if x is 20 percent more than y and y is 60 percent less than z , then x is what percent of z ?
"z = 100 ; y = 40 so x = 48 x as % of z = 48 / 100 * 100 = > 48 % answer will be ( b )"
multiply(add(const_1, divide(20, const_100)), subtract(const_100, 60))