how many zeroes are there at the end of the number n , if n = 70 ! + 140 ! ?
"the number of zeroes at the end of 70 ! will be less than the number of zeroes at the end of 140 ! hence it is sufficient to calculate the number of zeroes at the end of 70 ! the number of zeroes = [ 70 / 5 ] + [ 70 / 25 ] + [ 70 / 125 ] = 14 + 2 + 0 = 16 the answer is c ."
add(divide(70, add(const_4, const_1)), const_2)