# Thread:

1. ## Exponential cipher

I tried to work through this ex in my book which is not typical of the ex I have done and I am confused after first part
for part a I worked out that inverse of 5 in Z36 is 29. hope this is correct
but I have no clue as to where to and how to start part b - which is attached here. Can someone please guide me in detail as I am studying this for the first type.

2. ## Re: Exponential cipher

Originally Posted by vidhi96
I tried to work through this ex in my book which is not typical of the ex I have done and I am confused after first part
for part a I worked out that inverse of 5 in Z36 is 29. hope this is correct
This is correct : $5\times 29 = 145 = 4\times 36 + 1$

Originally Posted by vidhi96
but I have no clue as to where to and how to start part b - which is attached here. Can someone please guide me in detail as I am studying this for the first type.
The table gives you a correspondence $C : \{A,\dots,Z\} \rightarrow \{1,\dots,26\}$. So for a letter $\alpha$, the cipher letter is $C^{-1}(E(C(\alpha)))$ (I didn't check, but in order to apply $C^{-1}$, one must have $m^5 (\mathrm{mod}\, 37) \in \{1,\dots,26\},\ \forall m\in\{1,\dots,26\}$).

When you have a word, it's a sequence of letter : you encrypt every letter of this sequence and have this way a sequence of cipher letter. It's your cipher text.

3. ## Re: Exponential cipher

i am more confused. What I figured out by now is message ext is <23 8 5 14> spelling WHEN.

so now I need to find c - which is chipher text is that correct

Originally Posted by pece
This is correct : $5\times 29 = 145 = 4\times 36 + 1$

The table gives you a correspondence $C : \{A,\dots,Z\} \rightarrow \{1,\dots,26\}$. So for a letter $\alpha$, the cipher letter is $C^{-1}(E(C(\alpha)))$ (I didn't check, but in order to apply $C^{-1}$, one must have $m^5 (\mathrm{mod}\, 37) \in \{1,\dots,26\},\ \forall m\in\{1,\dots,26\}$).

When you have a word, it's a sequence of letter : you encrypt every letter of this sequence and have this way a sequence of cipher letter. It's your cipher text.

4. ## Re: Exponential cipher

Originally Posted by vidhi96
i am more confused. What I figured out by now is message ext is <23 8 5 14> spelling WHEN.
Now you have to apply $E$ to each of these numbers and then retranslate the result into letters.

5. ## Re: Exponential cipher

Originally Posted by pece
Now you have to apply $E$ to each of these numbers and then retranslate the result into letters.
Ok I'll try and type it and send it to you tomorrow
{"extraction_info": {"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 14, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0}, "config": {"markdown_headings": true, "markdown_code": true, "boilerplate_config": {"ratio_threshold": 0.18, "absolute_threshold": 10, "end_threshold": 15, "enable": true}, "remove_buttons": true, "remove_image_figures": true, "remove_link_clusters": true, "table_config": {"min_rows": 2, "min_cols": 3, "format": "github"}, "remove_chinese": true, "remove_edit_buttons": true, "extract_latex": true}, "english_confidence": 0.9621368646621704, "perplexity_flag": "middle"}