# Thread:

1. ## [SOLVED] Lines and Planes?

It says, Find the equation of the plane in xyz-space through the point P = (3, 5, 3) and perpendicular to the vector n = (-5, -5, -4). Can someone show me, step by step how to work this problem out or explain to me what I'm doing? I'm so lost.

2. Originally Posted by Bracketology
It says, Find the equation of the plane in xyz-space through the point P = (3, 5, 3) and perpendicular to the vector n = (-5, -5, -4). Can someone show me, step by step how to work this problem out or explain to me what I'm doing? I'm so lost.
Let $R=<x,y,z>-<3.5,3>=<x-3,y-5,z-3>$

Then the plane is $n\cdot R=0.$

3. Thanks, figured it out
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