a hexagon is formed abcdef which perimeter 36 cm . a polygon is formed by joining the points ae & bd . find the area of the polygon abde ?
a regular hexagon consist of 6 equilateral triangle . each of side 6 cm . so the area of 1 equilateral triangle is = ¼ ( √ 3 a 2 ) = 9 √ 3 cm 2 the figure formed by joining polygon abde consist of 2 equilateral triangle and 4 half equilateral triangle which employs area of 4 equilateral triangle . so , the area of polygon abde = 4 * ( area of equilateral traingle ) = 4 * 9 √ 3 = 36 √ 3 cm 2 answer : c
multiply(triangle_area_three_edges(divide(36, add(const_2, const_4)), divide(36, add(const_2, const_4)), divide(36, add(const_2, const_4))), const_4)