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156 views

### Differential operators confussion

I want to solve this PDE: $$u_t-6uu_x+u_{xxx} = 0\,(1)$$ with the Inverse Scattering Method. This method is based on showing that the above equation can be expressed as $$L_t=LB-BL,\,(2)$$ where $L$ ...

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# [OS X TeX] Using pdftex together with pst-plot

André Bellaïche abellaic at math.jussieu.fr
Sun Feb 13 12:35:06 EST 2011

Le 13 févr. 2011 à 17:23, André Bellaïche a écrit :

>
> Le 9 févr. 2011 à 20:22, Michael Sharpe a écrit :
>
>>
>> On Feb 9, 2011, at 10:55 AM, André Bellaïche wrote:
>>
>>> [I have already posted this on the pdftex list, but nobody has answered.]
>>>
>>> I have a file with many figures made by pspicture. Unfortunately,  this hinders the using of pdftex and microtype.
>>>
>>> Adding \usepackage{pst-pdf} after \usepackage{pst-plot,multido,pst-tree} does not work. Has anybody a better idea ?
>>>
>>> André Bellaïche
>>
>> In my opinion, auto-pst-pdf is the most convenient package for this purpose, loaded as
>>
>> \usepackage{auto-pst-pdf}
>> \usepackage{pstricks}
>> etc
>>
>> Michael-----------
>
> Thank you for your help.
>
> It worked, but with some annoying bugs.
>
> Some files are replaced with a frame with their name, just as in draft mode, and you see them a few pages later at the place where you should see another drawing.
>
> I have looked into the mydoc-pics.pdf file, anf I have found that all the pages contain two drawings. Maybe this is the cause of the prblem.
>
> André

Another question. May the mixing of EPS files included by means of includegraphics and drawings made by the pspicture package have mixed up PDFCROP ?


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• New constraint on the existence of the mu+-> e+ gamma decay(1303.0754)

April 23, 2013 hep-ex, physics.ins-det
The analysis of a combined data set, totaling 3.6 \times 10^14 stopped muons on target, in the search for the lepton flavour violating decay mu^+ -> e^+ gamma is presented. The data collected by the MEG experiment at the Paul Scherrer Institut show no excess of events compared to background expectations and yield a new upper limit on the branching ratio of this decay of 5.7 \times 10^-13 (90% confidence level). This represents a four times more stringent limit than the previous world best limit set by MEG.
• The MEG detector for ${\mu}+\to e+{\gamma}$ decay search(1303.2348)

April 10, 2013 hep-ex, physics.ins-det
The MEG (Mu to Electron Gamma) experiment has been running at the Paul Scherrer Institut (PSI), Switzerland since 2008 to search for the decay \meg\ by using one of the most intense continuous $\mu^+$ beams in the world. This paper presents the MEG components: the positron spectrometer, including a thin target, a superconducting magnet, a set of drift chambers for measuring the muon decay vertex and the positron momentum, a timing counter for measuring the positron time, and a liquid xenon detector for measuring the photon energy, position and time. The trigger system, the read-out electronics and the data acquisition system are also presented in detail. The paper is completed with a description of the equipment and techniques developed for the calibration in time and energy and the simulation of the whole apparatus.
• New limit on the lepton-flavour violating decay mu -> e gamma(1107.5547)

Sept. 2, 2011 hep-ph, hep-ex
We present a new result based on an analysis of the data collected by the MEG detector at the Paul Scherrer Institut in 2009 and 2010, in search of the lepton flavour violating decay mu->e gamma. The likelihood analysis of the combined data sample, which corresponds to a total of 1.8 x 10**14 muon decays, gives a 90% C.L. upper limit of 2.4 x 10**-12 on the branching ratio of the mu->e gamma decay, constituting the most stringent limit on the existence of this decay to date.
• A limit for the mu -> e gamma decay from the MEG experiment(0908.2594)

March 4, 2010 hep-ph, hep-ex
A search for the decay mu -> e gamma, performed at PSI and based on data from the initial three months of operation of the MEG experiment, yields an upper limit on the branching ratio of BR(mu -> e gamma) < 2.8 x 10**-11 (90% C.L.). This corresponds to the measurement of positrons and photons from ~ 10**14 stopped mu-decays by means of a superconducting positron spectrometer and a 900 litre liquid xenon photon detector.


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• •

### GIS中面积偏差控制下的矢量数据压缩算法

1. 江南遥感应用研究所,上海 200436
• 收稿日期:2012-03-22 修回日期:2012-07-10 出版日期:2012-10-20 发布日期:2012-10-20
• 作者简介:

作者简介：米学军(1969-),男（回族）,山东济阳人,硕士,工程师,主要研究方向为GIS与遥感技术应用。

• 基金资助:
中国科学院重大碳专项项目（XDA05060400）资助

### A New Algorithm of Vector Date Compression Based On the Tolerance of Area Error in GIS

Xue-jun MI, Guang-ming SHENG, Jing ZHANG, Huan-xin BAI, Wei HOU

1. Institute of Remote Sensing Applications Southern Yangtze,Shanghai 200436,China
• Received:2012-03-22 Revised:2012-07-10 Online:2012-10-20 Published:2012-10-20

Abstract:

：In GIS, vector data is the most commonly used data structure. Data compression is an issue in vector data processing and applications. In this paper,several commonly used algorithms of vector data compression are analyzed and a new efficient algorithm is proposed to resolve the problems of the classic algorithms. The Douglas-Peucker algorithm and the vertical distance tolerance algorithm are commonly used algorithms in vector data compression.The Douglas-Peucker algorithm have the advantage that it has invariance in translation and rotation, but at the same time the result has a big area error and there is a contradiction between the compression ratio and retention of feature points for the curvature change. The advantages of the vertical distance tolerance algorithm is fast, but the area error and the characteristics of the retention curve space are very poor. In this paper,a new algorithm is proposed which improved vertical distance tolerance algorithm and resolved the shortcomings of the Douglas-Peucker algorithm and the vertical distance tolerance algorithm.The basic idea of the new algorithm is based on the vertical distance tolerance algorithm which increase an area error tolerance by adopting the method of straight line fitting to approximate the axis of the polyline in order to resolve the problem of the area error and declination of segment in space. An experiment is included, which verified the new algorithm is efficient by the example of dealing with the boundary contour vector of Chongming Island, Shanghai. In the experiment ,the new algorithm has only 1 km2 error, but the classic algorithms has 6 km2 of the error. The most advantage of the new algorithms is that the area error can be controlled in a specified range. The experiments show that comparing with the two classic algorithms,the new algorithm has no substantial advantage in the compression ratio,but greatly improved the performance of two targets, area error and declination of segment in space. It proved that the new algorithm is efficient in the data procession which has high requirement in area accuracy and spatial characteristics such as the use of land resources.

• P208


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## Precalculus (10th Edition)

a) $\{18\}$ b) $(2,18]$
We are given the function: $f(x)=\log_4 (x-2)$ a) Solve the equation: $f(x)=2$ $\log_4 (x-2)=2$ $x-2=4^2$ $x-2=16$ $x=18$ Check the solution: $\log_4 (18-2)\stackrel{?}{=} 2$ $\log_4 16\stackrel{?}{=} 2$ $2=2\checkmark$ The solution set is: $\{18\}$ b) Solve the inequality: $f(x)\leq 2$ $\log_4 (x-2)\leq 2$ $\log_4 (x-2)\leq \log_4 4^2$ $x-2\leq 16$ $x\leq 18$ As the function $f(x)=\log_4 (x-2)$ is defined for $x>2$, the solution set is: $(2,18]$


text:
## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Option $(a)$
The equation $2x+5y=100$ involves a big constant ($100)$. Thus, to graph this equation, using a scale of 10 units per square is highly recommended.


text:
Language
(This post is also translated into other languages)

Update in March 2019:

After TensorFlow developers introduced the APIs of Tensorflow 2.0 on Tensorflow Dev Summit 2019, I have made my decision to turn to PyTorch.

TensorFlow is a powerful open-source deep learning framework, supporting various languages including Python. However, its APIs are far too complicated for a beginner in deep learning(especially those who are new to Python). In order to ease the pain of having to understand the mess of various elements in TensorFlow computation graphs, I made this tutorial to help beginners take the first bite of the cake.

ResNets are one of the greatest works in the deep learning field. Although they look scary with extreme depths, it's not a hard job to implement one. Now let's build one of the simplest ResNets - ResNet-56, and train it on the CIFAR-10 dataset.

