# Thread:

1. ## cube problem

Suppose each edge is 6 inches long. Find the measure of the angle formed by diagonal GB and edge GC.
I can do similar problems but the angle on this one is killing me. Can someone please help m figure it out? thanks sooooo much

2. Hello, daydreembelievr!

Suppose each edge is 6 inches long.
Find the measure of the angle formed by diagonal $GB$ and edge $GC$.

Triangle $BCG$ is a right triangle.
Code:
```            * B
           /|
          / |
         /  |   _
        /   | 6√2
       /    |
      /     |
     / θ    |
  G *-------* C 
        6```

$GC$ is an edge of the cube: . $GC \:=\:6$

$BC$ is the diagonal of a face: . $BC \:=\:6\sqrt{2}$

Then: . $\tan\theta\:=\:\frac{6\sqrt{2}}{6} \:=\:<br /> \sqrt{2}\quad\Rightarrow\quad \theta \:\approx\:54.7^o$

3. I was having so much trouble visualizing it in 2D, but now that makes a lot of sense. thanks so much
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