# Neutralino Dark Matter Detection

Assuming supersymmetry exists and a neutralino is stable, it's often seen as a leading dark matter candidate. What would be expected from the interaction of a neutralino and its anti-particle? Has there been any unambiguous detection of such an interaction?

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## 2 Answers

Dear Michael, neutralino carries no conserved charges that can take arbitrarily large values (and no spin) and it is identical with its antiparticle, much like in the case of photons. That still allows two neutralinos to annihilate.

Neutralinos only carry a "1" charge under the $Z_2$ symmetry called R-parity. This means that the number of neutralinos must be conserved modulo 2. This is compatible with the annihilation of pairs of neutralinos. The annihilation of neutralino pairs was important when the Universe was young. With the right TeV-like mass and MSSM-like annihilation cross section, models may predict that the dark matter density has been diluted exactly to the observed value (plus minus a few orders of magnitude which is still a nontrivial agreement).

The products of this annihilation are most typically two photons (but two gluons or gamma-Z are also possible) and the resulting gamma rays are so rare in the present era that it's hard to observe them. However, people have still tried to argue that they should be observable, at least under various assumptions:

http://arxiv.org/abs/astro-ph/9712318

As far as I know, none of those gamma rays has been observed as of today.

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Lubos: Dark matter is supposedly 23% of the universe mass/energy. Why are "the resulting gamma rays are so rare in the present era"? Dark matter "out-masses" baryons by 5:1. – Michael Luciuk Apr 23 '11 at 12:44
maybe because dark matter is not made of neutralinos at all? – lurscher Apr 23 '11 at 21:28

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@Michael: In Lubos' scenario, the neutralino equilibrium period would have ended considerably before the radiation decoupling, so the the annihilation gammas made up until then would never be detected in the present time. Only those made by pairs interacting since the decoupling. – dmckee♦ Apr 24 '11 at 0:55
Thanks dmckee. Good point. – Michael Luciuk Apr 24 '11 at 1:41

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– stringpheno Apr 24 '11 at 3:56
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It could be that the neutralino is a Majorana fermion. The $Z_2$ structure could be a signature of a Majorana fermion. The Majorana fermion is the charge conjugate fermion of the form $\psi_c~=~\gamma^2\psi^*$ with $\psi_c~=~\psi$. This has some interesting statistics. For fermions the exchange of a wave function introduces a negative sign. The additional constraint that $\psi~=~\gamma^2\psi^*$, means that the $\gamma^2$ introduces a braid structure into the exchange statistics of Majorana fermions. If this is the case the neutralino is its own anti-particle. The annihilation of the neutralino particle could then be a type of decay process.

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Er...perhaps I'm about to expose myself as an ignoramus, but aren't the super-symmetric partners of fermions (like, say, neutrinos) bosons automatically? Or do things change when you get Majorana particles running around the place? – dmckee♦ Apr 24 '11 at 0:51
@dmckee The neutralino isn't related to the neutrino despite the apparent name similarity (similarly, the neutron and neutrino aren't closely related). Neutralinos is actually a mixture of different states of the supersymmetric partners of the Z, photon, and higgs bosons (since they are uncharged and have the same quantum numbers they can mix to form 4 different eigenstates which look like different particles). The least massive such particle is the most likely candidate for the cold dark matter WIMPs. – Wedge Feb 24 at 23:40
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