stacy and heather are 40 miles apart and walk towards each other along the same route . stacy walks at constant rate that is 1 mile per hour faster than heather ' s constant rate of 5 miles / hour . if heather starts her journey 24 minutes after stacy , how far from the original destination has heather walked when the two meet ?
"original distance between s and h = 40 miles . speed of s = 5 + 1 = 6 mph , speed of h = 5 mph . time traveled by h = t hours - - - > time traveled by s = t + 24 / 60 = t + 2 / 5 hours . now , the total distances traveled by s and h = 40 miles - - - > 6 * ( t + 2 / 5 ) + 5 * t = 40 - - - > t = 188 / 55 hours . thus h has traveled for 188 / 55 hours giving you a total distance for h = 5 * 188 / 55 = 17 miles . c is thus the correct answer . p . s . : based on the wording of the question , you should calculatehow far from theoriginal destination has heather walkedwhen the two meet . ' original destination ' for h does not make any sense . original destination for h was situated at a distance of 20 miles ."
multiply(divide(subtract(40, multiply(24, divide(add(1, 5), const_60))), add(5, add(1, 5))), 5)