:

1. ## Solve for y as a function of x

The Eq is supposed to be solved for Y as a function of X :

$y^x = x^y + 1$

2. Originally Posted by xterminal01
The Eq is supposed to be solved for Y as a function of X :

$y^x = x^y + 1$
Take the natural log of both sides...

$xln|y|=yln|x|$
$\frac{y}{x}=\frac{ln|y|}{ln|x|}$
$\frac{y}{x}=log_xy$

I'm now as lost as you are...

3. Recall $\log(a+b)$ has not property.

4. Set $g(x,y)=y^{x}-x^{y}-1$

$\frac{\partial{g}}{\partial{y}}=xy^{x-1}-x^{y}\ln(x),$
whose value at (1,2) equals 1 ? Is this correct?

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