determining the slope of the tangent line
{"Image DocumentName": "Determining the Slope of the Tangent Line", "Image ImageDescription": "Because h is smaller, the point X+h is closer to the original point X than before. Therefore, the slope of this second line is closer in value to the slope of the tangent line than what the slope of the first line was. To determine the slope of the tangent line, let us draw a different line that intersects the curve at both point X and point X + h. X. What is the slope of this line? From before, the slope of the line will be \u0394y/\u0394x: \u0394y=y(X+h)\u2013y(X) X+h. X+h. \u0394x=(X+h)\u2013X=h. This line is still not the tangent line at point X, but we can make it look more like the tangent line if we make the h a smaller value: If you calculate the slope for this second line, it will have the same form as the above equation, except now h is a smaller value and therefore y(X+h) will be a different value.", "Image XResolution": "37", "Image YResolution": "37", "Image ResolutionUnit": "Pixels/Centimeter", "Image Software": "SlidePlayer", "Image YCbCrPositioning": "Centered"}