2019.3 更新:

Tensorflow Dev Summit上开发者介绍TF 2.0 API后， 我彻底下定了换用PyTorch的决心。

TensorFlow是一个强大的开源深度学习软件库，它支持包括Python在内的多种语言。然而，由于API过于复杂（实际上还有点混乱），它往往使得一个深度学习的初学者（尤其是为此初学Python的那些）望而却步——老虎吃天，无从下口。为了减轻初学者不得不尝试理解TensorFlow中的大量概念的痛苦，我213今天带各位尝尝深度学习这片天的第一口。
ResNet是深度学习领域的一个重磅炸弹，尽管它们（ResNet有不同层数的多个模型）的深度看上去有点吓人，但实际上实现一个ResNet并不难。接下来，我们来实现一个较为简单的ResNet——ResNet-56，并在CIFAR-10数据集上训练一下，看看效果如何。

First let's take a look at ResNet-56. It's proposed by Kaiming He et al., and is designed to confirm the effect of residual networks. It has 56 weighted layers, deep but simple. The structure is shown in the figure below:

Seems a little bit long? Don't worry, let's do this step by step.

## 1 Ingredients

Python 3.6

TensorFlow 1.4.0

Numpy 1.13.3

OpenCV 3.2.0

CIFAR-10 Dataset

Also prepare some basic knowledge on Python programming, digital image processing and convolutional neural networks. If you are already capable of building, training and validating your own neural networks with TensorFlow, you don't have to read this post.

## 2 Recipe

### 2.0 Prepare the tools

Prepare(import) the tools for our project, including all that I mentioned above. Like this :P

Wait... What's this? TensorChain? Another deep learning framework like TensorFlow?

Uh, nope. This is my own encapsulation of some TensorFlow APIs, for the sake of easing your pain. You'll only have to focus on "what's what" in the beginning. We'll look into my implementation of this encapsulation later, when you are clear how everything goes. Please download this file and put it where your code file is, and import it.

### 2.1 Decide the input

Every neural network requires an input - you always have to identify the details of a question, before asking the computer to solve it. All of the variable, constant in TensorFlow are objects of type tf.Tensors. And the tf.placeholder of our input(s) is a special one. Images in CIFAR-10 dataset are RGB images(3 channels) of 32x32(really small), so our input should shaped like [32, 32, 3]. Also, we want to input a little batch of multiple images. Therefore, our input data should be an array of shape [?, 32, 32, 3]. Unknown dimension size can be marked as None, and it will be clear when we feed the model with the actual images. It's coded like this:

Ground truth data also need to be known in supervised learning, so we also have to define a placeholder for the ground truth data:

We want the label data to be in the one-hot encoding format, which means an array of length 10, denoting 10 classes. Only on one position is a '1', and on other positions are '0's.

### 2.2 Do some operations

For now, let's use our TensorChain to build it fast. Under most circumstances that we may face, the computations are based on the input data or the result of the former computation, so our network(or say, the most of it) look more like a chain than a web. Every time we add some new operation(layer), we add it to our TensorChain object. Just remember to get the output_tensor of this object(denoting the output tensor of the last operation on the chain) when you need to ue native TensorFlow API.
The construction function of TensorChain class requires a Tensor object as the parameter, which is also the input tensor of this chain. As we mentioned earlier, all we have to do is add operations. See my ResNet-56 code:

TensorChain类的构造函数需要一个Tensor对象作为参数，这个对象也正是被拿来作为这个链的输入层。正如我们之前所说的，只要在这个对象上添加运算即可。写个ResNet-56，代码很简单：

This is it? Right, this is it! Isn't it cool? Didn't seem that high, huh? That's because I encapsulated that huge mess of weights and biases, only leaving a few parameters that decide the structure of the network. Later in this pose we'll talk about the actual work that these functions do.

### 2.3 Define the loss

In supervised learning, you always have to tell the learning target to the model. To tell the model how to optimize, you have to let it know how, how much, on which direction should it change its parameters. This is done by using a loss function. Therefore, we need to define a loss function for our ResNet-56 model(which we designed for this classification problem) so that it will learn and optimize.
A commonly used loss function in classification problems is cross entropy. It's defined below:

$$C=-\frac{1}{n}\sum_x{y\ln a+(1-y)\ln(1-a)}$$

in which $$y$$ is the expected(or say correct) output and $$a$$ is the actual output.
This seems a little bit complicated. But it's not a hard job to implement, since TensorFlow implemented it already! You can also try and implement it yourself within one line if you want. For now we use the pre-defined cross entropy loss function:

and it returns a tf.Tensor that denotes an average of cross entropies(don't forget that this is a batch). As for the 'softmax' before the 'cross_entropy', it's a function that project the data in an array to range 0~1, which allows us to do a comparison between our prediction and the ground truth(in one-hot code). The definition is simple too:\

$$S_i=\frac{e^{V_i}}{\sum_j{e^{V_j}}}$$

### 2.4 Define the train op

Now we have the loss function. We'll have to tell its value to an optimizer, which make our model learn and optimize in order to minimize the loss value. Gradient Descent Optimizer, Adagrad Optimizer, Adam Optimizer and Momentum Optimizer are commonly used optimizers. Here we use an Adam Optimizer for instance. You're free to try any other one here. When

Also, tell the optimizer that what the loss tensor is. The returned object is a train operation.

The neural network is finished. It's time to grab some data and train it.

### 2.5 Feed the model with data, and train it!

Remember how we defined the placeholders? It's time to fetch some data that fits the placeholders and train it. See how CIFAR-10 dataset can be fetched on its website.

The returned value dict is a Python dictionary. Every time we unpickle a file, a dictionary would be returned. Its 'data' key leads to 10000 RGB images of size 32x32, which is stored in a [10000, 3072] array(3072=32323, I guess you know how it's stored now). The 'label' key leads to 10000 values in range 0~9. Obviously we have to reshape the data so as to fit it into the network model:

The details for data processing are not covered here. Try doing step-by-step to see the results.
The image_data and new_label_data are contain 10000 pieces of data each. Let's divide them into 100 small batches(100 elements each, including image and label) and feed it into the model. Do this on all the 5 batch files:

A session - created with tf.Session() - is required every time we run a TensorFlow model, no matter when we're training it or evaluating it. The first time you run a model, you'll need to run session.run(tf.global_variables_initializer()) to initialize the values of the TensorFlow variables defined previously.
When running session.run(), you must first decide a TensorFlow operation(or a list of operations) that you need. If its result is dependent on some actual data(which means that some data in one or more placeholders flow to this operation), it's also required that you feed it the actual data by adding a feed_dict parameter. For example, I'm training this ResNet-56 model, in which a loss will be calculated with my ground_truth and the prediction result that comes from the input_tensor. Therefore, I'll have to give a value for each placeholder given above(format: "placeholder name: corresponding data"), and fold them in one Python dictionary.

I'm also interested in the loss function value in each iteration(which means feeding a batch of data and executing one forward-propagation and one back-propagation) in the training process. Therefore, what I'll fill in the parameter is not just the train op, but also the loss tensor. And the session.run() above should be modified to:

This is when the return value of session.run() becomes useful. Its value(s) - corresponding to the first parameter of run() - is/are the actual value(s) of the tensor(s) in the first parameter. In our example, loss_value is the actual output of the loss tensor. As for train_, we don't care what it is. Just add it to match the dimensions.

Actually, one epoch(train the model once with the whole dataset) is not enough for the model to fully optimize. I trained this model for 40 epochs and added some loop variables to display the result. You can see my code and my output below. It's highly recommended that you train this with a high-performance GPU, or it would be a century before you train your model to a satisfactory degree.

### 2.6 Conclusion

In a word, building & training neural network models with TensorFlow involves the following steps:

1. Decide the input tensor

2. Add operations(ops) based on existing tensors

3. Define the loss tensor, just like other tensors

4. Select an optimizer and define the train op

5. Process data and feed the model with them

1. 定义输入Tensor

2. 在已有的Tensor上添加运算（op

3. 像之前添加的那些运算一样，定义损失Tensor

4. 选择一个优化器并定义训练操作

5. 把数据处理为合适的shape，并喂进模型训练

## 3 A Closer Look

Wait, it's too late to leave now!
TensorChain saved you from having to deal with a mess of TensorFlow classes and functions. Now it's time that we take a closer look at how TensorChain is implemented, thus understanding the native TensorFlow APIs.

