a present value of a machine is $ 1000 . its value depletiation rate is 10 % per annum then find the machine value after 2 years ?
"p = $ 1000 r = 10 % t = 2 years machine value after 2 years = p [ ( 1 - r / 100 ) ^ t ] = 1000 * 9 / 10 * 9 / 10 = $ 810 answer is b"
multiply(1000, power(subtract(const_1, divide(10, const_100)), 2))