how many zeroes are there at the end of the number n , if n = 100 ! + 200 ! ?
"the number of zeroes at the end of 100 ! will be less than the number of zeroes at the end of 200 ! hence it would be sufficient to calculate the number of zeroes at the end of 100 ! number of zeroes = [ 100 / 5 ] + [ 100 / 25 ] + [ 100 / 125 ] = 20 + 4 + 0 = 24 correct option : e"
add(divide(100, add(const_4, const_1)), const_2)