ages of two persons differ by 20 years . if 6 year ago , the elder one be 3 times as old the younger one , find their present age
"explanation : let the age of younger person is x , then elder person age is ( x + 20 ) = > 3 ( x - 6 ) = ( x + 20 - 6 ) [ 6 years before ] = > 3 x - 18 = x + 14 = > x = 16 so other person age is x + 20 = 36 answer : option c"
subtract(divide(subtract(add(multiply(6, 6), 20), 6), subtract(6, const_1)), const_1)