at 3 : 40 , the hour hand and the minute hand of a clock form an angle of
"angle between hands of a clock when the minute hand is behind the hour hand , the angle between the two hands at m minutes past h ' o clock = 30 ( h − m / 5 ) + m / 2 degree when the minute hand is ahead of the hour hand , the angle between the two hands at m minutes past h ' o clock = 30 ( m / 5 − h ) − m / 2 degree here h = 3 , m = 40 and minute hand is ahead of the hour hand . hence the angle = 30 ( m / 5 − h ) − m / 2 = 30 ( 40 / 5 − 3 ) − 40 / 2 = 30 ( 8 − 3 ) − 20 = 30 × 5 − 20 = 130 ° answer is c ."
subtract(multiply(multiply(multiply(const_60, 3), const_2), divide(40, const_60)), multiply(divide(divide(multiply(multiply(const_60, 3), const_2), 3), const_4), add(divide(40, const_60), 3)))