in an examination , a student scores 4 marks for every correct answer and loses 1 mark for every wrong answer . if he attempts all 200 questions and secures 240 marks , the number of questions he attempts incorrectly , is :
"let the number of correct answers be x . number of incorrect answers = ( 200 â € “ x ) . 4 x â € “ ( 200 â € “ x ) = 240 or 5 x = 440 or x = 88 . number of incorrect answers = 200 - 88 = 112 answer : d"
divide(add(240, 200), add(4, 1))