# Tpofofn

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# 241 Actions

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| Mar23 | comment   | An eigenvector is a non-zero vector such that…@ScottH.  I think that you are confusing the notions of a space and a basis.  A basis is a non-zero vector which is linearly independent (i.e. cannot contain the zero vector) and spans the space.  An eigenvector cannot be zero because it is a basis.  The space spanned by the eigenvector must contain the zero vector.                                                                                                                                           |
| Mar22 | comment   | An eigenvector is a non-zero vector such that…An eigenspace is spanned by a non-zero eigenvector associated with a particular eigenvalue.  The eigenspace must be at least one dimensional and therefore excludes using the zero vector as an eigenvector.                                                                                                                                                                                                                                                            |
| Mar6  | comment   | New vector positionIs the axis aligned with one of your coordinate axes.  If so, then you can omit that axis in your calculations.  Don't include it in your distance calculations and don't include it in your scaling calculations.  If it is not aligned with a coordinate axis, then you need something more sophisticated.                                                                                                                                                                                       |
| Mar6  | comment   | New vector positionIt is essentially the same equation just written a different way.  The steps you need to go through are as follows: (1) compute the average distance, (2) compute the relative vector to the center $v_i - c$, (3) normalize it to unit length by dividing it by its own length, (4) scaling it to the average length and then finally (5) adding the center back onto the result.  The referenced post does essentially the same thing, except that it distributes the scaling to each component. |
| Mar5  | comment   | New vector positionAlmost.  You should use: npX = (vts[0] - cs[0]) / (distanceFromCenter[for this point]) * averageDistance + cs[0]                                                                                                                                                                                                                                                                                                                                                                                   |
| Mar5  | comment   | New vector positionJust the magnitude of the vector.  I believe that you compute it in your first loop and call it distanceFromCenter.                                                                                                                                                                                                                                                                                                                                                                                |
| Mar5  | revised   | How to get Euler angles with respect to initial Euler angleadded 435 characters in body                                                                                                                                                                                                                                                                                                                                                                                                                               |
| Mar5  | answered  | New vector position                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                   |
| Mar5  | answered  | How to get Euler angles with respect to initial Euler angle                                                                                                                                                                                                                                                                                                                                                                                                                                                           |
| Mar5  | comment   | New vector positionSo you have 8 points (for example) and a center point.  You want to update the 8 points based on their distance to the center point.  It is not clear what you want the new points to be based on their distance to the center point.  Please clarify                                                                                                                                                                                                                                              |
| Mar5  | comment   | New vector positionobserving your code, it appears that you are summing the coordinates in oldCoordArray.  If you divide by the number of points, you should have the center of the points.                                                                                                                                                                                                                                                                                                                           |
| Mar5  | comment   | New vector positionI guess I meant, compute the average coordinate in each axis separately (i.e. x, y, z).                                                                                                                                                                                                                                                                                                                                                                                                            |
| Mar5  | comment   | New vector positionIs it safe to assume that you want to compute the new center so that it has a minimum average distance to each point?  If so, compute average distances in each of the coordinates separately.  These three average coordinates will give you the new center point.                                                                                                                                                                                                                                |
| Mar5  | comment   | Identifying a pattern in an arrayDo you know what type of process generated the array or is it completely unknown?                                                                                                                                                                                                                                                                                                                                                                                                    |
| Mar5  | revised   | identify unknown variables in a graph plotedited tags                                                                                                                                                                                                                                                                                                                                                                                                                                                                 |
| Mar5  | comment   | identify unknown variables in a graph plotPlease explain what you mean by "how many variables are responsible for the plot".  If you have a plot of distance vs. time then you have two variables (1) time (the independent variable) and (2) distance (the dependent variable).                                                                                                                                                                                                                                      |
| Mar3  | revised   | I cannot solve this problem about surface area of a coneInserted LaTeX to make more readable.                                                                                                                                                                                                                                                                                                                                                                                                                         |
| Mar3  | suggested | suggested edit on I cannot solve this problem about surface area of a cone                                                                                                                                                                                                                                                                                                                                                                                                                                            |
| Mar2  | answered  | What is the intuitive meaning of the basis of a vector space and the span?                                                                                                                                                                                                                                                                                                                                                                                                                                            |
| Feb27 | comment   | Subspace of a Vector Space must be non-empty.To have a subspace the span must form a group under vector addition.  A group must contain an identity element, the zero vector $\mathbf 0$.  A subspace spanned by ${\mathbf 0}$ is zero-dimensional (i.e. consists of one point).  This is the smallest subspace that one can have.                                                                                                                                                                                    |
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