# Thread:

1. ## Solving a radical equation.......

I cannot figure this part out for the life of me. I have it written in the picture so hopefully it's readable. Please let me know if you need another picture.

2. Originally Posted by redlinethecar
I cannot figure this part out for the life of me. I have it written in the picture so hopefully it's readable. Please let me know if you need another picture.
What picture?

3. Sorry, I fixed it. My mind is not working right now

4. $\left(\sqrt{x+2}+2\right)^2=\left(\sqrt{x+2}+2\rig ht)\left(\sqrt{x+2}+2\right)$

$=\left(\sqrt{x+2}\right)\left(\sqrt{x+2}\right)+\l eft(\sqrt{x+2}\right)2+2\left(\sqrt{x+2}\right)+2( 2)$

just as

$5^2=25$

$(3+2)^2=(3+2)(3+2)=3(3+2)+2(3+2)=3(3)+3(2)+2(3)+2( 2)$

$=9+6+6+4=25$

#### Search Tags

View Tag Cloud

Copyright © 2005-2013 Math Help Forum. All rights reserved.
{"extraction_info": {"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 5, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0}, "config": {"markdown_headings": true, "markdown_code": true, "boilerplate_config": {"ratio_threshold": 0.18, "absolute_threshold": 10, "end_threshold": 15, "enable": false}, "remove_buttons": true, "remove_image_figures": true, "remove_link_clusters": true, "table_config": {"min_rows": 2, "min_cols": 3, "format": "github"}, "remove_chinese": true, "remove_edit_buttons": true, "extract_latex": true}, "english_confidence": 0.9511208534240723, "perplexity_flag": "middle"}