a present value of a machine is $ 800 . its value depletion rate is 10 % per annum then find the machine value after 2 years ?
"p = $ 800 r = 10 % t = 2 years machine value after 2 years = p [ ( 1 - r / 100 ) ^ t ] = 800 * 9 / 10 * 9 / 10 = $ 648 answer is e"
multiply(800, power(subtract(const_1, divide(10, const_100)), 2))