p has $ 32 more than what q and r together would have had if both b and c had 1 / 6 of what p has . how much does p have ?
"p = ( 2 / 6 ) * p + 32 ( 4 / 6 ) * p = 32 p = 48 the answer is b ."
divide(32, subtract(1, multiply(divide(1, 6), const_2)))