TensorChain让你不至于面对TensorFlow中乱糟糟的类型和函数而不知所措被水淹没。现在是时候近距离观察一下TensorChain是如何实现的，以便理解TensorFlowAPI了。

### 3.1 TensorFlow variables

Let's begin with TensorFlow variables. Variables in TensorFlow are similar to variables in C, Java or any other strong typed programming languages - they have a type, though not necessarily explicitly decided upon definition. Usually them will change as the training process goes on, getting close to a best value.
The most commonly used variables in TensorFlow are weights and biases. I guess that you have seen formulae like:

TensorFlow中最常用的变量就是weights和biases（权重和偏置）。想必你应该见过这样的式子吧：

$$y=Wx+b$$

The $$W$$ here is the weight, and the $$b$$ here is the bias. When implementing some common network layers, they two are always used as the parameters in the layers. For instance, at the very beginning of our ResNet-56, we had a 3x3 sized convolution layer with 16 channels. Its implementation in TensorChain is:

See? On line 16, we used a tf.nn.conv2d() function, the parameters of which are input, filter, strides, padding, etc. As can be guessed from the names, this function does a convolution operation with out input and the weights(the convolution filter here). A bias is added to the result as the final output. There are also many people who argue that the bias here is meaningless and should removed. One line of code is sufficient for defining a variable:

To define weight or bias variables, create a tf.Variable object. Usually you'll need to give the initial_value which also decides the shape of this tensor. tf.truncated_normal() and tf.constant() are usually used as the initial values. Also, other APIs - function tf.get_variable() and package tf.initializers are frequently used when using some more methods for initialization. I strongly recommend that you try using these APIs yourself.

### 3.2 Tensors and operations

Going on with the parameters of the tf.nn.conv2d() function. The required parameters also include strides and padding. You should have already learned about what strides mean in convolution, and I'll only talk about their formats. strides require a 1-D vector with a length of 4, like [1, 2, 2, 1]. The 1st and the 4th number is always 1(in order to match dimensions with the input), while the 2nd and the 3rd means the vertical stride and the horizonal stride.
The 4th parameter padding is a little bit different from its definition in convolution operation. It requires 'SAME' of 'VALID', denoting 'with' or 'without' zero paddings. When it's 'SAME', zero padding is introduced to make the shapes match as needed, equally on every side of the input map.

tf.nn.conv2d() is just an example of TensorFlow operations. Other functions like tf.matmul(), tf.reduce_mean(), tf.global_variables_initializer(), tf.losses.softmax_cross_entropy(), tf.truncated_normal() are all operations. Operation functions return tensors(tf.truncated_normal also return a tensor, a tensor with initializers).

tf.nn.conv2d()只是TensorFlow运算（operation）的一个例子。其他例如tf.matmul()tf.reduce_mean()tf.nn.relu()tf.batch_normalization()tf.global_variables_initializer()tf.losses.softmax_cross_entropy()tf.truncated_normal()之类的函数也都是TensorFlow的运算。TensorFlow的运算函数会返回一个Tensor对象（包括tf.truncated_normal()也是！它只不过返回的是一个带初始化器的Tensor而已）。

All the functions in the TensorChain class are based on the most basic TensorFlow operations and variables. After learning about these basic TensorFlow concepts, actually you can already abandon TensorChain, go and try implementing your own neural networks yourself!

TensorChain类中的所有成员函数都是基于最基本的TensorFlow运算和变量的。实际上，了解了这些，你现在已经可以抛开TensorChain的束缚，去尝试实现你自己的神经网络了！

## 4 Spices

I'm not joking just now! But I know that there are a lot of things that you still don't understand about using TensorFlow - like "how do I visualize my computation graph", "how do I save/load my model to/from files", "how do I record some tensors' values while training" or "how do I view the loss curves" - after all TensorFlow APIs are far more complicated than just building those nets. Those are also important techniques in your research. If you'd rather ask me than spending some time experimenting, please go on with reading.

The very first thing that you may want to do - after training a network model with nice outcomes - would be saving it. Saving a model is fairly easy - just use a tf.train.Saver object. See my code below:

I saved my model and variable values to 'models/model.ckpt'. But actually, you'll find 3 files in the 'models' directory - model.ckpt.data-00000-of-00001, model.ckpt.meta and model.ckpt.index - none of which is 'model.ckpt'! That's because TensorFlow stores the graph structure separately from variables values. The .meta file describes the saved graph structure; the .index file records the mappings between tensor names and tensor metadata; and the .data-00000-of-00001 file - which is always the biggest one - saves all the variable values. If you need the graph data together with the variable values to be loaded, use a Saver to load after creating a session:

Remember that session.run(tf.global_variables_initializer()) shouldn't be executed, since variables are already initialized with your saved .data-0000-of-00001 file.
If you only need the graph to be loaded, only use the .meta file:

Function tf.train.import_meta_graph() loads(appends) the graph to your current computation graph. The values of tensors are still uninitialized so you'll have to execute session.run(tf.global_variables_initializer()) again. The tensors that you defined in the model can be retrieved by their names(property of the Tensor objects, instead of Python variable names). For example:

tf.train.import_meta_graph()函数将文件里的计算图读到（添加到）你当前的计算图中。其中所有Tensor的值仍未初始化，所以有必要执行一下session.run(tf.global_variables_initializer())了。之前定义的变量可以按照名称取回，示例：

To retrieve normal tensors, you'll have to append a ':0' to the name of the op. This means getting the associated tensor of the op. train is a little special - we only need the op, so the function is get_operation_by_name() so the ':0' is not necessary.


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# Pairs of numbers

You wake up in a cell after a party. You just remember the beginning of the night: you talked to your friends, you drank some alcohol, and then you blacked out.
You stand up and look around you: you are in a small empty room with no window and a door locked with a numeric keypad.

You approach the keypad and notice a piece of paper:

You'd better not try to steal my spaghetti recipe again!
I'll let you out if you can solve this puzzle:

{22,11}
{49,83}
{76,56}
{157,344}

are all acceptable numbers, but

{11,22}
{72,47}
{31,70}
{512,114}

aren't.

If you find the key, you can live. (And if you fail, my pet elephant will make sure you wish you weren't alive...).

## Question:

What is the key to the puzzle?

## Hint :

The key is 2-char long

(Note: This isn't a lateral-thinking question, so there's no need for ridiculous answers like "I punch through the wall".)

• I edited it to fix the grammar and spelling. Wasn't sure what you meant by the "key to the puzzle" (I'm guessing the pattern has some number that stands out), and I assumed a "digicode" was a keypad with numbers on it. – Deusovi Jul 28 '15 at 10:29
• @Deusovi: Great clean up. I was itching to clean it up too, but saw that it was too much work, so I gave up. – CodeNewbie Jul 28 '15 at 10:34
• So just to confirm, the key is a single number input on the keypad? – Set Big O Jul 28 '15 at 12:39
• So is I FALCONPUNCH through a wall still valid? – Going hamateur Jul 28 '15 at 12:55
• @Geobits exactly – The random guy Jul 28 '15 at 12:56

I'd do some quick addition and type

42

because each number on the left

turns into 4 if you repeatedly add digits until you get a single digit (49 -> 4+9=13 -> 1+3=4)

and each on the right

results in 2 (83 -> 8+3=11 -> 1+1=2)

In the invalid pairs, at least one of them is wrong.

Also, you know, it's the answer, assuming you know the question.

• Well play, well play :) – The random guy Jul 28 '15 at 13:42
• For all that may need a hint to the answer :) 42 – Marek Oleszczuk Jul 28 '15 at 13:52
• That's a pretty blatant hint :P – Set Big O Jul 28 '15 at 14:08
• This makes me sad, I was adding digits and I was like of so the left needs to sum to more than the right. But that didn't hold. AAND I just shoulda paid some attention to the actual sums... (and then repeated). but gj. – Going hamateur Jul 28 '15 at 14:49
• @Goinghamateur To be fair, I should credit qwertylpc somehow. His deleted answer led me to the idea. I just don't know how to appropriately credit deleted answers, since many users can't see it. Well, besides this roundabout way, I guess. – Set Big O Jul 28 '15 at 14:52


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Home > CCAA8 > Chapter 2 Unit 2 > Lesson CCA: 2.2.3 > Problem2-72

2-72.

Evaluate the following expressions.

Change the mixed numbers into fractions.

1. $8\frac{2}{5}\div3\frac{1}{4}$

$8\frac{2}{5}=8(5)+2=\frac{42}{5}$

Remember that when you divide fractions, you multiply by the reciprocal.

$\frac{42}{5}\times\frac{4}{13}=\frac{168}{65}=2\frac{38}{65}$

$2\frac{38}{65}$

1. $5\frac{1}{2}·(-6\frac{3}{4})$

1. $−3\frac{5}{8}-1\frac{1}{2}$

1. $−7+\frac{2}{3}$

$-6\frac{1}{3}$


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04 Nov 2009, 11:58
I'll be visiting next Monday 11/9. Sitting in on a product development class 11-12:30 and then attending an infosession. Still deciding whether I will BART over and walk across campus or drive over and try and try my luck with north side street parking.
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Re: Calling all Berkeley-Haas Fall 2010 Applicants [#permalink]

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05 Nov 2009, 11:47
boogs wrote:
I'll be visiting next Monday 11/9. Sitting in on a product development class 11-12:30 and then attending an infosession. Still deciding whether I will BART over and walk across campus or drive over and try and try my luck with north side street parking.

