what is the area inscribed by the lines y = 6 , x = 3 , y = 2 x - 4 on an xy - coordinate plane ?
"first , let ' s graph the lines y = 6 and x = 3 at this point , we need to find the points where the line y = 2 x - 4 intersects the other two lines . for the vertical line , we know that x = 3 , so we ' ll plug x = 3 into the equation y = 2 x - 4 to get y = 2 ( 3 ) - 4 = 2 perfect , when x = 3 , y = 2 , so one point of intersection is ( 3,2 ) for the horizontal line , we know that y = 6 , so we ' ll plug y = 6 into the equation y = 2 x - 4 to get 6 = 2 x - 4 . solve to get : x = 5 so , when y = 6 , x = 5 , so one point of intersection is ( 5,6 ) now add these points to our graph and sketch the line y = 2 x - 4 at this point , we can see that we have the following triangle . the base has length 2 and the height is 4 area = ( 1 / 2 ) ( base ) ( height ) = ( 1 / 2 ) ( 2 ) ( 4 ) = 4 answer : c"
multiply(subtract(subtract(2, const_2.0), 6), multiply(multiply(3, const_0_25), subtract(subtract(2, 6), 6)))