C. From S To Ttime limit per test1 secondmemory limit per test256 megabytesinputstandard inputoutputstandard outputYou are given three strings s, t and p consisting of lowercase Latin letters. You may perform any number (possibly, zero) operations on these strings.During each operation you choose any character from p, erase it from p and insert it into string s (you may insert this character anywhere you want: in the beginning of s, in the end or between any two consecutive characters). For example, if p is aba, and s is de, then the following outcomes are possible (the character we erase from p and insert into s is highlighted):  aba \rightarrow ba, de \rightarrow ade;  aba \rightarrow ba, de \rightarrow dae;  aba \rightarrow ba, de \rightarrow dea;  aba \rightarrow aa, de \rightarrow bde;  aba \rightarrow aa, de \rightarrow dbe;  aba \rightarrow aa, de \rightarrow deb;  aba \rightarrow ab, de \rightarrow ade;  aba \rightarrow ab, de \rightarrow dae;  aba \rightarrow ab, de \rightarrow dea; Your goal is to perform several (maybe zero) operations so that s becomes equal to t. Please determine whether it is possible.Note that you have to answer q independent queries.InputThe first line contains one integer q (1 \le q \le 100) — the number of queries. Each query is represented by three consecutive lines.The first line of each query contains the string s (1 \le |s| \le 100) consisting of lowercase Latin letters.The second line of each query contains the string t (1 \le |t| \le 100) consisting of lowercase Latin letters.The third line of each query contains the string p (1 \le |p| \le 100) consisting of lowercase Latin letters.OutputFor each query print YES if it is possible to make s equal to t, and NO otherwise.You may print every letter in any case you want (so, for example, the strings yEs, yes, Yes and YES will all be recognized as positive answer).ExampleInput
4
ab
acxb
cax
a
aaaa
aaabbcc
a
aaaa
aabbcc
ab
baaa
aaaaa
Output
YES
YES
NO
NO
NoteIn the first test case there is the following sequence of operation:   s =  ab, t =  acxb, p =  cax;  s =  acb, t =  acxb, p =  ax;  s =  acxb, t =  acxb, p =  a. In the second test case there is the following sequence of operation:   s =  a, t =  aaaa, p =  aaabbcc;  s =  aa, t =  aaaa, p =  aabbcc;  s =  aaa, t =  aaaa, p =  abbcc;  s =  aaaa, t =  aaaa, p =  bbcc. 
4
ab
acxb
cax
a
aaaa
aaabbcc
a
aaaa
aabbcc
ab
baaa
aaaaa

YES YES NO NO 
['implementation', 'strings', '*1300']