in a 200 m race , a beats b by 20 m and c by 38 m . in a race of 600 m b will beat c by
"it means , when a covers 200 m , b covers only ( 200 - 20 ) = 180 m and c covers only ( 200 - 38 ) = 162 m = > when c covers 162 m , b covers 180 m = > when b covers 600 m , c covers 162 / 180 × 600 = 540 m hence , b beats c by 600 - 540 = 60 metre answer : e"
subtract(600, multiply(inverse(multiply(divide(200, subtract(200, 38)), divide(subtract(200, 20), 200))), 600))