# Thread:

1. ## convexity and epigraph question

Prove that if the epigraph is a convex set then the function below the epigraph is convex.

Here's what I have so far.

The epigraph is going to be in $\mathbb{R}^{n+1}$ and the supporting function in $\mathbb{R}^n$.

In the epigraph we are going to have a hyperplane of n+1 dimensions and a hyperplane of n dimensions for $f(x_1,x_2,..x_n)$. So what I"m thinking is to find find the maximum slope of of the function $f$ and rotating the hyperplane in the epigraph so that both are going to be parallel (this is the part I have no idea on how to do, as we can possibly in 4+ dimensions. I have no idea how a rotation matrix will look like). At which point we simply lower the hyperplane from the epigraph to hit the function $f(x_1,x_2,..x_n)$ but still remain above $f(x_1,x_2,..x_n)$. Now every value from $f(x_1,x_2,..x_n)$ will be below the hyperplane (from the epigraph) showing that $f(x_1,x_2,..x_n)$ is convex.
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