# Thread:

1. ## Real analysis question on subsequence

Hi, my question is:

Let L be a real number and let (a_n) be a sequence of real numbers that does not converge to L (that is, it is either divergent or its limit is not equal to L). Use the definition of convergence to L to show that for some e greater than 0, (a_n) has a subsequence (a_n(_k)) such that (a_n(_k)) isn't in the interval (L - e, L+e) for all natural numbers k.

Any help would be hugely appreciated

2. ## Re: Real analysis question on subsequence

Originally Posted by sakuraxkisu
Let L be a real number and let (a_n) be a sequence of real numbers that does not converge to L (that is, it is either divergent or its limit is not equal to L). Use the definition of convergence to L to show that for some e greater than 0, (a_n) has a subsequence (a_n(_k)) such that (a_n(_k)) isn't in the interval (L - e, L+e) for all natural numbers k.

To say that $\left( {a_n } \right)\not \to L$ means that
$\left( {\exists \varepsilon > 0} \right)\left( {\forall N} \right)\left( {\exists n_N > N} \right)\left[ {\left| {L - a_{N_n } } \right| \geqslant \varepsilon } \right]$.

Find the first $N_1$ then apply the above and find $N_2>N_1$ that works.

By induction, find a sequence of integers $N_1<N_2<\cdots<N_m<\cdots.$

3. ## Re: Real analysis question on subsequence

Plato, great explanation, solved my other problem in the series also. I am glad that I bumped into this thread.

4. ## Re: Real analysis question on subsequence

Originally Posted by SeirraFalcom
Plato, great explanation, solved my other problem in the series also. I am glad that I bumped into this thread.
Update: I am stuck again in the test prep of my discrete math subject.
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