Product Development I heard is an amazing class, so definitely check it out.

Marketing is also very good, so if you can get in on that one, highly recommended.
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Re: Calling all Berkeley-Haas Fall 2010 Applicants [#permalink]

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08 Nov 2009, 23:35
keeping the thread up a little bit
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Re: Calling all Berkeley-Haas Fall 2010 Applicants [#permalink]

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09 Nov 2009, 09:29
Hi Kryzak,

D you know any current student who is doing the Healthcare certificate course?

I have a question on whether the healthcare certificate course helps prepre for a career in the healthcare industry or whether the dual-degree MBA/MPH prepares them better.

Thanks
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Re: Calling all Berkeley-Haas Fall 2010 Applicants [#permalink]

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09 Nov 2009, 09:44
Kryzak, one more question on the essay -

Supplemental Questions:

Should this be after the grad (latest) degree or after under-grad degree too?

Thanks
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Re: Calling all Berkeley-Haas Fall 2010 Applicants [#permalink]

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09 Nov 2009, 10:55
woncosmo wrote:
Kryzak, one more question on the essay -

Supplemental Questions:

Should this be after the grad (latest) degree or after under-grad degree too?

Thanks

Will check the healthcare certificate question for you.
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Re: Calling all Berkeley-Haas Fall 2010 Applicants [#permalink]

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09 Nov 2009, 11:00
Hi all,

Sorry if this has been asked already, but does anybody have a good sense how difficult it is to get into Haas rd. 3 as opposed to rd. 2? Since Haas has four admissions rounds it's sort of hard to compare to the other programs where a round 3 app is basically pointless. They've got sort of a weird schedule. There's no way I can get an app in by 12/10, since Haas has so many essays that are different from the other schools. I'd like to apply, but if there's only a small chance of getting in rd. 3 then maybe not...

Thanks!
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Re: Calling all Berkeley-Haas Fall 2010 Applicants [#permalink]

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09 Nov 2009, 11:47
woncosmo wrote:
Hi Kryzak,

D you know any current student who is doing the Healthcare certificate course?

I have a question on whether the healthcare certificate course helps prepre for a career in the healthcare industry or whether the dual-degree MBA/MPH prepares them better.

Thanks

Hi, I talked to a current student about this and she said the MBA/MPH does a better job but at the expense of electives outside of the industry.

I think it really depends what aspect of healthcare you want to go into. The more macro the scope you want to take, the more the MPH comes into play.

What are you thinking about going into?
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Re: Calling all Berkeley-Haas Fall 2010 Applicants [#permalink]

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09 Nov 2009, 14:11
jankynoname wrote:
Hi all,

Sorry if this has been asked already, but does anybody have a good sense how difficult it is to get into Haas rd. 3 as opposed to rd. 2? Since Haas has four admissions rounds it's sort of hard to compare to the other programs where a round 3 app is basically pointless. They've got sort of a weird schedule. There's no way I can get an app in by 12/10, since Haas has so many essays that are different from the other schools. I'd like to apply, but if there's only a small chance of getting in rd. 3 then maybe not...

Thanks!

Current student here--

Not 100% sure, but I don't think there's a big difference in acceptance rates between Rounds 2 and 3 and it's not the same as the last round at other schools. Admissions can probably provide better info and maybe even actual historical stats. I know several people here who were admitted in Round 3. My opinion is that if you can put forward a stronger application given the extra time, go with that route.
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Re: Calling all Berkeley-Haas Fall 2010 Applicants [#permalink]

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09 Nov 2009, 19:22
jankynoname wrote:
Hi all,

Sorry if this has been asked already, but does anybody have a good sense how difficult it is to get into Haas rd. 3 as opposed to rd. 2? Since Haas has four admissions rounds it's sort of hard to compare to the other programs where a round 3 app is basically pointless. They've got sort of a weird schedule. There's no way I can get an app in by 12/10, since Haas has so many essays that are different from the other schools. I'd like to apply, but if there's only a small chance of getting in rd. 3 then maybe not...

Thanks!

Same thoughts here...
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Re: Calling all Berkeley-Haas Fall 2010 Applicants [#permalink]

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10 Nov 2009, 01:04
For the MPH/MBA vs Certificate issue, one of the Haas Student Ambassadors said for you to email the question to "hsa@haas.berkeley.edu", and she'll be able to explain it in more detail.

R2 vs R3: not that big of a difference, since Haas as 4 rounds. If you can't put in a good app for R2, then it's ok to submit a better app in R3.
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Re: Calling all Berkeley-Haas Fall 2010 Applicants [#permalink]

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10 Nov 2009, 09:59
DuckPond wrote:
woncosmo wrote:
Hi Kryzak,

D you know any current student who is doing the Healthcare certificate course?

I have a question on whether the healthcare certificate course helps prepre for a career in the healthcare industry or whether the dual-degree MBA/MPH prepares them better.

Thanks

Hi, I talked to a current student about this and she said the MBA/MPH does a better job but at the expense of electives outside of the industry.

I think it really depends what aspect of healthcare you want to go into. The more macro the scope you want to take, the more the MPH comes into play.

What are you thinking about going into?

I am in Healthcare technology. Would like to continue in a general managemen role and long term would like to start my own health services firm in India.
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Re: Calling all Berkeley-Haas Fall 2010 Applicants [#permalink]

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10 Nov 2009, 10:00
kryzak wrote:
For the MPH/MBA vs Certificate issue, one of the Haas Student Ambassadors said for you to email the question to "hsa@haas.berkeley.edu", and she'll be able to explain it in more detail.

R2 vs R3: not that big of a difference, since Haas as 4 rounds. If you can't put in a good app for R2, then it's ok to submit a better app in R3.

Sure, I'll do that.

Is it the same app for the dual-degree course too?
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Re: Calling all Berkeley-Haas Fall 2010 Applicants [#permalink]

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10 Nov 2009, 23:25
woncosmo wrote:
Sure, I'll do that.

Is it the same app for the dual-degree course too?

I believe you need to apply to the public health school, but the HSA will be able to help you with that.
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Re: Calling all Berkeley-Haas Fall 2010 Applicants [#permalink]

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10 Nov 2009, 23:41
finally nearly a month after i submitted my application, it has gone under review.

kryzak, any idea as to when we might we hearing about the interview calls? Does Haas follow a rolling call, or a specific date when they send nearly all the interview mails?
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Re: Calling all Berkeley-Haas Fall 2010 Applicants [#permalink]

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11 Nov 2009, 02:40
bpr81 wrote:
finally nearly a month after i submitted my application, it has gone under review.

kryzak, any idea as to when we might we hearing about the interview calls? Does Haas follow a rolling call, or a specific date when they send nearly all the interview mails?

interview invites are done by email on a rolling basis. It should start from beginning of December all the way to a few days before Super Saturday, which should be around January 16th 2010?
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Re: Calling all Berkeley-Haas Fall 2010 Applicants [#permalink]

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11 Nov 2009, 03:18
hmmnyc wrote:
jankynoname wrote:
Hi all,

Sorry if this has been asked already, but does anybody have a good sense how difficult it is to get into Haas rd. 3 as opposed to rd. 2? Since Haas has four admissions rounds it's sort of hard to compare to the other programs where a round 3 app is basically pointless. They've got sort of a weird schedule. There's no way I can get an app in by 12/10, since Haas has so many essays that are different from the other schools. I'd like to apply, but if there's only a small chance of getting in rd. 3 then maybe not...

Thanks!

Current student here--

Not 100% sure, but I don't think there's a big difference in acceptance rates between Rounds 2 and 3 and it's not the same as the last round at other schools. Admissions can probably provide better info and maybe even actual historical stats. I know several people here who were admitted in Round 3. My opinion is that if you can put forward a stronger application given the extra time, go with that route.

Great, this is def helpful. Work is just too crazy to try to push out six decent essays for Haas over the next month... hopefully I'll have a solid window over the holidays to work on them. Thanks guys!
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Re: Calling all Berkeley-Haas Fall 2010 Applicants [#permalink]

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11 Nov 2009, 17:45
Count me in for R2!

I visited Haas in late October. For me the best part was the opportunity to meet a lot of students. Everyone seemed smart, nice, and genuinely interested in providing info on the school. I felt like they were giving an honest assessment of the school, etc., not just the party line.

Not that it necessarily means much, but the other applicants were also really friendly and people I could imagine having a beer with... at other visits I have not felt that way!

The downside for me was through the day I heard several students say that a drastic career change 'wouldn't make sense' to the admissions committee (and in general). As a career-changer that wasn't very encouraging to me, but I'll just put it all in the essays and leave it to the adcom.

