what is the remainder when 1041 * 1047 * 1050 * 1053 is divided by 33 ?
"take the remainder from each of 1041 / 33 , 1047 / 33 and so on . . 1044 / 33 gives remainder = 18 1047 / 33 gives remainder = 24 1050 / 33 gives remainder = 27 1053 / 33 gives remainder = 30 the net remainder is the product of above individual remainders . i . e = 18 * 24 * 27 * 30 break them into pairs 18 * 24 / 33 gives remainder 3 and 27 * 30 / 33 gives remainder 18 so 3 * 18 / 33 gives remainder 21 . d"
reminder(multiply(1047, 1041), 1050)