# Thread:

1. ## Sine and Cosine

Not sure what this question is asking me, when their is no numbers to calculate, can someone please explain this to me

If Cos(x)=m then what is the value of Cos (180-x)?

Thanks

2. $\cos(a-b) = \cos a \cos b + \sin a \sin b$

3. It's a trigonometric identity.

cos(180 - x) is always the opposite of cos(x).

You could come to that conclusion several ways, but the easiest method is to look at a typical angle Q on a graph and compare it with its supplement (which is defined as 180 - Q), and then you will see why the conclusion is true.

4. Originally Posted by icemanfan
It's a trigonometric identity.

cos(180 - x) is always the opposite of cos(x).

You could come to that conclusion several ways, but the easiest method is to look at a typical angle Q on a graph and compare it with its supplement (which is defined as 180 - Q), and then you will see why the conclusion is true.
so the answer that i would be looking for then is -cos(180-x), or am i way out to lunch on this one

5. Originally Posted by nuckers
so the answer that i would be looking for then is -cos(180-x), or am i way out to lunch on this one
Well, if cos(x) = m and cos(180 - x) is the opposite of cos(x), then what does cos(180 - x) equal in terms of m?

6. Originally Posted by nuckers
so the answer that i would be looking for then is -cos(180-x), or am i way out to lunch on this one
if $\cos{x} = m$ , then $\cos(180-x) = -m$

... that's all.

7. Originally Posted by icemanfan
Well, if cos(x) = m and cos(180 - x) is the opposite of cos(x), then what does cos(180 - x) equal in terms of m?
Ok, i understand now, thanks so much for the help
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