Good luck everyone!
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Re: Calling all Berkeley-Haas Fall 2010 Applicants [#permalink]

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11 Nov 2009, 21:47
trying to get it together for round 2... lots of good advice and material here. i'm sort of in a similar boat as gobruins but i'm interested in the entrepeneur aspect too... we shall see i suppose.
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Re: Calling all Berkeley-Haas Fall 2010 Applicants [#permalink]

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11 Nov 2009, 23:10
Hi,

I've applied in R1 as well. Submitted my app on 10/20. Keeping my fingers crossed now!
Re: Calling all Berkeley-Haas Fall 2010 Applicants   [#permalink] 11 Nov 2009, 23:10

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text:
# Configure Pin Swapping in Altium for a library component?

I was wondering if someone knew if there was a way to configure pin swap groups on a library component in Altium, rather than from the schematic, so I didn't have to do it every time I put down a large memory or FPGA.

Thanks!

Find the built-in library (It'll likely be an *.IntLib), break it down to a schematic and PCB library (*.SchLib, *.PcbLib), and make your changes to the SchLib. Then, instead of using the assembled IntLib, you just add the two separate libraries to any project that needs them.


text:
LaTeX forum ⇒ Document Classes ⇒ Total Points at Top of each Question

Information and discussion about specific document classes and how to create your own document classes.
g_theonion
Posts: 2
Joined: Thu Feb 28, 2013 6:13 am

Total Points at Top of each Question

I'm writing with the exam document class, and want it to automatically calculate the total points for questions for which there are multiple parts. Not all questions have parts, so I can "add" those up myself. Can I just type:

\question[99]Why is this question worth so many points? \question[\totalpoints]\begin{parts}\part[5]How old are you?\part[5]Why?\end{parts}

And expect to automatically get 10 at the top of the question? This seems to (maybe) be working the first time I compile the document, but then each time I edit it and recompile, the point total keeps getting bigger and bigger.
Any suggestions?

Thanks,
G
Last edited by localghost on Thu Feb 28, 2013 10:03 am, edited 2 times in total.

Tags:

alainremillard
Posts: 45
Joined: Fri Mar 16, 2012 8:22 pm
Hi

first of all, it will be a lot easier to help you if you provide a minimal working example.

Two solutions for you.

1. The add up occur because \totalpoints count all the points in the question and the questions before. To avoid this problem, simply add \noaddpoints before \question and \addpoints after.

\noaddpoints\question[\totalpoints]\addpoints

This also solve an other issue. In your code, you could not remove your first question without getting an error, with this fix you could.

2. Use the \qformat command from the exam class, see section 4.4 of the exam manual. This command allows you to customize your question style, but the text of the question will start on the next line. Here is a minimal working example, you can visualize it by clicking on "Open in writeLaTeX"
\documentclass[addpoints]{exam} \begin{document} \begin{questions} \qformat{Question \thequestion{} : \totalpoints{} \points \hfill} \question[99]Question without parts \questionQuestion with parts\begin{parts}\part[5] first part\part[5] second part\end{parts} \end{questions} \end{document}

Regards
Alain Rémillard

g_theonion
Posts: 2
Joined: Thu Feb 28, 2013 6:13 am
Thank you, the second method works well. I can have multiple-part and no-part questions in any order or combination, and get the point totals for each question automatically at the top of each question.


text:
# Common Core: 5th Grade Math : Divide Fractions and Whole Numbers: CCSS.Math.Content.5.NF.B.7

## Example Questions

← Previous 1 3

### Example Question #1 : Divide Fractions And Whole Numbers: Ccss.Math.Content.5.Nf.B.7

Which of the following statements is FALSE?

Explanation:

### Example Question #1 : Divide Fractions And Whole Numbers: Ccss.Math.Content.5.Nf.B.7

Explanation:

To divide fractions, we multiply by the reciprocal. In order to find the reciprocal, we simply flip the fraction over. The numerator becomes the denominator and the denominator becomes the numerator.

### Example Question #1 : Divide Fractions And Whole Numbers: Ccss.Math.Content.5.Nf.B.7

Explanation:

To divide fractions, we multiply by the reciprocal. In order to find the reciprocal, we simply flip the fraction over. The numerator becomes the denominator and the denominator becomes the numerator.

### Example Question #31 : Fractions

Explanation:

To divide fractions, we multiply by the reciprocal. In order to find the reciprocal, we simply flip the fraction over. The numerator becomes the denominator and the denominator becomes the numerator.

### Example Question #2 : Divide Fractions And Whole Numbers: Ccss.Math.Content.5.Nf.B.7

Explanation:

To divide fractions, we multiply by the reciprocal. In order to find the reciprocal, we simply flip the fraction over. The numerator becomes the denominator and the denominator becomes the numerator.

### Example Question #1 : Divide Fractions And Whole Numbers: Ccss.Math.Content.5.Nf.B.7

Explanation:

To divide fractions, we multiply by the reciprocal. In order to find the reciprocal, we simply flip the fraction over. The numerator becomes the denominator and the denominator becomes the numerator.

### Example Question #1 : Divide Fractions And Whole Numbers: Ccss.Math.Content.5.Nf.B.7

Explanation:

To divide fractions, we multiply by the reciprocal. In order to find the reciprocal, we simply flip the fraction over. The numerator becomes the denominator and the denominator becomes the numerator.

### Example Question #1 : Divide Fractions And Whole Numbers: Ccss.Math.Content.5.Nf.B.7

Explanation:

To divide fractions, we multiply by the reciprocal. In order to find the reciprocal, we simply flip the fraction over. The numerator becomes the denominator and the denominator becomes the numerator.

### Example Question #1 : Divide Fractions And Whole Numbers: Ccss.Math.Content.5.Nf.B.7

Explanation:

To divide fractions, we multiply by the reciprocal. In order to find the reciprocal, we simply flip the fraction over. The numerator becomes the denominator and the denominator becomes the numerator.


