the sum of first 45 natural numbers is
solution we know that ( 1 + 2 + 3 + . . . . . + 45 ) = n ( n + 1 ) / 2 therefore ( 1 + 2 + 3 + . . . . + 45 ) = ( 45 × 46 / 2 ) = 1035 . answer a
divide(multiply(45, add(45, const_1)), const_2)