# Thread:

1. ## Help Needed in Graphing Equations

I honestly don't know what I would do without this forum. This time, I am stumped by a graphing problem with equations. The question is...

Graph the equation 3y = 2x + 5 and calculate slope, x-intercept and y-intercept.

I have been working on this one problem for a while now and so far, I have deciphered that the x and y intercept is x=-5/2 and y=5/3...is that correct? If that is correct, then the slope should be 1...again if I am doing it right.

As always, any help would be greatly appreciated.

2. Originally Posted by dclary

I have been working on this one problem for a while now and so far, I have deciphered that the x and y intercept is x=-5/2 and y=5/3...is that correct?
They are correct.

Originally Posted by dclary
If that is correct, then the slope should be 1...again if I am doing it right.
The slope is not 1. You need to use the points you just found to find $m = \frac{y_2-y_1}{x_2-x_1}$ or find the eqn in the form $y=mx+c$

3. Hi Pickslides, thank you. To graph the equation for x=-5/2, I would go left 5 and up 2...right? and for the y=5/3, I would go up 5 and across to 3? I just want to make sure I am headed in the right direction. Thank you again for your help.

4. Originally Posted by dclary
Hi Pickslides, thank you. To graph the equation for x=-5/2, I would go left 5 and up 2...right? and for the y=5/3, I would go up 5 and across to 3? I just want to make sure I am headed in the right direction. Thank you again for your help.
No this is not correct. Draw your x and y axis, then mark the respective values you have found on each axis.

Your points are and $\left(x_1,y_1\right) = \left(\frac{-5}{2},0\right)$ and $\left(x_2,y_2\right) = \left(0, \frac{5}{3}\right)$

Now find the gradient using $m = \frac{y_2-y_1}{x_2-x_1}$

5. I finally got it figured out...thank you again Pickslides :-)
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