Please solve the programming task below using a self-contained code snippet in a markdown code block.

Given an integer n, return the number of trailing zeroes in n!.
Note that n! = n * (n - 1) * (n - 2) * ... * 3 * 2 * 1.
 
Please complete the following python code precisely:
```python
class Solution:
    def trailingZeroes(self, n: int) -> int:
```