a number when divided by a divisor leaves a remainder of 23 . when twice the original number is divided by the same divisor , the remainder is 11 . what is the value of the divisor ?
"let the number is n , the divisor = d , i will make the two equations - n = xd + 23 2 n = yd + 11 where x and y are integers solving them : d ( y - 2 x ) = 36 as d is also integer and 36 is a prime number , the d should be 36 to satisfy the above equation . hence answer is ' d '"
add(23, 11)