C. Star skytime limit per test2 secondsmemory limit per test256 megabytesinputstandard inputoutputstandard outputThe Cartesian coordinate system is set in the sky. There you can see n stars, the i-th has coordinates (xi, yi), a maximum brightness c, equal for all stars, and an initial brightness si (0 ≤ si ≤ c).Over time the stars twinkle. At moment 0 the i-th star has brightness si. Let at moment t some star has brightness x. Then at moment (t + 1) this star will have brightness x + 1, if x + 1 ≤ c, and 0, otherwise.You want to look at the sky q times. In the i-th time you will look at the moment ti and you will see a rectangle with sides parallel to the coordinate axes, the lower left corner has coordinates (x1i, y1i) and the upper right — (x2i, y2i). For each view, you want to know the total brightness of the stars lying in the viewed rectangle.A star lies in a rectangle if it lies on its border or lies strictly inside it.InputThe first line contains three integers n, q, c (1 ≤ n, q ≤ 105, 1 ≤ c ≤ 10) — the number of the stars, the number of the views and the maximum brightness of the stars.The next n lines contain the stars description. The i-th from these lines contains three integers xi, yi, si (1 ≤ xi, yi ≤ 100, 0 ≤ si ≤ c ≤ 10) — the coordinates of i-th star and its initial brightness.The next q lines contain the views description. The i-th from these lines contains five integers ti, x1i, y1i, x2i, y2i (0 ≤ ti ≤ 109, 1 ≤ x1i < x2i ≤ 100, 1 ≤ y1i < y2i ≤ 100) — the moment of the i-th view and the coordinates of the viewed rectangle.OutputFor each view print the total brightness of the viewed stars.ExamplesInput2 3 31 1 13 2 02 1 1 2 20 2 1 4 55 1 1 5 5Output303Input3 4 51 1 22 3 03 3 10 1 1 100 1001 2 2 4 42 2 1 4 71 50 50 51 51Output3350NoteLet's consider the first example.At the first view, you can see only the first star. At moment 2 its brightness is 3, so the answer is 3.At the second view, you can see only the second star. At moment 0 its brightness is 0, so the answer is 0.At the third view, you can see both stars. At moment 5 brightness of the first is 2, and brightness of the second is 1, so the answer is 3.
Input2 3 31 1 13 2 02 1 1 2 20 2 1 4 55 1 1 5 5
Output303
['dp', 'implementation', '*1600']