calculate the sum of first 60 natural numbers .
"solution we know that ( 1 + 2 + 3 + . . . . . + 60 ) = n ( n + 1 ) / 2 therefore ( 1 + 2 + 3 + . . . . + 60 ) = ( 60 × 61 / 2 ) = 1830 . answer c"
multiply(add(60, const_1), divide(60, const_2))