# Hypothesis Testing for Two Proportions

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• January 13th 2012, 02:10 PM
Ajhah
Hypothesis Testing for Two Proportions
I have a problem I am doing for hw for my Data Analysis II course, which involves the use of Minitab and need help. I solved it, but need to know if I had done it correctly.

Problem: A random sample of 78 women ages 21-29 in Denver showed that 23 have a college degree. Another random sample of 73 men in Denver in the same age group showed that 20 have a college degree. Based on information from Educational Attainment in the United States, Bureau of the Census, does this indicate that the proportion of Denver women ages 21-29 with college degrees is more than Denver men in this same age group?

My Minitab output:

Test and CI for Two Proportions

Sample X N Sample p
1 23 78 0.294872
2 20 73 0.273973

Difference = p (1) - p (2)
Estimate for difference: 0.0208992
95% lower bound for difference: -0.0998659
Test for difference = 0 (vs > 0): Z = 0.28 P-Value = 0.388

My Answer:
Decision: 0.388 > 0.05 , so Fail to reject the null hypothesis

Conclusion: There exists sufficient evidence at the 5% level of significance that the true proportion of Denver women ages 21-29 with college degrees is more than the true proportion of Denver men ages 21-29 with college degrees.
• January 13th 2012, 02:31 PM
pickslides
Re: Hypothesis Testing for Two Proportions
Decision is correct, fail to reject $H_0$ and therefore conclude there is no evidence to suggest the true proportion of women with college degrees is greater than the true proportion of men with college degrees.
• January 14th 2012, 01:52 PM
Ajhah
Re: Hypothesis Testing for Two Proportions
Sorry, I meant to type insufficient evidence. My bad...thanks for the help!
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