the ratio , by volume , of soap to alcohol to water in a certain solution is 20 : 50 : 80 . the solution will be altered so that the ratio of soap to alcohol is doubled while the ratio of soap to water is halved . if the altered solution will contain 100 cubic centimeters of alcohol , how many cubic centimeters of water will it contain ?
"soap : alcohol initial ratio soap : alcohol : water - - > 20 : 50 : 80 initial soap : alcohol = 20 / 50 = 20 : 50 after doubled soap : alcohol = 2 * 20 / 50 = 40 : 50 initial soap : water = 20 / 80 = 20 : 80 after halved soap : water : 1 / 2 * 20 / 80 = 10 / 80 = 10 : 80 after soap : alcohol : water - - > 40 : 50 : 320 - - > 4 : 5 : 32 given alcohol 100 cubic centimeter . ratio is 80 : 100 : 640 ( 4 : 5 : 32 ) for 100 cubic centimeter of alcohol - - - 640 cubic cm water is required . answer - b"
divide(divide(divide(divide(divide(volume_rectangular_prism(100, 80, 50), const_3), const_2), 20), 20), 20)