Solve the programming task below in a Python markdown code block.
Madoka wants to enter to "Novosibirsk State University", but in the entrance exam she came across a very difficult task:

Given an integer $n$, it is required to calculate $\sum{\operatorname{lcm}(c, \gcd(a, b))}$, for all triples of positive integers $(a, b, c)$, where $a + b + c = n$.

In this problem $\gcd(x, y)$ denotes the greatest common divisor of $x$ and $y$, and $\operatorname{lcm}(x, y)$ denotes the least common multiple of $x$ and $y$.

Solve this problem for Madoka and help her to enter to the best university!


-----Input-----

The first and the only line contains a single integer $n$ ($3 \le n \le 10^5$).


-----Output-----

Print exactly one interger — $\sum{\operatorname{lcm}(c, \gcd(a, b))}$. Since the answer can be very large, then output it modulo $10^9 + 7$.


-----Examples-----

Input
3
Output
1
Input
5
Output
11
Input
69228
Output
778304278


-----Note-----

In the first example, there is only one suitable triple $(1, 1, 1)$. So the answer is $\operatorname{lcm}(1, \gcd(1, 1)) = \operatorname{lcm}(1, 1) = 1$.

In the second example, $\operatorname{lcm}(1, \gcd(3, 1)) + \operatorname{lcm}(1, \gcd(2, 2)) + \operatorname{lcm}(1, \gcd(1, 3)) + \operatorname{lcm}(2, \gcd(2, 1)) + \operatorname{lcm}(2, \gcd(1, 2)) + \operatorname{lcm}(3, \gcd(1, 1)) = \operatorname{lcm}(1, 1) + \operatorname{lcm}(1, 2) + \operatorname{lcm}(1, 1) + \operatorname{lcm}(2, 1) + \operatorname{lcm}(2, 1) + \operatorname{lcm}(3, 1) = 1 + 2 + 1 + 2 + 2 + 3 = 11$