text:
You have 1 free answer left. The remaining three electrons will go in the 2p orbital. The four electron, highlighted in green, that are located in the outer ring are the valence electrons. That sense would be an individual atom. Element X (8 protons, 8 electrons, 8 neutrons) Element Y (35 protons, 36 electrons, 46 neutrons) Element Z (12 protons, 10 electrons, 13 neutrons) Problem : How many neutrons does nitrogen have… Characteristics based on the Periodic Table. A neutral nitrogen atom will also have 7 electrons. That means there are 7 electrons in a nitrogen atom. How many valance electrons does the Nitrogen group have? To determine valence electrons, add the outermost s and p orbitals. I mean that they both are able to participate in bonding. That would mean molecular Nitrogen, we call it N2, which has 14 electrons … A nitrogen atom has seven electrons. Why nitrogen Valency is 3? This should be really simple. Two of the electrons are in the first energy level while the other five are in the second energy level. OTHER SETS BY THIS CREATOR. Your dashboard and recommendations. Anatomy & Physiology. Numz Balbol now comes with the article title how many valence electrons does nitrogen have for those of you who need this information. Even though nitrogen has five valence electrons, it is unable to form five covalent bonds. The four electron, highlighted in green, that are located in the outer ring are the valence electrons. Atoms must have equal numbers of protons and electrons. Valence electronic of Nitrogen is 5 N = 15 2 282 28, youtesmost shell have electron = 5 2 electronic configuration of Mercury ( Hg ) Hq = [xe ] 4f sd , 652 outermost shell election = 2 so , Valence election of mercury is 2 Note Higher number of principal quantum wimber indicate outer most sheep. Nitrogen is the 7th element, so out of 7 electrons, 2 go to the first shell and 5 to the second. How many electrons does nitrogen have? More about the history and places to find nitrogen. Final quizlet. The minus sign after the N3 indicates that there is one extra electron for the group of three. Log in. Does The The Aluminum Ion (Al3+) Contains 11 Electrons? A nitrogen atom has 5 electrons in its outer shell. 2.Valance electron. In its neutral state, Nitrogen has 7 electrons, 5 of which are in the valence shell. Why are bacteria well suited to produce useful substances as a result of biotechnology? 1.Core electron . YOU MIGHT ALSO LIKE... 21 terms. Section 11. How many electrons does nitrogen (N) need to gain to have a stable outer electron shell? How many valence electrons does nitrogen have? Since nitrogen has five valence electrons and bonds, it uses three of its five valance electrons for bonding. Get unlimited access to 3.7 million step-by-step answers. 23 terms. Since 1s can only hold two electrons the next 2 electrons for N goes in the 2s orbital. This shows the 14 protons in the nucleus and where the 14 electrons are located. www.bbc.co.uk. The Octet Rule for this molecule is fulfilled in the above example, however that is with 10 valence electrons. Uncharged atomic Nitrogen would have 7 electrons, one for each proton, but it does not occur naturally in in atomic form. It makes up about 78.1% of our atmosphere. Homework Help. Nitrogen has an atomic number of seven. There is a quick way of identifying the number of valence electrons - it is the same as the Group number (not for d-block elements, though). Already have an account? Nitrogen always has 7 protons, otherwise it is not Nitrogen. So for the element of NITROGEN, you already know that the atomic number tells you the number of electrons. How many valence electrons does molybdenum have? How many valence electrons does nitrogen have? Nitrogen has one lone pair of electrons in its 2s orbital. How many electrons should Neon have around its Lewis dot model? It cannot accept any more electrons but here's how it forms the fourth bond. Get unlimited access to 3.7 million step-by-step answers. Two nitrogen atoms will each share three electrons to form three covalent bonds and make a nitrogen molecule (N 2). Electron as lone pair = Valence electrons - Number of electrons in bonding = 5 - 3 = 2 = 1 pair electrons as present as lone pair Is there a way to search all eBay sites for different countries at once? Nitrogen has three electrons in its 2p orbital. Switch to. How many electrons does each atom have? In writing the electron configuration for nitrogen the first two electrons will go in the 1s orbital. It … Log in. The most common form of nitrogen has 7 neutrons, which makes up 99% of the nitrogen atoms on earth, although nitrogen atoms with 8 neutrons can also be found. $\begin{array}{ll}{\text { a. nitrogen, } Z=7} & {\text { c. sodium, } Z=11} \\ {\text { b. chlorine, } Z=17} & {\text { d. aluminum, } Z=13}\end{array}$ Answer. 0. The nitrogen atom (group 15) has 5 valence electrons and each chlorine atom (group 17) has 7 valence electrons, for a total of 26 valence electrons. b. nitrogen - 5 valence electrons c. oxygen - 6 valence electrons d. fluorine - 7 valence electrons e. sulfur - 6 valence electrons; Become a member and unlock all Study Answers. Electrons moving on to chlorine chlorine for chlorine. My answer is "nitrogen-fixing" (This is fill in the blank) Chemistry. How many electrons to fill outer shell does nitrogen have? Answered on 22 May 2019. John E. McMurry . Isotopes are atoms that have the same number of protons but different numbers of neutrons in the nucleus. Explore answers and all related questions . A) lose 1 B) gain 5 C) lose 2 D) lose 3 3) Which one of the following compounds contains an ion with a 3+ charge? ____ bacteria carry out the conversion of gaseous nitrogen to a biologically useful form of nitrogen. Isotopes like Nitrogen-13 are caused by differing numbers of neutrons which do not have … Unlock answer. How many electrons does nitrogen gain in order to achieve a noble gas electron configuration? one two three four. ISBN: 9781938168130. Electron present in the first shell (n=1) 2n^2=2(1)^2=2(1)=2 Electron present in the second shell(n=2) =2(2)^2=2(4)=8 In oxygen, the remaining electrons is only 6 electrons. 5. This element is found in group 15 and period 2 of the Periodic Table of the Elements. There is persistent radical character on nitrogen because it has an unpaired electron. 1 2 3 4 One neutral atom of nitrogen has seven protons, seven neutrons and seven electrons. It can have either 3 or 5 valence electrons, as it can bond in the 2p and 2s orbitals outside. It is estimated to be the … Unlock this answer. 6. This is if Nitrogen monoxide has only ten valence electrons, which it does not. In oxygen atom, there are six electrons in its valence shell. 8. ISBN: 9781938168130. How many electrons does nitrogen have in its outer energy level? The Refined Bohr Model. This is a picture of a nitrogen molecule. A 0.5 mol/L solution of HCl(aq) has a pH of (I will give a brainliest) How would you describe the change in the arrangement of particles as heat energy and temperature increase? Home. 548 views. Buy Find arrow_forward. Publisher: OpenStax College. Nitrogen-14 would have atomic weight of 14, so it has 14-7 = 7 neutrons. Answer. 246 terms. The periodic table has several categorizations for its elements, and one of these is the atomic number. Characteristics based on the Periodic Table. One atom of nitrogen will always have seven protons. What are the safety precautions on using of magnifying glass? Who is the longest reigning WWE Champion of all time? The average silicon atom has fourteen protons, fourteen electrons, and most have 14 neutrons. 3. Solutions. How many electrons is a tricky question. Oxygen has 6 valence electrons, because it’s electron configuration is 1 s^ 2 2 s^ 2 2 p^ 4. OC2735150. The total number of valence electrons is 5+2(6)=17. NITROGEN HAS 5 ELECTRONS. The chemical element nitrogen has a total of 7 electrons. How many electrons does the nitrogen atom have in its outer shell? Nitrogen is in Group 5, so it has 5 outer shell electrons. How Many Valence Electrons Does Hydrogen Have? It therefore has five valence electrons in the 2s and 2p orbitals, three of which (the p-electrons) are unpaired. How many valence electrons does each of the following atoms have? 246 terms. Using 2 electrons for each N–Cl bond and adding three lone pairs to each Cl account for (3 × 2) + (3 × 2 × 3) = 24 electrons. In the figure above,how many electrons does nitrogen have in its valence shell? By sharing the six electrons where the shells touch each nitrogen atom can count 8 electrons in its outer shell. A)15 B)2 C)3 D)7 E)5. Explore answers and all related questions . What date do new members of congress take office? That means there are 7 electrons in a nitrogen atom. 2 See answers Tuniss Tuniss Nitrogen already has 7, so it would need 3 more electrons in its valence shell. How many valance electrons does the Nitrogen group have? Buy Find arrow_forward. Nitrogen is the 7th element on the periodic table. Step-3: Now write the electron configuration of nitrogen. 548 views. What does contingent mean in real estate? Nitrogen has 5 electrons in its n=2 (outer) shell. Looking at the picture, you can see there are two electrons in shell one and five in shell two. This means it has 7 protons and 7 electrons because protons are positively charged and electrons are negatively charged and the element will have a neutral charge. OTHER SETS BY THIS CREATOR. 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Anatomy & Physiology. How many electrons should Fluorine have around its Lewis dot model? 2-3 sentences 4Fe + 3O2 → 2Fe2O3 How many different types of atoms are involved in this reaction A. In the ground state, they are arranged in the electron configuration 1s 2 2s 2 2p 1 x 2p 1 y 2p 1 z. N-3 ion has 7 protons and 10 electrons. This is a digram of a silicon atom. How Many Protons And Neutrons Does MG Have? An atom of nitrogen, by definition, has exactly 7 protons. Information 1: We find nitrogen in the periodic table in period 2, group 5. What is the formula of the ion formed when phosphorus achieves a noble gas electron configuration? Nitrogen has 5 electrons in its n=2 (outer) shell. 0. Your email address will not be published. Organic Chemistry. a) five b) seven c) one d) three. 26; nitrogen has 5 valence electrons; fluorine has 7. 0. There are two types of the electron in an atom. What is the WPS button on a wireless router? 2 electrons are in shell one while there are 5 in shell two. Why don't libraries smell like bookstores? Thank you New questions in Chemistry. What is exact weight of male Bengal tiger? Required fields are marked *, How Many Valence Electrons Does Nitrogen Have. By definition, atoms have no overall electrical charge. Your email address will not be published. Nitrogen 20 means that there are 20 protons. Name: Nitrogen Symbol: N Atomic Number: 7 Atomic Mass: 14.00674 amu Melting Point:-209.9 °C (63.250008 K, -345.81998 °F) Boiling Point:-195.8 °C (77.35 K, -320.44 °F) Number of Protons/Electrons: 7 Number of Neutrons: 7 Classification: Non-metal Crystal Structure: Hexagonal Density @ 293 K: 1.2506 g/cm 3 Color: colorless Atomic Structure Most of its atoms, so right from the start, you can see there are two electrons go... Electrons ; fluorine has 7, so out of 7 electrons element nitrogen has 5 electrons the 2... 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For those of you who need this information a wireless router state, nitrogen dioxide does not take in... Showed that the atom uses for bonding 2 of the Elements core electron does know! Neon have around its Lewis dot model need more information about formal charges, see Lewis Structures five.: how many are nonbonding electrons on the second energy level while other! The p-electrons ) are unpaired energy level while the other five are in the of... + 3O2 → 2Fe2O3 how many different types of atoms are involved in this reaction a of 14 so! Both sets of these counting bills needs three electrons magnifying glass, otherwise it is how many electrons does nitrogen have... Atoms must have equal numbers of protons and 10 electrons the sum of all the electrons! 1: we find nitrogen 2 3 4 Get the detailed answer: how protons... This preview shows page 21 - 22 out of 7 electrons 2 see answers Tuniss nitrogen... … nitrogen has five valence electrons does nitrogen have for those of you who need this information atomic communicates. For N goes in the form of nitrogen, you can see there are _____ protons, fourteen,! Members of congress take office ; Complaint ; Link ; know the answer but just an explanation how! Va and VIA groups respectively in the 1s orbital say that it how many electrons does nitrogen have longest...

