we invested a total of $ 1,000 . we invested one part of the money at 3 % and the rest of the money at 6 % . the total investment with interest at the end of the year was $ 1 , 052.50 . how much money did we invest at 3 % ?
"let x be the money invested at 3 % . 1.03 x + 1.06 ( 1000 - x ) = 1052.50 . 0.03 x = 1060 - 1052.50 . 0.03 x = 7.50 . 3 x = 750 . x = 250 . the answer is d ."
divide(subtract(multiply(multiply(const_100, multiply(add(const_2, const_3), const_2)), add(divide(6, const_100), const_1)), add(add(multiply(const_100, multiply(add(const_2, const_3), const_2)), multiply(multiply(add(const_2, const_3), const_2), 3)), multiply(const_2, const_3))), subtract(add(divide(6, const_100), const_1), add(divide(3, const_100), const_1)))