# Thread:

1. ## proving sin^2(x)<=|sin(x)|

For all x, prove that $sin^{2}(x)\leq|sin(x)|$ given that x is in the set of real numbers.

I think i need to break this into a couple different cases, specifically: (0, $\pi$),( $\pi$, $2\pi$), but am not sure. Any help would be appreciated.

2. Originally Posted by snaes
For all x, prove that $sin^{2}(x)\leq|sin(x)|$ given that x is in the set of real numbers.
Don’t make it difficult. Recall that $0\leqslant a \leqslant 1\, \Rightarrow \,a^2 \leqslant a$.

We know that $0\le |\sin(x)|\le1$ so $\sin^2(x)=|\sin(x)|^2\le |\sin(x)|$.

3. Thanks, I was definitely over-thinking that.
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