in what ratio mental a at rs . 68 per kg be mixed with another metal at rs . 96 per kg so that cost of alloy ( mixture ) is rs . 80 per kg ?
( 96 - 80 ) / ( 80 - 68 ) = 16 / 12 = 4 / 3 answer : c
divide(divide(subtract(96, 80), subtract(96, 68)), subtract(const_1, divide(subtract(96, 80), subtract(96, 68))))