on dividing a number by 48 , we get 29 as remainder . on dividing the same number by 8 , what will be the remainder ?
"number = 48 x + 29 ( ∵ since the number gives 29 as remainder on dividing by 48 ) = ( 6 × 8 × x ) + ( 3 × 8 ) + 5 hence , if the number is divided by 8 , we will get 5 as remainder . answer : d"
multiply(subtract(divide(power(29, const_2), 48), floor(divide(power(29, const_2), 48))), 48)