a father is now 3 times as old as his son . 8 years back , he was 4 times as old as his son . the age of the son ( in years ) is
if father ' s age is f and son ' s age is s , then f = 3 s and f - 8 = 4 * ( s - 8 ) 3 s - 5 = 4 s - 32 s = 24 f = 72 years answer : b
subtract(multiply(8, 4), 8)