# Thread:

1. ## confused :(

Ok, I am graphing P=(1,2) with slope m=3. This is how I worked out

$y-2=3(x-1)$

= $y-2=3x-3$

= $y=3x-3+2$

= $y=3x-1$

If x=0 then;

$y=3(0)-1$

= $y=-1$

and so (0,-1)

this would be my second point no, or is this my run? In checking with the book's answer to see if I had done this right it showed my second point to be (2,5) with a run of 1 and a rise of 3......Did I do something wrong in the calculations!?

Thanks!!

2. You are right. When graphing a line by getting 2 points and drawing a line through them you can use any 2 points on a line. The book simply chose its points differently.

3. Originally Posted by badgerigar
You are right. When graphing a line by getting 2 points and drawing a line through them you can use any 2 points on a line. The book simply chose its points differently.
.....oh, ok. So in this case, having my second points (0,-1) I can then find the run of the slope no?!

Thanks !!!

4. So in this case, having my second points (0,-1) I can then find the run of the slope no?!
The run is the x-value of the 2nd point minus the x-value of the first point. The rise is the y-value of the second point minus the y-value of the first point.
They are pretty much only useful to find the slope using $m = \frac {rise}{run}$
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