Solve the programming task below in a Python markdown code block.
A string $s$ of length $n$ ($1 \le n \le 26$) is called alphabetical if it can be obtained using the following algorithm:

first, write an empty string to $s$ (i.e. perform the assignment $s$ := "");

then perform the next step $n$ times;

at the $i$-th step take $i$-th lowercase letter of the Latin alphabet and write it either to the left of the string $s$ or to the right of the string $s$ (i.e. perform the assignment $s$ := $c+s$ or $s$ := $s+c$, where $c$ is the $i$-th letter of the Latin alphabet).

In other words, iterate over the $n$ first letters of the Latin alphabet starting from 'a' and etc. Each time we prepend a letter to the left of the string $s$ or append a letter to the right of the string $s$. Strings that can be obtained in that way are alphabetical.

For example, the following strings are alphabetical: "a", "ba", "ab", "bac" and "ihfcbadeg". The following strings are not alphabetical: "z", "aa", "ca", "acb", "xyz" and "ddcba".

From the given string, determine if it is alphabetical.


-----Input-----

The first line contains one integer $t$ ($1 \le t \le 10^4$) — the number of test cases. Then $t$ test cases follow.

Each test case is written on a separate line that contains one string $s$. String $s$ consists of lowercase letters of the Latin alphabet and has a length between $1$ and $26$, inclusive.


-----Output-----

Output $t$ lines, each of them must contain the answer to the corresponding test case. Output YES if the given string $s$ is alphabetical and NO otherwise.

You can output YES and NO in any case (for example, strings yEs, yes, Yes and YES will be recognized as a positive answer).


-----Examples-----

Input
11
a
ba
ab
bac
ihfcbadeg
z
aa
ca
acb
xyz
ddcba
Output
YES
YES
YES
YES
YES
NO
NO
NO
NO
NO
NO


-----Note-----

The example contains test cases from the main part of the condition.