Angola,_Indiana | elevation | "324.002"^^xsd:double Angola,_Indiana | isPartOf | Pleasant_Township,_Steuben_County,_Indiana Angola,_Indiana | populationDensity | "524.481"^^xsd:double Angola,_Indiana | subdivisionName | United_States Angola,_Indiana | areaTotal | "16.55002402504704"^^<http://dbpedia.org/datatype/squareKilometre>
Angola,_Indiana | elevationAboveTheSeaLevel | 324.0 Angola,_Indiana | isPartOf | Pleasant_Township,_Steuben_County,_Indiana Angola,_Indiana | populationDensity | 524.5 (inhabitants per square kilometre) Angola,_Indiana | isPartOf | United_States Angola,_Indiana | areaTotal | 16.55 (square kilometres)
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Angola is in Pleasant Township which is part of Steuben County, in Indiana in the U.S. It has a population density of 524.5 people per sq km, 324 metres above sea level, and a total area of 16.55 sq km. At an elevation of 324 metres above sea level, Angola, is part of Pleasant Township (Steuben County), Indiana, in the United States. With a total area of 16.55 square kilometres, Angola, has a population density of 524.5 inhabitants per square kilometre. At an elevation of 324 metres above sea level, Angola (in Pleasant Township, Steuben County, Indiana), is in the United States. Angola, has a total area of 16.55 square kilometres, and a population density of 524.5 inhabitants per square kilometre. L-Angola tinsab f’Plaasant Township, li huwa parti mill-Konte ta’ Steuben, fl-Indiana fl-Istati Uniti. Fl-għoli ta’ 324 metru ‘il fuq mil-livell tal-baħar, l-Angola, hija parti mill-Plaasant Township (il-Konte ta’ Steuben), fl-Istati Uniti, fl-Istati Uniti. B’erja totali ta’ 16.55 kilometru kwadri, l-Angola, għandha densità tal-popolazzjoni ta’ 524.5 residenti għal kull kilometru kwadru. Fl-għoli ta’ 324 metru ‘il fuq mil-livell tal-baħar, l-Angola (f’Plaasant Township, il-Konte ta’ Steuben, l-Indiana), jinsab fl-Istati Uniti.
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