Answer the following question given this paragraph: 

The sum of the calculated atomic radii of sodium and chlorine atoms is 253 pm. The sodium cation is significantly smaller than a neutral sodium atom (102 versus 154 pm), due to the loss of the single electron in the 3s orbital. Conversely, the chloride ion is much larger than a neutral chlorine atom (181 versus 99 pm), because the added electron results in greatly increased electron–electron repulsions within the filled n = 3 principal shell. Thus, transferring an electron from sodium to chlorine decreases the radius of sodium by about 50%, but causes the radius of chlorine to almost double. The net effect is that the distance between a sodium ion and a chloride ion in NaCl is greaterthan the sum of the atomic radii of the neutral atoms.


Q: Transferring what from sodium to chlorine decreases the radius of sodium by about 50%?

 Choices:

- quark

- proton

- neutron

- electron

A:
electron