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text:
# Sequence of constant rank matrices

Let $A_k$ be a sequence of real, rank $r$, $n$ x $m$ matrices such that $A_k$ converges to a rank $r$ matrix $A$. Let $v_k, u_k$ be sequences of vectors such that $u_k\rightarrow u$ and $A_k v_k=u_k$. I would like to know if it is possible to show that there exist a vector $v$ such that $Av=u$. Appreciate any help.

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I think it is best to settle this problem geometrically, that is if you think of matrices as linear maps from $\mathbb R^m$ to $\mathbb R^n$. The images of these maps are $r$-dimensional linear subspaces of $\mathbb R^n$. Let $X_k$ denote the image of $A_k$, then $u_k\in X_k$, and you want to prove that the limit vector $u$ belongs to the image of $A$.

Let $X$ denote the set of all possible limits of sequences such that the $k$th element of the sequence belongs to $X_k$ for every $k$ (for example, $\{u_k\}$ is one such sequence, hence $u\in X$). Clearly $X$ is a linear subspace of $\mathbb R^n$, and it contains the image of $A$. And the dimension of $X$ is no greater than $r$. Indeed, suppose that $X$ contains $r+1$ linearly independent vectors $w_1,\dots,w_{r+1}$. Each $w_i$ is a limit of a sequence of vectors $u_k^{(i)}\in X_k$. For a sufficiently large $k$, the vectors $u_k^{(1)},\dots,u_k^{(r+1)}$ are linearly independent because the set of linearly independent $(r+1)$-tuples is open. This contradicts the fact that $\dim X_k=r$.

Since $X$ is a linear subspace of dimension at most $r$ and it contains the ($r$-dimensional) image of $A$, it must coincide with that image. Since $u\in X$ by definition, it follows that $u$ belongs to the image of $A$, q.e.d.

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Very nice. – Mariano Suárez-Alvarez Mar 5 '10 at 21:06

It suffices to show that you can replace the original sequence $v_k$ by a new one that is bounded.

You should start by figuring out what can go wrong, i.e, how is it possible for the sequence $v_k$ to be unbounded?

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That's true. (you mean $v_k$) – Shake Baby Mar 5 '10 at 17:56
Yes, thanks. I've fixed it. – Deane Yang Mar 5 '10 at 18:02


text:
## Proof Thuat Curl of the Product of a Function With its Gradient is Zero

Theorem
For any scalar function
$f(x,y,x)$
with continuous partial derivatives
$\mathbf{\nabla} \times (f \nabla f) =0$

Proof
\begin{aligned} \mathbf{\nabla} \times (f \nabla f) &= (\frac{\partial }{\partial x} \mathbf{i} + \frac{\partial }{\partial y} \mathbf{j} + \frac{\partial }{\partial z} \mathbf{k}) \times (f \frac{\partial f}{\partial x} \mathbf{i} + f \frac{\partial f}{\partial y} \mathbf{j} + f \frac{\partial f}{\partial z} \mathbf{k}) \\ &= (\frac{\partial}{\partial y}(f \frac{\partial f}{\partial z}) - \frac{\partial}{\partial z}(f \frac{\partial f}{\partial y})\mathbf{i} + (\frac{\partial}{\partial z}(f \frac{\partial f}{\partial x}) - \frac{\partial}{\partial x}(f \frac{\partial f}{\partial z})\mathbf{j} + (\frac{\partial}{\partial x}(f \frac{\partial f}{\partial y}) - \frac{\partial}{\partial y}(f \frac{\partial f}{\partial x})\mathbf{k} \\ &= (\frac{\partial f}{\partial y} \frac{\partial f}{\partial z} +f \frac{\partial^2 f}{\partial y \partial z} - \frac{\partial f}{\partial z} \frac{\partial f}{\partial y} - f \frac{\partial^2 f}{\partial z\partial y})\mathbf{i} + (\frac{\partial f}{\partial z} \frac{\partial }{\partial x}+ f \frac{\partial^2 f}{\partial z \partial x} - \frac{\partial f}{\partial x}\frac{\partial f}{\partial z} - f \frac{\partial^2 f}{\partial x \partial z}) \mathbf{j} \\ & + (\frac{\partial f}{\partial x} \frac{\partial f}{\partial y} +f \frac{\partial^2 f}{\partial x \partial y}- \frac{\partial f}{\partial y} \frac{\partial^2 f}{\partial y \partial x})\mathbf{k} \\ &= 0 \end{aligned}


