a is two years older than b who is twice as old as c . if the total of the ages of a , b nd c be 27 , then how old is b ?
"solution let c ' s age be x years . then , b ' s age = 2 x years . a ' s age = ( 2 x + 2 ) years . ∴ ( 2 x + 2 ) + 2 x + x = 27 ⇔ 5 x = 25 ⇔ x = 5 . hence , b ' s age = 2 x = 10 years . answer d"
divide(multiply(subtract(27, const_2), const_2), add(const_4, const_1))