Thread:

1. projectile + energy

a shell of mass 50kg at 60 degree to the horizontal with a speed 200 m/s . neglecting air resistance, the energy of the shell in joules at its highest point?

help me with this question!

2. Originally Posted by power0
a shell of mass 50kg at 60 degree to the horizontal with a speed 200 m/s . neglecting air resistance, the energy of the shell in joules at its highest point?
By conservation of Energy, it should be the same as initial energy when you threw the projectile.

So the answer is $\frac12 m v^2 = \frac12. 50.(200)^2 = 10^6 J = 1MJ$

help me with this question!
I am happy 7 is the largest font size

3. Originally Posted by power0
a shell of mass 50kg at 60 degree to the horizontal with a speed 200 m/s . neglecting air resistance, the energy of the shell in joules at its highest point?

help me with this question!
In the future, please don't yell when asking a question. We can read regular sized font quite nicely actually.

-Dan
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