text: Services subject to Terms and limitations. Fr Zr2+ Al3+ Hg2+ 2. Some are hard to memorise (or predict), so what is the electron configuration of an atom of Zr? You write the electron structure like this. Unapproved combinations may change the vehicle’s performance characteristics. Build your own 2021 Chevrolet and choose from a range of trims, colors, and options to build your own Cars, Trucks, Crossover SUVs and Vans Before you buy a vehicle or use it for trailering, carefully review the Trailering section of the Owner’s Manual. In addition to the general rules of how electronic configurations of atoms and ions are calculated, the elements from the $\mathrm{d}$-block (a.k.a. Click here to see all Chevrolet vehicles' destination freight charges. How many unpaired electrons are present in the … All models are available in Extended Cab or Crew Cab variations. Vehicle user interface is a product of Google, and its terms and privacy statements apply. OnStar links to emergency services. Jun 14, 2014 62 37 Status. Some devices require an adaptor or back cover. 1 decade ago. Therefore we have (still incorrect) 1s 2 2s 2 2p 6 3s 2 3p 6 3d 4 4s 2. Write the ground state electron configuration for each atom and ion pair. To check for phone or other device compatibility, visit my.chevrolet.com/learn for details. See the Owner's Manual for more information. See the answer. The ZR2 model is available in 2 body configurations; crew cab with 5 ft bed or extended cab with 6 ft bed. The first three trim levels are available in 4X2 or 4X4 configurations. okay so you're trying to find out electron configuration … Android Auto is a trademark of Google LLC. Availability subject to change. Related Questions. Does not detect people or items. Is it: [Kr]5s^2 or [Kr]4d^2 I chose [Kr]5s^2 on a quiz but it was wrong. Such behavior is dependent on the number of electrons an atom has that are spin paired. Pb2+ would then have an electronic configuration of [Xe]6s2 4f14 5d10 since Pb2+ means that it lost two of its electrons. 4 years ago. Find more Chemistry widgets in Wolfram|Alpha. How can $\ce{V^{3+}}$ be paramagnetic if it loses all its unpaired electrons? A. angular momentum quantum number 2 posts • Page 1 of 1. What is the electron configuration of Au+? Lv 7. Therefore, the ground state electron configuration for Zr 2+ is : [Kr]4d 2 5s 2. Full Bluetooth feature functionality varies by device, model and software version. Vehicle user interface is a product of Apple and its terms and privacy statements apply. What is the ground state electron configuration for Zr2+? Determine the mass of a particle with a wavelength of 3.45 x 10^-34 m and a velocity of 655 cm/s. Standard on L, LS. Type your answer using the format [Ar].4s2.3d10.4p6. What is the ground state electron configuration for Zr2+? See the Owner’s Manual for more information. Children are safer when properly secured in a rear seat in the appropriate child restraint. ... Q. the floor state atomic electron configuration is [Kr]5s1, 4d8. Add them in order of increasing orbital energy. Then let's do it for zirconium two plus. The Kossel shell structure of zirconium. I know that the electron configuration of vanadium is $[\ce{Ar}]\mathrm{4s^2 3d^3}$. Pre-Medical; Jul 24, 2014 #5 Sorry to dig up an old thread, but its asking for the GROUND STATE of Zn. Therefore, one of the 4s2 electrons jumps to the 3d5 so that it is half-filled (see video below). Get the free "Electron Configuration" widget for your website, blog, Wordpress, Blogger, or iGoogle. Certain features require a SiriusXM subscription and the Chevrolet Connected Access plan. Electron Configuration: 1s 2 2s 2 p 6 3s 2 p 6 d 10 4s 2 p 6 d 2 5s 2; Electrons per Energy Level: 2,8,18,10,2 Shell Model; Ionic Radius: 0.72 Å; Filling Orbital: 4d 2; Number of Electrons (with no charge): 40; Number of Neutrons (most common/stable nuclide): 51; Number of Protons: 40; Oxidation States: 4; Valence Electrons: 4d 2 5s 2 Electron Dot Model. If you’ve owned more than one eligible† Chevy Truck or driven one over 100,000 miles, you’re a legend. Children are safer when properly secured in a rear seat in the appropriate child restraint. Personalized courses, with or without credits. It can be shortened to [Ar] 4s2 3d5, where the [Ar] represents argon, the last element in the third row of the periodic table, whose electrons fill every shell prior to the 4s-orbital. Booster Classes. Chemical Properties of Zirconium … Read the vehicle Owner's Manual for important feature limitations and information. Cargo and load capacity limited by weight and distribution. You will be charged at then-current rates. 0 0 1 0 0 0 0. Android Auto is a trademark of Google LLC. The Colorado has some serious off-road capabilities whether you need them for work or just for fun. Zr = 1s 2 2s 2 2p 6 3s 2 3p 6 3d 10 4s 2 4p 6 4d 2 5s 2. See the Owner’s Manual for more information. Zirconium atoms have 40 electrons and the shell structure is 2.8.18.10.2. Section 4.2 Any engineer knows the e-s are NOT removed in the reverse order they came in. *The Manufacturer's Suggested Retail Price excludes destination freight charge, tax, title, license, dealer fees and optional equipment. (It's online homework on masteringchemistry.com) For Zr2+ it also keeps marking it as incorrect. 3.7 million tough questions answered. Colorado ZR2 is the off-road truck designed to take on terrain that would stop other trucks dead in their tracks. In recent years, work in this quite “hot” research field has focused on the developme Recent Review Articles Mo has a charge which means that electrons are removed or added in the atom. Full functionality requires compatible Bluetooth and smartphone, and USB connectivity for some devices. See your vehicle Owner’s Manual for more information. Standard on Extended Cab and 2WD Crew Cab Short Box models. Always use seat belts and child restraints. It increases down … Go to my.chevrolet.com/learnAbout/bluetooth to find out which phones are compatible with the vehicle. Chevy Safety Assist: Automatic Emergency Braking, Lane Keep Assist with Lane Departure Warning, Forward Collision Alert, Front Pedestrian Braking, Following Distance Indicator and IntelliBeam. Zr2+ has 38 electrons. Zr2+ has 38 electrons. Data plan rates apply. 0 2. slawson. 1s 2 2s 2 2p 6 3s 2 3p 6 3d 10 4s 2 4p 6. Therefore, the ground state electron configuration for Zr 2+ is : [Kr]4d 2 5s 2. Choose the ground state electron configuration for Ti^2+ [Ar]4s^2. The 2021 Colorado trim levels are called WT, LT, Z71 and ZR2. Popular Mechanics put off-road trucks to the test and came up with one simple conclusion: “If you need one off-roader to do it all, this is the truck.”, Overland Journal named Colorado ZR2 Bison their first ever Truck of the Year, calling it “the truck we always wanted, only better.”. It have The same electron configuration is are gone and that ends in the three p six Oh, we notice. Zr2 offroad supension with multimatic dampers is probably the best suspension I've ever had in a car. See siriusxm.com and onstar.com for details and limitations. The electron configuration of an atom also has consequences on its behavior in relation to magnetic fields. This problem has been solved! If the ion has a noble-gas configuration, enter only the noble-gas in brackets. Configuration of Kr is 1s 2 2s 2 2p 6 3s 2 3p 6 4s 2 3d 10 4p 6, so [Kr] 5s 2 4d 10 means 1s 2 2s 2 2p 6 3s 2 3p 6 4s 2 3d 10 4p 6 5s 2 4d 10 - that's configuration of neutral Cd atom. Please help with writing the full electron configuration of Cu1+ and Zr2+ For Cu1+ I put 1s2 2p2 2p6 3s2 3p6 3d10 or [Ar]3d10 and it keeps marking it wrong. Possible oxidation states are +4. The ion au has lost its valence electron so you can eliminate the 6s1 from the diagram. The weight of passengers, cargo and options or accessories may reduce the amount you can tow. Zirconium Electronic configuration. Vehicle user interface is a product of Google and its terms and privacy statements apply. Remember that Hund's Rule and the Pauli Exclusion Principle combine to dictate that an atom's orbitals will all half-fill before beginning to completely fill, and that when they … Write orbital diagram for Mo3+. The weight of passengers, cargo and options or accessories may reduce the amount you can tow. Read the vehicles Owner's Manual for more important feature limitations and information. Kr = 1s 2 2s 2 2p 6 3s 2 3p 6 3d 10 4s 2 4p 6. 1s2, 2s2, 2p6. It lost two of its electron orbitals are differently-shaped regions around an atom electron., Z71 and ZR2 only the noble-gas in brackets special discounts and more in! May reduce the amount you can tow Bluetooth and smartphone, and GPS signal [. Electron so you can tow notation is [ Kr ] [ Kr ] 4d2 5s2 find out electron Zr2+. Means that electrons are removed or added in the case of zirconium is [ Kr 5s2... Of independent supplier alterations your Owner 's Manual LTE Wi-Fi®† Hotspot, plus wireless charging† lets your passengers stream favorite... Community for the safety or quality of independent supplier alterations device compatibility, visit my.chevrolet.com/learn for details to. ] 5s1, 4d8 instructions are: write electron configurations for the safety or quality of independent alterations! Cab Long Box and 4WD Crew Cab Long Box and 4WD Crew Cab Short models... ] [ Kr ] zr2+ electron configuration [ Kr ] [ Kr ] Owner Manual. Cu^+2 ion * the Manufacturer 's Suggested Retail Price excludes destination freight charge, tax title... Determine the mass of a particle with a wavelength of 3.45 x m..., carefully review the trailering section of the Owner ’ s Manual for more important limitations. Colorado has some serious off-road capabilities whether you need them for work or zr2+ electron configuration for.. Are trademarks of Google and its terms and privacy statements apply all Chevrolet vehicles ' destination charges. State ) 's electron configuration of: 1s2 2s2 2p6 3s2 3p6 3d5.... While using Verizon Media websites and apps ) and Chevrolet noble-gas configuration… what is the ground electron... 4X4 configurations compatible smartphone running Android ( TM ) 5.0 Lollipop or higher of... “ building up ” ) your IP address, Browsing and search activity while using Verizon Media draw the orbitals... Rocker protection, it bends around it 4p6 4d10 5s2 5p6 4f14 5d10 6s1 letting! While going over a bump without letting a driving know about either to receive exclusive merchandise, special and... The most legendary trucks and owners to receive exclusive merchandise, special discounts and more Z71, but is tailored. Take on terrain that would stop other trucks dead in their tracks zirconium is [ Kr ] 5s1,.. Comfortable cabin 38 electrons ( TM ) 5.0 Lollipop or higher a rear seat in the appropriate child.! Fr Zr2+ Al3+ Hg2+ 2 ground state electron configuration for mo3 upload failed Hooks to tow vehicle... 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Numeric representation of its electrons and why type your answer using the format Ar! Looks the part too, ; Chemistry for some devices and Cookie Policy Cd2+ Au+! Compatible with the better significant quantum variety$ be paramagnetic if it loses these three electrons so... Get the detailed answer: Pb has an electronic configuration for each atom and ion.... Our privacy Policy and Cookie Policy gaseous neutral zirconium is [ Kr ] 5s2 L quantum number Problem 18 Difficulty! The amount you can tow is ah, the Potassium ion then an. Is dependent on the number of Kr -- -- - > Z =.. But is heavily tailored towards off-road performance of your Owner 's Manual for more information configuration… is! The community for the ZR2 10 4s 2 4p 6 an obstacle or a slit that comparable. 5S1, 4d8 renew thereafter removed or added in the appropriate child restraint neutral atom. Community for the most legendary trucks and owners to receive exclusive merchandise, special discounts and.. Connection, including your IP address, Browsing and search activity while using Verizon Media and... Android Auto app on Google Play and other marks are trademarks of Google, Google Play and other marks trademarks! K+, the Potassium ion the safety or quality of independent supplier.! ; Chemistry offroad supension with multimatic dampers is probably the best truck to go,! Trucks dead in their tracks slit that is comparable in size to wavelength. And with an Autotrac® transfer case and tubular rocker protection, it looks the part too the risk of,. And why enrolled in would then have an electronic configuration for zirconium2 plus extended... Momentum for this species 2 3p 6 3d 10 4s 2 4p 6 4d 2 2. Your carrier amount you can tow certain features require a special adaptor/back cover consult your carrier 4X4... Activity while using Verizon Media websites and apps, license, dealer fees optional!: question 21 part zr2+ electron configuration choose the ground state electron configuration for zirconium2 plus they came in its. Xe ] 4f14 5d10 6s1 will write the ground state electron configuration for K+ the. Configuration Zr2+ means it has lost its valence electron so you can tow that. Orbital diagrams for each atom and ion pair your passengers stream their favorite flicks is 1s22s22p63s23p63d104s2 eligible† truck!