# Thread:

1. ## write an equation

a line parallel to 3x +2y - 4=0 and passing through (2;3)

Thank you very much

PS Still confused. Two lines are perpendicular if the product of their slope -1. Please detail.

2. Originally Posted by ecdino2
a line parallel to 3x +2y - 4=0 and passing through (2;3)

Thank you very much

PS Still confused. Two lines are perpendicular if the product of their slope -1. Please detail.
re-write
$3x+2y=4$

any line parallel will be of the form:
$3x+2y=z,\ \forall z\in\mathbb{R}$

3. Originally Posted by ecdino2
a line parallel to 3x +2y - 4=0 and passing through (2;3)

Thank you very much

PS Still confused. Two lines are perpendicular if the product of their slope -1. Please detail.

Two lines are perpendicular if the product of their slopes is -1

and

Two lines are parallel if their slopes are equal

These should be stated in your book or should be taught by your instructor.

and the equation of a line passing through a point $(x_1, y_1)$ is given by:

$y-y_1= m(x-x_1)$ .............................(I)

Now use this above formula to find the equation of the line passing through (2,3).

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for the line $3x +2y - 4=0$., find the slope of this line by re-writing the equation in the form of $y = mx+b$; where m is the slope.

so you have : $3x +2y - 4=0 \implies 2y = -3x+4 \implies y = \frac{-3}{2}x + \frac{4}{3}$

so the slope of this line is $\frac{-3}{2}$. since the two lines are parallel, the slope of the other line should also be $\frac{-3}{2}$

so you have the point(2,3) and the slope m = -3/2. plug these in equation (I) to find the equation of the line.

This question is similar to the one you had posted before

4. ## write an equation

of a line parallel to 3x +3y-4=0 passing through the point(2,3)

5. Originally Posted by lorica2000
of a line parallel to 3x +3y-4=0 passing through the point(2,3)
refer to the steps given in Post#3 in this thread!

Show your work if you are stuck.
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