the points a ( 0 , 0 ) , b ( 0 , 4 a - 5 ) and c ( 2 a + 1 , 2 a + 5 ) form a triangle . if angle abc = 90 , what is the area of triangle abc ?
"1 / 2 bh = 1 / 2 ( 2 a + 1 ) ( 2 a + 5 ) now 4 a - 5 = 2 a + 5 2 a = 10 , a = 5 therefore , a ( 0,0 ) ; b ( 0,15 ) ; c ( 10,15 ) 1 / 2 * 11 * 15 = 82.5 answer : b"
divide(multiply(subtract(multiply(divide(add(5, 5), 5), 4), 5), add(multiply(divide(add(5, 5), 5), subtract(4, 5)), 1)), 5)