in the number 11,0 ab , a and b represent the tens and units digits , respectively . if 11,0 ab is divisible by 65 , what is the greatest possible value of b × a ?
"you should notice that 65 * 2 = 110 so 11,000 is divisible by 55 : 55 * 200 = 11,000 ( or you can notice that 11,000 is obviously divisible by both 5 and 11 so by 55 ) - - > b * a = 0 * 0 = 0 . next number divisible by 55 is 11,000 + 55 = 11,055 : b * a = 5 * 2 = 10 ( next number wo n ' t have 110 as the first 3 digits so we have only two options 0 and 25 ) . answer : c ! please post ps questions in the ps subforum : gmat - problem - solving - ps - 140 / please post ds questions in the ds subforum : gmat - data - sufficiency - ds - 141 / no posting of ps / ds questions is allowed in the mainmath forum . c"
subtract(multiply(reminder(reminder(multiply(add(divide(add(power(11,0, const_2), const_1000), 65), const_1), 65), 11,0), const_10), divide(subtract(reminder(multiply(add(divide(add(power(11,0, const_2), const_1000), 65), const_1), 65), 11,0), reminder(reminder(multiply(add(divide(add(power(11,0, const_2), const_1000), 65), const_1), 65), 11,0), const_10)), const_10)), const_10)